Title: Vectors
1Vectors represent quantities that have direction.
Vector quantities are drawn with an arrow. Head-
point of the arrow Tail- the bottom part of the
arrow
2Two vectors are shown
y
x
3Vector A is 6 units long. It is pointing to the
right.
y
x
4Vector A and B are identical.
y
x
5- They are identical
- because
- they are the same length
- and
- pointing in the same direction.
6These vectors are not identical.
y
x
7- They are not identical
- because
- they are not pointing
- in the same direction
- even though they have the
- same length.
8These three vectors are different.
y
x
9Two vectors with their tails together.
y
x
10What is the sum of vector A and B?
y
x
11Put tail of B to head of A
y
x
12The resultant goes from tail of A to head of B.
y
x
13A B B A
y
x
14What is the negative of vector A?
y
x
15It is a vector of same length but pointing in the
opposite direction.
y
x
16What is the value of C - D?
y
x
17C - D C (-D)
y
x
18C - D C (-D)
y
x
19C - D C (-D) E?
y
x
20What is 2 times vector A?
y
x
21It is a vector twice as long.
y
x
22What are the components of C?
y
x
23Complete the Parallelogram
y
x
24Locate the x and y components.
y
x
25Locate the x and y components.
y
x
26Draw a 2nd vector - Add
y
x
27What are the components of S?
y
x
28What are the components of S?
y
x
29What are the components of CS?
y
x
30What are the components of CS?
y
x
31Complete Parallelogram of CS?
y
x
32Find Resultant of CS?
y
x
33C S R ( w/components of R)
34C S R with components of R
35Vector R with its components
36Resolving A Vector Into Its Components
37What we will need
- We will need to be given a vector. The vector we
will use as an example will be
38Drawing the vector
39o
E
39What we will need?
- We will need to be given the direction of the two
components which we will be asked to find.
In this situation, we will find the horizontal
and the vertical components.
40Drawing the Component Directions
Vertical
39o
Horizontal
41Next
- We will find the magnitude in each direction. How?
We will construct a parallelogram with the
diagonal being the vector to be resolved into its
components.
42Completing the Parallelogram
Vertical
39o
Horizontal
43Continuing
- Next we will draw in the component vectors which
we have been asked to find.
44Drawing the Components
Vertical
39o
Horizontal
45Identifying the Sides
Vertical
hyp
opp
39o
Horizontal
adj
46What Trig Function will give the Horizontal
Component?
Vertical
hyp
opp
39o
Horizontal
adj
47Finding The Horizontal Component
48Finding The Vertical Component
Vertical
hyp
opp
39o
Horizontal
adj
49Finding The Vertical Component
50Here Is Another Vector
Block on Frictionless Incline
Gravity Is Acting
22o
51Identify Component Directions
22o
52Vectors at Right Angles Means?
- This means that each component vector will be
independent of the other.
53Completing the Parallelogram
22o
54Draw Component Vectors
Component along plane of ramp
22o
Component Perpendicular to ramp
55All that is left to do is to find the length of
the two components by whatever method you choose.
22o
56Find the Angle ?
?
22o
The correct answer is 22 degrees?
57Next Find the Magnitude of the Two Components
Component along plane of ramp
22o
Component Perpendicular to ramp
58Here Is an Acceleration Vector
You will be asked to find two components that are
not at right angles.
59With Components Directions Identified
85o
29o
60With Parallelogram Completed
85o
29o
61With Component Vectors Drawn
85o
29o
62All that is left to do is to find the length of
the two components.
85o
29o
63Determine the Angles in the Lower Triangle
A
85o
C
66o
85o
29o
64Determine Magnitude of a and b
A
85o
b
c
66o
85o
C
29o
a
B
65A
b
85o
c
66o
85o
29o
C
a
B
66Vector Addition
67Vector Addition
- In this problem we will add three displacement
vectors, first by using a scale drawing and then
by using a TI-83 calculator program called
VADD.
68The Problem
- A police cruiser chasing a speeding motorist
traveled 60 km S, then 35 km E 45o N, and
finally 50 km W. (a) What is the total
displacement of the cruiser?
69Selecting a Scale
Select a scale that will allow you to draw an
arrow to represent each displacement.
- This scale must be large enough to be easy to
work with, yet not so large that the drawing will
exceed the work area.
70Selecting a Scale
- A metric scale will be most useful if it is
divisible by ten.
Possible scale 1 cm 10 km
71Drawing the Vectorsandfinding theresultant
721 cm 10 km
N
Drawing Vectors
E
W
Represent the second displacement
35 km E 45o N
by an arrow 3.5 cm long, with its tail connected
to the head of the first vector.
Represent the first displacement 60 km S
orientated in a north-south orientation with the
arrow at the south end.
Represent the third displacement 50 km W
Draw a line from the tail of the first vector to
the head of the last vector.
Place an arrow on the end of the line where the
line meets the head of the third vector.
Resultant
1
N
3
by an arrow 5 cm long in a west direction.
by an arrow 6 cm long
E
S
2
E
W
731 cm 10 km
N
Find Resultant Displacement
E
W
Resultant
Measure the length of the line with your ruler
Convert this length to the magnitude of the
resultant.
Measured length is 4.3 cm
The resultant is
43 km
741 cm 10 km
N
Find Resultant Direction
E
W
Resultant
Measure the angle that the resultant is from
south.
Then express the direction using proper notation.
Measured angle is
43 km
36o
S 36o W
75- The displacement of the cruiser is
- 43 km S 36o W
76Finding Average Speed
The total distance traveled is
60 km 35 km 50 km 145 km
The time of travel is 1.3 hrs
77Finding Average Velocity
- The time of travel is 1.3 hrs
The displacement is 43 km S 36o W
78Note...
- The vector quantity, displacement, was divided by
a scalar quantity, time. - When dividing a vector quantity by a scalar
quantity, the answer is also a vector quantity
with the same direction as the original vector
quantity.
79Determining Direction
- All vector directions must be specified as
relative to a reference direction.
Use East as your reference direction.
80What is the direction of the vector below?
450 north of east
450
81520 South of West (SW)
520
(180-52) 1280) South of East
82Determining Direction
Angles measured counter-clockwise will be
identified as positive and angles measured
clockwise will be identified as negative.