Title: phy201_5
1Physics 201
5 Some Application of Newtons Laws
- Newtons Second law and Uniform Circular Motion
- Newtons Second law and Nonuniform Circular Motion
- Motion in Accelerated Frames of Reference
- Motion in the Presence of resistive Forces.
2In uniform circular motion the acceleration of
the object is
v
2
ˆ
a
-
r
r
c
ˆ
r
is the unit vector pointing from the
center of motion to the object
What causes this acceleration?
It must be a force
m
v
2
ˆ
F
-
r
r
c
where
m
is the mass of the object.
This force is called the CENTRIPETAL
force
3- Where do centripetal forces come from?
- gravity
- tension
- friction
4W
ma
mg
(
r
)
c
mM
v
2
(
)
G
m
G
is Newtons Gravitational constant
e
r
r
2
GM
v
in order that gravitational force
e
r
sustains uniform circular motion
5The force of gravity continually changes the
direction of motion of the object, thus keeping
it a constant orbit at constant speed as long
as the speed is given by
- If the speed increases the radius of the orbit
increases - If the speed decreases the radius of the orbit
decreases
6If speed increases and length of string is fixed
then the tension increases
7Car turning on flat road
Ff
v
- If the speed increases and the force of friction
does not the radius of turning increases
(skidding outward)
8Car turning on banked road
- 3 situations
- 1 Force of friction plays no role and banking
provides necessary centripetal force - 2 Banking too great and need outward force of
friction - 3 Banking not enough and thus need force of
friction to stop outward motion
N
Ff,out
Fc
Ff,in
?
W
9For turning speed v
,
total centripetal force required
toward center of motion
m
v
2
ˆ
F
-
r
c
r
this force continually deflects velocity to turn
car in circle of radius
r
N
Ff
direction of Ff is determined by the speed v
radius r and banking ?
Fc
?
W
Forces on car
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13Motion in Accelerated Frames of Reference
N
noninertial observer
T
Ffict
W
inertial observer
only seen by noninertial observer
14Motion in the Presence of resistive Forces.
R
-
b
v
consider object dropping in air or a liquid
Total vertical force
b
v
-
mg
d
v
Newtons
2
nd law
Þ
m
b
v
-
mg
dt
d
v
b
v
Þ
-
g
º
Differential Equation
dt
m
which has the solution
(
)
mg
(
)
-
bt
v
t
1
-
e
m
b