Title: Microstructure and Properties II
1Microstructure and Properties II
- MSE 27-302
- Fall, 2002 (2nd mini-course)
- Prof. A. D. Rollett
- http//neon.mems.cmu.edu/rollett/27302/ 27302.html
2Course Content
- 27-302 is the second of a pair of (mini-)courses
that describe the relationship between materials
microstructure and properties. - This course deals mainly with multi-phase
microstructures. There is a strong emphasis on
phase transformations as the basis for
understanding the origin of (useful)
microstructures. - 27-301 dealt mainly with single phase
microstructures and their properties. - Multi-phase materials made through natural
processes will be contrasted with (man-made)
composite materials and biomaterials. - Students are expected to learn a set of technical
skills in addition to improving various
attributes of scientist/engineers
(communications, ethics, how to design
experiments, )
3Topics
- Where does microstructure come from? Phase
transformations, kinetics of transformations, the
Kolmogorov-Johnson-Mehl-Avrami equation. - Properties of Composite materials background
material on glass-ceramics for Lab 1. - Phase transformations driving forces,
thermodynamics of nucleation (precipitation
reactions). - Transformations kinetics of growth a simple TTT
diagram. How to calculate and predict TTT and
CCT diagrams. - The role of interfaces in heterogeneous
nucleation example of the Al-Cu system
sequences of metastable precipitates. - The age-hardening curve methods of measuring
transformations. The similarities between
mechanical hardness and magnetic hardness. - Impact of precipitation on complex properties
example of fatigue as a microstructure-sensitive
property. - More complex diffusive transformations example
of Fe-C system for eutectoid reactions. - Continuous transformations spinodal
decomposition. - Coarsening of two-phase structures effect of
two-phase structures on creep properties
(Ni-alloys as an example). - Competition between transformation mechanisms
discussion of non-diffusive transformations
massive transformations, martensitic
transformations exploitation of martensitic
reactions for shape-memory alloys. - The ultimate in complicated microstructures
introduction to welding and joining.
4Technical topics
- Technical Issues
- S olid state transformations
- Differences between transformations from the
liquid state and transformations starting from
the solid state the influence of crystalline
structure - Driving forces - should the reaction take place?
- Nucleation and growth (thermodynamics, kinetics)
the rate at which reaction takes place - Influence of defects on transformations
- Prediction of temperature-time-transformation
(TTT) curves (and/or continuous-cooling-transforma
tion, CCT, curves) - Military transformations
- Precipitate coarsening
- These topics are some of the underpinnings for
understanding various phenomena that are
important for microstructure-property
relationships.
5Material Properties, Phenomena
- Examples of phenomena for which
microstructure-property relationships are
significant - Age Hardening
- Shape memory effect, alloys
- Alloy optimization
- Multiphase materials and creep
- Energy absorption in structures
- Fatigue resistance
- Exploitation of nanostructured, amorphous
materials - Optimization of Materials Design
- All the technical topics are relevant to
understanding and engineering the phenomena. - Certain material systems are important examples.
6Materials Systems
- Clearly there are too many material systems to
study in one course. Certain systems are very
useful as examples, however. - Al-Cu precipitation, metastable phases, age
hardening, effects of crystal structure,
coarsening - Fe-C-X (steel) allotropic transformations,
eutectoids, military transformations, tempering,
hardenability
7Student Input for 302
- In 27-301, each student was required to make a
short presentation in class. - In 27-302, student input will be sought through
discussion sessions. The objective is to learn
how to apply the understanding of
microstructure-property relationships to a
specific system(s). - The culmination of the student input exercise
will be a discussion of the pros and cons and
changing a given material (for a specific
application). - Discussions will be held in the second half of
the Weds class. - Next we discuss the sequence of steps required.
8Materials Design
- The sequence of steps leading towards the
discussion of materials design - Each student chooses an application for which a
material is critical in at least one component
(Oct. 23rd, Weds). - The application is analyzed to determine which
component is materials-critical (Oct. 30th,
Weds). - The material is analyzed to determine its
microstructure and likely processing history
(Oct. 30th, Weds). - The microstructure-property relationships are
analyzed (Nov. 13th, Weds). - Possible changes to the microstructure are
analyzed for their effect on properties (Nov.
20th, Weds). - Discussion between a pro-change group and a
status-quo group on the merits of optimization
of the material (Nov. 25th, Monday). - Each student writes up a report on materials
optimization.
9Applications
- Stents
- Sutures
- Bone substitute
- Stealth aircraft (Low Observable materials)
- Nuclear reactors (fuels)
- Solar cells
- Light weight armor (ceramic armor)
10302 Jeopardy 1
1. Rank is sum of the rank of the quantities on
each side
4. -RT lnX0/Xe.
Q1. How is the rank of a property tensor
determined from the rank of each related quantity?
Q4. What is the formula for the driving force
for precipitation in a simple 2-phase system?
2. Free energy
5. No nucleation barrier
Q2. What thermodynamic quantity should we use to
predict whether or not a reaction will occur?
Q5. Name a key difference between discontinuous
and continuous phase transformation.
3. 2-fold symmetry axes (diads)
6. Approximately 3 times the yield stress.
Q3. Which symmetry element is found on lt110gt
directions in fcc materials?
Q6. How much greater is the hardness than the
yield stress (same units)?
11302 Jeopardy 2
1. Proportional to undercooling
4. -Hf (?T/Tmelt).
Q1. How is driving force related to undercooling?
Q4. What is the formula for the driving force
for solidification?
2. Difference between the temp. at which the
composition intersects the solvus (liquidus) and
the current temp.
5. Two phases in a composite generally
expand/contract at different rates with ?T.
Q2. How is the undercooling defined?
Q5. What is one cause of residual stress in a
composite material?
3. Einstein notation
6. Differentiate the total energy.
Q3. What is the name for the convention that
states that repeated indices are summed over?
Q6. How do we determine the point at which an
energy release rate is zero?
12302 Jeopardy 3
1. Balance between rates of adding surface
energy and gaining free energy from transformation
4. Because large interfacial energies mean high
barriers to nucleation (and heterogeneous sites,
if available, operate first).
Q1. How does one determine the barrier to
nucleation?
Q4. Why is homogeneous nucleation only observed
in a few cases?
2. In precipitation of pro-eutectoid ferrite,
the thermodynamic term involves the log of a
ratio of terms in (1-X).
5. 16pg3/?GV2.
Q2. Why is the driving force for a eutectoid
decomposition small compared to decomposition of
a simple solid solution (e.g. pro-eutectoid
decomposition of austenite)?
Q5. What is the formula for the critical free
energy of nucleation?
6. It is a volumetric energy and is subtracted
off the chemical free energy for transformation.
3. 2g/?GV
Q3. What is the formula for the critical radius?
Q6. What is the role of elastic energy in
nucleation?
13302 Jeopardy 4
4. The rate increases because of increasing
driving force but then decreases because of
decreasing diffusion rate.
1. 16pg3/?GV-?GS 2
Q1. What is the free energy barrier in the
presence of an elastic energy?
Q4. Why does the growth rate first increase with
undercooling and then decrease?
2. Al2Cu platelets aligned with 100 planes.
5. D ?2C ?C/?t.
Q2. What effect does elastic anisotropy have on
precipitation in the Al-Cu system?
Q5. What is the diffusion equation (w/o source
terms)?
3. Matching of close-packed planes, e.g.
110bcc// 111fcc
6. Linearized gradients.
Q3. What impact does atomic matching have on the
orientation relationship between parent and
product phases?
Q6. What approximation can we make to solve the
diffusion equation for ppt growth in 1D?
14302 Jeopardy 5
4. Solute diffuses from small precipitates to
large ones.
1. The change in concentration around one
precipitate affects the concentration around
adjacent precipitates.
Q1. What is the cause of impingement of
concentration fields?
Q4. What causes coarsening of precipitates?
2. Grain boundaries act as short circuit
diffusion paths for transport of solute to
precipitates.
5. ltR3(t)gt - ltR3(t0)gt k t.
Q2. Why do precipitates grow more rapidly on
grain boundaries than in the bulk (at low
temperatures)?
Q5. What is the relationship between radius and
time for coarsening?
3. Decreasing radius of a precipitate raises its
solubility.
6. x ?C0/ (Cb - Ce) v(Dt).
Q3. What does the Gibbs-Thomson effect do to
precipitates?
Q6. What is the relationship between ppt size
and time for diffusion controlled growth in 1D?
15Office hours, CAs
- Office hours will be as in 301 330-5 Monday,
1130-1230 Weds/Fri. - The CA for the Lab is Ms. Mitra Taheri.
16Exam Rules
- No books no lecture notes no computers
- One cheat sheet with notes (both sides if you
like) hand in the the cheat sheet with the exam
paper/book. You must write the notes yourself
copying and pasting is OK, but not literal cut
and paste. The idea of the cheat sheet is for
you to go through the course material and extract
the most important ideas, equations, etc. - Calculator OK (but not a device, such as a Palm
Pilot, in which you can store lecture notes etc.)
1727-302, Labs
- Lab 1 Investigation of precipitation in
glass-ceramics. Purpose to demonstrate the
effect of phase transformation on mechanical and
optical properties. - Lab 2 Short experiments on crystallization of
amorphous metals, magnetic domain imaging and age
hardening curves.
18Calendar 302
Please consult the separate file posted on the
website.
19Topic List 302
- Where does microstructure come from? Phase
transformations, kinetics of transformations, the
Kolmogorov-Johnson-Mehl-Avrami equation. - Properties of Composite materials rule of
mixtures. Background material on glass-ceramics
for Lab 1. - Phase transformations driving forces,
thermodynamics of nucleation (precipitation
reactions). - Transformations kinetics of growth a simple TTT
diagram. - The role of interfaces in heterogeneous
nucleation example of the Al-Cu system
sequences of metastable precipitates. - The age-hardening curve methods of measuring
transformations. - Impact of precipitation on complex properties
example of fatigue as a microstructure-sensitive
property. - More complex diffusive transformations example
of eutectoid reactions. - Continuous transformations spinodal
decomposition. - Coarsening of two-phase structures effect of
two-phase structures on creep properties
(Ni-alloys as an example). - Competition between transformation mechanisms
discussion of non-diffusive transformations
massive transformations, martensitic
transformations exploitation of martensitic
reactions for shape-memory alloys. - Parallels between magnetic and mechanical
hardness. - The ultimate in complicated microstructures
introduction to welding and joining not
addressed in 2001. - Cellular structures foams, wood, bread(!), bone,
composites. - Guest Lecture (Prof. E. Towe) quantum dot
structures in semiconductors.
20Sample problem 1
- KJMA equation (transformation kinetics) an
alloy is recrystallized at 2 different
temperatures, 400 and 500C. The KJMA exponent
is found to be 2. By interpolating the f vs time
data, the time required for 50 recrystallization
is found to be 30s and 5m, respectively.
Estimate the activation energy for the process. - Answer use the form of the equation from the
homeworkt-ln(.5)/k1/ngt k -ln(.5)/ tn
Assume kk0exp-Q/RT gt -Q/RTln(k/k0)So,
-QRT1ln(k1/k0) RT2ln(k2/k0)-Q/R(1/T1-1/T2)
ln(k1/k2)QR ln(t12/t22) /(1/T1-1/T2)Q 8.31
ln(302/3002) (1/673 - 1/773)Q 199,086 J/mole
21Sample Problem 2
- Composites a certain type of (cheap) plywood is
made up of two thin outer sheets of a high
density wood with a lower density filler material
inside. If the modulus of the cladding is 10
Gpa, and each sheet is 2mm thick, and the modulus
of the filler layer is 100 Mpa with a thickness
of 10mm, what is the stiffness of the plywood,
measured through the thickness? - Apply elementary isostress theory. Modulus
VA(1/EA) VB(1/EB) 1/14 (4/10 10/0.1)
GPa 0.14 GPa. - The composite is dominated by the softer filler
layer because of the loading method. It would be
much stiffer if it were loaded on its edge.
22Sample Problems 3
- Nucleation in a problem on solidification, the
latent heat is 50,000 J/mole and the melting
point (liquidus) is 850C. The molar volume is
106 m-3. No appreciable nucleation is observed
in a carefully controlled experiment in which
only homogeneous nucleation can occur. What is
the volumetric driving force for an undercooling
of 50C? - Answer - use the expression for driving force
where the latent heat (enthalpy) is known.
?GV(?H?T/Te)/Vm 50,000.50/(850273)/10-6
2.23.109 J.m-3 - Based on this information, what is the apparent
interfacial energy? - Answer assume that ?G 60kT at the point where
nucleation occurs 601.38.10-23112316pg3/3
/(2.23.109)2so, g 3v(0.276) 0.65 J.m-2.
23Sample Problem 4
- Precipitate growth rates for a precipitate that
is pure element B, and a solvus line described by
log10(XB) 2.853 - 2.875.103/T, where XB is the
composition in atomic , what is the growth rate
at T600C for a matrix composition X0B1.5 1
minute after nucleation has taken place? Assume
1D growth (e.g. of a slab of precipitate
nucleated on a grain boundary). The pre-factor
and activation energy for diffusion of B in A are
7.4.10-5 m2.s-1 and Q217.2 kJ.mole-1,
respectively. - Answer - first calculate the equilibrium
concentration of matrix (alpha) in equilibrium
with the precipitate (beta) XB 0.36Then the
growth rate is given by v?X/2(Xb-Xe) v(D/t)
(1.5-0.36)/2/(100-0.36)v(7.4.10-5exp-217,200/8.
31/873/60) 2.0 10-12 m.s-1, or 7nm per hour! - Pretty slow!
24Sample Problem 5
- Coherency Loss show how the following
expression can be derived for the critical size
of a precipitate at which coherency is
lost. rcrit 3?g/4µd2. - Answer recall that ?Gcoherent 4µd2 4pr3/3
4pr2gcoherent ?Gnon-coherent
4pr2gnon-coherentAt the transition size, the two
free energies will be the same, and above this
size, the precipitate with incoherent interface
will have the lower energy. Therefore we can
write that 4µd24prcrit3/3 4prcrit2gcoherent
4prcrit2gnon-coherentWrite
?g(gnon-coherent - gcoherent)Thus rcrit
3?g/4µd2.
25Sample Problem 6
- Coherency Loss, contd. for the problem outlined
in number 5, given a (cubic) precipitate with
lattice parameter 3.9 Ã…, and a matrix with a3.8
Å, shear modulus µ45GPa, and an observed loss of
coherency at r5nm, what difference in
interfacial energy would you estimate for
incoherent versus coherent interfaces? - Answer turn the equation around and estimate
the difference rcrit 3?g/4µd2 ltgt ?g
rcrit 4µd2 /3.The misfit ?a/a 0.1/3.8
0.0263.Thus ?g 5.10-9 4 45.109 0.02632 /3
0.21 J.m-2. - This is a reasonable value.
26Sample Problem 7
- Spinodal Decomposition how can we represent the
phenomenology of spinodal decomposition? One key
is to postulate a function for the dependence of
free energy on composition. The simplest form
that will yield a G(X) curve with a central
hump is this G(X) 25,000 4(X-0.5)4 -
(X-0.5)2 J. mole-1 - Based on this constitutive description, we can
now ask, for example, what the limits of the
chemical spinodal are? - Answer differentiate the formula to find the
curvature and set it equal to zero to locate the
inflection points d2G/dX2 25,000
443(X-0.5)2 - 2 0 48(X-0.5)2 2 X
0.5 v(2/48) 0.704 or 0.296 - We can also easily obtain the miscibility gap
because of the symmetry of the function about
X0.5 dG/dX0 gtdG/dX 25,000 44(X-0.5)3 -
2(X-0.5) 0 gt(X-0.5)2 1/8 gt X 0.146 or
0.854
27Sample Problem 7 graph
- A plot of G(X) 4(X-0.5)4 - (X-0.5)2
Chemical Spinodal
Miscibility Gap
28Sample Problem 8
- Heterogeneous Nucleation versus Homogeneous
Consider problem 5.5 from PE and estimate the
ratio between the homogeneous and heterogeneous
nucleation rates. The critical free energy for
homogeneous nucleation is 10-19 J and the
temperature is 500C. Assume that the effective
grain boundary thickness is 0.4nm and the grain
size 25µm gAA 500, gAB 600 mJ.m-2. - Answer First calculate the contact angle gAA
2gAB cosq q cos-1 (gAA/ 2gAB) 53.1 - Then calculate the shape factor, S(q)S(q) 0.5
(2 cosq)(1 - cosq)2 0.208 - The ratio in nucleation rates is given by PE Eq.
5.25 Nhet/Nhomo C1/C0 exp-(?Ghomo-?Ghetero)
/kT
29Sample Problem 8, contd.
- Nhet/Nhomo C1/C0 exp(?Ghomo-?Ghetero)/kT
?/D exp(?Ghomo- S(q) ?Ghomo)/kT ?/D
exp((1- S(q) ?Ghomo)/kT 0.4/25,000
exp(1-0.208)10-19/(1.38. 10-23 773) 0.027 - Note the sign of the exponential which gives a
large number. The ratio of the (effective) grain
boundary thickness to grain size decreases the
ratio quite significantly. In practical terms,
heterogeneous nucleation is most significant at
(or adjacent) to the nucleation sites
(boundaries, dislocations etc.).
gab
a
Grainboundary in alpha
q
gaa
b
30Sample Problem, no. 9
- From Dieter, p219 (adapted)
- Question Al-4Cu (by wt.) has a yield stress of
600MPa. Estimate the particle size and spacing. - Solution recognize that this stress relates to
age hardening beyond the peak hardness.
Therefore use the Orowan bowing stress to
estimate the stress. s ltMgt tcrss ltMgt
Gb/l - G27.6GPa b0.25nm ltMgt3.1spacing
3.127,6000.25.10-9/ 600 35.7 nm - Now we must estimate the volume fraction of
particles for which we use the phase diagram,
assuming that we are dealing with the equilibrium
phase, q, which is 54 w/o Cu, and the a in
equilibrium with it, 0.5 w/o Cu. - Wt. Al (54-4)/(54-0.5) 93.5 wt. q
4-0.5/(54-0.5)6.5 - Volume of a 93.5gm/2.7 gm/cm3 34.6 cm3
- Volume of q 6.5/ 4.443 gm/cm3 1.5 cm3
- Volume fraction of a 0.96 volume fraction of q
0.04. - Use l4r(1-f)/3f (slide 22) r
30.0435.7/4/(1-0.04) 1.12 nm.
31Cheating Policy
- Students are referred to the University Policy
About Cheating and Plagiarism (Organization
Announcement No. 297, 6116/80). It shall be the
policy in this course to discourage cheating to
the extent possible, rather than to try to trap
and to punish. On the other hand, in fairness to
all concerned, cheating and plagiarism will be
treated severely. - Cheating includes but is not necessarily limited
to - 1.Plagiarism, explained below.
- 2.Submission of work that is not the
student's own for reports or quizzes. - 3.Submission or use of falsified data.
- Plagiarism includes (but is not limited to)
failure to indicate the source with quotation
marks or footnotes, where appropriate, if any of
the following are reproduced in the work
submitted by a student - 1.A graph or table of data.
- 2. Specific language.
- 3.Exact wording taken from the work,
published or unpublished, of another person."
32Test, Exams, Grading Policy
- Homeworks 1 per week 100 points
- Quizzes 1 per week 20 points
- Exams two see weighting below
- Grading Policy A gt 90 B gt 80 C gt
70 D gt 55 - The instructor will request an Oral exam in
borderline cases. - Weighting ()Homeworks 15Quizzes 5Lab 30E
xams 50 - Notes the distribution between the two exams is
to be determined. The quizzes are mainly there
to encourage students to stay on top of the
material. The 30 weighting for the Lab (or
Project) reflects the number of units assigned to
the Lab part of the class.