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Measuring Simple Harmonic Motion

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The longer length has to travel a longer distance. ... A desktop toy pendulum swings back and forth once every 1.0 s. How long is this pendulum? ... – PowerPoint PPT presentation

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Title: Measuring Simple Harmonic Motion


1
Chapter 11
  • Section 2

2
Measuring Simple Harmonic Motion
  • In order to measure simple harmonic motion we
    have to identify a few important terms that we
    use.
  • Amplitude is the maximum displacement from
    equilibrium.
  • Period is the time that it takes a complete cycle
    to occur.
  • Frequency is the number of cycles or vibrations
    per unit of time, which is normally 1 second.

3
Period of a Simple Pendulum
  • The period of a simple pendulum depends on
    pendulum length and free-fall acceleration.
  • The longer the string or pendulum arm the longer
    the period.
  • When the amplitude is small the period does not
    depend on the mass or on the amplitude.
  • We use the following formula

4
Pendulums of Different Lengths
  • If we compare two pendulums with different
    lengths and the same amplitude we can see why
    only length matters.
  • Since the smaller length has a smaller distance
    to travel, but the same acceleration, it has to
    travel faster.
  • The longer length has to travel a longer
    distance.
  • This is kind of like the different lanes of a
    track.

5
Example Problem 4
  • What is the period of a 3.98 m long pendulum?
    What is the period of a 99.4 cm long pendulum?
  • 4.00 s 2.00 s

6
Example Problem 5
  • A desktop toy pendulum swings back and forth once
    every 1.0 s. How long is this pendulum?
  • 0.25 m

7
Example Problem 6
  • What is the free-fall acceleration at a location
    where a 6.00 m long pendulum swings through
    exactly 100 cycles in 492 s?
  • 9.79 m/s2

8
Example Problem 7 (Book Problem B)
  • You need to know the height of a tower, but
    darkness obscures the ceiling. You note that a
    pendulum extending from the ceiling almost
    touches the floor and that its period is 12 s.
    How tall is the tower?
  • L 36 m

9
Period of a Mass-Spring System
  • The period of a mass-spring system depends upon
    the mass and the spring constant.
  • This makes sense because the restoring force in
    this system is the spring force.
  • Remember that the spring force is dependent upon
    the spring constant.
  • Also, since a heavier mass has more inertia then
    it will be harder to accelerate and will have a
    greater period.

10
Period of a Mass-Spring System
  • The greater the spring constant the more force it
    takes to move the spring hence increasing the
    period also.
  • We can find the period of a mass-spring system by
    using the following formula

11
Example Problem 8
  • A 1.0 kg mass attached to one end of a spring
    completes one oscillation every 2.0 s. Find the
    spring constant.
  • 9.9 N/m

12
Example Problem 9 (Book Problem C)
  • The body of a 1275 kg car is supported on a frame
    by four springs. Two people riding in the car
    have a combined mass of 153 kg. When driven over
    a pothole in the road, the frame vibrates with a
    period of 0.840 s. For the first few seconds,
    the vibration approximates simple harmonic
    motion. Find the spring constant of a single
    spring.
  • k 20000 N/m

13
Problems to Work
  • Pg 379 Practice B
  • Pg 381 Practice C
  • Pg 381 Section Review
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