Title: 19'3 Magnetic Fields
119.3 Magnetic Fields
- Stationary charged particles do NOT interact with
a magnetic field. - Charge moving through a magnetic field experience
a magnetic force. - Value of the force is maximum when the charge
moves perpendicularly to the field lines. - Value of the force is zero when the charge moves
parallel to the field lines.
2Magnetic Fields in analogy with Electric Fields
- Electric Field
- Distribution of charge creates an electric field
E(r) in the surrounding space. - Field exerts a force Fq E(r) on a charge q at r
- Magnetic Field
- Moving charge or current creates a magnetic field
B(r) in the surrounding space. - Field exerts a force F on a charge moving q at r
3Strength of the Magnetic Field
- Define the magnetic field, B, at a given point in
space in terms of the magnetic force imparted on
a moving charge at that point. - Observations show that the force is proportional
to - The field
- The charge
- The velocity of the particle
- The sine of the angle between the field and the
direction of the particles motion.
4Strength and direction of the Magnetic Force on a
charge in motion
F
B
q
v
5Magnetic Field Magnitude
6Magnetic Field Units
- F newton
- v m/s
- q C
- B tesla (T).
- Also called weber (Wb) per square meter.
- 1 T 1 Wb/m2.
- 1 T 1 N s m-1 C-1.
- 1 T 1 N A-1 m-1.
- CGS unit is the Gauss (G)
- 1 T 104 G.
7Right Hand Rule
- Provides a convenient trick to remember the
spatial relationship between F, v, and B. - Consider the motion of positive charge
- Direction of force reversed if negative charge.
8Example Proton traveling in Earths magnetic
field.
- A proton moves with a speed of 1.0 x 105 m/s
through the Earths magnetic field which has a
value of 55 mT a particular location. When the
proton moves eastward, the magnetic force acting
on it is a maximum, and when it moves northward,
no magnetic force acts on it. What is the
strength of the magnetic force? And what is the
direction of the magnetic field?
919.4 Magnetic Force on Current-carrying conductor.
- A magnetic force is exerted on a single charge in
motion through a magnetic field. - That implies a force should also be exerted on a
collection of charges in motion through a
conductor I.e. a current. - And it does!!!
- The force on a current is the sum of all
elementary forces exerted on all charge carriers
in motion.
1019.4 Magnetic Force on Current
x x x x x x x x x x x x x
x x x x x x x x x x x
- If B is directed into the page we use blue
crosses representing the tail of arrows
indicating the direction of the field, - If B is directed out of the page, we use dots.
- If B is in the page, we use lines with arrow
heads.
. . . . . . . . . . . . .
. . . . . . . . . . .
11- Force on a wire carrying current in a magnetic
field.
Bin
x x x x x x x x x x x x x
x x x x x x x x x x x
x x x x x x x x x x x x x
x x x x x x x x x x x
x x x x x x x x x x x x x
x x x x x x x x x x x
Bin
Bin
I
I 0
I
12Force on a wire carrying current in a magnetic
field.
x x x x x x x x x x x x
x x x x x x x x x x x x x
x x x x x x x x x x x x x
x x x x
vd
q
A
Magnetic Field and Current at right angle from
each other.
13Force on a wire carrying current in a magnetic
field.
- General Case field at angle q relative to
current.
B
B sin q
q
I
14Voice Coil
15Mini-Quiz
- In a lightning strike, there is a rapid flow of
negative charges from a cloud to the ground. In
what direction is a lightning strike deflected by
the Earths magnetic field?
16(No Transcript)
17Example Wire in Earths B Field
- A wire carries a current of 22 A from east to
west. Assume that at this location the magnetic
field of the earth is horizontal and directed
from south to north, and has a magnitude of 0.50
x 10-4 T. Find the magnetic force on a 36-m
length of wire. What happens if the direction of
the current is reversed?
B0.50 x 10-4 T. I 22 A l 36 m Fmax BIl
1819.5 Torque on a Current Loop
- Imagine a current loop in a magnetic field as
follows
19I
F
B
B
F
a/2
b
F
F
a
20In a motor, one has N loops of current
21Example Torque on a circular loop in a magnetic
field
30.0o
- A circular loop of radius 50.0 cm is oriented at
an angle of 30.0o to a magnetic field of 0.50 T.
The current in the loop is 2.0 A. Find the
magnitude of the torque.
B
r 0.500 m q 30o B 0.50 T I 2.0 A N 1
2219.6 Galvanometer/Applications
- Device used in the construction of ammeters and
voltmeters.
Scale
Current loop or coil
Magnet
Spring
23Galvanometer used as Ammeter
- Typical galvanometer have an internal resistance
of the order of 60 W - that could significantly
disturb (reduce) a current measurement. - Built to have full scale for small current 1 mA
or less. - Must therefore be mounted in parallel with a
small resistor or shunt resistor.
60 W
Galvanometer
Rp
2460 W
Galvanometer
Rp
- Lets convert a 60 W, 1 mA full scale
galvanometer to an ammeter that can measure up to
2 A current. - Rp must be selected such that when 2 A passes
through the ammeter, only 0.001 A goes through
the galvanometer.
- Rp is rather small!
- The equivalent resistance of the circuit is also
small!
25Galvanometer used as Voltmeter
- Finite internal resistance of a galvanometer must
also addressed if one wishes to use it as
voltmeter. - Must mounted a large resistor in series to limit
the current going though the voltmeter to 1 mA. - Must also have a large resistance to avoid
disturbing circuit when measured in parallel.
Rs
60 W
Galvanometer
26Maximum voltage across galvanometer
Suppose one wish to have a voltmeter that can
measure voltage difference up to 100 V
Large resistance
2719.7 Motion of Charged Particle in magnetic field
Bin
- Consider positively charge particle moving in a
uniform magnetic field. - Suppose the initial velocity of the particle is
perpendicular to the direction of the field. - Then a magnetic force will be exerted on the
particle and make follow a circular path.
r
28The magnetic force produces a centripetal
acceleration.
The particle travels on a circular trajectory
with a radius
29Example Proton moving in uniform magnetic field
- A proton is moving in a circular orbit of radius
14 cm in a uniform magnetic field of magnitude
0.35 T, directed perpendicular to the velocity of
the proton. Find the orbital speed of the proton.
r 0.14 m B 0.35 T m 1.67x10-27 kg q 1.6
x 10-19 C
30Example 2
Consider the mass spectrometer. The electric
field between the plates of the velocity selector
is 950 V/m, and the magnetic fields in both the
velocity selector and the deflection chamber have
magnitudes of 0.930 T. Calculate the radius of
the path in the system for a singly charged ion
with mass m2.1810-26 kg.