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Magnetic Fields Due to Currents

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Ch 29-4 Ampere's Law. Ampere's Law: magnetic analogue of Gauss's law ... Ch 29-4 Ampere's Law. Magnetic Field outside a long straight wire with a current: ... – PowerPoint PPT presentation

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Title: Magnetic Fields Due to Currents


1
CHAPTER-29
  • Magnetic Fields Due to Currents

2
Ch 29-2 Calculating Magnetic Field Due to a
Current
  • Biot Savart Law
  • Magnetic field dB due to a differential
    current-length element ids-element of a length
    vector ds in the direction of current i at a
    point P at a distance r from the current-length
    element ds is given by
  • dB? (i ds sin?)/r2
  • dB(?0/4?) (i ds sin?)/r2
  • dB(?0/4?) (i ds x r)/r3 (Biot-Savart)

3
Ch 29-2 Calculating Magnetic Field Due to a
Current
  • Magnetic Field lines due to a Current in a Long
    Straight Wire encircles the wires clockwise (
    current into the page) or counter clockwise (
    current pout of the page).
  • Direction of B is tangent to those circles in the
    direction of field lines

4
Ch 29-2 Calculating Magnetic Field Due to a
Current
  • Magnetic Field Due to a Current in a long
    straight wire
  • Right hand rule
  • Grasp the element in your right hand with your
    extended thumb pointing in the direction of the
    current. Your finger will then naturally curl
    around in the direction of magnetic field line
    due to that element.

5
Ch 29-2 Calculating Magnetic Field Due to a
Current
  • Magnetic Field Due to a Current in a long
    straight wire
  • B ?0i/2?R
  • Magnetic Field Due to a Current in a semi-long
    straight wire
  • B ?0i/4?R
  • Magnetic Field Due to a Current in a Circular Arc
    of Wire
  • B (?0i/4?R) ?(rad)

6
Ch 29-3 Forces Between Two Parallel Currents
  • Force on Wire b of length L with current ib due
    to magnetic field of very long wire a at the
    location of b
  • Fbaib Lx Ba
  • and Ba ?0ia/2?d
  • Fbaib Lx Ba?0iaib (Lx Ba )/2?d
  • Fba ?0iaib (LBa sin?)/2?d
  • Fba ?0iaib LBa /2?d
  • Fba/L ?0iaib LBa /2?d
  • Parallel currents attracts each other
  • Antiparallel currents repels eaxh other

7
Ch 29-4 Amperes Law
  • Amperes Law magnetic analogue of Gausss law
  • Gauss law ?surf E.dA qenc/ ?0
  • Amperes Law ?loop B.ds ?0 ienc
  • integral to be evaluated along Ampereian loop,
    ienc is net current enclosed by the loop
  • Curled-straight right-hand rule to determine sign
    for current direction
  • Curl your right hand rule around the Amperian
    loop, with the fingers pointing in the direction
    of integration. A current through the loop in the
    direction of outstretched thumb is ve and
    opposite is ve.
  • ?loop B.ds ?loop B ds cos??0 ienc?0 (i1-i2)
  • ? is angle between B and ds
  • ?loop Bds cos??loop Bds B?loop ds?0 (i1-i2)
  • B2?r?0 ienc

8
Ch 29-4 Amperes Law
  • Magnetic Field outside a long straight wire with
    a current
  • B ?loop Bds cos?
  • B?loop dsB2?r? ienc (?0)
  • B2?r?0 ienc (outside a very long wire)
  • Magnetic Field inside a long straight wire with a
    current
  • B ?0 ienc/2?r
  • ienc (ienc/?R2)?r2 iencr2 /R2
  • B ?0 ienc/2?r (?0 iencr)/2?R2

9
Ch 29-5 Solenoids and Toroids
  • Solenoids Helical coil of wire producing uniform
    magnetic field at the center.
  • Length of the coil is much greater than the coil
    radius
  • B-field of the solenoid
  • ?loop B.ds ?0 ienc
  • ?loop B.ds
  • ?ab B.ds ?bc B.ds ?cd B.ds ?da B.ds
  • ?ab B.ds Bh
  • ienciNinh
  • Then Bh ?0 inh
  • B?0 in
  • n is number of turns per unit length of the
    solenoid.

10
Ch 29-5 Solenoids and Toroids
  • Toroid Hollow solenoid curved to meet its two
    ends.
  • B field inside a torus is given by
  • ?loop B.ds ?0 ienc
  • ?loop B.ds B 2?r?0 Ni
  • B?0 Ni/2?r

11
Ch 29-6 A Current Carrying Coil as a Magnetic
Dipole
  • Z component of magnetic field of a current
    carrying coil Bz given by
  • B?Bz (?0 /2?) (NiA) /z3
  • (?0 /2?) ?/z3
  • where z-axis is from south to north axis
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