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Electrochemistry Chap 17

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... to each atom so that you know what is oxidized and what is reduced ... Metals corrode because the oxidize easily. Different metals corrode at different rates ... – PowerPoint PPT presentation

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Title: Electrochemistry Chap 17


1
Electrochemistry - Chap 17
  • Galvanic Cells
  • Standard Reduction Potentials
  • Cell Potential, Electrical Work, and Free Energy
  • Dependence of Cell potential on Concentration
  • Batteries
  • Corrosion
  • Electrolysis
  • Electrolytic Processes

2
Review of Terms
  • oxidation-reduction (redox) reaction
    involves a transfer of electrons from the
    reducing agent to the oxidizing agent.
  • oxidation loss of electrons
  • reduction gain of electrons

3
Review - Steps in Balancing Oxidation-Reduction
  • Equations in Acidic solutions
  • 1. Assign oxidation numbers to each atom so that
    you know what is oxidized and what is reduced
  • 2. Split the skeleton equation into two
    half-reactions-one for the oxidation reaction
    (element increases in oxidation number) and one
    for the reduction (element decreases in oxidation
    number)
  • Fe2 (aq) ? Fe3 (aq)
  • MnO4- (aq) ? Mn2 (aq)

4
Review - Steps in Balancing Oxidation-Reduction
  • 3. Complete and balance each half reaction
  • Fe2(aq) ? Fe3(aq)
  • MnO4-(aq) ? Mn2(aq)
  • a. Balance all atoms except O and H
  • b. Balance O atoms by adding H2O to one side of
    the equation
  • MnO4-(aq) ? Mn2(aq) 4 H2O
  • c. Balance H atoms by adding H to one side of
    the equation
  • 8 H(aq) MnO4-(aq) ? Mn2(aq) 4 H2O
  • d. Balance the electric charge by adding
    electrons (e-) to the more positive side
  • Fe2(aq) ? Fe3(aq) e- oxidation
  • 8 H(aq) MnO4-(aq) 5 e- ? Mn2(aq) 4 H2O
    reduction

5
Review - Steps in Balancing Oxidation-Reduction
  • 4. Combine the two half-reactions to obtain the
    balanced oxidation-reduction equation
  • a. Multiply each half reaction by a factor which
    will allow the e-s to cancel when the equations
    are added
  • 5 Fe2(aq) ? 5 Fe3(aq) 5 e- oxidation
  • 8 H(aq) MnO4-(aq) 5 e- ? Mn2(aq) 4 H2O
    reduction
  • b. Simplify the equation by canceling species
    which occur on both sides of the equation and
    reduce the coeffi-
  • cients to the smallest whole number.
  • Check
  • 5 Fe2(aq) 8 H(aq) MnO4-(aq) ?
  • 5 Fe3(aq) Mn2(aq) 4 H2O

6
Review - Additional Steps for Balancing Oxidation
Reduction Equations in Basic Solutions
  • 5. Add the same number of OH- ions to both sides
    of the equation as H ions
  • 6. Note that when H reacts with OH-, it forms
    H2O. Cancel any H2Os that occur on both sides of
    the equation and reduce the equation to simplest
    terms

7
Electrochemistry
  • The study of the interchange of chemical and
    electrical energy.
  • Which chemically is redox reactions!!!

8
Half-Reactions
  • The overall reaction is split into two
    half-reactions, one involving oxidation and one
    reduction.
  • 8H MnO4? 5Fe2 ? Mn2 5Fe3 4H2O
  • Reduction 8H MnO4? 5e? ? Mn2 4H2O
  • Oxidation 5Fe2 ? 5Fe3 5e?

9
Galvanic Cell
  • A device in which chemical energy is changed to
    electrical energy.
  • Spontaneous process
  • Common use? Batteries!!!

10
Galvanic Cell
  • a galvanic cell uses a spontaneous redox reaction
    to produce a current that can be used to do work
  • The oxidation reaction occurs at the anode
    (negative electrode)
  • The reduction reaction occurs at the cathode
    (positive electrode)

11
Galvanic Cell
12
Galvanic Cell
Typical reaction Anode M ? M e- Cathode
M e- ? M
13
Cell Potential
  • Cell Potential or Electromotive Force (emf)
    The pull or driving force on the electrons.
  • the unit of electrical potential is the volt (V)
    which is defined as 1 joule of work per coulomb
    of charge transferred

14
Standard Reduction Potentials
  • the reactions in a galvanic cell are always
    oxidation-reduction reactions that can be written
    into two half-reactions
  • We can then assign the potential for each of the
    half-reactions so that when the cell is
    constructed for a given pair of half reactions,
    we obtain the cell potential by summing the
    potentials
  • the standard hydrogen electrodes potential is
    arbitrarily set to zero volts

15
Standard Reduction Potentials
  • The E? values corresponding to reduction
    half-reactions with all solutes at 1M and all
    gases at 1 atm.
  • Cu2 2e? ? Cu
  • E? 0.34 V vs. SHE
  • SO42? 4H 2e? ? H2SO3 H2O
  • E? 0.20 V vs. SHE

16
Line notation
  • A short code for an electrochemical cell
    Line Notation
  • Cu2 2e? ? Cu
  • E? 0.34 V vs. SHE
  • SO42? 4H 2e? ? H2SO3 H2O
  • E? 0.20 V vs. SHE
  • PtH(aq), SO42?(aq), H2SO3 (aq)Cu2(aq), Cu(s)
  • The anode components are listed to the left side
    of the double line and cathode are on the right
    side of the double line. The electrode is listed
    on either end of the equation separated by a
    single line if it is a different material (see
    the platnum electrode above)

17
emf and Work
From the above equations you can calculate the
maximum cell potential and work Any real
spontaneous process actual work realized is
less than the calculated maximum
18
Free Energy and Cell Potential
  • ?G? ?nF??
  • n number of moles of electrons
  • F Faraday 96,485 coulombs per mole of
    electrons
  • So we can in turn relate work to free energy for
    a galvanic cell

19
Standard Conditions
  • When using standard conditions all concentrations
    are 1M
  • What happens when we place a higher concentration
    of one of the components
  • Le Châteliers principle will drive the
    reaction

20
Concentration Cell
  • Because cell potentials are dependent on
    concentration
  • a cell in which both compartments have the same
    components but at different concentrations can be
    made!!

21
The Nernst Equation
  • We can calculate the potential of a cell in which
    some or all of the components are not in their
    standard states.

Free energy equation from chap 16
Using the above equation and substituting into
the first equation yields eq3
Doing some simple algebra yields eq4
Eq4 at 25oC yields eq5
22
Calculation of Equilibrium Constants for Redox
Reactions
  • At equilibrium, Ecell 0 and Q K.

23
Batteries
  • A battery is a galvanic cell or, more commonly, a
    group of galvanic cells connected in series.
  • Look at the various examples in the book Lead,
    Dry cell and Fuel cells

24
Fuel Cells
  • . . . galvanic cells for which the reactants are
    continuously supplied.
  • 2H2(g) O2(g) ? 2H2O(l)
  • anode 2H2 4OH? ? 4H2O 4e?
  • cathode 4e? O2 2H2O ? 4OH?

25
Corrosion
  • Can be viewed as returning metal to their natural
    state.
  • Metals corrode because the oxidize easily
  • Different metals corrode at different rates
  • Due to anomalies among the metals
  • Al forms Al2O3 a thin film that protects the
    rest of the metal
  • Iron forms various oxides that flake off and
    expose a new layer of metal

26
Corrosion
  • Some metals, such as copper, gold, silver and
    platinum, are relatively difficult to oxidize.
    These are often called noble metals.

27
Corrosion of Iron
  • Iron or steel has a non-uniform surface
  • Anodic surface and cathodic surface
  • 4Fe2 O2 (42n)H2O ? 2Fe2O3.nH2O 8H

28
Electrolytic Cell
  • in an electrolytic cell electrical energy is used
    to produce a chemical change
  • the process of electrolysis involves forcing a
    current through a cell to produce a chemical
    change for which the cell potential is negative
  • electrolysis has great practical importance
    examples, charging a battery, producing aluminum
    metal, and chrome plating

29
Electrolytic Plating
  • Disposition of neutral metal on the electrode
    from ions in the solution of the electrolytic
    cell
  • Process used in Chromium, Silver, Gold, and
    Copper plating

30
Stoichiometry of Electrolysis
  • How much chemical change occurs with the flow of
    a given current for a specified time?
  • current and time ? quantity of charge ?
  • moles of electrons ? moles of analyte ?
  • grams of analyte
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