Title: Wave Properties
1Wave Properties
2Coherent sources
Two sources of light are said to be coherent if
the waves emitted from them have the same
frequency and are 'phase-linked' that is, they
have a zero or constant phase difference.
3Path Difference
- Suppose we go along the centre line between the
two sources. - At all points we are the same distance from
either of the sources. - There is zero path difference. Since the waves
are in phase and produced at the same frequency
and travelling at the same speed, they must still
be in phase. - So they must reinforce.
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5Path Difference
- We also see regions of constructive interference
symmetrically on either side of the centre line.
Thus the waves must be in phase. - This is because the waves have a path difference
of one or more whole wavelengths. - We often describe this in terms of half
wavelengths, so for there to be constructive
interference, there must be a path difference of
an even number of half wavelengths. - The reverse side of the argument applies to odd
numbers of half wavelengths. If the path
difference is ½ a wavelength or 1 ½ and so on, we
get regions of cancellation. - This is because the waves are in antiphase.
6Single Slit Diffraction
? - is the diffraction angle l - is the
wavelength a is the width of the slit.
7Diffraction
- If the slit is narrow, the diffraction is more
marked. - The wavelength remains the same.
- Diffraction does not need a slit. Waves can bend
round a barrier by diffraction. Radio signals
can be picked up behind hills for this reason. - The longer the wavelength, the more the waves
will diffract. - All waves diffract.
8One wide slit
9One Narrow slit
We can explain the effect of diffraction using
the idea of secondary wavelets. In the middle
these form a plane wave-front. At the edges,
circular wave-fronts move into the shadow region.
The maxima and minima are caused respectively by
constructive and destructive interference.
10Secondary wavelets
11INTERFERENCE
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14where ? - is the wavelength (m) w - is the
fringe spacing (m) s - is the slit spacing (m) D
- is the distance from the slits to the screen
(m).
15Can you derive this!!!!
? - is the angle, ??- is the wavelength, d - is
the slit width n - the spectrum order
d sin ? n?
16- Parallel rays of a monochromatic light of
wavelength l are incident on a diffraction
grating in which the slit separation is d. If
the grating has N lines per metre, the grating
spacing is given by d 1 - N
- Constructive interference only occurs along a few
precise lines, one of which is shown in the
diagram. Light from A must be in phase with
light from B, and this can only happen when the
path difference is a whole number of complete
wavelengths. - AC nl, where n 0, 1, 2, 3...
- s o AC d sin q
- where q is the angle of diffraction.
- So d sin q nl
-
- The term n is called the spectrum order. If n
1, we have the first diffraction maximum. -
- Sin q can never be greater than 1, so there is a
limit to the number of spectra that can be
obtained.
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18The Diffraction Grating
- The diffraction grating has the advantage over
the double slit method of measuring wavelength in
that - the maxima are more sharply defined
- the beam passes through more slits than two, so
the intensity is brighter - the angles are larger so that they can be
measured with greater precision.
19Double Slit Interference
20Remember
Double slits the pattern is due to
interference. Single slit, its due to
diffraction.