Title: Gregor Mendel
1Gregor Mendel
2Gregor Mendel
- Austrian monk
- Studied science and mathematics at University of
Vienna - Conducted breeding experiments with the garden
pea Pisum sativum - Carefully gathered and documented mathematical
data from his experiments - Formulated fundamental laws of heredity in early
1860s - Had no knowledge of cells or chromosomes
- Did not have a microscope
3Fruit and Flower of theGarden Pea
4Garden Pea TraitsStudied by Mendel
5Blending Inheritance
- Theories of inheritance in Mendels time
- Based on blending
- Parents of contrasting appearance produce
offspring of intermediate appearance - Mendels findings were in contrast with this
- He formulated the particulate theory of
inheritance - Inheritance involves reshuffling of genes from
generation to generation
6Mendels Monohybrid CrossesAn Example
7One-Trait Inheritance
- Mendel performed cross-breeding experiments
- Used true-breeding (homozygous) plants
- Chose varieties that differed in only one trait
(monohybrid cross) - Performed reciprocal crosses
- Parental generation P
- First filial generation offspring F1
- Second filial generation offspring F2
- Formulated the Law of Segregation
8Mendels Monohybrid CrossesAn Example
9Law of Segregation
- Each individual has a pair of factors (alleles)
for each trait - The factors (alleles) segregate (separate) during
gamete (sperm egg) formation - Each gamete contains only one factor (allele)
from each pair - Fertilization gives the offspring two factors for
each trait
10Modern Genetics View
- Each trait in a pea plant is controlled by two
alleles (alternate forms of a gene) - Dominant allele (capital letter) masks the
expression of the recessive allele (lower-case) - Alleles occur on a homologous pair of chromosomes
at a particular gene locus - Homozygous identical alleles
- Heterozygous different alleles
11Homologous Chromosomes
12Genotype Versus Phenotype
- Genotype
- Refers to the two alleles an individual has for a
specific trait - If identical, genotype is homozygous
- If different, genotype is heterozygous
- Phenotype
- Refers to the physical appearance of the
individual
13Punnett Square
- Table listing all possible genotypes resulting
from a cross - All possible sperm genotypes are lined up on one
side - All possible egg genotypes are lined up on the
other side - Every possible zygote genotypes are placed within
the squares
14Punnett Square ShowingEarlobe Inheritance
Patterns
15Try this one
- MONOHYBRID CROSS
- Cross a heterozygous tall plant with a
heterozygous tall plant (use T tall and t
short) Determine expected genotype and phenotype
ratios.
16Try these!Show work
- Cross a heterozygous red flower with a white
flower. What is the genotype and phenotype ratio
for the offspring? Key R red r white
17Two-Trait Inheritance
- Dihybrid cross uses true-breeding plants
differing in two traits - Observed phenotypes among F2 plants
- Formulated Law of Independent Assortment
- The pair of factors for one trait segregate
independently of the factors for other traits - All possible combinations of factors can occur in
the gametes
18Try Mendels Classic Dihybrid Cross
- Cross two heterozygous tall, heterozygous green
pod producing plants. Use a punnett square to
show expected offspring and complete a phenotype
ratio. - Key
- T tall G green pods
- t short g yellow pods
19Two-Trait (Dihybrid) Cross
20Must Know Your Vocab!
- Homozygous?
- Heterozygous?
- Genotype?
- Phenotype?
21Try this one DIHYBRID CROSS2 traits
- Key T tall R red
- t short r white
- Cross two heterozygous tall, heterozygous red
flowered plants. - What is the phenotypic ratio of the offspring?
22Two-Trait (Dihybrid) Cross
23P-square practice
- Practice crosses on a separate sheet of paper.
- Show parental cross
- Show p-square
- Show phenotype ratio
24- WHATs IN YOUR GENES?
- Mom 22 autosomes plus X sex chromosome
- Dad 22 autosomes plus X or Y chromosome
25(No Transcript)
26Boy or Girl?
- Dad determines this sperm carries 22 autosomes
and either an X or Y sex chromosome - BOYS your mom gave you the X and dad gave you
the Y so what?
27(No Transcript)
28(No Transcript)
29Sex-linked disorders carried on the X
chromosome
- Colorblindness
- Hemophilia
- Baldness (?)
30Analyze Sex-linked traits
31(No Transcript)
32(No Transcript)
33- - Albinism ppt
- Huntingtons ppt
- Final concepts
34Autosomal Recessive Pedigree Chart
35Autosomal Dominant Pedigree Chart
36INHERITING A GENE - ALBINISM
37This is an albino skunk. The cells are not able
to produce the protein that causes color.
38Cells in the skin produce a black-brown pigment
called melanin.
39The chemical melanin is produced by specialized
cells in the epidermis called melanocytes.
40The melanin leaves the melanocytes and enters
other cells closer to the surface of the skin.
41Different shades of skin colors is determined by
the amount of melanin deposited in these
epidermal cells
42Sunlight causes melanocytes to increase
production of melanin.
43A tan fades because the cells break down the
melanin.
44Some organisms, such as the octopus, can rapidly
change from light to dark.
45They control the color by scattering the melanin
in the cell for a dark color, and concentrating
the melanin in the center for light color.
46Melanin is made by the melanocytes by chemically
changing the amino acid, phenylalanin, into
tyrosine and then into melanin.
47An enzyme is required to change tyrosine into
melanin.
48If the enzyme is not present, then melanin cannot
be produced by the melanocytes.
49The result of no melanin is an albino.
50The eyes of an albino appear pink because there
is no dark melanin in the eye to absorb light.
51The blood in the retina and iris reflects red
light, resulting in pink eyes.
52The gene that produces this enzyme is on
chromo-some 9
53If both the genes produce the enzyme tyrosinase,
there is plenty to convert tyrosine to melanin.
54If neither gene produces tryosinase, no melanin
is produced and
55The crow is an albino rather than the normal black
56What if one gene is normal and one gene does not
produce the enzyme?
57The one normal gene produces enough enzyme to
make normal crow color
58This albino squirrel received one albino gene
from the father and one albino gene from the
mother.
59But what if a squirrel gets a normal gene from
one parent and an albino gene from the other
parent?
60The one functioning gene produces enough enzyme
to make melanin for normal coloration.
61Is it possible for two normal colored cockatiels
to have an albino offspring?
62Yes! Remember the albino has two genes for
albinism. One gene from the father and one gene
from the mother.
63To be albino, both genes must be albino genes
64A normal colored bird could have one albino gene
and one normal gene.
65If the sperm of a normal colored male pigeon has
an albino gene and the ova it fertilizes has an
albino gene than the offspring will be albino.
66The same happens in humans. A normal pigment
father and mother can have an albino offspring.
67We can see this in a genetic family tree called
a pedigree. The circles are females, the squares
are males. The open symbols are normal
coloration, the black symbols are albino.
68The parents in the circle have normal pigment.
69Most of the offspring received at least one
normal gene from a parent.
70But one female offspring received an albino gene
from both the mother and the father.
71A Punnett square is a matrix to show the genetics
of a mating.
72What is the probability of an albino doe giving
birth to a normal fawn if she has mated with a
normal male?
73The female must have two albino genes (use small
a for the albino gene
- aa
74Since the albino gene is relatively rare, the
male probably has two normal genes of color.
(Capital A stands for the normal gene)
- AA
75AA X aa
76Next, add the possible sperm and ova genes.
A A
a a
Aa
Aa
Aa
Aa
77As long as there is one normal gene, none of the
offsprings will be albino
A A
a a
Aa
Aa
Aa
Aa
78Therefore, all offsprings will have a normal and
an albino gene.
A A
a a
Aa
Aa
Aa
Aa
79An albino must get one albino gene from the
father and one albino gene from the mother.
80Then how could an albino female penguin have an
albino chick.
81The normal colored father must have one normal
coloration gene and one albino gene.
82There is only one way for two normal colored
parents to produce an albino offspring.
83Both parents must have one normal gene and one
albino gene.
84Aa X Aa
Both parents have one gene for normal and one
gene for albinism.
85Aa X Aa
The fathers sperm is 50 with normal gene and
50 with albino gene.
A
a
86Aa X Aa
50 of the mothers ova have a normal gene and
50 of the ova have the albino gene
A
a
A
a
87Aa X Aa
The ova and sperm may combine to form an
offspring with two normal genes, a normal gene
and an albino gene, or two albino genes.
A
a
A
AA
Aa
a
aa
Aa
88Aa X Aa
Only the offspring with two albino genes will
lack pigment.
A
a
A
AA
Aa
a
aa
Aa
89Sometimes an albino is born and there is no
history of albinism in the colony.
90The color gene in the cell that produced this
white flower changed to an albino gene.
91A change in a gene is called a mutation.
92(No Transcript)
93(No Transcript)
94(No Transcript)
95(No Transcript)