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HYDRAULIC 1 CVE 303

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Find the critical hump height? HYDRAULIC JUMP Introduction : Local non-uniform flow phenomenon supercritical flow going into subcritical. – PowerPoint PPT presentation

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Title: HYDRAULIC 1 CVE 303


1
HYDRAULIC 1CVE 303

2
Basics of Fluid Flow
  • Types of flow The type of flow depends on the
    manner in which the particles unite, the
    particles group themselves in a variety of ways
    e.g. regular or irregular. The type of flow is
    identified by the Reynolds number.
  • Flow of an IDEAL FLUID No Viscousity
  • Flow of a REAL FLUID Viscousity included
  • Laminar (low velocity, motion in layers)
  • Turbulent Flow ( high velocity, chaotic motion)
  • Steady flow (conditions at any point remain
    constant, may differ from point to point)
  • Uniform Flow ( velocity is the same at any given
    point in the fluid)
  • Flow lines Path lines, Stream lines and Streak
    lines
  • Straight line streamlines of moving particle- One
    dimensional flow (Flow in pipes)
  • Curve Two dimensional flow (Flow over a
    spillway)
  • Streamlines represented in space Three
    dimensional (flow in a river bed)
  • Motion of Fluid Particles
  • Lagrangian method
  • Eulerian method

3
  • Equation of continuity of a liquid flow If an
    incompressible liquid us is continuously flowing
    through a pipe or a channel (whose
    cross-sectional area may or may not be constant)
    the quantity of liquid passing per second is the
    same at all sections.
  • Questions
  • Water is flowing through a tapered pipe having
    end diameter of 150m and 50m respectively. Find
    the discharge at the larger end and velocity head
    at the smaller end if the velocity of water at
    the larger end is 2m/s.
  • A circular pipe of 250 mm diameter carries an oil
    of specific gravity 0.8 at the rate of 120
    litres/s and under a pressure of 20kPa. Calculate
    the total energy in meters at a point which is 3m
    above the datum line.
  • A horizontal pipe 100 m long uniformly tapers
    from 300 mm diameter to 200 mm diameter. What is
    the pressure head at the smaller end, if the
    pressure at the larger end is 100 KPa and the
    pipe is discharging 50 litres of water per
    second. (5 marks

4
Bernoullis Equation and its applications
  • Introduction
  • Energy of liquid in motion
  • Potential Energy a liquid posses by virtue of
    its position
  • Kinetic Energy posessed by a liquid by virtue of
    its motion
  • Pressure head of a liquid particle in motion
  • Total Energy This is the sum of a liquids
    Potential, Kinetics and Pressure energy
  • Total Head of a liquid in motion

5
Bernoullis equation (contd.)
  • Definition For a perfect incompressible fluid,
    flowing in a continuous stream, the total energy
    of a particle remains the same, while the
    particles moves from one point to another.
  • Limitations of Bernoullis equation
  • Practical application of Bernoullis equation
  • Venturimeter ( Convergent cone, throat,
    divergent cone)
  • Discharge through a venturimeter
  • Inclined venturimeter
  • Orificemeter
  • Pitot tube

6
  • Questions
  • A pipe 500 m long has a slope of 1 in 100 and
    tapers from 1 m diameter at the higher end to 0.5
    m at the lower end. The quantity of water flowing
    is 900 l/sec. If the pressure at the higher end
    is 70KPa. Find the pressure at the lower end.
  • A pipe AB branches into two pipes C and D. The
    pipe has a diameter of 0.45 m at A, 0.3 m at B,
    0.2 m at C and 0.15 m at D. Find the discharge at
    A if the velocity of water at A is 2 m/s also
    find the velocities at B and D if the velocity at
    C is 4 m/s.
  • A venturimeter with a 150 mm diameter at inlet
    and 100 mm at throat is laid with its axis
    horizontal and is used for measuring the flow of
    oil specific gravity 0.9. The oil mercury
    differential manometer shows a guage difference
    of 200 mm. Assume coefficient of meter as 0.98.
    Calculate the discharge in litres per minute
  • A venturimeter has 400 mm diameter at the main
    and 150 mm at the throat. If the difference of
    pressure is 250 mm of mercury and the metre
    coefficient is 0.97, calculate the discharge of
    oil (specific gravity 0.75) through the
    venturimeter

7
OPEN CHANNEL FLOW
  • General Definition An open channel is a passage
    through which the water flows under the force of
    gravity and atmospheric pressure e.g. canals,
    sewers, aqauduct. It is also known as
    free-surface flow or gravity flow. The flow here
    is not due to pressure as in the case of pipe
    flow. Most open channel flow are turbulent flow
    and froude number is the relevant parameter here
  • Types of open channel flow
  • Natural streams and rivers
  • Artificial canals, flumes
  • Sewers, tunnels, partially full pipelines
  • Gutters
  • Applications of artificial channels
  • Water power development
  • Irrigation
  • Water supply
  • Drainage
  • Flood control
  • Reynolds no. for pipes
  • Reynolds no. for open channels
  • Wetted perimeter Length of cross-sectional
    border in contact with water. Length where
    friction acts.
  • Slopes in open channel flow

8
Open channel flow (contd.)
  • Uniform flow through open channels
  • Chezys formula
  • Values of Chezys constant in the formula for
    discharge in open channel
  • Mannings formula
  • Basins formula
  • Kutters formula
  • Geometric properties of cross-sections
  • Trapezoidal channels
  • Triangular channels
  • Rectangular channels

9
  • Exercises
  • A trapezoidal channel 3.5 m wide at the bottom
    has side and bed slopes of 11 and 11000
    respectively. Using mannings formula, find the
    discharge through the channel, if the depth of
    water is 0.5 m. Take N 0.03.
  • A non symmetrical trapezoidal cross-section with
    b 1.2 m, m1 2 and m2 1, So 0.00009, Q
    120 m3/s and y 0.6 m, find the mannings
    roughness factor n.
  • Unnatural streams cross-section can be
    approximated by a parabolic shape with B 4m and
    a depth y 2 m. If the stream is laid on a slope
    of 0.001 m/m and n 0.028, determine the
    discharge.

10
SPECIFIC ENERGY
  • Introduction
  • Specific energy diagram
  • Critical conditions
  • E Emin i.e.
  • Critical depth
  • Critical velocity
  • Subcritical y1 gt yc tranquil, upper stage flow
    V lt Vc
  • Supercritical y1 lt yc rapid, lower stage flow V
    gtVc
  • Froudes number
  • Critical depth in non rectangular channels
  • Occurrence of critical flow

11
  • Critical energy
  • Occurrence of Critical Flow
  • Change from mild to steep slope in a channel
  • Entrance from a reservoir into a steep slope
    channel
  • Free fall from mild slope channel
  • Free fall from steep slope channel
  • Humps and Contractions
  • Questions
  • A rectangular channel 3.25 m wide discharges
    2600 litres of water per second. What is the
    critical depth and critical velocity?
  • A channel of rectangular section 8 m wide is
    discharging water at the rate of 12 m3/s with an
    average velocity of 1.2 m/s. Find the type of
    flow?
  • A rectangular channel 3 m wide carries 4 m3/s of
    water in subcritical uniform flow at a depth of
    1.2 m, a frictionless hump is to be installed
    across the bed. Find the critical hump height?

12
HYDRAULIC JUMP
  • Introduction Local non-uniform flow phenomenon
    supercritical flow going into subcritical. The
    shooting flow is an unstable type of flow and
    does not continue on the downstream side, the
    flow transform itself to the streaming flow by
    increasing its depth. The rise in water level
    which occurs during the transformation of the
    unstable shooting flow to the stable streaming
    flow is called hydraulic jump.
  • Depth relations
  • Energy losses
  • Types of jumps
  • Stilling basins

13
  • Questions
  • A horizontal rectangular channel of constant
    breadth has a sluice opening from the bed
    upwards. When the sluice is partially opened
    water issues at 6 m/s with a depth of 600 mm.
    Determine the loss of head per KN of water.
  • A discharge of 1000 l/s flows along a
    rectangular channel 1.5 m wide. If a standing
    wave is to be formed at a point where the
    upstream depth is 180 mm. What would be the rise
    in water level?
  • Water flows at the rate of 1 m3/s along a channel
    of rectangular section of 1.6 m width. If a
    standing wave occurs at a point where upstream
    depth is 250 mm. Find the rise in water level
    after the hydraulic jump. Also find the loss of
    head in the standing wave.
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