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Vedic Mathematics

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Title: Vedic Mathematics


1
Vedic Mathematics
  • By
  • Dr. SUDHA GUPTA
  • Department of Mathematics
  • Lakshmibai College, University of Delhi

2
What is Vedic Mathematics ?
  • It is an ancient technique, which simplifies
    multiplication, divisibility, complex numbers,
    squaring, cubing, square and cube roots. Even
    recurring decimals and auxiliary fractions can be
    handled by Vedic Mathematics.

3
Who Brought Vedic Mathematics to Limelight ?
  • The ancient systems of Mathematics was
    rediscovered from Vedas by Jagadguru Swami
    Bharathikrishna Tirthaji of Govardhan Peeth, Puri
    Jaganath(1884-1960)

4
What is the basis of Vedic Mathematics ?
  • 16 Sutras
  • 13 Sub-Sutras

5
Vedic Mathematical Sutras
,dkf/kdsu iwosZ.k Ekadhikena Purvena (vkuqIs) kwUeUr (Anurupye) Sunyamanyat Of"Vlef"V Vyastisamastih
fufkya uorpjea nkr Nikhilam Navatascaramam Dasatah LkadyuOodyukHke Sankalana vyavakalanabhyam ks"kk.³dsu pjes.k Sesanyankena Caramena
Å/oZfrZXHkke Urdhva-tiryagbhyam Ikwj.kkiwj.kkHke Puranapuranabhyam LkksikUReURe Sopantyadvayamantyam
IkjkoRZ kstsr Paravartya Yojayet PkyudyukHke Calana-Kalanabhyam ,dUwusu iwosZ.k Ekanyunena Purvena
kwUa lkEleqPps Sunyam Samyasamuccaye konwue Yavadunam Xkqf.krleqPp Gunitasamuccayah
Xkq.kdleqPp Gunakasamuccayah Xkq.kdleqPp Gunakasamuccayah Xkq.kdleqPp Gunakasamuccayah
6
Multiplication of Numbers
  • The sutra which is used for multiplication
    isfufkya uorpjea nkr
  • Which literally translated, means All from 9
    and the last from 10

7
Procedure for Multiplication
  • Suppose we have to multiply 9 by 7
  • We should take, as base for our calculations,
    that power of 10 which is nearest to the numbers
    to be multiplied. In this case 10 itself is that
    power
  • Put the two numbers 9 and 7 above and below on
    the left hand side.
  • Subtract each of them from the base (10) and
    write down the remainders (1 and 3) on the right
    hand side with a connecting minus sign ( - )
    between them to show that the numbers to be
    multiplied are both of them less that 10.
  • The product will have two parts one on the left
    side and one on the right. A vertical dividing
    line may be drawn for the purpose of demarcation
    of the two parts.
  • Now, the left hand side digit (of the answer) can
    be arrived at in one of 4 ways-
  • v  Subtract the base 10 from the sum of the given
    numbers (9 and 7 i.e. 16) and put (16-10) i.e. 6
    as the left hand part of the answer.
  • 9 7 10 6
  • v  or Subtract the sum of the two deficiencies
    (134) from the base (10)
  • 10 1 3 6
  • v  or Cross subtract deficiency (3) on the
    second row from the original number (9) in the
    first row.
  • 9 3 6
  • v  or Cross subtract in the converse way (i.e. 1
    from 7) .
  • 7 1 6
  • Now, Vertically mulitply the two deficit figures
    (1 and 3) . The product is 3 . And this is the
    right hand side portion of the answer.
  • Thus 9 x 7 63

8
Multiplication of Numbers
  • Next Sutra is Å/oZfrZXHkke (Urdhvatriyagbhayam)
  • which means
  • Vertically and Crosswise

9
12 X 13
  • Suppose we have to multiply 12 by 13
  • We multiply the left hand most digits 1 of the
    multiplicand vertically by the left hand most
    digits 1 of the multiplier, get their product 1
    and set it down as the left hand most part of the
    answer.
  • We then multiply 1 and 3 1 and 2 crosswise, add
    the two, get 5 as the sum and set it down as the
    middle part of the answer.
  • We multiply 2 and 3 vertically, get 6 as their
    product and put it down as the last (the right
    hand most) part of the answer.
  • Thus 12 x 13 156

10
Special Sub-Sutra for Multiplication by
11vURksjso (Antyayoreva) which means Only
the last two digits
  • The following example illustrate this very easy
    methods. 13 423 x
    11
  • Write down the number with naught placed at both
    ends. This is a
  • naught sandwich 0 1 3 4 2 3 0
  • Add the final two digits, 3 0 3 and write the
    answer below 0 .
  • 0 1 3 4 2 3 0
  • 3
  • For the tens digit, add the final two digits to
    that point, that is 2 3 5.
  • 0 1 3 4 2 3 0
  • 5 3
  • Continue to add adjacent digits, that is 42 6,
    347, 13 4,
  • and 011
  • 0 1 3 4 2 3 0
  • 1 4 7 6 5 3
  • The answer is 1 4 7, 6 5 3 2

11
Multiplication by 12
  • The sutra used to obtained the product of any
    number with 12 is
  • LkksikUReURe (Sopantyadvayamantyam)
  • which means
  • The ultimate and twice the penultimateThis is
    very similar to multiplication by 11 but we just
    double the digit to the left before adding

12
Multiplication by 12
  • For example 6 5 2 1 4 x 12
  • Ø  we start with the nought sandwich 0 6 5
    2 1 4 0
  • Ø  The ultimate digit is 0 and the penultimate
    digits is 4, so the ultimate plus twice the
    penultimate is 0 8 8.
  • 0 6 5 2 1 4 0
  • 8
  • Ø  For the tens column, the ultimate is 4 and the
    penultimate is 1, so 42 6.
  • 0 6 5 2 1 4 0
  • 6 8

Ø  Likewise, 1 4 5, and 2 10 12. With 12
we set down 2 and carry 1. 0 6 5 2 1 4 0
2 5 6 8 1 Ø 5 12 Carry 1 18
and again we carry 1. Ø The final step is 6 0
Carry 1 7. 0 6 5 2 1 4 0 7 8 2 5 6 8
1 1 Ø The answer is 7 8 2 5 6 8
13
  • Thank you
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