Title: Vedic Mathematics
1Vedic Mathematics
- By
- Dr. SUDHA GUPTA
- Department of Mathematics
- Lakshmibai College, University of Delhi
2What is Vedic Mathematics ?
- It is an ancient technique, which simplifies
multiplication, divisibility, complex numbers,
squaring, cubing, square and cube roots. Even
recurring decimals and auxiliary fractions can be
handled by Vedic Mathematics.
3Who Brought Vedic Mathematics to Limelight ?
- The ancient systems of Mathematics was
rediscovered from Vedas by Jagadguru Swami
Bharathikrishna Tirthaji of Govardhan Peeth, Puri
Jaganath(1884-1960)
4What is the basis of Vedic Mathematics ?
5Vedic Mathematical Sutras
,dkf/kdsu iwosZ.k Ekadhikena Purvena (vkuqIs) kwUeUr (Anurupye) Sunyamanyat Of"Vlef"V Vyastisamastih
fufkya uorpjea nkr Nikhilam Navatascaramam Dasatah LkadyuOodyukHke Sankalana vyavakalanabhyam ks"kk.³dsu pjes.k Sesanyankena Caramena
Å/oZfrZXHkke Urdhva-tiryagbhyam Ikwj.kkiwj.kkHke Puranapuranabhyam LkksikUReURe Sopantyadvayamantyam
IkjkoRZ kstsr Paravartya Yojayet PkyudyukHke Calana-Kalanabhyam ,dUwusu iwosZ.k Ekanyunena Purvena
kwUa lkEleqPps Sunyam Samyasamuccaye konwue Yavadunam Xkqf.krleqPp Gunitasamuccayah
Xkq.kdleqPp Gunakasamuccayah Xkq.kdleqPp Gunakasamuccayah Xkq.kdleqPp Gunakasamuccayah
6Multiplication of Numbers
- The sutra which is used for multiplication
isfufkya uorpjea nkr - Which literally translated, means All from 9
and the last from 10
7Procedure for Multiplication
- Suppose we have to multiply 9 by 7
- We should take, as base for our calculations,
that power of 10 which is nearest to the numbers
to be multiplied. In this case 10 itself is that
power - Put the two numbers 9 and 7 above and below on
the left hand side. - Subtract each of them from the base (10) and
write down the remainders (1 and 3) on the right
hand side with a connecting minus sign ( - )
between them to show that the numbers to be
multiplied are both of them less that 10. - The product will have two parts one on the left
side and one on the right. A vertical dividing
line may be drawn for the purpose of demarcation
of the two parts. - Now, the left hand side digit (of the answer) can
be arrived at in one of 4 ways-
- v Subtract the base 10 from the sum of the given
numbers (9 and 7 i.e. 16) and put (16-10) i.e. 6
as the left hand part of the answer. - 9 7 10 6
- v or Subtract the sum of the two deficiencies
(134) from the base (10) - 10 1 3 6
- v or Cross subtract deficiency (3) on the
second row from the original number (9) in the
first row. - 9 3 6
- v or Cross subtract in the converse way (i.e. 1
from 7) . - 7 1 6
- Now, Vertically mulitply the two deficit figures
(1 and 3) . The product is 3 . And this is the
right hand side portion of the answer. - Thus 9 x 7 63
8Multiplication of Numbers
- Next Sutra is Å/oZfrZXHkke (Urdhvatriyagbhayam)
- which means
- Vertically and Crosswise
912 X 13
- Suppose we have to multiply 12 by 13
- We multiply the left hand most digits 1 of the
multiplicand vertically by the left hand most
digits 1 of the multiplier, get their product 1
and set it down as the left hand most part of the
answer. - We then multiply 1 and 3 1 and 2 crosswise, add
the two, get 5 as the sum and set it down as the
middle part of the answer. - We multiply 2 and 3 vertically, get 6 as their
product and put it down as the last (the right
hand most) part of the answer. - Thus 12 x 13 156
10Special Sub-Sutra for Multiplication by
11vURksjso (Antyayoreva) which means Only
the last two digits
- The following example illustrate this very easy
methods. 13 423 x
11 - Write down the number with naught placed at both
ends. This is a - naught sandwich 0 1 3 4 2 3 0
- Add the final two digits, 3 0 3 and write the
answer below 0 . - 0 1 3 4 2 3 0
- 3
- For the tens digit, add the final two digits to
that point, that is 2 3 5. - 0 1 3 4 2 3 0
- 5 3
- Continue to add adjacent digits, that is 42 6,
347, 13 4, - and 011
- 0 1 3 4 2 3 0
- 1 4 7 6 5 3
- The answer is 1 4 7, 6 5 3 2
11Multiplication by 12
- The sutra used to obtained the product of any
number with 12 is - LkksikUReURe (Sopantyadvayamantyam)
- which means
- The ultimate and twice the penultimateThis is
very similar to multiplication by 11 but we just
double the digit to the left before adding
12Multiplication by 12
- For example 6 5 2 1 4 x 12
- Ø we start with the nought sandwich 0 6 5
2 1 4 0 - Ø The ultimate digit is 0 and the penultimate
digits is 4, so the ultimate plus twice the
penultimate is 0 8 8. - 0 6 5 2 1 4 0
- 8
- Ø For the tens column, the ultimate is 4 and the
penultimate is 1, so 42 6. - 0 6 5 2 1 4 0
- 6 8
Ø Likewise, 1 4 5, and 2 10 12. With 12
we set down 2 and carry 1. 0 6 5 2 1 4 0
2 5 6 8 1 Ø 5 12 Carry 1 18
and again we carry 1. Ø The final step is 6 0
Carry 1 7. 0 6 5 2 1 4 0 7 8 2 5 6 8
1 1 Ø The answer is 7 8 2 5 6 8
13