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Work by Friction

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Work by Friction A box s 10 m across a surface. A frictional force of 20 N is acting on the box. What is the work done by friction? What happened to this energy? – PowerPoint PPT presentation

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Title: Work by Friction


1
Work by Friction
  • A box slides 10 m across a surface. A frictional
    force of 20 N is acting on the box.
  • What is the work done by friction?
  • What happened to this energy?

2
Work by Friction
  • A box slides 10 m across a surface. A frictional
    force of 20 N is acting on the box.
  • What is the work done by friction? 200 J
  • What happened to this energy?
  • It turned into sound and heat.

3
Heat Energy
  • 3U Physics

4
Remember the 2nd Law
  • You cant break even.
  • Youre always going to get less useful energy out
    than was put in because some energy will be lost
    to entropy.

5
The 2nd Law
  • Entropy refers to the disorder of a system.
  • Entropy always increases.

6
The 2nd Law
  • For our purposes, the 2nd Law means that heat
    will always move from materials at higher
    temperatures to materials at lower temperatures.

7
Some definitions
  • Temperature is a measure of the average kinetic
    energy of the particles (measured in oC or K).

8
Some definitions
  • Temperature is a measure of the average kinetic
    energy of the particles (measured in oC or K).
  • Thermal energy is the total kinetic energy and
    potential energy of the particles of a material
    (measured in J).

9
Some definitions
  • Temperature is a measure of the average kinetic
    energy of the particles (measured in oC or K).
  • Thermal energy is the total kinetic energy and
    potential energy of the particles of a material
    (measured in J).
  • Heat is a measure of the thermal energy
    transferred from a warm body to a cooler one.

10
Heat Transfer
  • Heat may be transferred by
  • conduction
  • convection
  • radiation

11
Conduction
  • In a solid, every atom is physically bonded to
    its neighbours in some way. If heat energy is
    supplied to one part of a solid, the atoms
    vibrate faster and these vibrations are passed on
    to the next atom, and so on

12
Conduction
  • In metals, not only do the atoms vibrate more
    when heated, but the free electrons move around
    more as well. These transfer the energy much
    faster than just vibrations in bonds.

13
Convection
  • Actually, heat doesnt rise.
  • Heated gas or liquid rises because it is less
    dense than the cooler material surrounding it
    (which will sink to replace the rising material).

14
Convection
  • Note that radiators actually heat primarily by
    convection, not radiation.

15
Radiation
  • Radiation is the transfer of heat in the form of
    infrared (long wavelength) light.
  • It travels in straight lines in every direction
    and can even travel through a vacuum.

16
Radiation
  • Warm-blooded creatures typically maintain a body
    temperature warmer than their surroundings and
    will lose heat energy by radiating infrared light.

17
Radiation
  • Cold-blooded creatures will not.

18
Specific Heat Capacity
  • The specific heat capacity (c) of a material is
    the amount of energy that must be added to raise
    the temperature of 1.0 kg of material by 1oC or
    1K.
  • c is different for different materials.

19
Specific Heat Capacity
  • c is different for different materials, e.g.
  • csteel 452 J/kgoC
  • cglass 840 J/kgoC
  • cwater 4186 J/kgoC

20
Heat
  • The amount of heat (Q) required to raise the
    temperature of a quantity m of a material by an
    amount DT is therefore
  • Q mcDT

21
Heat Example 1
  • Calculate the energy required to raise the
    temperature of 5.0 kg of water by 75oC.

22
Heat Example 1
  • Calculate the energy required to raise the
    temperature of 5.0 kg of water by 75oC.
  • m 5.0 kg
  • c 4186 J/kgoC
  • DT 75oC
  • Q ?

23
Heat Example 1
  • Calculate the energy required to raise the
    temperature of 5.0 kg of water by 75oC.
  • m 5.0 kg Q mcDT
  • c 4186 J/kgoC Q (5.0 kg)(4186
  • DT 75oC J/kgoC)(75oC)
  • Q ? Q 1.6 x 106 J

24
Conservation of Energy
  • Heat will be transferred from a hot object to a
    cold object such that the heat lost by the hot
    object is equal to the heat gained by the cold
    object.
  • Qlost Qgained

25
Heat Example 2
  • A 0.500 kg pot of hot water for tea has cooled to
    40.0oC. How much boiling water must be added to
    raise the temperature of the tea water to 65.0oC?

26
Heat Example 2
  • A 0.500 kg pot of hot water for tea has cooled to
    40.0oC. How much boiling water must be added to
    raise the temperature of the tea water to 65.0oC?
  • So the cold water needs its temperature raised
    from 40.0oC to 65oC DTcold 25oC

27
Heat Example 2
  • A 0.500 kg pot of hot water for tea has cooled to
    40.0oC. How much boiling water must be added to
    raise the temperature of the tea water to 65.0oC?
  • So the cold water needs its temperature raised
    from 40.0oC to 65oC DTcold 25oC
  • And the hot water needs its temperature lowered
    from 100.0oC to 65.0oC DThot 35.0oC

28
Heat Example 2
  • Heat lost by hot water Heat gained by cold
    water
  • mhotcDThot mcoldcDTcold

29
Heat Example 2
  • Heat lost by hot water Heat gained by cold
    water
  • mhotcDThot mcoldcDTcold
  • mhotDThot mcoldDTcold

30
Heat Example 2
  • Heat lost by hot water Heat gained by cold
    water
  • mhotcDThot mcoldcDTcold
  • mhotDThot mcoldDTcold
  • mhot mcoldDTcold/DThot

31
Heat Example 2
  • Heat lost by hot water Heat gained by cold
    water
  • mhotcDThot mcoldcDTcold
  • mhotDThot mcoldDTcold
  • mhot mcoldDTcold/DThot
  • mhot (0.500 kg)(25.0oC)/(35.0oC)

32
Heat Example 2
  • Heat lost by hot water Heat gained by cold
    water
  • mhotcDThot mcoldcDTcold
  • mhotDThot mcoldDTcold
  • mhot mcoldDTcold/DThot
  • mhot (0.500 kg)(25.0oC)/(35.0oC)
  • mhot 0.357 kg

33
Heat More Practice
  • Homework Set 9 Heat Energy
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