Optical Fiber Communications - PowerPoint PPT Presentation

1 / 20
About This Presentation
Title:

Optical Fiber Communications

Description:

Optical Fiber Communications Author: alfamily Last modified by: yaalquda Created Date: 8/16/2006 12:00:00 AM Document presentation format: On-screen Show Other titles: – PowerPoint PPT presentation

Number of Views:344
Avg rating:3.0/5.0
Slides: 21
Provided by: alfa63
Category:

less

Transcript and Presenter's Notes

Title: Optical Fiber Communications


1
Optical Fiber Communications
  • Lecture 10

2
Topics
  • Single Mode Fiber
  • Mode Field Diameter
  • Propagation Modes in Single Mode Fiber
  • Graded Index Fiber

3
Single Mode Fiber
  • Single Mode fiber are constructed by
  • letting dimensions of core diameter be a few
    wavelengths and
  • by having small index difference between core and
    cladding
  • In practice core cladding index difference varies
    between 0.1 and 1.0 percent
  • Typical single mode fiber may have a core radius
    of 3 micron and NA 0.1 at wavelength 0.8 micron

4
Mode Field Diameter
  • Geometric distribution of light in propagation
    mode is important when predicting performance
    characteristics.
  • Mode Field Diameter (MFD) is analogues to core
    diameter in multimode fibers except not all light
    that propagates is carried in the core
  • Many models for characterizing MFD with main
    consideration of how to approximate electric
    field distribution

5
(No Transcript)
6
MFD
  • Assume electric field distribution to be Gaussian
  • Where r is radius, Eo is field at zero radius,
    and Wo is the width of the electric field
    distribution
  • Take width 2Wo of MFD to be 2e-1radius of optical
    electric field (e-2 of optical power)

7
MFD
  • The MFD width 2Wo can be defined for LP01 mode as

8
Propagation Modes in Single Mode Fiber
  • In single mode fiber there are two independent
    degenerate propagation modes
  • These modes are similar but their polarization
    planes are orthogonal
  • Electric field of light propagating along the
    fiber is linear superposition of these two
    polarization mode

9
Fig. 2-24 Polarizations of fundamental mode
10
contd
  • Choose one of the modes to have its transverse
    electric field along x direction and the other in
    y direction
  • In ideal fiber, two modes are degenerate with
    equal propagation constants and will maintain
    polarization state injected into the fiber
  • In actual fiber there are imperfections, such as
    asymmetrical lateral stress, noncircular cores
    and variations in refractive index profiles
  • These imperfections break circular symmetry

11
contd
  • The modes propagate with different phase
    velocities and the difference between their
    effective refractive indices is called
    birefringence
  • Or
  • If light is injected into the fiber so that both
    modes are excited, then one will be delayed in
    phase

12
contd
  • When this phase difference is an integral mpi,
    the two mode will beat at this point and input
    polarization state will be reproduced.
  • The length over which this beating occurs is the
    fiber beat length

13
Example
  • A single mode optical fiber has a beat length of
    8 cm at 1300nm, the modal birefringence
  • Or

14
Graded Index Fiber Structure
  • In graded index fiber, core refractive index
    decreases continuously with increasing radial
    distance r from center of fiber and constant in
    cladding
  • Alpha defines the shape of the index profile
  • As Alpha goes to infinity, above reduces to step
    index
  • The index difference is

15
contd
  • NA is more complex that step index fiber since it
    is function of position across the core
  • Geometrical optics considerations show that light
    incident on fiber core at position r will
    propagate only if it within NA(r)
  • Local numerical aperture is defined as
  • And

16
contd
  • Number of bound modes

17
Examples
  • If a 9.5 micron, find n2 in order to design a
    single mode fiber, if n11.465.
  • Solution,
  • The longer the wavelength, the larger refractive
    index difference is needed to maintain single
    mode condition, for a given fiber

18
Examples
  • Compute the number of modes for a fiber whose
    core diameter is 50 micron. Assume that n11.48
    and n21.46. Wavelength 0.8 micron.
  • Solution
  • For large V, the total number of modes supported
    can be estimated as

19
Example
  • What is the maximum core radius allowed for a
    glass fiber having n11.465 and n21.46 if the
    fiber is to support only one mode at wavelength
    of 1250nm.
  • Solution

20
HW
  • Due 2/11/08
  • 2-2
  • 2-8
  • 2-11
  • 2-18
  • 2-19
  • 2-21
  • 2-24
  • 2-25
  • 2-27
  • 2-28
Write a Comment
User Comments (0)
About PowerShow.com