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Lesson 2.4, page 301 Dividing Polynomials

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Lesson 2.4, page 301 Dividing Polynomials Objective: To divide polynomials using long and synthetic division, and to use the remainder and factor theorems. – PowerPoint PPT presentation

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Title: Lesson 2.4, page 301 Dividing Polynomials


1
Lesson 2.4, page 301Dividing Polynomials
  • Objective To divide polynomials using long and
    synthetic division, and to use the remainder and
    factor theorems.

2
How do you divide a polynomial by another
polynomial?
  • Perform long division, as you do with numbers!
    Remember, division is repeated subtraction, so
    each time you have a new term, you must SUBTRACT
    it from the previous term.
  • Work from left to right, starting with the
    highest degree term.
  • Just as with numbers, there may be a remainder
    left. The divisor may not go into the dividend
    evenly.

3
Dividing a Poly by a Binomial
4
See Example 1, page 302.
  • Check Point 1(x2 14x 45) ? (x 9)

5
Check Point 2(7 11x - 3x2 2x3) ? (x - 3)
6
Missing Terms?
  • Write the polynomial in standard form.
  • If any power is missing, use a zero to hold the
    place of that term.
  • Divide as before.

7
Check Point 3(2x4 3x3 7x - 10) ? (x2 2x)
8
Synthetic Division
  • a simpler process (than long division) for
    dividing a polynomial by a binomial uses
    coefficients and part of the divisor
  • See Example 4, page 306.

9
STEPS for Synthetic Division, pg. 306
  • 1) Write polynomial in descending order of the
    degrees.
  • 2) List the coefficients. (If one power is
    missing, put a zero to hold that place.)
  • 3) Write the constant c of the divisor x - c to
    the left.
  • 4) Bring down the first coefficient.
  • 5) Multiply the first coefficient by c, write
    the product under the 2nd coefficient and add.
  • 6) Multiply this sum by c, write it under the
    next coefficient and add. Repeat until all
    coefficients have been used.
  • 7) The numbers on the bottom row are the
    coefficients of the answer. The first power on
    the variable will be one less than the highest
    power in the original polynomial.

10
Check Point 4, page 307
  • Use Synthetic Division x3 7x 6 by x 2.
  • Caution What is missing?

11
The Remainder Theorem, pg. 307
  • If the polynomial f(x) is divided by
  • x c, then the remainder is the same value as
    f(c).
  • Also
  • f(x) (x c) q(x) r
  • divisor (quotient) remainder

12
See Example 5, pg. 308
  • Check Point 5
  • Given f(x) 3x3 4x2 5x 3, use the
    remainder theorem to find f(- 4).

13
Dividing a Poly by a Binomial
  • If a binomial divides into a polynomial with no
    remainder, the binomial is a factor of the
    polynomial.

14
Factor Theorem, pg. 308
  • For the polynomial f(x), if f(c) 0,
  • then x c is a factor of f(x)
  • Remember . . . If something is a factor, then it
    divides the term evenly with 0 remainder.

15
See Example 6, pg. 309.
  • Check Point 6 Solve the equation
  • 15x3 14x2 3x 2 0, given that -1
  • is a zero of f(x) 15x3 14x2 3x 2.

16
Determine if -1 is a zero ofg(x) x4 - 6x3 x2
24x -20.
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