Thermodynamics and Statistical Mechanics - PowerPoint PPT Presentation

1 / 32
About This Presentation
Title:

Thermodynamics and Statistical Mechanics

Description:

Thermodynamics and Statistical Mechanics Partition Function Free Expansion of a Gas Free Expansion Isothermal Expansion Isothermal Expansion Entropy Change ... – PowerPoint PPT presentation

Number of Views:57
Avg rating:3.0/5.0
Slides: 33
Provided by: Phili169
Learn more at: https://www.rpi.edu
Category:

less

Transcript and Presenter's Notes

Title: Thermodynamics and Statistical Mechanics


1
Thermodynamics and Statistical Mechanics
  • Partition Function

2
Free Expansion of a Gas
3
Free Expansion
4
Isothermal Expansion
5
Isothermal Expansion
Reversible route between same states.
dQ dW dU Since T is constant, dU 0.
Then, dQ dW.
6
Entropy Change
The entropy of the gas increased. For the
isothermal expansion, the entropy of
the Reservoir decreased by the same amount. So
for the system plus reservoir, DS 0 For the
free expansion, there was no reservoir.
7
Statistical Approach
8
Statistical Approach
9
Partition Function
10
Boltzmann Distribution
11
Maxwell-Boltzmann Distribution
  • Correct classical limit of quantum statistics is
    Maxwell-Boltzmann distribution, not Boltzmann.
  • What is the difference?

12
Maxwell-Boltzmann Probability
wB and wMB yield the same distribution.
13
Relation to Thermodynamics
14
Relation to Thermodynamics
15
Chemical Potential
  • dU TdS PdV mdN
  • In this equation, m is the chemical energy per
    molecule, and dN is the change in the number of
    molecules.

16
Chemical Potential
17
Entropy
18
Entropy
19
Helmholtz Function
20
Chemical Potential
21
Chemical Potential
22
Boltzmann Distribution
23
Distributions
24
Distributions
25
Ideal Gas
26
Ideal Gas
27
Ideal Gas
28
Entropy
29
Math Tricks
  • For a system with levels that have a constant
    spacing (e.g. harmonic oscillator) the partition
    function can be evaluated easily. In that case,
    en ne, so,

30
Heat Capacity of Solids
  • Each atom has 6 degrees of freedom, so based on
    equipartition, each atom should have an average
    energy of 3kT. The energy per mole would be 3RT.
    The heat capacity at constant volume would be the
    derivative of this with respect to T, or 3R. That
    works at high enough temperatures, but approaches
    zero at low temperature.

31
Heat Capacity
  • Einstein found a solution by treating the solid
    as a collection of harmonic oscillators all of
    the same frequency. The number of oscillators was
    equal to three times the number of atoms, and the
    frequency was chosen to fit experimental data for
    each solid. Your class assignment is to treat the
    problem as Einstein did.

32
Heat Capacity
Write a Comment
User Comments (0)
About PowerShow.com