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CHE 111 - Module 4

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Title: CHE 111 - Module 4


1
CHE 111 - Module 4
0
  • CHAPTER 4 5
  • LECTURE NOTES

2
Stoichiometry Balancing Equations
0
  • Remember we stated in the previous chapter that
    stoichiometry is the study of the quantitative
    relationships between the amounts of reactants
    and products in chemical reactions.
  • We use BALANCED equations to understand
    stoichiometric relationships of the elements and
    compounds within a chemical reaction.

3
The Balanced Equation
0
  • 2Al(s) 3Br2(l) ? Al2Br6(s)
  • 2mol of Al 3mol of Br2 1mol of Al2Br6
  • 2 atoms of Al 2 atoms of Al
  • 6 atoms of Br 6 atoms of Br
  • The number of the same atom of each element
    must be equal on each side of the equation.

4
A Closer Look at the Equation
0
  • 2Al(s) 3Br2(l) ? Al2Br6(s)
  • The chemicals on the left are the reactants and
    the right are the products.
  • The coefficient in front of the chemical denotes
    the stoichiometric relationship.
  • The numerical subscript represents the number of
    atoms present in the molecule.
  • The letter subscripted denotes the phase of
    matter.

5
Balancing Equations
0
  • For example the following is balanced.
  • CH4 2O2 ? CO2 2H2O
  • Try to balance the following
  • Fe2S3 O2 ? Fe2O3 S
  • Al H2SO4 ? Al2(SO4)3 H2
  • Ca Al2Br6 ? CaBr2 Al

6
Balanced Equations
  • Check your answer from the previous slide
  • 2Fe2S3 3O2 ? 2Fe2O3 6S
  • 2Al 3H2SO4 ? Al2(SO4)3 3H2
  • 3Ca Al2Br6 ? 3CaBr2 2Al

7
Types of Reactions
0
  • Combination Reactions
  • Decomposition Reactions
  • Displacement (Single-Replacement) Reactions
  • Metathesis (Double-Replacement) Reactions
  • Combustion Reactions

8
Combination Reactions
0
  • A combination reaction is a reaction where two
    substances chemically combine to form another
    substance.
  • A B ? AB
  • 2Na(s) Cl2(g) ? 2NaCl(s)
  • P4(s) 6Cl2(g) ? 4PCl3(s)

9
Decomposition Reaction
0
  • A decomposition reaction is when a single
    compound decomposes into two or more other
    substances.
  • AB ? A B
  • 2KClO3(s) ? 2KCl(s) 3O2(g)
  • 2NO2(g) ? 2NO(g) O2(g)

10
Displacement Reaction
0
  • A displacement (single replacement) reaction is a
    reaction where one element displaces another
    element.
  • A BC ? B AC
  • Zn(s) 2HCl(aq) ? ZnCl2(aq) H2(g)
  • Cu(s) 2AgNO3(aq) ? Cu(NO3)2(aq) 2Ag(s)

11
Metathesis Reaction
0
  • A metathesis (double replacement) reaction is a
    reaction where two compounds switch cations to
    form two new compounds.
  • AB- CD- ? AD- CB-
  • CaCl2(aq) Na2CO3(aq) ? CaCO3(s) 2NaCl(aq)
  • AgNO3(aq) KCl(aq) ? ???

12
SOLUBILITY
0
  • Solubility the amount of a substance that can
    be dissolved in a given quantity of solvent (like
    water) at a specific temperature
  • Unsaturated amount of substance less than
    saturated
  • Saturated the exact amount at solubility
  • Supersaturated excess amount of substance

13
How Solubility Influences Rxn
0
  • When a substance is soluble in water, it will
    appear with a subscript of (aq) meaning that the
    substance is broken up into its ions
    incorporated into the water lattice.
  • When a substance is insoluble in water, it will
    be written with a subscript of (s), (l), or (g)
    and will precipitate out of solution.

14
Solubility of Ionic Compounds in Water
Soluble Compounds Exceptions
Sodium, potassium, and ammonium compounds
Acetates and nitrates
Halides (chlorides, bromides, Lead(II), silver, and mercury (I) and iodides) halides are insoluble
Sulfates Calcium, strontium, barium, and Lead(II) sulfates are insoluble
15
Insolubility of Ionic Compounds in Water
Insoluble Compounds Exceptions
Carbonates and phosphates Sodium, potassium, and ammonium compounds are soluble.
Hydroxides Sodium, potassium, calcium, strontium, and barium compounds are soluble
Sulfide Sodium, potassium, calcium, and ammonium compounds are soluble
16
A Look at Metathesis Again
0
  • Looking back at slide 10 to the first reaction
    when the cations rearranged, the CaCO3 being
    insoluble by our definition is recorded as CaCO3
    (s). The CaCO3 would precipitate out of solution
    as a solid.
  • Looking at AgNO3(aq) KCl(aq) ? ?, we can
    rearrange the cations and conclude that the AgCl
    is a solid and will precipitate out of solution

17
Types of Metathesis Reactions
0
  • Three classifications of metathesis reactions
  • Precipitation reaction - formation of a solid
  • Pb(NO3)2(aq) Na2CO3(aq) ? PbCO3(s) 2NaNO3(aq)
  • Neutralization reaction - formation of water
  • HCl(aq) NaOH(aq) ? NaCl(aq) H2O(l)
  • Gas formation reaction - CO2, H2S, SOx, NOx are
    typically formed

18
Precipitation Reactions
0
  • A solid precipitate is produced in the
    rearrangement of cations as follows
  • Pb(NO3)2(aq) Na2CO3(aq) ? PbCO3(s)
    2NaNO3(aq)
  • The Ionic Equation is expressed as
  • Pb2 2NO3- 2Na CO3-2 ? PbCO3(s)
    2Na 2NO3-
  • After neglecting the spectator ions, the net
    ionic equation will look like
  • Pb2(aq) CO3-2(aq) ? PbCO3(s)

19
Reviewing Ionic Compounds
0
  • Ca2 2Cl- ? CaCl2
  • Each ion comes together based on charge to
    form an overall neutral ionic compound.
  • 3Ca2 2PO4-3 ? Ca3(PO4)2
  • The cation and the polyatomic ion come
    together based on charge to form an overall
    neutral ionic compound.

20
Net Ionic Equations (NIE)
0
  • If you were given the reactants Ca(NO3)2 and
    Na3PO4 you should be able to predict the
    precipitate and write a balance equation, the
    ionic equation, and the net ionic equation (NIE)
    for this reaction.
  • The NIE for these reactants is as follows
  • 3Ca2(aq) 2PO4-3(aq) ? Ca3(PO4)2(s)

21
Common Polyatomic Ions
0
  • carbonate ion CO3-2
  • sulfate ion SO4-2
  • sulfite ion SO3-2
  • hydroxide OH-
  • phosphate PO4-3
  • permanganate MnO4-
  • chromate CrO4-2
  • dichromate Cr2O7-2
  • ammonium NH4
  • oxalate C2O4-2
  • bicarbonate HCO3-
  • cyanide ion CN-
  • acetate C2H3O3-

22
Neutralization Reaction
0
  • A neutralization reaction is a reaction that
    occurs between an acid and a base with the
    production of a salt and water.
  • HCl(aq) NaOH(aq) ? NaCl(aq) H2O(l)
  • acid base salt
    water

23
Gas Formation Reaction
0
  • A gas formation reaction is a metathesis reaction
    that generates a gas as a product.
  • Metal carbonates or bicarbonates acid
  • Metal sulfides acid
  • Metal sulfites acid
  • Ammonium salts and strong base

24
Metal Carbonates
0
  • Metal carbonates or bicarbonates when combined
    with an acid form salt, water and carbon dioxide
    gas.
  • Na2CO3(aq) 2HCl(aq) ? 2NaCl(aq) H2O(l)
    CO2(g)
  • Where CO2 gas is given off

25
Metal Sulfides
0
  • Metal sulfides when combined with an acid form
    salt and hydrogen sulfide gas.
  • Na2S(aq) 2HCl(aq) ? 2NaCl(aq) H2S(g)
  • Where H2S gas is given off

26
Metal Sulfites
0
  • Metal sulfites when combined with an acid form
    salt, water, and sulfur dioxide gas.
  • Na2SO3(aq) 2HCl(aq) ? 2NaCl(aq) H2O(l)
    SO2(g)
  • Where SO2 gas is given off

27
Ammonium Salts
0
  • Ammonium salts when combined with a base produce
    salt, water and ammonia.
  • NH4Cl (aq) NaOH(aq) ? NaCl(aq) H2O(l) NH3(g)
  • Where ammonia gas is given off

28
Combustion Reactions
0
  • A combustion reaction is a reaction with
    molecular oxygen to form products in which all
    elements are combined with oxygen.
  • CH4 2O2 ? CO2 2H2O

29
Limiting Reactants
0
  • One of the reactants is in limited supply and
    thus restricts the amount of product formed.
  • Think of it as If you wanted to bake a batch of
    peanut butter cookies and the recipe calls for 1
    cup of peanut butter and all you have is ½ a cup,
    even though you have all the other ingredients,
    you can at most make ½ a batch of cookies.

30
Limiting Reactants (cont.)
0
  • Consider the combustion reaction
  • CH4 2O2 ? CO2 2H2O
  • How much CO2 can be produced if you have 0.13g of
    methane and 0.45g of O2?

31
Percent Yield
0
  • The maximum amount of product that can be
    obtained from a chemical reaction is the
    theoretical yield.
  • The actual amount produced in a chemical process
    is the actual yield.
  • The percent yield is equal to the actual yield
    divided by the theoretical yield times 100.

32
Redox Reactions
0
  • Oxidation of an element takes place when
    electrons are lost from the valence shell of the
    element.
  • Reduction of an element takes place when
    electrons are added to the valence shell of the
    element.
  • Redox reactions show the transfer of electrons
    that takes place during oxidation and reduction.

33
Redox Reactions (cont.)
0
  • All oxidation and reduction reactions involve
    transfer of electrons between substances.
  • View CD-ROM screen 5.12
  • Ag accepts electrons for Cu and is reduced to Ag
    and Cu loses electrons to Ag and is oxidized to
    Cu2 in the following redox rxn
  • 2Ag(aq) Cu(s) ? 2Ag(s) Cu2(aq)

34
Redox Reactions (cont.)
0
  • The oxidation half reaction is
  • Cu(s) 2e- ? Cu2(aq)
  • The reduction half reaction is
  • 2Ag(aq) 2e- ? 2Ag(s)
  • Cu is called the reducing agent because it caused
    Ag to be reduced and Ag is called the
    oxidizing agent because it caused Cu to be
    oxidized.

35
Determining Oxidation Numbers
0
  • Each atom in a pure element has an oxidation
    number of zero.
  • For monoatomic ions, the ox. number is equal to
    its ionic charge.
  • F is always 1, other halogens are 1 as well
    except with oxygen or fluorine.
  • The ox. number for H is 1 except with hydrides
    (CaH2).and O is 2 except with peroxides (H2O2).
  • The ? ox. must 0 for a compound or to the
    overall charge of polyatomic ion being considered.

36
Balancing Redox Reactions
0
  • We can use the balance of electrons transferred
    in a redox reaction to help us balance the
    overall equation.
  • Consider the unbalanced equation
  • Zn(s) HCl(aq) ? ZnCl2(aq) H2(g)
  • The balanced equation takes into consideration
    the oxidation of the Zn and the reduction of the
    H.

Zn(s) 2HCl(aq) ? ZnCl2(aq) H2(g)
37
Molarity
0
  • Molarity Moles of Solute
  • Liters of Total Solution
  • Symbol for molarity is M
  • Units are moles/Liter

38
Solution Preparation
  • To prepare a 1.0M solution of NaCl, you would
    determine how many grams of NaCl is contained in
    1.0 moles of NaCl and then dissolve that amount
    in a 1.0L volumetric flask. You would then qs
    with distilled H2O.
  • 1.0M NaCl 1 mole (or 58.44g) NaCl
  • 1.0L of solution
  • How much NaCl would you use to make a 0.1M
    solution of NaCl?

As 1/10 of a mole 5.844g NaCl, you would
dissolve 0.1mole (5.844g) of NaCl in 1.0L of
solution.
39
Acids
  • An acid is defined as follows
  • Arrhenius releases H when dissolved in H2O
  • Bronsted-Lowrey a substance that can donate a
    proton to another substance
  • Lewis a substance that can accept a pair of
    electrons from another atom to form a new bond

40
Bases
  • A base is defined as follows
  • Arrhenius releases OH- when dissolved in H2O
  • Bronsted-Lowrey a substance that can accept a
    proton from another substance
  • Lewis a substance that can donate a pair of
    electrons to another atom to form a new bond

41
pH and Concentrations of Acids and Bases
  • pH -log H
  • 1 acidic 7 basic 14
  • When dealing with H less than 0.1M (pH1),
    we use activity coefficients instead of pH.

42
pH of Household Items
  • pH of vinegar 2.80
  • pH of soda 2.90
  • pH of orange juice 3.80
  • pH of pure water 7.00
  • pH of blood 7.40
  • pH of ammonia 11.00
  • pH of oven cleaner 11.7

43
Titration
  • A method for quantitative analysis of a substance
    by essentially complete reaction in solution with
    a measured quantity of a reagent of known
    concentration.
  • Often used in redox reactions
  • Many redox reactions go rapidly to completion in
    aqueous media to determine the equivalency point.
  • Typically used for neutralization reactions.
  • Acid is titrated with a base using an indicator
    to determine the equivalency point of the
    neutralization reactions.

44
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