Mini-Unit: Colligative Properties - PowerPoint PPT Presentation

1 / 10
About This Presentation
Title:

Mini-Unit: Colligative Properties

Description:

Day 2 - Notes Mini-Unit: Colligative Properties Calculations with Colligative Properties After today you will be able to Explain what a colligative property is ... – PowerPoint PPT presentation

Number of Views:126
Avg rating:3.0/5.0
Slides: 11
Provided by: KarenRa6
Category:

less

Transcript and Presenter's Notes

Title: Mini-Unit: Colligative Properties


1
Mini-Unit Colligative Properties
Day 2 - Notes
  • Calculations with Colligative Properties

2
After today you will be able to
  • Explain what a colligative property is
  • Calculate b.p. elevation and f.p. depression

3
  • Recall, colligative properties are properties of
    a solution which are affected by the number of
    dissolved particles in the solvent.
  • The chemical makeup of the solute does not
    matter. The effect is the same. Sugar has the
    same affect as salt on a solvent.

4
Affected Colligative Properties
  • Three colligative properties that are affected
    are
  • Vapor pressure (lowering)
  • Boiling point (elevation)
  • Freezing point (depression)
  • \
  • .There are others, but these are the ones we
    will talk about in this class.

5
Boiling Point Elevation (?TB)
  • Recall, boiling point is the point at which V.P.
    atmospheric pressure.
  • i depends on the number of particles the solute
    breaks into
  • KB a constant that depends on the solvent
  • For H2O,
  • m molality of the solution (mol/kg)

?TB (i)(KB)(m)
KB 0.512C/m
6
Vant Hoff Factor (i)
  • To obtain the i-value
  • When dissolved, ionic compounds will break apart
    into separate ions.
  • Examples NaCl ? i
  • MgCl2 ? i
  • Ca(SO4) ? i
  • Ba3(PO4)2 ? i

2
Na1 Cl-1
Mg2 2Cl-1
3
Ca2 (SO4)-2
2
3Ba2 2(PO4)-3
5
7
Example
  • a) What is the change in the boiling point of a
    0.335m solution of KBr in H2O? b) What is the new
    boiling point?
  • ?TB
  • i
  • m
  • KB

?
?TB(i)(KB)(m)
KBr ? K1 Br-1
?TB(2)(0.512C/m)(0.335m)
0.335m
a) ?TB0.343C
0.512C/m
Water boils at 100C so
0.343C
100C


b) 100.343C
8
Freezing Point Depression (?TF)
  • Recall, freezing point is the temperature at
    which a liquid ? solid
  • i depends on the number of particles
  • KB a constant
  • For H2O,
  • m molality

?TF (i)(KF)(m)
KF 1.86C/m
9
Example
  • a) What is the change in the freezing point of a
    2.5m solution of BaF2 in H2O? b) What is the new
    freezing point?
  • ?TF
  • i
  • KF
  • m

?TF(i)(KF)(m)
?
?TF (3) (1.86C/m)(2.5m)
BaF2? Ba2 2F-1
a) ?TF -14C
1.86C/m
2.5m
Water freezes at 0C so
14C
0C
-

b) -14C
10
Questions?Complete WS2
Write a Comment
User Comments (0)
About PowerShow.com