Title: Motion
1Motion ForcesLesson 3
- Action and Reaction
- Newtons Third Law
- Momentum
- Conservation of Momentum
2 Newtons Third Law
- Newtons Third Law of Motion
- When one object exerts a force on a second
object, the second object exerts an equal but
opposite force on the first.
3 Newtons Third Law
- How can a horse pull a cart if the cart is
pulling back on the horse with an equal but
opposite force?
- Arent these balanced forces resulting in no
acceleration?
4Newtons Third Law
- forces are equal and opposite but act on
different objects - they are not balanced forces
- the movement of the horse depends on the forces
acting on the horse
5Action and Reaction
- When a force is applied in nature, a reaction
force occurs at the same time. - When you jump on a trampoline, for example, you
exert a downward force on the trampoline. - Simultaneously, the trampoline exerts an equal
force upward, sending you high into the air.
6Action and Reaction Forces Dont Cancel
- According to the third law of motion, action and
reaction forces act on different objects. - Thus, even though the forces are equal, they are
not balanced because they act on different
objects.
7Action and Reaction Forces Dont Cancel
- For example, a swimmer acts on the water, the
reaction of the water pushes the swimmer
forward. - Thus, a net force, or unbalanced force, acts on
the swimmer so a change in his or her motion
occurs.
8Rocket Propulsion
- In a rocket engine, burning fuel produces hot
gases. The rocket engine exerts a force on these
gases and causes them to escape out the back of
the rocket. - By Newtons third law, the
- gases exert a force on the
- rocket and push it forward.
9Newtons Third Law
- The hammer exerts a force on the nail to the
right. - The nail exerts an equal but opposite force on
the hammer to the left.
10Momentum
- A moving object has a property called momentum
that is related to how much force is needed to
change its motion. - The momentum of an object is the product of its
mass and velocity - Momentum is given the symbol p and can be
calculated with the following equation
11 Momentum
p mv
- Momentum
- quantity of motion
p momentum (kgm/s) m mass (kg) v velocity
(m/s)
12Force and Changing Momentum
- By combining these two relationships, Newtons
second law can be written in this way - In this equation mvf is the final momentum and
mvi is the initial momentum
13Law of Conservation of Momentum
- The momentum of an object doesnt change unless
its mass, velocity, or both change. - Momentum, however, can be transferred from one
object to another. - The law of conservation of momentum states that
if a group of objects exerts forces only on each
other, their total momentum doesnt change.
14Law of Conservation of Momentum
- The results of a collision depend on the momentum
of each object. - When the first puck hits the second puck from
behind, it gives the second puck momentum in the
same direction.
15When Objects Collide
- If the pucks are speeding toward each other with
the same speed, the total momentum is zero.
16Newtons Third Law
- Both objects accelerate.
- The amount of acceleration depends on the mass of
the object.
- Small mass ? more acceleration
- Large mass ? less acceleration
17Conservation of Momentum
- Law of Conservation of Momentum
- The total momentum in a group of objects doesnt
change unless outside forces act on the objects.
pbefore pafter
18Conservation of Momentum
- Elastic Collision
- KE is conserved
- Inelastic Collision
- KE is not conserved
19 Momentum
- Find the momentum of a bumper car if it has a
total mass of 280 kg and a velocity of 3.2 m/s.
GIVEN p ? m 280 kg v 3.2 m/s
WORK p mv p (280 kg)(3.2 m/s) p 896
kgm/s
20 Momentum
- The momentum of a second bumper car is 675
kgm/s. What is its velocity if its total mass
is 300 kg?
GIVEN p 675 kgm/s m 300 kg v ?
WORK v p m v (675 kgm/s)(300 kg) v
2.25 m/s
21Conservation of Momentum
- A 5-kg cart traveling at 1.2 m/s strikes a
stationary 2-kg cart and they connect. Find
their speed after the collision.
BEFORE Cart 1 m 5 kg v 4.2 m/s Cart 2 m
2 kg v 0 m/s
AFTER Cart 1 2 m 7 kg v ?
p 21 kgm/s
p 0
v p m v (21 kgm/s) (7 kg) v 3 m/s
pbefore 21 kgm/s
pafter 21 kgm/s
22Conservation of Momentum
- A 50-kg clown is shot out of a 250-kg cannon at a
speed of 20 m/s. What is the recoil speed of the
cannon?
BEFORE Clown m 50 kg v 0 m/s Cannon m 250
kg v 0 m/s
AFTER Clown m 50 kg v 20 m/s Cannon m 250
kg v ? m/s
p 0
p 1000 kgm/s
p 0
p -1000 kgm/s
pbefore 0
pafter 0
23Conservation of Momentum
- Sonow we can solve for velocity.
GIVEN p -1000 kgm/s m 250 kg v ?
WORK v p m v (-1000 kgm/s)(250 kg) v
- 4 m/s (4 m/s backwards)
24Rocket Challenge
- After I check your fill in the blank notes. Come
and get the instructions for the paper rockets.
Depending on time you might have time to do all
3. If not you will complete them on Tuesday. - You will use the best design and make it for your
larger one we will do next week.