Title: Yesterday
1Yesterdays Homework
2Calculate the pH of solutions having the
following ion concentrations at 298o K.
- H 1.0 x 10-2
- log H -2
- pH 2
3Calculate the pH of solutions having the
following ion concentrations at 298o K.
- H 3.0 x 10-6
- log H 0.477 6
- -5.523
- pH 5.523
4Calculate the pH of solutions having the
following ion concentrations at 298o K.
- OH- 8.2 x 10-6
- log OH- 0.913 6
- -5.087
- pOH 5.087
5Calculate the pH of solutions having the
following ion concentrations at 298o K.
- pOH 5.087
- pH pOH 14
- pH 14 pOH
- 14 5.087
- 8.913
6Calculate the pH of solutions having the
following ion concentrations at 298o K.
- OH- 1.0 x 10-6
- log OH- -6
- pOH 6
- pH 14 6
- 8
7Calculate the pH of solutions having the
following ion concentrations at 298o K.
- OH- 6.5 x 10-4
- log OH- 0.812 - 4
- pOH 3.188
- pH 14 3.188
- 10.812
8Calculate the pH of solutions having the
following ion concentrations at 298o K.
- H 3.6 x 10-9
- log H 0.556 - 9
- pH 8.444
- pOH 14 8.444
- 5.556
9Calculate the pH of solutions having the
following ion concentrations at 298o K.
10Calculate the pH of solutions having the
following ion concentrations at 298o K.
- H 2.5 x 10-2
- log H 0.397 2
- pH 1.603
- pOH 14 1.603
- 12.397
11- Now lets try it the other way around
12Given the pH, calculate the H and OH- for
the following solution.
- pH 7.40
- -log H 7.40
- log H -7.40
- .60 8
- H 4.0 x 10-8
-
13Given the pH, calculate the H and OH- for
the following solution.
- pOH 14 7.40
- 6.60
- log OH- -6.60
- .40 7
- OH- 2.5 x 10-7
-
14One last thing
- If you have a solution of 1.0 M HCl, what is the
H? -
15One last thing
- HCl is a strong acid.
- That means it dissociates completely.
- If HCl 1.0, then H 1.0
-
16One last thing
- Same with strong bases.
- If NaOH 1.0, then OH- 1.0
-
17Homework