Title: ROTATIONAL KINETIC ENERGY
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2Session
Rotational Mechanics - 5
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4Session Objective
- Rolling of a body Description
- Rolling of a body - Mathematical expression
- Instantaneous center of rotation
5Rolling of a body
Rolling without slipping Motion is combined
rotation and translation.
Point of contact has no relative motion with
surface
6Rolling of a body
Friction (f) is responsible for rolling without
slipping
No work is done by f when body rolls without
slipping
7Relationship between linear angular velocity
The point in contact with surface is momentarily
at rest. Linear velocity is velocity of center
of mass (o).
8Relationship between linear angular velocity
9Dynamics of rolling
Rolling without slipping Linear motion of
center of mass circular motion about center of
mass.
Point P is at rest with respect to the surface at
this instant. It is the instantaneous center of
rotation .
10Kinetic Energy
When considered with respect to P
11Kinetic Energy with respect to instantaneous axis
of rotation
Velocity vQ of the point Q, with respect to the
instantaneous centre rotation
are valid about instantaneous point of rotation.
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13Class Exercise - 1
14Solution
Ring I mr2
For same mass and KE, sphere has maximum
linearvelocity.
Hence, answer is (c).
15Class Exercise - 2
16Solution
For a sphere,
Hence, answer is (a).
17Class Exercise - 3
18Solution
Speed at B v
19Solution contd..
Hence, answer is (d).
20Class Exercise - 4
21Solution
Loss in PE Gain in KE
22Solution contd..
Hence, answer is (b).
23Class Exercise - 5
24Solution
Loss in PE Gain in KE when M has dropped a
height h.
25Solution contd..
Hence, answer is (c).
26Class Exercise - 6
A ring and a cylinder of the same mass m and the
same radius R are released with the same velocity
at the same time on a flat horizontal surface
such that they start rolling immediately on
release towards a wall equidistant from both. The
rolling friction is finite. Which of the two will
reach the wall first?
27Solution
For rolling,
As m and v are same, KE is same for both. For the
ring I mr2
28Solution contd..
So the cylinder will reach first.
29Class Exercise - 7
30Solution
As friction is negligible, Loss in KE Gain in PE
The body is probably a hollowsphere.
31Solution contd..
Hint/Formula
32Class exercise - 8
33Solution
34Class Exercise - 9
A disc of radius R is spin about its axis so that
its angular velocity is w. Then it is slowly
placed on a rough horizontal surface of
coefficient of friction m. How long will the disc
takes to stop? (Plane of the disc is parallel to
surface all through the rotation.)
35Solution
Take a concentric ring of radius r andwidth dr
(as one of a series ofconcentric rings making up
the disc).
36Solution contd..
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