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MAGM 262

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MAGM 262 Hydraulic Fundamentals Mr. Conrado * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * Hydraulics- fluid power for the masses Matthew R. Bono ... – PowerPoint PPT presentation

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Title: MAGM 262


1
MAGM 262
Hydraulic Fundamentals
Mr. Conrado
2
Hydraulics- fluid power for the massesMatthew R.
Bono
3
Common Examples
  • Automobile Brakes

Hydraulic Fluid Pressurized by foot pedal and
booster closes piston, slows rotor and wheel
4
Common Examples
  • Heavy Machinery
  • Videos

5
Hydraulic Fundamentals
  • Hydraulic systems are everywhere from
  • Large excavation equipment
  • Steering in your car
  • Shocks
  • Power trains

6
Hydraulic Fundamentals
  • Using liquids to transfer force
  • They conform to their container
  • Practically incompressible
  • Apply pressure in all directions
  • Flow in any direction through lines and hoses.

7
Hydraulic Fundamentals
  • Liquids for all practical purposes are
    incompressible.
  • When a substance is compressed it takes up space.
    A liquid does not do this even under large
    pressures.
  • The space any substance occupies is called
    displacement.

8
Hydraulic Fundamentals
  • Gases are compressible
  • When a gas is compressed it takes up less space
    and its displacement is less. For this reason
    liquids are best used for hydraulic systems.

9
Hydraulic Fundamentals
  • Hydraulics doing work.
  • Pascals law Pressure exerted on a confined
    liquid is transmitted undiminished in all
    directions and acts as a equal force on all equal
    areas.
  • Thus a force exerted on any part of a confined
    liquid the liquid will transmit that force
    (pressure) in all directions within the system.
  • In this example a 500 pound force acting upon a
    piston with a 2 inch radius creates a pressure of
    40 psi on the fluid.
  • Ex For a 2 diameter piston
  • Area ?(3.14) x radius squared.
  • A 3.14 x (2x 2)
  • A 3.14 x 4
  • A 12.56
  • Pressure Force Area
  • P 500lbs 12.5 Sq. In.
  • P 40 psi
  • This same liquid with a pressure of 40 psi acting
    on a piston with a 3 inch diameter can support
    1130 pounds.

10
Hydraulic Fundamentals
  • This same liquid with a pressure of 40 psi acting
    on a piston with a 3 inch diameter can support
    1130 pounds.
  • Ex For a 3 diameter piston
  • Area ?(3.14) x radius squared.
  • A 3.14 x (3x 3)
  • A 3.14 x 9
  • A 28.26
  • Force Pressure x Area
  • F 40 psi x 28.26
  • F 1130.4

11
Hydraulic Fundamentals
  • Pascals Law
  • To understand how this works we must understand a
    very simple but fundamental formula.
  • To find one of the three areas two of the others
    must be known.
  • Force The push or pull acting on a body usually
    expressed in pounds.
  • Pressure The force of the fluid per unit area.
    Usually expressed in pounds per square inch or
    psi.
  • Area A measure of surface space. Usually
    calculated in square inches.
  • To calculate the area of a circle use the formula
    Area Pi (3.14) x radius squared.
  • Ex For a 2 diameter piston A3.14x(2x2) or
    A 12.5 sq. in.

12
Hydraulic Fundamentals
  • Pascals Law
  • With the knowledge of the surface area it is
    possible to determine how much system pressure
    will be required to lift a given weight.
  • The pressure needed for a 500 pound given weight
    is calculated with the formula
  • Pressure Force Area
  • P 500lbs 12.5 Sq. In.
  • P 40 psi

13
Hydraulic Fundamentals
  • Mechanical Advantage
  • Here we see and example of how a hydraulic system
    can create a mechanical advantage.
  • We can calculate the items in question by using
    the systems known items and Pascals law.
  • For system pressure we use PFA
  • P 50lps 1sq.in (cylinder 2)
  • P 50psi
  • Now we know the system pressure we can calculate
    the load force for cylinders 1 3 and the piston
    area for 4. Do so on a separate piece of paper
    and wait for instructions.

14
Hydraulic Fundamentals
50psi
  • Cylinder One
  • Solve for Force
  • FP x A
  • F 50psi x 5 in²
  • Cancel out square inches to leave pounds and
    multiply
  • F 250lbs.

15
Hydraulic Fundamentals
  • Cylinder One
  • Solve for Force
  • FP x A
  • F 50psi x 5 in²
  • F 50 pounds/sq inch x 5 sq inches
  • Cancel out square inches to leave pounds and
    multiply
  • F 50 lbs x 5
  • F 250lbs.

250 pounds
16
Hydraulic Fundamentals
  • Cylinder Three
  • Solve for Force
  • FP x A
  • F 50psi x 3in²
  • Cancel out square inches to leave pounds and
    multiply
  • F 150 pounds

150 pounds
50psi
17
Hydraulic Fundamentals
  • Cylinder four
  • Solve for Area
  • A F P
  • A 100 pounds 50 psi
  • A 100 pounds 50 pounds/ square inch
  • Cancel pounds to get in² and divide
  • A 100 50 square inches
  • A 2.00 in²

2.0 in²
18
Hydraulic Fundamentals
150 lbs
150 lbs
2 in²
Cylinder One FP x A F 50psi x 5 in² F 50
lbs/sq inch x 5 sq inches F 50 lbs x 5 F
250lbs.
Cylinder Three FP x A F 50psi x 3in² F 150
pounds
Cylinder Two PFA P 50 lbs 1in² P 50psi
Cylinder Four A F P A 100 pounds 50
psi A 100 pounds 50 pounds/ square inch A
100 50 square inches A 2.00 in²
19
Parts of a Closed System
  • Reservoir
  • Filter
  • Pump
  • Valve
  • Cylinder
  • Lines

20
How It Works
  • Motor Spins Pump
  • Pump Moves fluid
  • a. Out of reservoir
  • Through filter
  • Through Pump
  • c. Into valve
  • Valve directs fluid to ram
  • Pressurized side of ram moves
  • Fluid on other side of ram returns to reservoir

21
What can change
  • How to Power the System
  • Elbow Grease- like a automotive jack
  • Electric Motor
  • Fueled Motors
  • gasoline, diesel, aviation anything else
  • System Design
  • Flow Rates
  • Pressures
  • Location
  • Point of Action

22
How it worksHorsepower, Flow Rate and Pressure
  • As motor power goes up the pump has more power to
    move fluid
  • This can increase flow rate or pressure

23
How it works
  • Flow Rate
  • Hydraulic systems rely on filling a given area
    with fluid
  • The more fluid you pump into the area the faster
    the implement moves
  • If your trying to float a rubber boat in a
    swimming pool what will do it faster a garden
    hose or a fire hose

24
How it works
  • Pressure
  • Hydraulic systems like the jaws of life can
    create incredible amounts of force
  • What shoots further, water from a hose spraying
    a cone or spraying a jet

25
Advantages
  • Force Multiplier
  • Automobile Brakes
  • Controllable-
  • variable speed and power
  • High power low weight-
  • Especially air powered
  • Very Mobile-
  • Harvesting Equipment
  • Possibilities-
  • Diesel Hydraulic Hybrid Delivery Trucks
  • Roller Coasters

26
Force Multiplier Automobile Brakes
  • The force of your foot can stop an entire car,
    with help from hydraulics

27
Controllable-
  • Large harvesting equipment can do dozens of
    things at one time all with hydraulic power

28
Controllable- Cotton Picker Header
Each row of cotton goes through the picking
zone Each spindle moves independently of the
others while machine moves through field, blows
lint into hopper and discards waste
29
Very Mobile
  • The jaws of life in the last slide are used by
    hundreds of rescue outfits across the US and are
    readily carried everywhere they go

30
Why does it Matter
  • Hydraulic systems are in everything from aircraft
    to theater performances in Las Vegas. Someone had
    to design, build and maintain all these systems,
    why couldnt it be you?

31
Homework
  • Micrometer worsheet

32
Lab
  • Bottle Jack Lab
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