Title: Chapter 15 Acid-Base Equilibria
1Chapter 15Acid-Base Equilibria
CHEMISTRY
2Acids and Bases
- Arrhenius Definition
- Acids - are substances that produce hydrogen ions
(protons or H) in solution. - Bases - are substances that produce hydroxide
ions in solution. - Strong Acids and Strong Bases totally ionize
in solution - Weak Acids and Weak Bases partially ionize in
solution
3Acid Dissociation in Water
- General Rxn. when Acid dissolves in H2O
- HCl H2O H3O Cl-
acid base conj. Acid conj. base
4Properties of H2O _at_ 25 oC
- H2O (l) D H (aq) OH- (aq)
- Neutral, can act as an acid and a base
- Kw HOH- 1.0 x 10-14 only _at_ 25 oC
- Kw water dissociation constant
5Acidity vs. Basicity
- If H gtOH- , solution is acidic
- If H ltOH- , solution is basic
- The term pX -log concentration of X
- So pH -log concentration of H
- pOH -log concentration of
OH- - pH power of hydrogen the power of H to which
10 is raised
6pH
- Kw HOH- 1.0 x 10-14 _at_ 25 oC
- pKw -log H -log OH- - log 1.0 x 10-14
14 - pH -log H
- pOH -log OH-
7Properties of H2O _at_ 25 oC
- pKw - log 1.0 x 10-14 14
- pH pOH 14
- pH 7 pOH 7
- pH pOH
8Things to Remember
- pKw - log 1.0 x 10-14 14 _at_ 25 oC
- pH pOH 14
- pH lt7 acidic
- pH gt 7 basic
- pH is between 0 - 14
9Broensted-Lowrys Definition
-
- Acid is a proton (H) donor.
- Base is a proton (H) acceptor.
- Broensted-Lowry Definition is more general
- It even applies to bases that have no OH such as
NH3.
10Terminologies
- H proton
- OH- hydroxide ion
- H3O hydronium ion
- Conjugate base acid minus proton
- Conjugate acid base plus proton
11More Terminologies
- Conjugate acid-base pair
- Consists of 2 substances related to each other by
the donation and acceptance of a single proton
(H). - Acid Dissociation Constant (Ka)
12Acid Equilibrium
- Equilibrium Expression for the reaction
- HCl H2O H3O Cl-
acid base conj. Acid conj. Base - Ka H3O Cl- HCl-
HClH2O HCl
13Equations
- pH - log H
- pOH - log OH-
- H 10 pH
- OH- 10 - pOH
- Kw 10 - pKw
- pKw pH pOH
- pKw - log Kw
- Pw HOH-
14Sample Problem
- At 40 oC, a solution has Kw 2.916 x 10-14 pH
7.51 - Calculate the following
- A. pOH of the solution
- B. hydrogen ion concentration H
- C. hydroxide ion concentration OH-
- D. pKw
- E. Is the solution acidic basic or neutral?
15Equilibrium
- K H3O Cl- HCl-
HClH2O HCl - H2O removed from top and bottom since H3O is
simply H dissolved in water. - Remember Keq products
reactants
16Terminologies
- H proton
- OH- hydroxide ion
- H3O hydronium ion
- Conjugate base acid minus proton
- Conjugate acid base plus proton
17Problems on Acid Dissociation
- Write the simple dissociation reaction for each
of the following acids. Omit water. - A.) HNO3
- B.) CH3COOH (acetic acid)
- C.) NH4
- D.) Al(H2O)33
18Acid Strength
- Strength of acid is given by the equilibrium
position of the dissociation reaction - HA (aq) H2O (l) H3O A-
- Strong acid totally ionized and equilibrium
lies far to the right - Weak acid only partially ionized and
equilibrium lies far to the left
19Strong Acid vs. Weak Acid
- Strong Acid yields a weak conjugate base (one
that has weak affinity for proton weaker than
H2O) - Weak Acid yields a strong conjugate base (one
that has strong affinity for proton stronger
than H2O)
20Comparison
Property Strong Acid Weak Acid
Ka value Large Ka Small Ka
Equil. Position Far to the right Far to the Left
Equil. Concn H HA0 H ltlt HA0
Conj. Base Strength vs H2O A- much weaker base than H2O A- much stronger base than H2O
21Please Note!
- Tuesdays experiment is Experiment 29 Choice I.
22Sample Problems
- Given OH- 1.0 x 10-12 M, calculate pH. Is
the solution basic, acidic or neutral? - Given H 4.30 x 10-6 M, calculate pH. Is the
solution basic, acidic or neutral?
23Strong Acids and Bases
- If the molarity of the acid or base is less than
10-6 M then the autoionization of water needs to
be taken into account. In other words, water is
the primary source of H and OH-, so the pH would
be neutral.
24Acids and Bases A Brief Review
- Acids taste sour and cause dyes to change color.
- Bases taste bitter and feel soapy.
- Arrhenius acids increase H bases increase
OH- in solution. - Arrhenius acid base ? salt water.
- Problem the definition confines us to aqueous
solution.
25Brønsted-Lowry Acids and Bases
- Conjugate Acid-Base Pairs
- Whatever is left of the acid after the proton is
donated is called its conjugate base. - Similarly, whatever remains of the base after it
accepts a proton is called a conjugate acid. - Consider
- After HA (acid) loses its proton it is converted
into A- (base). Therefore HA and A- are
conjugate acid-base pairs. - After H2O (base) gains a proton it is converted
into H3O (acid). Therefore, H2O and H3O are
conjugate acid-base pairs. - Conjugate acid-base pairs differ by only one
proton.
26Brønsted-Lowry Acids and Bases
- Relative Strengths of Acids and Bases
- The stronger the acid, the weaker the conjugate
base. - H is the strongest acid that can exist in
equilibrium in aqueous solution. - OH- is the strongest base that can exist in
equilibrium in aqueous solution.
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28Brønsted-Lowry Acids and Bases
- Relative Strengths of Acids and Bases
- The conjugate base of a strong acid (e.g. Cl-)
has negligible acid-base properties. - Similarly, the conjugate acid of a strong base
has negligible acid-base properties.
29The Autoionization of Water
- The Ion Product of Water
- In pure water the following equilibrium is
established - at 25 ?C
- The above is called the autoionization of water.
30The pH Scale
- In most solutions H(aq) is quite small.
- We define
- In neutral water at 25 ?C, pH pOH 7.00.
- In acidic solutions, H gt 1.0 ? 10-7, so pH lt
7.00. - In basic solutions, H lt 1.0 ? 10-7, so pH gt
7.00. - The higher the pH, the lower the pOH, the more
basic the solution.
31The pH Scale
- Most pH and pOH values fall between 0 and 14.
- There are no theoretical limits on the values of
pH or pOH. (e.g. pH of 2.0 M HCl is -0.301.)
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33The pH Scale
- Other p Scales
- In general for a number X,
- For example, pKw -log Kw.
-
34The pH Scale
- Measuring pH
- Most accurate method to measure pH is to use a pH
meter. - However, certain dyes change color as pH changes.
These are indicators. - Indicators are less precise than pH meters.
- Many indicators do not have a sharp color change
as a function of pH. - Most indicators tend to be red in more acidic
solutions.
35The pH Scale
36Strong Acids and Bases
- Strong Acids
- The strongest common acids are HCl, HBr, HI,
HNO3, HClO3, HClO4, and H2SO4. - are strong electrolytes.
- All strong acids ionize completely in solution
37Strong Acids and Bases
- Strong Acids
- The strongest common acids are HCl, HBr, HI,
HNO3, HClO3, HClO4, and H2SO4. - Strong acids are strong electrolytes.
- All strong acids ionize completely in solution
- HNO3(aq) H2O(l) ? H3O(aq) NO3-(aq)
- Since H and H3O are used interchangeably, we
write - HNO3(aq) ? H(aq) NO3-(aq)
38Strong Acids and Bases
- Strong Acids
- In solutions the strong acid is usually the only
source of H. (If the molarity of the acid is
less than 10-6 M then the autoionization of water
needs to be taken into account.) - Therefore, the pH of the solution is the initial
molarity of the acid. - Strong Bases
- Most ionic hydroxides are strong bases (e.g.
NaOH, KOH, and Ca(OH)2).
39Strong Acids and Bases
- If the molarity of the acid or base is less than
10-6 M then the autoionization of water needs to
be taken into account. In other words, water is
the primary source of H and OH-, so the pH would
be neutral.
40Strong Acids and Bases
- Strong Bases
- Strong bases are strong electrolytes and
dissociate completely in solution. - The pOH (and hence pH) of a strong base is given
by the initial molarity of the base. Be careful
of stoichiometry. - In order for a hydroxide to be a base, it must be
soluble. - Bases do not have to contain the OH- ion
- O2-(aq) H2O(l) ? 2OH-(aq)
- H-(aq) H2O(l) ? H2(g) OH-(aq)
- N3-(aq) H2O(l) ? NH3(aq) 3OH-(aq)
41pH of Strong Acids and Bases
- The pH (and hence pOH) of a strong acid is given
by the initial molarity of the acid. - The pOH (and hence pH) of a strong base is given
by the initial molarity of the base. - Be careful of stoichiometric ratios!
42Please Note!
- Tuesdays experiment is Experiment 29 Choice I.
43Bronsted-Lowry Acids and Bases
- Bronsted-Lowry acids compounds that donate a
proton (H) - Bronsted-Lowry Bases compounds that accept a
proton (H) - Note that Bronsted-Lowry bases need not have the
OH group on the formula
44Weak Acids
- Weak acids are only partially ionized in
solution. - There is a mixture of ions and unionized acid in
solution. - Therefore, weak acids are in equilibrium
45Weak Acids
- Ka is the acid dissociation constant.
- Note H2O is omitted from the Ka expression.
(H2O is a pure liquid.) - The larger the Ka the stronger the acid (i.e. the
more ions are present at equilibrium relative to
unionized molecules). - If Ka gtgt 1, then the acid is completely ionized
and the acid is a strong acid.
46NOTE
- For Weak Acids and Weak Bases
- USE ICE to determine H, OH-, pH and pOH.!
47Sample A Problem
- A solution of 0.10 M formic acid (HCOOH) has a pH
of 2.38 at 25 oC. - A. Calculate Ka for formic acid at this
temperature. - B. What percent of this solution is ionized?
48Important Reminder
- Please Take Note
- Kw 1.0 x 10-14 is only true at 25 oC
- Therefore, pH pOH 14 is also true
ONLY at 25 oC - If the temperature is not 25 oC, then Kw will be
equal to something else and pKw will not be equal
to 14.
49Sample Problem
- At the freezing point of water which is 0 oC,
Kw 1.2 x 10-15. - Calculate H and OH- for a neutral solution
at this temperature.
50Sample Problem
- The Ka of acetic acid is 1.8 x 10-5.
- A. Calculate the pH of a 0.30 M solution of
CH3COOH. - B. Calculate OH- and pOH.
- C. Calculate Kb.
- Calculate ionization.
51A Simple Trick
- Use of approximation eliminates the difficulty
of quadratic equations. - Approximation is Valid if
- X_______ x 100 lt 5
- Initial Concn.
52Relationship between Ka and Kb
- Ka x Kb 1.0 x 10 -14 only at 25 oC.
53pH of polyprotic acids
- Treat polyprotic acids as separate steps!
- 1. H2A (aq) D H (aq) HA- (aq) Ka1
- 2. HA- (aq) D H (aq) A-2 (aq) Ka2
- Initial H in Step 2 is Equil. H from Step
1. - Total H SUM from Steps 1 2
54HOMEWORK
- What is the pH of a 1.00 M solution of tartaric
acid, H2C4H4O6 (aq.) at 25.0 oC? - Answer pH 1.49
55Sample Problem
- The Ka of acetic acid is 1.8 x 10-5. Calculate
the Kb of of CH3COOH.
56Sample Problem
- The Ka of ammonia is 1.8 x 10-5. Calculate the
pH of a 0.15 M solution of NH3.
57Sample Problem
- Calculate the concentration of an aqueous
solution of NaOH that has a pH of 11.50.
58HOMEWORK
- What is the pH of a 1.00 M solution of tartaric
acid, H2C4H4O6 (aq.) at 25.0 oC? - Answer pH 1.49
59Weak Acids
- Calculating Ka from pH
- Weak acids are simply equilibrium calculations.
- The pH gives the equilibrium concentration of H.
- Using Ka, the concentration of H (and hence the
pH) can be calculated. - Write the balanced chemical equation clearly
showing the equilibrium. - Write the equilibrium expression. Find the value
for Ka. - Write down the initial and equilibrium
concentrations for everything except pure water.
We usually assume that the change in
concentration of H is x.
60Weak Acids
- Calculating Ka from pH
- Substitute into the equilibrium constant
expression and solve. Remember to turn x into pH
if necessary. - Using Ka to Calculate pH
- Percent ionization is another method to assess
acid strength. - For the reaction
61Weak Acids
- Using Ka to Calculate pH
- Percent ionization relates the equilibrium H
concentration, Heqm, to the initial HA
concentration, HA0. - The higher percent ionization, the stronger the
acid. - Percent ionization of a weak acid decreases as
the molarity of the solution increases. - For acetic acid, 0.05 M solution is 2.0 ionized
whereas a 0.15 M solution is 1.0 ionized.
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63Weak Acids
- Polyprotic Acids
- Polyprotic acids have more than one ionizable
proton. - The protons are removed in steps not all at once
- It is always easier to remove the first proton in
a polyprotic acid than the second. - Therefore, Ka1 gt Ka2 gt Ka3 etc.
64Weak Acids
Polyprotic Acids
65Weak Bases
- Weak bases remove protons from substances.
- There is an equilibrium between the base and the
resulting ions - Example
- The base dissociation constant, Kb, is defined as
66Weak Bases
- Types of Weak Bases
- Bases generally have lone pairs or negative
charges in order to attack protons. - Most neutral weak bases contain nitrogen.
- Amines are related to ammonia and have one or
more N-H bonds replaced with N-C bonds (e.g.,
CH3NH2 is methylamine). - Anions of weak acids are also weak bases.
Example OCl- is the conjugate base of HOCl (weak
acid)
67Relationship Between Ka and Kb
- We need to quantify the relationship between
strength of acid and conjugate base. - When two reactions are added to give a third, the
equilibrium constant for the third reaction is
the product of the equilibrium constants for the
first two - Reaction 1 reaction 2 reaction 3
- has
68Relationship Between Ka and Kb
- For a conjugate acid-base pair
- Therefore, the larger the Ka, the smaller the Kb.
That is, the stronger the acid, the weaker the
conjugate base. - Taking negative logarithms
69Acid-Base Properties of Salt Solutions
- Nearly all salts are strong electrolytes.
- Therefore, salts exist entirely of ions in
solution. - Acid-base properties of salts are a consequence
of the reaction of their ions in solution. - The reaction in which ions produce H or OH- in
water is called hydrolysis. - Anions from weak acids are basic.
- Anions from strong acids are neutral.
70Acid-Base Properties of Salt Solutions
- An Anions Ability to React with Water
- Anions, X-, can be considered conjugate bases
from acids, HX. - If X- comes from a strong acid, then it is
neutral. - If X- comes from a weak acid, then
- The pH of the solution can be calculated using
equilibrium!
71Acid-Base Properties of Salt Solutions
- An Cations Ability to React with Water
- Polyatomic cations with ionizable protons can be
considered conjugate acids of weak bases. - Some metal ions react in solution to lower pH.
- Combined Effect of Cation and Anion in Solution
- An anion from a strong acid has no acid-base
properties. - An anion that is the conjugate base of a weak
acid will cause an increase in pH.
72Sample Problem
- A solution of NH3 in water has a pH of 10.50.
What is the initial molarity of the solution?
73Other Weak Bases
- Amines ex. Methylamine (CH3NH2)
- carbonate ion (CO32-)
- hypochlorite ion (ClO-1)
74Weak Bases
- Also use ICE!
- Calculation is the same as for weak acids!
- Main difference is that you get OH- and pOH
first.
75Effects of Salts on pH
- Conjugate bases of strong acids have no effect on
pH. - Conjugate acids of strong bases have no effect on
pH. - Conjugate bases of weak acids increase pH (more
basic). - Ex. F- (aq) H2O(l) D HF (aq)
OH- (aq) - Conjugate acids of weak bases decrease pH (more
acidic). - NH4(aq) H2O (l) D NH3 (aq)
H3O (aq)
76Relationship Between Ka and Kb
77Acid-Base Properties of Salt Solutions
- Combined Effect of Cation and Anion in Solution
- A cation that is the conjugate acid of a weak
base will cause a decrease in the pH of the
solution. - Metal ions will cause a decrease in pH except for
the alkali metals (Grp. I) and alkaline earth
metals.(Grp.II) - When a solution contains both cations and anions
from weak acids and bases, use Ka and Kb to
determine the final pH of the solution.
78Sample Problem
- Determine whether the resulting solution in water
will be acidic, basic or neutral. - A. KClO3-
- B. NaCH3COO-
- C. Na2HPO4 Ka for HPO4- 4.2 x 10-13
- D. NH4Cl-
79Sample Problem
- Predict whether the potassium salt of citric acid
(K2HC6H5O7-) will form an acidic, basic or
neutral solution in water.
80Weak Acids
- Polyprotic Acids
- Polyprotic acids have more than one ionizable
proton. - The protons are removed in steps not all at once
- It is always easier to remove the first proton in
a polyprotic acid than the second. - Therefore, Ka1 gt Ka2 gt Ka3 etc.
81Weak Acids
Polyprotic Acids
82Sample Problem
- The solubility of CO2 in pure water at 25 oC and
0.1 atm is 0.0037 M. The common practice is to
assume that all of the dissolved CO2 is in the
form of carbonic acid (H2CO3), which is produced
by the reaction between the CO2 and H2O. - What is the pH of a 0.0037 M solution of H2CO3?
- Ka1 4.3 x 10-7
- Ka2 5.6 x 10 -11
83Answer
- pH 4.4
- x1 4.0 x 10-5 M
- CO3- 5.6 x 10-11 M
84Sample Problem
- Calculate the pH and concentration of oxalate ion
(C2O42-), in a 0.020 M solution of oxalic acid
(H2C2O4)
85Answer
- pH 1.8
- oxalate 6.4 x 10-5 M
86Acid-Base Behavior and Chemical Structure
- Factors that Affect Acid Strength
- Consider H-X. For this substance to be an acid
we need - H-X bond to be polar with H? and X?- (if X is a
metal then the bond polarity is H?-, X? and the
substance is a base), - the H-X bond must be weak enough to be broken,
- the conjugate base, X-, must be stable.
87Acid-Base Behavior and Chemical Structure
- Binary Acids
- Acid strength increases across a period and down
a group. - Conversely, base strength decreases across a
period and down a group. - HF is a weak acid because the bond energy is
high. - The electronegativity difference between C and H
is so small that the C-H bond is non-polar and
CH4 is neither an acid nor a base.
88Acid-Base Behavior and Chemical Structure
89Acid-Base Behavior and Chemical Structure
- Oxyacids
- Oxyacids contain O-H bonds.
- All oxyacids have the general structure Y-O-H.
- The strength of the acid depends on Y and the
atoms attached to Y. - If Y is a metal (low electronegativity), then the
substances are bases. - If Y has intermediate electronegativity (e.g. I,
EN 2.5), the electrons are between Y and O and
the substance is a weak oxyacid.
90Acid-Base Behavior and Chemical Structure
- Oxyacids
- If Y has a large electronegativity (e.g. Cl, EN
3.0), the electrons are located closer to Y than
O and the O-H bond is polarized to lose H. - The number of O atoms attached to Y increase the
O-H bond polarity and the strength of the acid
increases (e.g. HOCl is a weaker acid than HClO2
which is weaker than HClO3 which is weaker than
HClO4 which is a strong acid).
91Acid-Base Behavior and Chemical Structure
Oxyacids
92Acid-Base Behavior and Chemical Structure
- Carboxylic Acids
- Carboxylic acids all contain the COOH group.
- All carboxylic acids are weak acids.
- When the carboxylic acid loses a proton, it
generate the carboxylate anion, COO-.
93Lewis Acids and Bases
- Brønsted-Lowry acid is a proton donor.
- Focusing on electrons a Brønsted-Lowry acid can
be considered as an electron pair acceptor. - Lewis acid electron pair acceptor.
- Lewis base electron pair donor.
- Note Lewis acids and bases do not need to
contain protons. - Therefore, the Lewis definition is the most
general definition of acids and bases.
94Lewis Acids and Bases
- Lewis acids generally have an incomplete octet
(e.g. BF3). - Transition metal ions are generally Lewis acids.
- Lewis acids must have a vacant orbital (into
which the electron pairs can be donated). - Compounds with p-bonds can act as Lewis acids
- H2O(l) CO2(g) ? H2CO3(aq)
95Lewis Acids and Bases
- Hydrolysis of Metal Ions
- Metal ions are positively charged and attract
water molecules (via the lone pairs on O). - The higher the charge, the smaller the metal ion
and the stronger the M-OH2 interaction. - Hydrated metal ions act as acids
- The pH increases as the size of the ion increases
(e.g. Ca2 vs. Zn2) and as the charge increases
(Na vs. Ca2 and Zn2 vs. Al3).
96Lewis Acids and Bases
Hydrolysis of Metal Ions
97End of Chapter 16Acid-Base Equilibria
98Problem 1
- Give the conjugate base of the following
Bronsted-Lowry acids - H2SO3
- H2AsO4-
- NH4
99Problem 2
- By what factor does H change for a pH change
of - A. 2.00 units
- B. 0.50 units
100Problem 3
- Calculate OH- and pH for
- A.) 1.5 x 10-3 M Sr(OH)2. Sr(OH)2 is a strong
base. - B.) a solution formed by adding 10 mL of 0.100 M
HBr to 20.0 mL of 0.200 M HCl
101Problem
-
- Calculate the pH of a solution made by adding
15.00 grams of NaH in enough water to make 2.5 L
of solution
102Problem
- Write the ionization and equilibrium expressions
for HBrO2.
103Problem
- A particular sample of vinegar has a pH of 2.9.
Assuming acetic acid is the only acid in the
vinegar, find the initial concentration of acetic
acid in the vinegar.
104Problem
- The acid dissociation constant for benzoic acid
(HC7H5O2) is 6.3 x 10-5. Calculate the
equilibrium concentrations of H3O, C7H5O2- and
HC7H5O2 if the initial concentration of HC7H5O2
is 0.050 M.
105Problem
- Calculate the pH of 0.120 M pyridine (C5H5N).
Kb for pyridine is 1.7 x 10-9.
106Problem
- A 0.200 M solution of a weak acid, HA is 9.4
ionized. Using this information, calculate H,
A-, HA and Ka for HA.
107Problem
- An unknown salt is either NaF, NaCl, or NaOCl.
When 0.05 mole of the salt is dissolved in water
to form 0.500 L of solution, the pH of the
solution is 8.08. What is the identity of the
salt?
108Problem
- Write the chemical equation and the Kb expression
for the ionization of the following bases in
aqueous solution - A. Dimethylamine (CH3)2NH
- B. Formate ion (HCOO-)
- C. Carbonate ion (CO32-)
109Problem
- Calculate the molar concentration of OH- ions in
a 0.075M solution of ethylamine. - Kb of C2H5NH2 6.4 x 10-4.
- Calculate the pH of this solution.
110Problem
- Ka for acetic acid (CH3COOH) is 1.8 x 10-5 while
Ka for hypochlorous (HClO) ion is 3.0 x 10-8. - A. Which is the stronger acid?
- B. Which is the stronger conjugate base?
Acetate ion (CH3COO-) or chlorous (ClO-) ion? - C. Calculate kb values for CH3COO- and ClO-.
111Solubility vs. Ksp
- Solubility refers to the quantity that
dissolves to form a saturated solution. Unit is
gm/liter or moles/liter for molar solubility. - - solubility if affected by temperature
- Solubility product constant is the equilibrium
constant for the equilibrium that exists between
the ionic solute and its saturated aqueous
solution
112Ksp
- Solubility product constant the equilibrium
constant indicating how soluble the product is in
water. - Example CaF2 (s) D Ca2 (aq) 2F- (aq)
- Ksp Ca2F-2
113Problem 1
- Give the ionization equation and Ksp expression
for the reaction - Ag2CrO4 (s) D ? ?
114Problem 2
- The Ksp for CaF2 is 3.9 x 10-11 at 25 oC.
Assuming that CaF2 dissociates completely upon
dissolving and that there are no other important
equilibria affecting its solubility - a.
calculate the solubility of CaF2 in moles per
liter. - b. calculate the solubility of CaF2 in grams per
liter.
115Problem 3
- The Ksp for LaF3 is 2.0 x in 10-19. What is the
solubility of LaF3 in water in moles per liter? - What is the solubility of LaF3 in water in grams
per liter?
116Answer
117Factors Affecting Solubility
- Common-Ion Effect
- Concentration
118Problem 4
- Calculate the molar solubility of CaF2 at 25 oC
in a solution that is - A. 0.010 M in Ca(NO3)2
- B. 0.025 M in NaF
119Precipitation of Ions
- Remember Q, the reaction quotient?
- If Q gt Ksp, prepitations occurs until Q
Ksp Q Ksp, equilibrium exists (saturated
solution) Q lt Ksp, solid dissolves until Q Ksp.
120Problem 1
- A solution contains 1.0 x 10-12 M Ag and 2.0 x
10-2 M Pb2. When Cl- is added, both AgCl and
Ksp precipitate from the solution. - What concentration of Cl- is necessary to begin
the precipitation of each salt? - Which salt precipitates first?
121Insoluble Chlorides
- Of the common metals ions, only Ag, Hg2 2, Pb
2 form insoluble chlorides.
122Qualitative Analysis
- Order of separation of ions Cl-
? S2- ? (OH)- ? (PO4) 3- ? NH4 - 1st step add 6M HCl
- 2nd step add H2S and 0.20 M HCl
- 3rd step add (NH4)2S
- 4th step add (NH4)2HPO4 and NH3