Title: Circuit Analysis Techniques
1LECTURE 2
2Circuit Analysis Techniques
3Circuit Analysis Techniques
- Voltage Division Principle
- Current Division Principle
- Nodal Analysis with KCL
- Mesh Analysis with KVL
- Superposition
- Thévenin Equivalence
- Nortons Equivalence
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8Circuit Analysis using Series/Parallel Equivalents
- Begin by locating a combination of resistances
that are in series or parallel. Often the place
to start is farthest from the source. - Redraw the circuit with the equivalent resistance
for the combination found in step 1. - Repeat steps 1 and 2 until the circuit is reduced
as far as possible. Often (but not always) we
end up with a single source and a single
resistance. - Solve for the currents and voltages in the final
equivalent circuit.
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10Working Backward
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12Voltage Division
13Application of the Voltage-Division Principle
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15Current Division
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17Application of the Current-Division Principle
18- Voltage division and
- current division
19 20Although they are veryimportant
concepts,series/parallel equivalents andthe
current/voltage divisionprinciples are not
sufficient to solve all circuits.
21Node Voltage (Nodal) Analysis
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25Writing KCL Equations in Terms of the Node
Voltages for Figure 2.16
node 1
node 2
node 3
26node 1
node 2
node 3
27No. of unknown v1, v2, v3 No. of linear
equation 3 Setting up nodal equation with KCL
at Node 1, Node 2, Node 3
28No. of unknown v1, v2, v3 No. of linear
equation 3 Setting up nodal equation with KCL
at Node 1, Node 2, Node 3
29Problem with node 3, it is rather hard to set the
nodal equation at node 3, but still solvable.
Why? As there is no way to determinethe current
through the voltage source, but v3Vs
v3
Problem with node 3, it is rather hard to set the
nodal equation at node 3 but still solvable.
Same as before.
30May Not Be That Simple
31Circuits with Voltage Sources
- We obtain dependent equations if we use all of
the nodes in a network to write KCL equations. - Any branch with a voltage source
- define SUPERNODE, sum all current either in or
out at the supernode with KCL - use KVL to set up dependent equation involving
the voltage source.
32At node 1
At the supernode
33A
B
Summing all the current out from the supernode A
Why? As the current via the 10V source is equal
to the current via R4 plus the current via R3
34B
Summing all the current into the supernode B
35-v1 -10 v2 0
36- Any branch with a voltage source
- define supernode, sum all current either in or
out at the - supernode with KCL
- use KVL to set up dependent equation involving
the - voltage source.
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39Node-Voltage Analysis with a Dependent Source
- First, we write KCL equations at each node,
including the current of the controlled source
just as if it were an ordinary current source. - Next, we find an expression for the controlling
variable ix in terms of the node voltages.
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42Substitution yields
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44Node-Voltage Analysis
1. Select a reference node and assign variables
for the unknown node voltages. If the reference
node is chosen at one end of an independent
voltage source, one node voltage is known at the
start, and fewer need to be computed.
2. Write network equations. First, use KCL to
write current equations for nodes and supernodes.
Write as many current equations as you can
without using all of the nodes. Then if you do
not have enough equations because of voltage
sources connected between nodes, use KVL to write
additional equations.
3. If the circuit contains dependent sources,
find expressions for the controlling variables in
terms of the node voltages. Substitute into the
network equations, and obtain equations having
only the node voltages as unknowns.
4. Put the equations into standard form and solve
for the node voltages. 5. Use the values found
for the node voltages to calculate any other
currents or voltages of interest.
45Step 1.Reference node
Step 1. v1
Step 2.
Step 1 v2
46Step 1
Step 1
v2
v1
Step 2
v3
node 1
supernode
Step 1
ref
supernode
Step 3
47Mesh Current Analysis
48Definition of a loop
Definition of a mesh
49Choosing the Mesh Currents
When several mesh currents flow through one
element, we consider the current in that element
to be the algebraic sum of the mesh currents.
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51Writing Equations to Solve for Mesh Currents
If a network contains only resistors and
independent voltage sources, we can write the
required equations by following each current
around its mesh and applying KVL.
52For mesh 1, we have
For mesh 2, we obtain
For mesh 3, we have
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54Mesh Currents in Circuits Containing Current
Sources
A common mistake is to assume the voltages
across current sources are zero. Therefore, loop
equation cannot be set up at mesh one due to the
voltage across the current source is unknown
Anyway, the problem is still solvable.
55As the current source common to two mesh,
combine meshes 1 and 2 into a supermesh. In other
words, we write a KVL equation around the
periphery of meshes 1 and 2 combined.
It is the supermesh.
Mesh 3
Three linear equations and three unknown
56Creating a supermesh from meshes 1 and 3
-7 1 ( i1 - i2 ) 3 ( i3 - i2 ) 1 i3
0 1
Around mesh 2 1 ( i2 - i1 ) 2 i2 3
( i2 - i3 ) 0 2
Finally, we relate the currents in meshes 1 and
3 i1 - i3 7 3
Rearranging, i1 - 4 i2 4 i3
7 1 -i1 6 i2 - 3 i3 0 2 i1
- i3 7 3
Solving, i1 9 A, i2 2.5 A, and i3 2
A.
57supermesh of mesh1 and mesh2
branch current
current source
58Three equations and three unknown.
59Mesh-Current Analysis
1. If necessary, redraw the network without
crossing conductors or elements. Then define the
mesh currents flowing around each of the open
areas defined by the network. For consistency, we
usually select a clockwise direction for each of
the mesh currents, but this is not a requirement.
2. Write network equations, stopping after the
number of equations is equal to the number of
mesh currents. First, use KVL to write voltage
equations for meshes that do not contain current
sources. Next, if any current sources are
present, write expressions for their currents in
terms of the mesh currents. Finally, if a current
source is common to two meshes, write a KVL
equation for the supermesh.
3. If the circuit contains dependent sources,
find expressions for the controlling variables in
terms of the mesh currents. Substitute into the
network equations, and obtain equations having
only the mesh currents as unknowns.
4. Put the equations into standard form. Solve
for the mesh currents by use of determinants or
other means. 5. Use the values found for the mesh
currents to calculate any other currents or
voltages of interest.
60Superposition
- Superposition Theorem the response of a circuit
to more than one source can be determined by
analyzing the circuits response to each source
(alone) and then combining the results
Insert Figure 7.2
61Superposition
Insert Figure 7.3
62Superposition
- Analyze Separately, then Combine Results
63Use superposition to find the current ix.
Current source is zero open circuit as I 0
and solve iXv Voltage source is zero short
circuit as V 0 and solve iXv
64Use superposition to find the current ix.
The controlled voltage source is included in all
cases as it is controlled by the current ix.
65Voltage and Current Sources
Insert Figure 7.7
66Voltage and Current Sources
Insert Figure 7.8
67Voltage and Current Sources
Insert Figure 7.9
68Source Transformation
Under what condition, the voltage and current of
the load is the same whenoperating at the two
practical sources?For voltage source
For current source
,
We have,
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70Voltage and Current Sources
- Equivalent Voltage and Current Sources for
every voltage source, there exists an equivalent
current source, and vice versa
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72Thevenins Theorem
- Thevenins Theorem any resistive circuit or
network, no matter how complex, can be
represented as a voltage source in series with a
source resistance
73Thevenins Theorem
- Thevenin Voltage (VTH) the voltage present at
the output terminals of the circuit when the load
is removed
Insert Figure 7.18
74Thevenins Theorem
- Thevenin Resistance (RTH) the resistance
measured across the output terminals with the
load removed
75Thévenin Equivalent Circuits
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78Thévenin Equivalent Circuits
79Thévenin Equivalent Circuits
80Finding the Thévenin Resistance Directly
When zeroing a voltage source, it becomes a short
circuit. When zeroing a current source, it
becomes an open circuit. We can find the
Thévenin resistance by zeroing the sources in the
original network and then computing the
resistance between the terminals.
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83Computation of Thévenin resistance
84Equivalence of open-circuit and Thévenin voltage
85A circuit and its Thévenin equivalent
86Superposition
As the voltage source does not contribute any
output voltage, Only the current source has the
effect.
87Determine the Thévenin and Norton Equivalents of
Network A in (a).
Source transformation
88Find the Thévenin equivalent of the circuit shown
in (a).
v
As i -1, therefore, the controlled voltage
source is -1.5V.Use nodal analysis at node v,
Thus, Rth v/I 0.6/1 0.6 ohms
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90Applications of Thevenins Theorem
- Load Voltage Ranges Thevenins theorem is most
commonly used to predict the change in load
voltage that will result from a change in load
resistance
91Applications of Thevenins Theorem
- Maximum Power Transfer
- Maximum power transfer from a circuit to a
variable load occurs when the load resistance
equals the source resistance - For a series-parallel circuit, maximum power
occurs when RL RTH
92Applications of Thevenins Theorem
Insert Figure 7.30
93Nortons Theorem
- Nortons Theorem any resistive circuit or
network, no matter how complex, can be
represented as a current source in parallel with
a source resistance
94Nortons Theorem
- Norton Current (IN) the current through the
shorted load terminals
Insert Figure 7.35
95Computation of Norton current
96Nortons Theorem
- Norton Resistance (RN) the resistance measured
across the open load terminals (measured and
calculated exactly like RTH)
97Nortons Theorem
- Norton-to-Thevenin and Thevenin-to-Norton
Conversions
Insert Figure 7.39
98Step-by-step Thévenin/Norton-Equivalent-Circuit
Analysis
1. Perform two of these a. Determine the
open-circuit voltage Vt voc. b. Determine
the short-circuit current In isc. c. Zero
the sources and find the Thévenin resistance Rt
looking back into the terminals.
992. Use the equation Vt Rt In to compute the
remaining value. 3. The Thévenin equivalent
consists of a voltage source Vt in series with Rt
. 4. The Norton equivalent consists of a current
source In in parallel with Rt .
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101Maximum Power Transfer
The load resistance that absorbs the maximum
power from a two-terminal circuit is equal to the
Thévenin resistance.
102Graphical representation of maximum power transfer
Power transfer between source and load
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