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Mathematical Induction II

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Mathematical Induction II Lecture 20 Section 4.3 Wed, Feb 16, 2005 Putnam Question B-1 (1981) Find limn [(1/n5) h = 1..n k = 1..n (5h4 18h2k2 + 5k4)]. – PowerPoint PPT presentation

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Title: Mathematical Induction II


1
Mathematical Induction II
  • Lecture 20
  • Section 4.3
  • Wed, Feb 16, 2005

2
Putnam Question B-1 (1981)
  • Find
  • limn?? (1/n5) ?h 1..n ?k 1..n (5h4 18h2k2
    5k4).
  • Solution
  • Express ?h?k 5h4, ?h?k 18h2k2, and ?h?k 5k4 as
    polynomials in n.
  • Simplify the polynomials.
  • Divide by n5.
  • Take the limit as n ? ?.
  • The answer is -1.

3
Lets Play Find the Flaw
  • Theorem For every positive integer n, in any
    set of n horses, all the horses are the same
    color.
  • Proof
  • Basic Step.
  • When n 1, there is only one horse, so trivially
    they are (it is) all the same color.

4
Find the Flaw
  • Inductive Step
  • Suppose that any set of k horses are all the same
    color.
  • Consider a set of k 1 horses.
  • Remove one of the horses from the set.
  • The remaining set of k horses are all the same
    color.

5
Find the Flaw
  • Replace that horse and remove a different horse.
  • Again, the remaining set of k horses are all the
    same color.
  • Therefore, the two horses that were removed are
    the same color as the other horses in the set.
  • Thus, the k 1 horses are all the same color.

6
Find the Flaw
  • Thus, in any set of n horses, the horses are all
    the same color.

7
Example
  • Find a formula for
  • 1 3 5 (2n 1).
  • Clever solution
  • 1 3 5 (2n 1)
  • (1 2 3 2n) (2 4 6 2n)
  • (1 2 3 2n) 2(1 2 3 n)
  • (2n)(2n 1)/2 2(n(n 1)/2)
  • n2.

8
Exercise
  • Find a formula for
  • 12 32 52 (2n 1)2.
  • Then verify it using mathematical induction.
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