Title: Solving Rational Equations and Inequalities
1Solving Rational Equations and Inequalities
8-5
Warm Up
Lesson Presentation
Lesson Quiz
Holt Algebra 2
2Warm Up Find the least common multiple for each
pair.
1. 2x2 and 4x2 2x
2x2(2x 1)
2. x 5 and x2 x 30
(x 5)(x 6)
Add or subtract. Identify any x-values for which
the expression is undefined.
3.
x ? 0
4.
3Objective
Solve rational equations and inequalities.
4Vocabulary
rational equation extraneous solution rational
inequality
5A rational equation is an equation that contains
one or more rational expressions. The time t in
hours that it takes to travel d miles can be
determined by using the equation t , where
r is the average rate of speed. This equation is
a rational equation.
6To solve a rational equation, start by
multiplying each term of the equation by the
least common denominator (LCD) of all of the
expressions in the equation. This step eliminates
the denominators of the rational expression and
results in an equation you can solve by using
algebra.
7Check It Out! Example 1a
Multiply each term by the LCD, 3x.
10x 12 6x
Simplify. Note that x ? 0.
4x 12
Combine like terms.
x 3
Solve for x.
8Check It Out! Example 1b
Multiply each term by the LCD, 4x.
24 5x 7x
Simplify. Note that x ? 0.
24 12x
Combine like terms.
x 2
Solve for x.
9Check It Out! Example 1c
Solve the equation x 1.
Multiply each term by the LCD, x.
x2 6 x
Simplify. Note that x ? 0.
x2 x 6 0
Write in standard form.
(x 2)(x 3) 0
Factor.
x 2 0 or x 3 0
Apply the Zero Product Property.
x 2 or x 3
Solve for x.
10An extraneous solution is a solution of an
equation derived from an original equation that
is not a solution of the original equation. When
you solve a rational equation, it is possible to
get extraneous solutions. These values should be
eliminated from the solution set. Always check
your solutions by substituting them into the
original equation.
11Check It Out! Example 2a
Solve the equation .
Multiply each term by the LCD, (x 4)(x 4).
Divide out common factors.
Simplify. Note that x ? 4.
16 2x 8
x 4
Solve for x.
The solution x 4 is extraneous because it makes
the denominators of the original equation equal
to 0. Therefore, the equation has no solution.
12Check It Out! Example 2b
Multiply each term by the LCD, 6(x 1).
Divide out common factors.
6 6x x(x x)
Simplify. Note that x ? 1.
Use the Distributive Property.
6 6x x2 x
13Check It Out! Example 2b Continued
Write in standard form.
0 x2 5x 6
0 (x 6)(x 1)
Factor.
Apply the Zero Product Property.
x 6 0 or x 1 0
Solve for x.
x 6 or x 1
The solution x 1 us extraneous because it makes
the denominator of the original equation equal to
0. The only solution is x 6.
14Check It Out! Example 3
On a river, a kayaker travels 2 mi upstream and 2
mi downstream in a total of 5 h. In still water,
the kayaker can travel at an average speed of 2
mi/h. Based on this information, what is the
average speed of the current of this river? Round
to the nearest tenth.
15Check It Out! Example 3 Continued
The answer will be the average speed of the
current.
- List the important information
- The kayaker spent 5 hours kayaking.
- She went 2 mi upstream and 2 mi downstream.
- Her average speed in still water is 2 mi/h.
16Check It Out! Example 3 Continued
Let c represent the speed of the current. When
the kayaker is going upstream, her speed is equal
to her speed in still water minus c. When the
kayaker is going downstream, her speed is equal
to her speed in still water plus c.
Distance (mi) Average Speed (mi/h) Time (h)
Up 2 2 c
Down 2 2 c
17The LCD is (2 c)(2 c).
Simplify. Note that x ? 2.
5(2 c)(2 c) 2(2 c) 2(2 c)
Use the Distributive Property.
20 5c2 4 2c 4 2c
20 5c2 8
Combine like terms.
5c2 12
Solve for c.
c 1.5
The speed of the current cannot be negative.
Therefore, the average speed of the current is
about 1.5 mi/h.
18Check It Out! Example 3 Continued
If the speed of the current is about 1.5 mi/h,
the kayakers speed when going upstream is 2
1.5 0.5 mi/h. It will take her about 4 h to
travel 2 mi upstream. Her speed when going
downstream is about 2 1.5 3.5 mi/h. It will
take her 0.5 h to travel 2 mi downstream. The
total trip will take about 4.5 hours which is
close to the given time of 5 h.
19Check It Out! Example 4
Julien can mulch a garden in 20 minutes. Together
Julien and Remy can mulch the same garden in 11
minutes. How long will it take Remy to mulch the
garden when working alone?
20Check It Out! Example 4 Continued
1
Multiply by the LCD,20m.
11m 220 20m
Simplify.
Solve for m.
220 9m
24 m
It will take Remy about 24 minutes to mulch the
garden working by himself.
21A rational inequality is an inequality that
contains one or more rational expressions. One
way to solve rational inequalities is by using
graphs and tables.
22Check It Out! Example 5a
(4, 4)
The graph of Y1 is at or below the graph of Y2
when x lt 3 or when x 4.
Vertical asymptote x 3
23Check It Out! Example 5a continued
Use a table. The table shows that Y1 is
undefined when x 3 and that Y1 Y2 when x 4.
The solution of the inequality is x lt 3 or x 4.
24Check It Out! Example 5b
(5, 2)
The graph of Y1 is at or below the graph of Y2
when x 5.
Vertical asymptote x 1
25Check It Out! Example 5b continued
Use a table. The table shows that Y1 is
undefined when x 1 and that Y1 Y2 when x
5.
The solution of the inequality is x 5.
26You can also solve rational inequalities
algebraically. You start by multiplying each term
by the least common denominator (LCD) of all the
expressions in the inequality. However, you must
consider two cases the LCD is positive or the
LCD is negative.
27Check It Out! Example 6a
Case 1 LCD is positive.
Step 1 Solve for x.
Multiply by the LCD.
Simplify. Note that x ? 2.
6 4x 8
Solve for x.
2 4x
Rewrite with the variable on the left.
28Check It Out! Example 6a Continued
Step 2 Consider the sign of the LCD.
LCD is positive.
x 2 gt 0
Solve for x.
x gt 2
29Check It Out! Example 6a Continued
Case 2 LCD is negative.
Step 1 Solve for x.
Multiply by the LCD. Reverse the inequality.
Simplify. Note that x ? 2.
6 4x 8
Solve for x.
2 4x
Rewrite with the variable on the left.
30Check It Out! Example 6a Continued
Step 2 Consider the sign of the LCD.
LCD is negative.
x 2 lt 0
Solve for x.
x lt 2
31Check It Out! Example 6b
Case 1 LCD is positive.
Step 1 Solve for x.
Multiply by the LCD.
Simplify. Note that x ? 3.
9 lt 6x 18
Solve for x.
9 lt 6x
Rewrite with the variable on the left.
32Check It Out! Example 6b Continued
Step 2 Consider the sign of the LCD.
LCD is positive.
x 3 gt 0
Solve for x.
x gt 3
33Check It Out! Example 6b Continued
Case 2 LCD is negative.
Step 1 Solve for x.
Multiply by the LCD. Reverse the inequality.
Simplify. Note that x ? 3.
9 gt 6x 18
Solve for x.
9 gt 6x
Rewrite with the variable on the left.
34Check It Out! Example 6b Continued
Step 2 Consider the sign of the LCD.
LCD is negative.
x 3 lt 0
Solve for x.
x lt 3