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OUTLINE

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... p+n junction n+p junction On the p-side, = qNA On the n-side, = qND s A qN dx d e - = E ) ( ) ( 1 x -qNA C x qN x s s A + = + - = e e E ) ( ) ... – PowerPoint PPT presentation

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Title: OUTLINE


1
Lecture 14
  • OUTLINE
  • pn junction electrostatics
  • Reading Chapter 5

2
Qualitative Electrostatics
Band diagram
Electrostatic potential
Electric field
Charge density
3
Game Plan for Obtaining r(x), E(x), V(x)
  • Find the built-in potential Vbi
  • Use the depletion approximation ? r (x)
  • (depletion-layer widths xp, xn unknown)
  • Integrate r (x) to find E(x)
  • boundary conditions E(-xp)0, E(xn)0
  • Integrate E(x) to obtain V(x)
  • boundary conditions V(-xp)0, V(xn)Vbi
  • For E(x) to be continuous at x0, NAxp NDxn
  • solve for xp, xn

4
Built-In Potential Vbi
For non-degenerately doped material
5
Vbi for One-Sided pn Junctions
pn junction
np junction
6
The Depletion Approximation
On the p-side, ? qNA
qN
d
E
-

A
e
dx
s
-qNA
qN
)
(
x



-

)
(
C
x
x
A
E
e
1
e
s
s
On the n-side, ? qND
-qN
-
x

)
(
D
xn
)
(
x
E
e
s
7
Electric Field in the Depletion Layer
The electric field is continuous at x 0 ?
NAxp NDxn
8
Electrostatic Potential in the Depletion Layer
On the p-side
(arbitrarily choose the voltage at x xp to be 0)
On the n-side
9
  • At x 0, expressions for p-side and n-side must
    be equal
  • We also know that NAxp NDxn

10
Depletion Layer Width
  • Eliminating xp, we have
  • Eliminating xn, we have
  • Summing, we have

11
One-Sided Junctions
If NA gtgt ND as in a pn junction
What about a np junction?
where
12
Example
  • A pn junction has NA1020 cm-3 and ND 1017cm-3.
    What is a) its built in potential, b)W , c)xn ,
    and d) xp ?
  • Solution
  • a)
  • b)
  • c)
  • d)

13
Summary
  • For a non-degenerately-doped pn junction at
    equilibrium
  • Built-in potential
  • Depletion-layer width
  • For a one-sided (pn or pn) junction at
    equilibrium
  • Built-in potential
  • Depletion-layer width
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