Title: In the movie
1In the movie Armaggedon a comet the size of
Texas (800 miles or 1250 km in diameter) was
heading for Earth. If the density were 800
kg/m3, the mass would be about 8.x10 20 kg. How
far would a ball on the surface fall in 1.0
second?
Physics 1710Warm-up Quiz
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- About 5 m
- About 7 cm
- About 2 cm
- None of the above
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2Physics 1710Chapter 12 Apps Gravity
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g G M/ R2 g(6.67x10-11 N m2/kg2)(8x1020
kg)/(625x103 m)2 g 0.14 N/kg d ½ g t 2 0.5
(0.14 m/s2)(1 sec)2 0.0 7 m 7 cm
3Physics 1710Chapter 13 Apps Gravity
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- 1' Lecture
- The gravitational force constant g is equal to
g G M/(Rh) 2, M and R are the mass and
radius of the planet. - The gravitation field is the force divided by the
mass. - The gravitation potential energy for a point mass
is proportional to the product of the masses and
inversely proportional to the distance between
their centers. - The escape velocity is the initial velocity at
the surface required to leave a body. vescape
v 2GM/R
4Physics 1710Chapter 13 Apps Gravity
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- Does the position of the moon affects us as
astrology claims?
Peer Instruction Time
5Does the position of the moon affects us as
astrology claims?
Physics 1710Chapter 13 Apps Gravity
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- Yes, I strongly agree
- Yes, I Agree
- No, I disagree
- No, I strongly disagree
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6Physics 1710Chapter 13 Apps Gravity
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- Astrology Does the moon affect us?
- F - G M m/ d 2
M 7.36x1023 kg d 3.84x108 m F/m
(7x10-11)(7x1023)/(4x108)2 3x10-4 N/kg 30 µ
g
d moon3.84x108 m
M 7.36x1023 kg
7Physics 1710Chapter 13 Apps Gravity
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- Gravitational Potential Energy
- U -?8R Fd r
- U -?8R G Mm/r 2d r
- U GMm/R mgR
- U 0 as r ?8
F
d r
8Physics 1710Chapter 13 Apps Gravity
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- Escape Velocity
- If K is such that E 0 as r ?8, then
- KR ½ m v 2 UR GMm/ R
- and
- vescape v 2GM/R v2gR
U8 0
UR GMm/R
K8 0
K ½ m v 2
9Were the astronauts in danger of jumping off the
Armaggedon comet? (Hint What is the escape
velocity from our Armaggedon comet? M 8x1020
kg, R 6.25x10 5 m, g 0.14 N/kg)
Physics 1710Chapter 13 Apps Gravity
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- Yes. Definitely.
- Maybe.
- No. Definitely not.
- Not enough information.
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10Physics 1710Chapter 13 Apps Gravity
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- Escape Velocity
- vescape v 2GM/R v2gR
- v2(0.14 N/kg)(625 km) 400 m/s
- 900 mph. Safe!
vescape v 2GM/R v2gR??
11Physics 1710Chapter 13 Apps Gravity
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- Escape Velocity of Earth?
- vescape v 2GM/R v2gR
- v2(9.8 N/kg)(6.3 x10 6 m) 11,000 m/s
- 25,000 mph. Stuck!
vescape v 2GM/R v2gR??
12Physics 1710Chapter 13 Apps Gravity
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- Total Energy
- for Gravitationally Bound Mass
- E K U
- E ½ m v 2 GMm/r
- E L2/2mr 2 GMm/r
- Bound orbit if E 0 and
- - dE/dr ro 2 (L2/2mro) - GMm 0
- E - GMm/2ro
13Physics 1710Chapter 13 Apps Gravity
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- Total Energy
- for Gravitationally Bound Mass
- E K UE - GMm/2ro
r
L2 /2mr 2 GMm/r
E lt 0
ro - 2E/(GMm)
14Physics 1710Chapter 13 Apps Gravity
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- Summary
- The force of attraction between two bodies with
mass M and m respectively is proportional to the
product of their masses and inversely
proportional to the distance between their
centers squared. - F - G M m/ r 2
- The proportionality constant in the Universal
Law of Gravitation G is equal to 6.673 x 10 11 N
m2 /kg2 .
15Physics 1710Chapter 13 Apps Gravity
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- Summary
- The gravitational force constant g is equal to
- G M/(Rh) 2, R is the radius of the planet.
- Keplers Laws
- The orbits of the planets are ellipses.
- The areal velocity of a planet is constant.
- The cube of the radius of a planets orbit
- is proportional to the square of the period.
- The gravitation field is the force divided by
the mass. - g Fg / m
16Physics 1710Chapter 13 Apps Gravity
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- Summary
- The gravitation potential energy for a point
mass is proportional to the product of the masses
and inversely proportional to the distance
between their centers - U GMm / r
- The escape velocity is the minimum speed a
projectile must have at the surface of a planet
to escape the gravitational field. - vescape v 2GM/R
- Total Energy E is conserved for two body
geavitational problem bodies are bound for E 0 - E L2/2mr 2 GMm/r