Title: Projectile motion
1Projectile motion
- A projectile is an object upon which the only
force acting is gravity. - It is assumed that the influence of air
resistance is negligible.
2Monkey and Hunter Experiment
3Only one force (weight) is acting on the cannon
ball.
Horizontal motion Constant velocity
vertical motion Constant downward acceleration g
4Horizontal motion No horizontal force gt
constant velocity
Vertical motion Downward force (weight) gt
uniform downward acceleration (g)
5A projectile motion
Speed of projection u Angle of projection a
u
Initial horizontal speed u cos a Initial
vertical speed u sin a
u sin a
a
u cos a
Horizontal displacement x u cos a t Vertical
displacement y u sin a t ½ gt2
6Time of flight
t 0
- Put y 0
- 0 u sin a t ½ gt2
- t(u sin a ½ gt) 0
- t 0 (rejected) or t 2u sin a / g
t time of flight
7Range
Range final horizontal displacement
horizontal speed x time of flight
u cos a x 2u sin a / g 2 u2 sin a cos a / g
u2 sin 2 a /g
8Maximum Range
Range 2 u2 sin a cos a / g u2 sin
2 a /g Maximum range u2 /g when sin 2 a 1
i.e. 2a 90o a 45o
9Summary
- Vertical motion y ut sin q ½ gt2
- Horizontal motion x ut cos q
- Time of flight Put y 0
- ? t 2usin q / g
- Range Put t 2u sin q / g
- ? x u2sin 2q / g
10Exercise (HKAL 1998) page 28
- A small object is thrown horizontally towards a
vertical wall 1.2 m away. It hits the wall 0.8 m
below its initial horizontal level. At what speed
does the object hit the wall? (Neglect air
resistance.)
wall
1.2 m
0.8 m
11Solution
wall
1.2 m
u
0.8 m
? ut 1.2 ? u 1.2/0.4 3 ms-1 At the wall, (v
u at) Horizontal velocity 3 (0)(0.4) 3
ms-1 Vertical velocity 0 (10)(0.4) 4
ms-1 The speed at the wall (32 42)½ 5
ms-1
- Horizontal motion x ut cos q
- ? 1.2 ut cos 0o
- ? ut 1.2
- Vertical motion y ut sin q ½ gt2
- ? 0.8 ut sin 0o ½ gt2
- ? 0.8 ½ (10)t2
- ? 0.8 ½ (10)t2
- ? t 0.4 s
-
12Class work page 13
- (a) Time of flight
- By s ut ½ at2
- -100 10 sin 30ot ½ (-10) t2
- 5t2 5t 100 0
- (t 5)(t 4) 0
- t 5 s or t -4 s (rejected)
13Class work page 13
- (b) Horizontal distance moved
- u cos 30o x time of flight
- 10 cos 30o x 5
- 43.3 m
14Class work page 13
- (c) Direction of flight
- vx 10 cos 30o 8.66 ms-1
- vy 10 sin 30o (-10)(5) -45 ms-1
- tan q vy / vx 45/8.66
- q 79.1o
- ? The particle makes an angle of 79.1o to the
horizontal when it reaches the sea.
15Class work page 13
vx
q
vy
v
- (d) Speed of the ball
- sqrt(vx2 vy2)
- sqrt(8.662 452)
- 45.83 ms-1
-
16Homework
- Textbook page 51 (6, 7)
- Reference book page 116 (8, 12, 16)
- Due date 2nd October
- Test Chapter 4 projectile motion
- 2nd October