Math 3680 - PowerPoint PPT Presentation

1 / 59
About This Presentation
Title:

Math 3680

Description:

Example: The receptor interleukin-8 is measured as a test for ectopic (tubal) pregnancy. For 17 women with ectopic pregnancy, 14 tested positive and 3 tested negative. – PowerPoint PPT presentation

Number of Views:136
Avg rating:3.0/5.0
Slides: 60
Provided by: mathUntEd
Learn more at: http://www.math.unt.edu
Category:
Tags: math | pregnancy | tubal

less

Transcript and Presenter's Notes

Title: Math 3680


1
Math 3680 Lecture 3 Probability
2
  • We hear about chance in several different
    contexts
  • 1. A certain horse is given 51 odds to win a
    race.
  • 2. A banker recommends a certain stock for
    investment.
  • 3. Josh Hamilton is batting 0.361 for the season.
  • 4. In a recent poll, 48 of Americans approve of
    the presidents performance.
  • 5. The chance of being dealt the queen of spades
    is 1 in 52.
  • 6. The chance of winning a Pick 4 lottery game is
    1 in 10,000.

We have three different types of
probabilities   1) Expert opinion
(subjective) 2) Relative frequency
(empirical) 3) Equally likely outcomes
(theoretical)
3
  • Definition The probability of event A is
    denoted P(A).
  • 1) Chances are between 0 and 100. That is
  • 0 P(A) 1.
  • We denote an impossible event (the empty set) by
    Ø
  • P(Ø) 0.

4
There is a technical difference between the
phrases impossible and probability zero.
Example I pick a real number in the interval
0,1 and you try to guess my number. Its not
impossible, but the probability that you pick my
number is zero. Question Would the same be
true if I told you that I rounded my number to
six decimal places?
5
  • 2) The chance of something not happening is 100
    minus the chance of it happening. That is,
  • P(not E) P(E )
    1 - P(E).
  • This event, not E, is referred to as the
    complement of E.

6
  • 3) When you draw at random, we assume that all
    the possible outcomes are equally likely, so
    that
  • number of favorable
    outcomes
  • P(E)
  • number of possible
    outcomes
  • The word draw is used to suggest select, or
    pick, or choose. There are two ways that
    draws can be made
  • 1. Draws with replacement, such as rolling a die
    repeatedly or tossing a coin repeatedly.  
  • 2. Draws without replacement, such as dealing
    cards from a deck or 5 CD random shuffle.

7
  • 4) If E implies F, then F is more likely
    than E.
  • If , then
    P(E) P(F).
  • Example Let E a dealt card is a heart
  • Let F a dealt card is red

8
  • Definition Conditional probability.
  • The conditional probability that A happens given
    thatB happens is denoted by
  • P(A B)
  • Formula
  • Here, A n B denotes the intersection of A and B
    that is, the event that A and B both happen.

9
  • Ex Two tickets are drawn without replacement
    from the box
  • A) What is the chance that the second ticket is
    ,
  • given the first is ? (Conditional
    probability)
  •  
  • B) What is the chance that the first ticket is
    ?
  • (Unconditional probability)
  • C) What is the chance that the second ticket is
    ?
  • (Again unconditional probability!)
  • D) Repeat if the draws are made with replacement.

1
2
3
4
2
4
2
2
10
  • Example Five cards are dealt off the top of a
    well-shuffled deck.
  • A) Find the chance that the fifth card is the
    queen of spades.
  • B) Find the chance that the fifth card is the
    queen of spades, given that the first four cards
    are hearts.

11
  • Example A penny is tossed five times.
  • A) Find the chance that the fifth toss is a
    head. 
  • B) Find the chance that the fifth toss is a
    head, given that the first four tosses are tails.

12
Example A box has three tickets red, white
and blue. Two tickets are drawn at random
without replacement. What is the chance that the
red ticket is drawn first, and the white ticket
second?
  • Solution 1 Counting the possibilities.
  •  
  • RW WR BR
  • RB WB BW
  •  
  • So the chance is

1
6
13
  • Solution 2 Multiplication Rule. Imagine a
    large group of people attempting this experiment.
    Roughly one-third will get the first draw
    correct.
  • Of these people, about half will get the second
    draw correct. Thus, from the original
    population,
  • will get both draws correct.

1
1
1


6
2
3
14
  • Definition Multiplication Rule.
  • The chance that events A and B both happen is
    found by multiplying the chance that event A
    happens by the chance that B happens, given that
    A has happened
  • P(A n B) P(A) P(B A)

15
  • Example A deck of cards is shuffled and two
    cards are dealt. What is the probability that
    both are hearts?
  • Method 1 List the possible outcomes.

16
(No Transcript)
17
Example A deck of cards is shuffled and two
cards are dealt. What is the probability that
both are hearts? Method 2 Use the
multiplication rule.
18
  • Example Five cards are dealt from a
    well-shuffled deck. What is the probability that
    all 5 are hearts?

19
  • Example In poker, what is the probability of
    being dealt a flush?

20
  • Example A die is rolled four times. What is
    the probability that all four rolls are
    different?

21
  • Definition Independent. We say that two
    events A and B are independent if the outcome of
    event A does not influence the outcome of event
    B. In mathematical notation,
  • P(B A) P(B)

22
  • Example A coin is tossed twice. Let
  • A the first flip lands heads
  • B the second flip lands heads
  • Are events A and B independent?

23
  • Example A die is rolled once. Let
  • A the die lands on four
  • B the die lands on six
  • Are events A and B independent?

24
  • Example Two cards are dealt. Let
  • A the first card is an ace
  • B the second card is an ace
  • Are events A and B independent?

25
  • Example One card is dealt. Let
  • A the card is a jack
  • B the card is a heart
  • Are events A and B independent?

26
  • Rule of thumb
  • When drawing with replacement, the draws are
    independent.
  • When drawing without replacement, the draws are
    dependent.

27
  • Example A die is rolled 10 times. Find the
    chance of ...
  • A) getting 10 sixes
  •  
  • B) not getting 10 sixes
  • C) all the rolls showing 5 or fewer dots
  • D) getting at least one six
  • Are B) and C) the same?

28
  • Definition Mutually Exclusive. Two events
    are called mutually exclusive (or disjoint) if
    they cannot occur simultaneously.
  • WARNING Disjoint is a different concept than
    independent.
  • If E and F are disjoint, then P(F E) 0.
  • If E and F are independent, then P(F E)
    P(F).

29
  • Example A coin is flipped twice. Let
  • A the first flip lands heads
  • B the second flip lands heads
  • Are events A and B disjoint?

30
Example A die is rolled once. Let A the
die lands on four B the die lands on six
Are events A and B disjoint?
31
  • Example Two cards are dealt. Let
  • A the first card is an ace
  • B the second card is an ace
  • Are events A and B disjoint?

32
  • Example One card is dealt. Let
  • A the card is a jack
  • B the card is a heart
  • Are events A and B disjoint?

33
  • Property If A and B are disjoint, then



P(B)
P(A)
P(A or B)
Note The word or has a different meaning in
probability than in ordinary English usage. It
does not mean exclusive or. That is, A or
B means A, or B, or both A and B.
34
  • Example A card is dealt from a shuffled deck.
    What is the probability that the card is a face
    card?

Solution P(jack or queen or king) P(jack)
P(queen) P(king)
35
  • Example A card is dealt from a well-shuffled
    deck. What is the probability that it is a red?
  •  
  • Solution
  • P(heart or diamond) P(heart) P(diamond)
  • (mutually exclusive)

36
  • Example Two dice are rolled. Whats the
    probability that an ace (one dot) appears?
  •  
  • Common Mistake
  • P(ace on first or ace on second)
  • P(ace on first ) P(ace on second)

37
  • Correct Answer 1 Look at a chart of the 36
    possible outcomes for the roll of two dice. There
    are 11 pairs in which an ace appears. So the
    answer is .

11
36
38
  • Because these two events are not mutually
    exclusive, the first (incorrect) method produced
    an answer that was too big instead of
    .
  • Subtracting something makes sense. After all,
    the probability of an ace appearing on 7 dice
    cannot be .

12
K
36
11
36
7
6
39
  • Correct Answer 2 Use the general formula for
    events which are not mutually exclusive

-


P(A n B )
P ( B)
P(A)
P(A or B)
Notice that the Rule of Addition saves a lot of
time.
40
  • Example A card is dealt. What is the
    probability it is either a queen or a spade?

41
  • Example True or false? In a shuffled deck of
    cards
  • A) The chance that the top card is the jack of
    clubs is 1/52.
  •  
  • B) The chance that the bottom card is eight of
    hearts is 1/52.
  • C) The chance that the top card is the jack
    of clubs or the bottom card is the eight of
    hearts is 2/52.

42
  • D) The chance that the top card is the jack of
    clubs or the bottom card is the jack of clubs is
    2/52.
  •   
  • E) The chance that the top card is the jack of
    clubs and the bottom card is the eight of hearts
    is
  • F) The chance that the top card is the jack
    of clubs and the bottom card is the jack of clubs
    is

1
1

52
52
43
  • Example Four tickets are drawn from a box that
    contains 5 tickets each numbered from 1 to 5.
    Find P(at least one 2) if the draws are made

A) with replacement B) without replacement
44
  • Example Suppose that P(A) 0.2, P(B) 0.3
    and 0.4. Use a Venn
    diagram to find the following quantities
  • 1.
  • 2.
  • 3.
  • 4.

P(A or B)
P(A n B )
P(A n B )
P(A n B )
P(A B)
45
Multiplication Trees and Bayes Rule
46
  • Example Suppose there are two electrical
    components. The chance that the first component
    fails is 20. If the first fails, the chance that
    the second fails is 30. However, if the first
    works, the chance that the second fails is 10.
  • Find the probability that
  • 1. At least one component works.
  • 2. Exactly one component works.
  • 3. The second component works.

47
  • Solution A multi-stage problem like this can be
    visualized with a tree diagram

Works
0.72
0.9
Works
0.8
0.1
Fails
0.08
Works
0.14
0.2
0.7
Fails
0.3
Fails
0.06
48
Works
0.72
0.9
Works
0.8
0.1
Fails
0.08
Works
0.14
0.2
0.7
Fails
0.3
Fails
0.06
P(at least one component works) P(exactly one
component works) P(second component works)
49
  • Example In a class of 50 students, what is the
    probability that at least two share a birthday?

50
  • Example In Barcelona, the local men tend not to
    be overweight due to genetic and dietary reasons.
    However, the tourists from around the world who
  • visit Barcelona tend to be as overweight as the
    rest of Europe and America.
  • Suppose
  • 2 of Barcelona men are overweight
  • 35 of Barcelonas male tourists are overweight
  • 10 of the men in Barcelona are tourists
  • If a man is selected at random, what is the
    probability that hes overweight?

51
(No Transcript)
52
  • Example Suppose 2 of Barcelona men are
    overweight, while 35 of Barcelonas male
    tourists are overweight. Also, suppose 10 of the
    men in Barcelona are tourists.
  • If you see an overweight man at a distance in
    Barcelona, what is the probability that hes a
    tourist?
  • Solution Let A man is overweight, B man
    is a tourist.
  • Then we are given
  • P(A B) 0.35
  • P(A B ) 0.02
  • P(B) 0.1
  • But we want P(B A) the reverse conditional
    probability.

53
(No Transcript)
54
  • Example In a study of 101 patients, 37 do not
    have coronary artery disease (CAD) and 64 have
    CAD. All 101 patients were given a certain test
    for CAD. Of the 37 patients without CAD, 34 had a
    negative test while 3 had a positive test. Of the
    64 patients with CAD, 54 had a positive test and
    10 had a negative test.
  • A man in his 50s with a family history of CAD
    sees a doctor, complaining of chest pain. Because
    of his age and family history, the doctor
    estimates the probability that the patient has
    CAD as 0.6. The patient is then given the above
    test, and it comes back positive. Find the
    posterior probability that the patient has CAD.

55
  • Solution We begin with the tree diagram

Test positive
0.506
54/64
Disease positive
Test negative
0.6
0.094
10/64
Test positive
0.032
3/37
0.4
Disease negative
Test negative
0.368
34/37
56
(No Transcript)
57
  • Definition
  • Sensitivity P(test positive disease
    positive)
  • Specificity P(test negative disease
    negative)
  • In a perfect world, both of these conditional
    probabilities would be 100, but thats
    unrealistic. Bayes rule allows us to take the
    information from a clinical trial and use it in a
    diagnostic setting.
  • Measuring these two quantities is absolutely
    essential in a clinical medical trial. Lets look
    up how many articles have been published which
    contain these words in the abstract.

58
  • Example The receptor interleukin-8 is measured
    as a test for ectopic (tubal) pregnancy. For 17
    women with ectopic pregnancy, 14 tested positive
    and 3 tested negative. For 55 women without an
    ectopic pregnancy, 10 tested positive and 45
    tested negative.
  • (a) Find the sensitivity and specificity of the
    test.
  • (b) An obstetrician treats a woman with mild
    pelvic pain. Based on her professional
    experience, the doctor believes the probability
    of an ectopic pregnancy to be 0.2. The patient is
    tested, and the test returns negative. Find the
    posterior probability of an ectopic pregnancy.

59
(No Transcript)
Write a Comment
User Comments (0)
About PowerShow.com