Title: Chemical Kinetics Chapter 13
1Chemical KineticsChapter 13
An automotive catalytic muffler.
2 313.1
4Factors Affecting Reaction Rate
- Chemical nature
- Bond strengths
- General reactivity
- Ability to establish contact with one another
- Physical state
- Surface area for liquids, solids, and
heterogeneous mixtures - Amount of Mixing
- Particle shape/size
5Factors (Cont.)
- Concentration of reactants
- Molarity for solutions
- Pressure effects for gases
- Volume effects for gases
- Temperature
- Catalysts
6Your Turn!
- Which of the following would speed a reaction?
- stirring it
- dissolving the reactants in water, if ionic
- adding a catalyst
- grinding any solids
- all of these
7Measuring Rates
- instantaneous rate (text uses this unless
specified) - average rate
- initial rate
8DBr2 a DAbsorption
13.1
9Fig. 13.5
10instantaneous rate rate for specific instance
in time
13.1
11(No Transcript)
12Fig. 13.6
13rate a Br2
rate k Br2 rate law
rate constant
3.50 x 10-3 s-1
13.1
14Your Turn!
- What is the average rate of B between 10 and 40
s? - -0.006 M/s
- 0.006 M/s
- -0.002 M/s
- 0.002 M/s
- cant tell form the information
15Rates And Stoichiometry
- Rates based on each substance are related to one
another by the stoichiometric coefficients of the
reaction - Examine the reaction aA bB ?dD
- the stoichiometric relationship between
substances A and B is given as a mole A b mole
B - RateA(b/a)RateB
16Consider the combustion of propane
- Compared to the rate with respect to propane
- Rate with respect to oxygen is five times faster
- Rate with respect to carbon dioxide is three
times faster - Rate with respect to water is four times faster
- Since the rates are all related any may be
monitored to determine the reaction rate
17Learning Check
- In the reaction 2A 3B ?5D We measured the rate
of disappearance of substance A to be
3.510-5M/s. What is the rate of appearance of
D? - In the reaction 3A 2B ?C, we measured the rate
of B. How does the rate of C relate?
8.7510-5 M/s
RC1/2 RB
18- 3A 2B C ? Products
- Rate k A2BC3
- The exponents in the rate law are generally
unrelated to the chemical equations coefficients - Never simply assume the exponents and
coefficients are the same - The exponents must be determined from the results
of experiments - The exponent in a rate law is called the order of
reaction with respect to the corresponding
reactant
19Your Turn!
- In the reaction 2CO(g) O2(g) ?2CO2(g), the rate
of the reaction of CO is measured to be 2.0 M/s.
What would be the rate of the reaction of O2? - the same
- twice as great
- half as large
- you cannot tell from the given information
20Learning Check
- The rate law for the reaction 2A B?3C is
- rate 0.045M-1s-1 AB
- if the concentration of A is 0.2M and that of B
is 0.3M, what will be the reaction rate?
rate0.045 M-1 s-1 0.20.3
rate0.0027 M/s
21Determine the rate law
22- The initial rate for the reaction of nitrogen
monoxide and oxygen was measured at 25 ºC for
various concentrations shown in the table below.
Determine the rate equation for the reaction, the
value of the rate constant with proper units, and
the initial rate if NOO20.010 M - Exp NO O2 initial rate mol/L mol/L
mol/Ls - 1 0.020 0.010 0.028
- 2 0.020 0.020 0.057
- 3 0.020 0.040 0.114
- 4 0.040 0.020 0.227
- 5 0.010 0.020 0.014
23- Concentration rate data for reaction A B C ?
Products Initial Conc.mol/L Initial Rate
mol/Ls A B C Rate 0.10 0.10
0.10 0.20 0.20 0.10
0.10 0.40 0.30 0.10 0.30 0.60 0.30 0.2
0 0.30 2.40 0.30 0.30
0.60 5.40 Determine the rate law for this
reactionDetermine the rate constant for the
reactionDetermine the overall reaction order for
the reactionDetermine the rate of reaction when
AB0.50 mol/L
24- A certain reaction follows the equation 2A B ?
3C D. - Experimental results yielded the following data.
Determine the rate law, reaction order for A and
B, the overall reaction order, the value for the
rate constant k, and the rate of reaction when
A B 1.0 mol/L - Concentration rate data for reaction A B ? C
D - Initial Concentration mol/L
- A B Rate
- 0.40 0.30 1.0e-4
- 0.80 0.30 4.0e-4
- 0.80 0.60 1.6e-3
25Your Turn!
- For the following data, determine the order of
NO2 in the reaction at 25 2 NO2(g) F2(g)?
2 NO2F(g)
Exp. NO2 F2 Rate NO2 disappearance (M/s)
1 0.001 0.005 2 (10-4)
2 0.002 0.005 4 (10-4)
3 0.006 0.002 4.8 (10-4)
- 0
- 1
- 2
- 3
- not enough information given
26Your Turn!
- Chlorine Dioxide, ClO2, is a reddish-yellow gas
that is soluble in water. In basic solution it
gives ClO3- and ClO2- ions. 2ClO2(aq)
2OH-(aq)? 6ClO3- (aq) ClO2- (aq) H2O(l) - The rate law is RatekClO22OH-, what is the
value of the rate constant given that when
ClO20.060M, OH- 0.030, the reaction rate
is 0.0248 M/s - 0.02 M-1 /s
- 0.02 M/s
- 0.02 s-
- None of these
2.3(102) M-2 s-1
27Zero-Order Reactions
- Ratek A0 k
- Plot of reactant vs. time will be linear
- The equation of the line will be
AA0-kt - A amount remaining after elapsed time, t.
- Aooriginal amount
- Diffusion controlled - usually are fast reactions
in viscous media - Rate is independent of concentrations of
reactants, but the reaction still requires
reactants
28Learning Check
- The rate law for the reaction of A?B is zero
order in A and has a rate constant of 0.02 M/s.
If the reaction starts with 1.50 M A, how much is
present 15 seconds after the reaction begins?
29Learning Check
- The rate law for the reaction of A?2B is zero
order in A and has a rate constant of 0.12 M/s.
If the reaction starts with 1.50 M A, after what
time will the concentration of A be 0.90M?
30Your Turn!
- Which of the following is the correct set of
units for the rate constant for a zero order
reaction? - M/s
- M-1/s
- M-2/s
- Cant tell from the given data
31First Order Reactions
- RatekA1
- Typically these reactions are decomposition type,
or radioactive decay - If the rate law is specified as dA/dtkA or
Integrating the equation gives us
32Learning Check
- The radioactive decay of a new atom occurs so
that after 21 days, the original amount is
reduced to 33. What is the rate constant for
the reaction in s-?
k 6.1110-7 s-1
33- Consider the first order decomposition reaction
- N2O5 ? N2O4 O2
- For which rate kN2O5. At 45?C the rate
constant is 6.22e-4 s-1. - If the initial concentration of dinitrogen
pentoxide is 0.100 M, how long will it take for
the concentration to drop to 0.0100 M?
34i-Clicker Classroom Participation
35i-Clicker Classroom Participation
36- Consider the first order decomposition reaction
- N2O5 ? N2O4 O2 for which rate kN2O5. At
45?C the rate constant is 6.22e-4 s-1. - If at 100?C the concentration falls from 0.800 to
0.100 M in 45.0 minutes, what is the rate
constant at 100?C?
37Fig. 13.12
38Derive the equation for half-life
39Learning Check
- The half-life of I-132 is 2.295h. What
percentage remains after 24 hours?
0.302 h-1 k
A .0711
40Your Turn!
- What is the half-life of a new element,
Barclium-146, if, after 2.2 h, 1.3 remains? - 2.0 h
- 0.35 h
- 0.51 h
- None of these
41i-Clicker Classroom Participation
42- Hydrogen peroxide decomposes in dilute sodium
hydroxide at 20 ºC in a first-order reaction
where the rate constant is 1.06e-3 min-1 - 2 H2O2 (aq) ? 2 H2O (l ) O2 (g)
- If the initial concentration of H2O2 is 0.202
mol/L what is the concentration after exactly 100
minutes? - What fraction of the original hydrogen peroxide
is remaining after 100 minutes? - What is the rate of reaction after 100 minutes?
- What is the half-life of this reaction at 20 ºC
43Second Order Reaction
- Are of several types RatekA2,
RatekA1B1 and RatekA2B0, etc
44Learning Check
- The rate constant for the second order reaction
2A?B is 5.310-5 M-1s-1. What is the original
amount present if, after 2 hours, there is 0.35M
available?
A00.40 M
45Second Order Half-Life
- Depends on the amount present at the start of the
time period - What is the relationship between k and t1/2 for
this reaction type?
46Learning Check
- The rate constant for a second order reaction is
4.510-4 M-1s-1. What is the half-life if we
start with a reactant concentration of 5.0 M?
t1/2 440 s 7.4 min
47i-Clicker Classroom Participation
48- The gas-phase decomposition of hydrogen iodide is
second order with a rate constant of 30. L/mol
min at 443 ºC. How much time does it take for
the concentration to fall from 0.010 mol/L to
0.0050 mol/L at this temperature? - What will be the HI concentration after just 12
minutes? - HI (g) ? 1/2 H2 (g) 1/2 I2 (g)
49- a) If k0.020 L/mol s for the second order
reaction NOCl ? NO Cl2 what will the
concentration be after 30 minutes if the initial
concentration is 0.0500 M - b) How long will it take for the concentration of
NOCl to fall from 0.0500 to 0.001 M at the same
temperature?
50Your Turn!
- Which order has a half-life that is independent
of the original amount? - Zero
- First
- Second
- None depend on the original quantity
51Your Turn!
- A 0.10M solution of moxium, a new antidepressant
is bottled. The drug decays to fortium, a toxic
chemical as a second order process. The rate
constant is 2.310-3 M-1h-1. What quantity of
moxium is present after 90. days? - 0.098M
- 5.5(10-5)M
- 0.067M
- None of the above
52- Graphical methods can be used to determine the
first-order rate constant, note
53- A plot of lnAt versus t gives a straight line
with a slope of -k
The decomposition of N2O5. (a) A graph of
concentration versus time for the decomposition
at 45oC. (b) A straight line is obtained from a
logarithm versus time plot. The slope is negative
the rate constant.
54Learning Check
- Determine the order of the reactant graphically
0 order plot 1st order plot 2nd order plot
55- Graphical methods can also be applied to
second-order reactions - A plot of 1/Bt versus t gives a straight line
with a slope of k
Second-order kinetics. A plot of 1/HI versus
time (using the data in Table 15.1).
56Collision Theory Of Reactions
- For a reaction to occur, three conditions must be
met - Reactant particles must collide
- Collision energy must be enough to break
bonds/initiate - Particles must be oriented so that the new bonds
can form
57Potential Energy Diagrams
- Demonstrate the energy needs and products as a
reaction proceeds - Tell us whether a reaction is exothermic or
endothermic - Tell us if a reaction occurs in one step or
several steps - Show us which step is the slowest
58Potential Energy Diagrams
What about the reverse reaction?
59i-Clicker Classroom Participation
Where does Ea come from?
60 61Features of PE Diagrams
Connect to the graph Activation Energies
Activated Complexes
Product Energy
P.E.
Enthalpy of reaction
Reactant Energy
Reaction Coordinate (progress of reaction)
62Exothermic reaction of NO O3
63Your Turn!
- Examine the Potential energy diagram. Which is
the Slowest (Rate Determining) Step? - Step 1
- Step 2
- Cant tell from the given information
64Fig. 13.13
65Fig. 13.16
66Temperature Effects
- Changes in temperature affect the rate constant,
k, according to the Arrhenius equation - p is the steric factor
- Z is the frequency of collisions.
- Ea is the activation energy
- R is the Ideal Gas Constant (8.314 J/mol K)
- T is the temperature (K)
- A is the frequency factor
67Working With The Arrhenius Equation
- Linear Form To determine the Ea and A value
Ratio form Can be used when A isnt known.
68Learning Check
- Given that k at 25C is 4.6110-1 M/s and that at
50C it is 4.6410-1 M/s, what is the activation
energy for the reaction?
208 J/molEa
69Working With The Arrhenius Equation
- Given the following data, predict k at 75C using
the graphical approach
k (M/s) T C
0.000886 25
0.000894 50
0.000918 150
0.000908 100
graph
ln (k) -0.0278/T-0.1917
k8.2510-1
70- The reaction CH3I HI ? CH4 I2 was observed to
have rate constants - k 3.2 L/(mol s) at 350?C and
- k23 L/(mol s) at 400?C.
- What is the value of Eafor this reaction
expressed in kJ/mol? - What would the rate constant be at 300?C?
71Your Turn!
- In the reaction 2N2O5(g) ?4 NO2(g) O2(g) the
following temperature and rate constant
information is obtained. What is the activation
energy of the reaction? - 99.7 kJ
- -99.7 kJ
- 1004 kJ
- -1004 kJ
- none of these
T (K) k (s-1)
338 328 318 4.87(10-3) 1.50(10-3) 4.98(10-4)
72- The first order reaction 2NO2 ? 2 NO O2 has an
activation energy of 111 kJ/mol. At 400?C, k
7.8 L/mol s - 1. What is the value of k at 430?C?
- 2. If the NO2 is 1.5e-2M, what is the rate of
reaction at 430 ?C?
73i-Clicker Classroom Participation
74Reaction Mechanisms
- The rate determining step is the slowest step of
the reaction that accounts for most of the
reaction time - Elementary steps sum to the overall reaction
- Catalysts interact with the reactant, they will
appear in the mechanism - Intermediates are temporary products, formed in
an early step and consumed in a later step
75Learning Check
- The reaction mechanism that has been proposed for
the decomposition of H2O2 is - H2O2 I- ? H2O IO- (slow)
- H2O2 IO- ? H2O O2 I- (fast)
- Which is the rate determining step?
- Are there any intermediates?
76Learning Check
- The reaction mechanism that has been proposed for
the decomposition of H2O2 is - H2O2 I- ? H2O IO- (slow)
- H2O2 IO- ? H2O O2 I- (fast)
- What is the expected rate law?
77Learning Check
- The reaction A 3 B ? D F was
studied and the following mechanism was finally
determined - A B ? C (fast)
- C B ? D E (slow)
- E B ? F (very fast)
- What is the expected rate law?
78Catalysts
- Speed a reaction, but are not consumed by the
reaction - May appear in the rate law
- Lower the Ea for the reaction.
- May be heterogeneous or homogeneous
79CATALYSIS
- Catalysis and activation energy
-
MnO2 catalyzes decomposition of H2O2 2 H2O2 ---gt
2 H2O O2
Uncatalyzed reaction
Catalyzed reaction
80Iodine-Catalyzed Isomerization of cis-2-Butene
Figure 15.19
81Catalytic Actions
- May serve to weaken bonds through induction
- May serve to change polarity through
amphipathic/surfactant effects - May reduce geometric orientation effects
- Heterogeneous catalyst reactant and product
exist in different states. - Homogeneous catalyst reactants and catalyst
exist in the same physical state
82Heterogeneous catalysts
83i-Clicker Classroom Participation
84i-Clicker Classroom Participation
85- For the reaction
- C2H6(g) 2CH3(g) rate kC2H6
- If k 5.50 E4 s1 and C2H6initial 0.0200 M,
calculate - the rate of reaction after 30 min.
86Solutions slides- graphs to accompany previous
slides
87Reactant vs. time
return to problem
88Ln Reactant vs time
return to problem
89Inverse Reactant vs time
return to problem
90return to the problem