Chemical Kinetics Chapter 13 - PowerPoint PPT Presentation

1 / 83
About This Presentation
Title:

Chemical Kinetics Chapter 13

Description:

Title: BS5-13 Subject: Kinetics: The Study of Reaction Rates Author: Nancy J Mulllins Last modified by: David Myton Created Date: 1/7/2005 9:26:22 PM – PowerPoint PPT presentation

Number of Views:116
Avg rating:3.0/5.0
Slides: 84
Provided by: NancyJM3
Category:

less

Transcript and Presenter's Notes

Title: Chemical Kinetics Chapter 13


1
Chemical KineticsChapter 13
An automotive catalytic muffler.
2
  • Rate of reaction -

3
13.1
4
Factors Affecting Reaction Rate
  • Chemical nature
  • Bond strengths
  • General reactivity
  • Ability to establish contact with one another
  • Physical state
  • Surface area for liquids, solids, and
    heterogeneous mixtures
  • Amount of Mixing
  • Particle shape/size

5
Factors (Cont.)
  • Concentration of reactants
  • Molarity for solutions
  • Pressure effects for gases
  • Volume effects for gases
  • Temperature
  • Catalysts

                                                                                                                        
6
Your Turn!
  • Which of the following would speed a reaction?
  • stirring it
  • dissolving the reactants in water, if ionic
  • adding a catalyst
  • grinding any solids
  • all of these

7
Measuring Rates
  • instantaneous rate (text uses this unless
    specified)
  • average rate
  • initial rate

8
DBr2 a DAbsorption
13.1
9
Fig. 13.5
10
instantaneous rate rate for specific instance
in time
13.1
11
(No Transcript)
12
Fig. 13.6
13
rate a Br2
rate k Br2 rate law
rate constant
3.50 x 10-3 s-1
13.1
14
Your Turn!
  • What is the average rate of B between 10 and 40
    s?
  • -0.006 M/s
  • 0.006 M/s
  • -0.002 M/s
  • 0.002 M/s
  • cant tell form the information

15
Rates And Stoichiometry
  • Rates based on each substance are related to one
    another by the stoichiometric coefficients of the
    reaction
  • Examine the reaction aA bB ?dD
  • the stoichiometric relationship between
    substances A and B is given as a mole A b mole
    B
  • RateA(b/a)RateB

16
Consider the combustion of propane
  • Compared to the rate with respect to propane
  • Rate with respect to oxygen is five times faster
  • Rate with respect to carbon dioxide is three
    times faster
  • Rate with respect to water is four times faster
  • Since the rates are all related any may be
    monitored to determine the reaction rate

17
Learning Check
  • In the reaction 2A 3B ?5D We measured the rate
    of disappearance of substance A to be
    3.510-5M/s. What is the rate of appearance of
    D?
  • In the reaction 3A 2B ?C, we measured the rate
    of B. How does the rate of C relate?

8.7510-5 M/s
RC1/2 RB
18
  • 3A 2B C ? Products
  • Rate k A2BC3
  • The exponents in the rate law are generally
    unrelated to the chemical equations coefficients
  • Never simply assume the exponents and
    coefficients are the same
  • The exponents must be determined from the results
    of experiments
  • The exponent in a rate law is called the order of
    reaction with respect to the corresponding
    reactant

19
Your Turn!
  • In the reaction 2CO(g) O2(g) ?2CO2(g), the rate
    of the reaction of CO is measured to be 2.0 M/s.
    What would be the rate of the reaction of O2?
  • the same
  • twice as great
  • half as large
  • you cannot tell from the given information

20
Learning Check
  • The rate law for the reaction 2A B?3C is
  • rate 0.045M-1s-1 AB
  • if the concentration of A is 0.2M and that of B
    is 0.3M, what will be the reaction rate?

rate0.045 M-1 s-1 0.20.3
rate0.0027 M/s
21
  • Table 13.2 from Page 529

Determine the rate law
22
  • The initial rate for the reaction of nitrogen
    monoxide and oxygen was measured at 25 ºC for
    various concentrations shown in the table below.
    Determine the rate equation for the reaction, the
    value of the rate constant with proper units, and
    the initial rate if NOO20.010 M
  • Exp NO O2 initial rate mol/L mol/L
    mol/Ls
  • 1 0.020 0.010 0.028
  • 2 0.020 0.020 0.057
  • 3 0.020 0.040 0.114
  • 4 0.040 0.020 0.227
  • 5 0.010 0.020 0.014

23
  • Concentration rate data for reaction A B C ?
    Products Initial Conc.mol/L Initial Rate
    mol/Ls A B C Rate 0.10 0.10
    0.10 0.20 0.20 0.10
    0.10 0.40 0.30 0.10 0.30 0.60 0.30 0.2
    0 0.30 2.40 0.30 0.30
    0.60 5.40 Determine the rate law for this
    reactionDetermine the rate constant for the
    reactionDetermine the overall reaction order for
    the reactionDetermine the rate of reaction when
    AB0.50 mol/L

24
  • A certain reaction follows the equation 2A B ?
    3C D.
  • Experimental results yielded the following data.
    Determine the rate law, reaction order for A and
    B, the overall reaction order, the value for the
    rate constant k, and the rate of reaction when
    A B 1.0 mol/L
  • Concentration rate data for reaction A B ? C
    D
  • Initial Concentration mol/L
  • A B Rate
  • 0.40 0.30 1.0e-4
  • 0.80 0.30 4.0e-4
  • 0.80 0.60 1.6e-3

25
Your Turn!
  • For the following data, determine the order of
    NO2 in the reaction at 25 2 NO2(g) F2(g)?
    2 NO2F(g)

Exp. NO2 F2 Rate NO2 disappearance (M/s)
1 0.001 0.005 2 (10-4)
2 0.002 0.005 4 (10-4)
3 0.006 0.002 4.8 (10-4)
  1. 0
  2. 1
  3. 2
  4. 3
  5. not enough information given

26
Your Turn!
  • Chlorine Dioxide, ClO2, is a reddish-yellow gas
    that is soluble in water. In basic solution it
    gives ClO3- and ClO2- ions. 2ClO2(aq)
    2OH-(aq)? 6ClO3- (aq) ClO2- (aq) H2O(l)
  • The rate law is RatekClO22OH-, what is the
    value of the rate constant given that when
    ClO20.060M, OH- 0.030, the reaction rate
    is 0.0248 M/s
  • 0.02 M-1 /s
  • 0.02 M/s
  • 0.02 s-
  • None of these

2.3(102) M-2 s-1
27
Zero-Order Reactions
  • Ratek A0 k
  • Plot of reactant vs. time will be linear
  • The equation of the line will be
    AA0-kt
  • A amount remaining after elapsed time, t.
  • Aooriginal amount
  • Diffusion controlled - usually are fast reactions
    in viscous media
  • Rate is independent of concentrations of
    reactants, but the reaction still requires
    reactants

28
Learning Check
  • The rate law for the reaction of A?B is zero
    order in A and has a rate constant of 0.02 M/s.
    If the reaction starts with 1.50 M A, how much is
    present 15 seconds after the reaction begins?
  • AA0-kt
  • A1.2M

29
Learning Check
  • The rate law for the reaction of A?2B is zero
    order in A and has a rate constant of 0.12 M/s.
    If the reaction starts with 1.50 M A, after what
    time will the concentration of A be 0.90M?
  • AA0-kt
  • t5 s

30
Your Turn!
  • Which of the following is the correct set of
    units for the rate constant for a zero order
    reaction?
  • M/s
  • M-1/s
  • M-2/s
  • Cant tell from the given data

31
First Order Reactions
  • RatekA1
  • Typically these reactions are decomposition type,
    or radioactive decay
  • If the rate law is specified as dA/dtkA or
    Integrating the equation gives us

32
Learning Check
  • The radioactive decay of a new atom occurs so
    that after 21 days, the original amount is
    reduced to 33. What is the rate constant for
    the reaction in s-?

k 6.1110-7 s-1
33
  • Consider the first order decomposition reaction
  • N2O5 ? N2O4 O2
  • For which rate kN2O5. At 45?C the rate
    constant is 6.22e-4 s-1.
  • If the initial concentration of dinitrogen
    pentoxide is 0.100 M, how long will it take for
    the concentration to drop to 0.0100 M?

34
i-Clicker Classroom Participation
35
i-Clicker Classroom Participation
36
  • Consider the first order decomposition reaction
  • N2O5 ? N2O4 O2 for which rate kN2O5. At
    45?C the rate constant is 6.22e-4 s-1.
  • If at 100?C the concentration falls from 0.800 to
    0.100 M in 45.0 minutes, what is the rate
    constant at 100?C?

37
Fig. 13.12
38
Derive the equation for half-life
39
Learning Check
  • The half-life of I-132 is 2.295h. What
    percentage remains after 24 hours?

0.302 h-1 k
A .0711
40
Your Turn!
  • What is the half-life of a new element,
    Barclium-146, if, after 2.2 h, 1.3 remains?
  • 2.0 h
  • 0.35 h
  • 0.51 h
  • None of these

41
i-Clicker Classroom Participation
42
  • Hydrogen peroxide decomposes in dilute sodium
    hydroxide at 20 ºC in a first-order reaction
    where the rate constant is 1.06e-3 min-1
  • 2 H2O2 (aq) ? 2 H2O (l ) O2 (g)
  • If the initial concentration of H2O2 is 0.202
    mol/L what is the concentration after exactly 100
    minutes?
  • What fraction of the original hydrogen peroxide
    is remaining after 100 minutes?
  • What is the rate of reaction after 100 minutes?
  • What is the half-life of this reaction at 20 ºC

43
Second Order Reaction
  • Are of several types RatekA2,
    RatekA1B1 and RatekA2B0, etc

44
Learning Check
  • The rate constant for the second order reaction
    2A?B is 5.310-5 M-1s-1. What is the original
    amount present if, after 2 hours, there is 0.35M
    available?

A00.40 M
45
Second Order Half-Life
  • Depends on the amount present at the start of the
    time period
  • What is the relationship between k and t1/2 for
    this reaction type?

46
Learning Check
  • The rate constant for a second order reaction is
    4.510-4 M-1s-1. What is the half-life if we
    start with a reactant concentration of 5.0 M?

t1/2 440 s 7.4 min
47
i-Clicker Classroom Participation
48
  • The gas-phase decomposition of hydrogen iodide is
    second order with a rate constant of 30. L/mol
    min at 443 ºC. How much time does it take for
    the concentration to fall from 0.010 mol/L to
    0.0050 mol/L at this temperature?
  • What will be the HI concentration after just 12
    minutes?
  • HI (g) ? 1/2 H2 (g) 1/2 I2 (g)

49
  • a) If k0.020 L/mol s for the second order
    reaction NOCl ? NO Cl2 what will the
    concentration be after 30 minutes if the initial
    concentration is 0.0500 M
  • b) How long will it take for the concentration of
    NOCl to fall from 0.0500 to 0.001 M at the same
    temperature?

50
Your Turn!
  • Which order has a half-life that is independent
    of the original amount?
  • Zero
  • First
  • Second
  • None depend on the original quantity

51
Your Turn!
  • A 0.10M solution of moxium, a new antidepressant
    is bottled. The drug decays to fortium, a toxic
    chemical as a second order process. The rate
    constant is 2.310-3 M-1h-1. What quantity of
    moxium is present after 90. days?
  • 0.098M
  • 5.5(10-5)M
  • 0.067M
  • None of the above

52
  • Graphical methods can be used to determine the
    first-order rate constant, note

53
  • A plot of lnAt versus t gives a straight line
    with a slope of -k

The decomposition of N2O5. (a) A graph of
concentration versus time for the decomposition
at 45oC. (b) A straight line is obtained from a
logarithm versus time plot. The slope is negative
the rate constant.
54
Learning Check
  • Determine the order of the reactant graphically

0 order plot 1st order plot 2nd order plot
55
  • Graphical methods can also be applied to
    second-order reactions
  • A plot of 1/Bt versus t gives a straight line
    with a slope of k

Second-order kinetics. A plot of 1/HI versus
time (using the data in Table 15.1).
56
Collision Theory Of Reactions
  • For a reaction to occur, three conditions must be
    met
  • Reactant particles must collide
  • Collision energy must be enough to break
    bonds/initiate
  • Particles must be oriented so that the new bonds
    can form

57
Potential Energy Diagrams
  • Demonstrate the energy needs and products as a
    reaction proceeds
  • Tell us whether a reaction is exothermic or
    endothermic
  • Tell us if a reaction occurs in one step or
    several steps
  • Show us which step is the slowest

58
Potential Energy Diagrams
                                                                                                                                                                                                                                                                                                
What about the reverse reaction?
59
i-Clicker Classroom Participation
Where does Ea come from?
60

61
Features of PE Diagrams
Connect to the graph Activation Energies
Activated Complexes
Product Energy
P.E.
Enthalpy of reaction
Reactant Energy
Reaction Coordinate (progress of reaction)
62
Exothermic reaction of NO O3
63
Your Turn!
  • Examine the Potential energy diagram. Which is
    the Slowest (Rate Determining) Step?
  • Step 1
  • Step 2
  • Cant tell from the given information

64
Fig. 13.13
65
Fig. 13.16
66
Temperature Effects
  • Changes in temperature affect the rate constant,
    k, according to the Arrhenius equation
  • p is the steric factor
  • Z is the frequency of collisions.
  • Ea is the activation energy
  • R is the Ideal Gas Constant (8.314 J/mol K)
  • T is the temperature (K)
  • A is the frequency factor

67
Working With The Arrhenius Equation
  • Linear Form To determine the Ea and A value

Ratio form Can be used when A isnt known.
68
Learning Check
  • Given that k at 25C is 4.6110-1 M/s and that at
    50C it is 4.6410-1 M/s, what is the activation
    energy for the reaction?

208 J/molEa
69
Working With The Arrhenius Equation
  • Given the following data, predict k at 75C using
    the graphical approach

k (M/s) T C
0.000886 25
0.000894 50
0.000918 150
0.000908 100
graph
ln (k) -0.0278/T-0.1917
k8.2510-1
70
  • The reaction CH3I HI ? CH4 I2 was observed to
    have rate constants
  • k 3.2 L/(mol s) at 350?C and
  • k23 L/(mol s) at 400?C.
  • What is the value of Eafor this reaction
    expressed in kJ/mol?
  • What would the rate constant be at 300?C?

71
Your Turn!
  • In the reaction 2N2O5(g) ?4 NO2(g) O2(g) the
    following temperature and rate constant
    information is obtained. What is the activation
    energy of the reaction?
  • 99.7 kJ
  • -99.7 kJ
  • 1004 kJ
  • -1004 kJ
  • none of these

T (K) k (s-1)
338 328 318 4.87(10-3) 1.50(10-3) 4.98(10-4)
72
  • The first order reaction 2NO2 ? 2 NO O2 has an
    activation energy of 111 kJ/mol. At 400?C, k
    7.8 L/mol s
  • 1. What is the value of k at 430?C?
  • 2. If the NO2 is 1.5e-2M, what is the rate of
    reaction at 430 ?C?

73
i-Clicker Classroom Participation
74
Reaction Mechanisms
  • The rate determining step is the slowest step of
    the reaction that accounts for most of the
    reaction time
  • Elementary steps sum to the overall reaction
  • Catalysts interact with the reactant, they will
    appear in the mechanism
  • Intermediates are temporary products, formed in
    an early step and consumed in a later step

75
Learning Check
  • The reaction mechanism that has been proposed for
    the decomposition of H2O2 is
  • H2O2 I- ? H2O IO- (slow)
  • H2O2 IO- ? H2O O2 I- (fast)
  • Which is the rate determining step?
  • Are there any intermediates?

76
Learning Check
  • The reaction mechanism that has been proposed for
    the decomposition of H2O2 is
  • H2O2 I- ? H2O IO- (slow)
  • H2O2 IO- ? H2O O2 I- (fast)
  • What is the expected rate law?

77
Learning Check
  • The reaction A 3 B ? D F was
    studied and the following mechanism was finally
    determined
  • A B ? C (fast)
  • C B ? D E (slow)
  • E B ? F (very fast)
  • What is the expected rate law?

78
Catalysts
  • Speed a reaction, but are not consumed by the
    reaction
  • May appear in the rate law
  • Lower the Ea for the reaction.
  • May be heterogeneous or homogeneous

79
CATALYSIS
  • Catalysis and activation energy

MnO2 catalyzes decomposition of H2O2 2 H2O2 ---gt
2 H2O O2
Uncatalyzed reaction
Catalyzed reaction
80
Iodine-Catalyzed Isomerization of cis-2-Butene
Figure 15.19
81
Catalytic Actions
  • May serve to weaken bonds through induction
  • May serve to change polarity through
    amphipathic/surfactant effects
  • May reduce geometric orientation effects
  • Heterogeneous catalyst reactant and product
    exist in different states.
  • Homogeneous catalyst reactants and catalyst
    exist in the same physical state

82
Heterogeneous catalysts
83
i-Clicker Classroom Participation
84
i-Clicker Classroom Participation
85
  • For the reaction
  • C2H6(g) 2CH3(g) rate kC2H6
  • If k 5.50 E4 s1 and C2H6initial 0.0200 M,
    calculate
  • the rate of reaction after 30 min.

86
Solutions slides- graphs to accompany previous
slides
  • Ch 13 Brady Senese, 5th

87
Reactant vs. time
return to problem
88
Ln Reactant vs time
return to problem
89
Inverse Reactant vs time
return to problem
90
return to the problem
Write a Comment
User Comments (0)
About PowerShow.com