Title: Types of Chemical Reactions
1Types of Chemical Reactions
- 6.2 Assigning oxidation numbers for individual
atoms of monatomic and polyatomic ions - 6.3 Identifying the nomenclature of ionic
compounds, binary compounds, and acids - 6.4 Classifying chemical reactions as
composition, decomposition, single replacement,
or double replacement - AHSGE Reading 4.2 Demonstrate the ability to
preview and predict. - Other AOD C.6.1 Define stoichiometry,
reactants, and products.
2What are some types of chemical reactions?
- Synthesis
- Decompostion
- Single Replacement/Single Displacement
- Double Replacement/Double Displacement
- Combustion
- Complete combustion yields ________.
- Incomplete combustion yields __________.
3Classes of Reactions
- Precipitation reactions
- Acid-base reactions
- Oxidation-reduction reactions
- Almost all reaction types can be put into one of
these three classes.
4Precipitation Reactions
- What do you think this reaction would involve?
- AKA, double replacement/double displacement
- Example K2CrO4(aq) Ba(NO3)2(aq) ? ???
- What does (aq) mean?
- What are some other designations?
- What is the name of K2CrO4? Ba(NO3)2?
- What would the products be in a double
displacement reaction? - Would either product be a solid (precipitate)?
5Three Ways to Write the Reaction Equation
- Molecular equation shows the overall balanced
reaction (reactants and products) - Complete ionic equation shows a balanced
equation of the actual FORMS of the reactants and
products in the reaction - Net ionic equation balanced equation showing
ONLY the ions involved in the reaction. - Ions that remain in solution (as ions) are not
shown. (spectator ions)
6K2CrO4(aq) Ba(NO3)2(aq) ? ???
- Molecular equation
K2CrO4(aq) Ba(NO3)2(aq) ? 2 KNO3 (aq)
BaCrO4(s) - Complete ionic equation
2K(aq) CrO42-(aq) Ba2(aq) 2NO3-(aq) ?
BaCrO4(s) 2K(aq) 2NO3-(aq) - Net ionic equation
- What is the only CHANGE in this rxn?
- CrO42-(aq) Ba2(aq) ? BaCrO4(s)
7Examples
- See Sample Exercise 4.9, p.155.
- P. 182 (29a)
- BaCl2(aq) Na2SO4(aq) ? BaSO4(s) 2NaCl(aq)
- Net ionic equation
Ba2(aq) SO42-(aq) ? BaSO4(s) - What happened to the Cl2 and the Na2 part of
the molecular equation? - What would the complete ionic equation look like?
8Assignment
- P.182 30, 34, 36
- Special note on 34 You are MAKING UP a chemical
reaction that will produce the specified solid. - It should be a precipitation (double
displacement) reaction.
9Acid-Base Reactions
- Acid-Base definitions
- Arrhenius
- Acid a substance that produces H when
dissolved in water - Base - a substance that produces OH- when
dissolved in water - Bronsted-Lowry
- Acid a proton donor
- Base a proton acceptor
10Predicting Acid-Base Reactions
- What element do acid chemical formulas start
with? - Most bases contain hydroxide ions.
- Using Arrhenius definitions, H OH- ? ??
- So Acid-Base reactions yield _________.
11Example NaOH HCl
- What is the acid? Base?
- Molecular equation NaOH HCl ? NaCl H2O
(Whats missing from this equation???) - Complete ionic equation Na(aq) OH-(aq)
H(aq) Cl-(aq) ? Na(aq) Cl-(aq) H2O(??) - Net ionic equation ????
- Assignment P.183 (46, 48)
12Oxidation-Reduction (Redox) Reactions
- Def reactions in which one or more electrons are
transferred - Example 2Na(s) Cl2(g) ? 2NaCl(s)
- What is the charge on Na(s)?
- On Cl in Cl2?
- On Na in Nacl?
- On Cl in NaCl?
13Redox Reactions, continued
- Includes most reactions involving energy
production (i.e., photosynthesis, combustion). - Example CH4(g) 2O2(g) ? CO2(g) 2H2O(g)
energy - How do we calculate the charges on elements in
covalent molecules to determine a transfer of
electrons?
14Oxidation States (aka, Oxidation Numbers)
- Def the imaginary charges the atoms in a
covalent molecule would have if the shared
electrons were assigned to the atom with the most
electronegativity - Rules for Assigning Oxidation States (Table 4.2,
p.167)
15Rules for Assigning Oxidation States
- Give the oxidation states for all the atoms in
the following molecules - O2
- CH4
- CO2
- H2O
- SF6
- NO3-
- Fe3O4
16CH4(g) 2O2(g) ?
CO2(g) 2H2O(g) energy
- For which atoms did the oxidation state change?
- C went from -4 to 4.
- This change shows that each C atom LOST 8
electrons. - O went from 0 to -2.
- This shows that each O atom ______ ____ electrons.
17Oxidation and Reduction
- Oxidation an INCREASE in oxidation state (LOSES
e-s) - Reduction a DECREASE in oxidation state (GAINS
e-s) - If an atom is oxidized, it is called the reducing
agent (electron donor). - If an atom is reduced, it is called the _______
agent (electron acceptor). - OIL RIG Oxidation Involves Loss Reduction
Involves Gain
18CH4(g) 2O2(g) ?
CO2(g) 2H2O(g) energy
- Which element is oxidized in this equation?
- Which element is reduced?
- Which compound is the oxidizing agent?
- Which compound is the reducing agent?
- Example 2Al(s) 3I2(s) ? 2AlI3(s)
- Assignment Pp.183-184 (58, 60, 62)
19Balancing Redox Reactions
- If it does not balance easily using the normal
rules, use the half-reaction method. - Uses two separate reaction equations
- Oxidation half-reaction balance the substance
being oxidized - Reduction half-reaction balance the substance
being reduced - Example Ce4(aq) Sn2(aq) ? Ce3(aq)
Sn4(aq) - Sn2(aq) ? Sn4(aq) ---- __________ half-reaction
- Ce4(aq) ? Ce3(aq) --- __________ half-reaction
- But how would you balance this????
20Actual Balancing Steps
- Varies by whether the reaction occurs in acidic
or basic solutions! - Acidic solutions (solns) follow steps on p.172
- Basic solns follow acidic steps, THEN add steps
2-4 on p.177.
21Steps in Acidic Solutions
- Write the two half-reactions.
- For each half-reaction!
- Balance all elements EXCEPT H and O.
- Balance O by adding H2O.
- Balance H by adding H.
- Balance any charge by adding e-s.
- Multiple either of the half-reactions by an
integer to have equal number of e-s in both
half-reactions, if needed. (You want the e-s to
cancel in the next step.) - Add the half-reactions, cancelling any identical
species. - Check that both elements AND charges are balanced
in final equation.
22Example
Zn(s) NO3-(aq) ? Zn2 NO2(g)
- Half-reactions
- Oxidation Zn(s) ? Zn2(aq)
- Reduction NO3-(aq) ? NO2(g)
- Balancing steps
- Already done ?
- NO3-(aq) ? NO2(g) H2O(l)
- 2H(aq) NO3-(aq) ? NO2(g) H2O(l)
- e- 2H(aq) NO3-(aq) ? NO2(g) H2O(l) AND
Zn(s) ? Zn2(aq) 2e-
23Example (continued..)
Zn(s) NO3-(aq) ? Zn2 NO2(g)
- Which half-reaction do we need to multiply, and
by what integer? - 2 e- 2H(aq) NO3-(aq) ? NO2(g) H2O(l)
2e- 4H(aq) 2NO3-(aq) ? 2NO2(g) 2H2O(l) - Zn(s) ? Zn2(aq) 2e-
- Add the two equations together
4H(aq) 2NO3-(aq) Zn(s) ? 2NO2(g) 2H2O(l)
Zn2(aq) - Check the balance of elements and charges!
24Try This One
MnO4-(aq) Zn(s) ? Mn2(aq) Zn2(aq)
- Write the half-reactions.
- Balancing steps
- Mn and Zn
- Add __________ to balance O.
- Add __________ to balance H.
- Add __________ to balance any charges.
- Multiply to get equal number of ____ in both
half-reactions. - Add them together.
- Check the elements and charges!
25Steps in Basic Solutions
- Start with the steps used for acidic solutions.
- Add OH- (equal to the final amount of H) to BOTH
sides of the equation. - Eliminate equal amounts of water from both sides
of the equation. - Check balance of elements and charges!
26Example (65(b))
Cl2(g) ? Cl-(aq) OCl-(aq)
- Acidic steps get you to 2H2O(l) 2Cl2(g) ?
2Cl-(aq) 2OCl-(aq) 4H(aq) - Add OH- to BOTH sides. How many???
4OH-(aq) 2H2O(l) 2Cl2(g) ? 2Cl-(aq)
2OCl-(aq) (4H(aq) 4OH-) - 4OH-(aq) 2Cl2(g) ? 2Cl-(aq) 2OCl-(aq)
2H2O(l) - Check balance of elements and charges!
- What is one more thing we can do to this final
equation????
27Assignment