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Algebra 1

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Title: Algebra 1


1
Algebra 1
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  • Lecture 1
  • Video Lectures and Notes
  • by
  • David V. Anderson

2
Introduction
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  • Welcome to the Stellar Schools course Algebra 1.
    As in our other courses, Stellar Schools follow a
    curriculum very similar to the one used by the
    Hillsdale Academy of Hillsdale, Michigan. In the
    case of Algebra 1, Hillsdale uses the text
  • Algebra 1 An Incremental Development, 3rd Ed.
  • John H. Saxon, Jr.
  • Saxon Publishers, Inc.
  • At Stellar Schools we assign this book as a
    secondary but required text. You are requested to
    obtain the Saxon book before continuing with this
    course.
  • The primary text for Algebra 1 is this set of
    lecture notes which is provided to you both in
    hardcopy and digital formats.
  • Our curriculum for Algebra 1 is mostly based on
    the Saxon text but also includes some additional
    items that we believe adds clarity to the
    presentation. In fact, the curriculum for this
    course (in accordance with the Stellar Schools
    format we apply to all courses) is defined as the
    universe of all possible examination questions
    and answers. All students are expected to master
    these knowledge items by demonstrating
    examination scores of 95 and above. In this text
    we specify these knowledge items in what we call
    learning concept statements or LCS.

3
About MasteringThe LCS
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  • Examinations you will take to demonstrate your
    mastery of this course will be based only on the
    collection of learning concept statements (LCS)
    presented in this course and on those from
    prerequisite mathematics courses. For an example,
    we show LCS 149 in the display below.

4
More About the LCS
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  • Mastering Algebra 1
  • There are well over two-thousand LCS in Algebra 1
    but any examination, for practical reasons, will
    only employ a small subset of questions
    addressing the subject matter. That subset will
    be determined by applying a random number
    generator to each subtopic in this course. Thus
    if and when you retake the courses examination,
    the questions will almost always be different
    than those encountered before- though they will
    be covering similar or related ground.
  • Do not be afraid. We expect you to achieve a
    mastery level of 95 before we will certify you
    as having mastered Algebra 1. You will not likely
    achieve this result the first time you attempt to
    take the course examination. But after review and
    further practice doing problems you will find
    your subsequent scores higher and higher until
    you exceed the proficiency level of 95.
  • Instructional Philosophy
  • The approach taken by Saxon math is what they
    call incremental development. New subject
    material is introduced in short chapters that
    are called lessons in the Saxon book. This
    approach also puts emphasis on continual review
    of content learned in earlier years. Thus it
    should not be surprising to find this Algebra 1
    book begins with a review of fractions.
  • Structure of Lecture Notes
  • These notes are built around the Learning
    Concept Statements (LCS). We make this quite
    explicit by directly quoting each LCS as we begin
    its description. The LCS are currently stored in
    a database and we simply paste the relevant row
    of the data array into the text of these notes to
    provide the precise LCS text.

5
Segment 1
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  • The first nine lessons from Saxons Algebra 1
    comprise Segment One. We chose this length for
    purposes of demonstrating the capabilities of the
    Stellar Schools instructional model. It has no
    mathematical or pedagogical relevance.
  • Lecture 1 Combining Fractions and Combining Line
    Segments
  • Adding and Subtracting Fractions

We begin by reviewing the mechanics of adding and
subtracting fractions. Before either of these
operations can be completed it is necessary to
put all of the terms to be combined to have the
same denominators. For any pair of terms we need
to find a common denominator. Since multiplying
the numerator and denominator of any fraction by
the same number does not alter the value of the
fraction we can then represent the sum n/k
m/l as ln/lk km/kl.
6
Finding A Common Denominator
In the step taken here, the first term is
multiplied by 1 l/l and the second term is
multiplied by 1 k/k. This produces the common
denominator lkkl. We also notice that the
numerators have now changed to ln and km.
  • So, for example, lets consider adding two
    fractions as follows
  • 8/9 3/4 ?
  • We multiply the terms by 1 4/4 and 1 9/9
    respectively to get
  • (4/4)(8/9) (9/9)(3/4) (48)/(49)
    (93)/(94) 32/36 27/36
  • Here we have carried out the indicated
    multiplications of numerator factors and of
    denominator factors. We postpone, for the minute,
    carrying out the indicated addition because that
    is the subject of the next LCS.

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7
Adding and Subtracting FractionsIf there are
more than two terms in the expression it may be
necessary to find new common denominators that
the 3rd, 4th, and other terms will share with the
first two terms.
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  • Another point is that this denominator, lk, may
    not be the smallest common denominator of the two
    fractions. The smallest such denominator is
    called the lowest common denominator. In a
    subsequent lesson we shall explore this
    mathematical topic further. But for the purposes
    of adding and subtracting fractions there is no
    need to find the lowest common denominator the
    common denominator as obtained above will be
    sufficient.
  • Given the close similarity of LCS numbers 2 and
    3, we have combined their presentations. Once the
    terms of the addition or subtraction problem are
    converted to have equal denominators, it is quite
    easy to perform the addition or subtraction
    simply by adding or subtracting the numerators
    and keeping the converted denominator. This is
    shown above in the LCS numbers 2 and 3.

8
Proper and Improper Fractions
  • We can continue with the example we developed for
    LCS 1
  • 32/36 27/36 (32 27)/36 59/36
  • This is a correct answer but it is in the form of
    an improper fraction. We will soon address
    converting this to a mixed format in LCS 6,
    below.

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________________________________________________
It should be recalled that proper
fractions (fractions of value less than one) can
be combined with whole numbers to form what is
called a mixed number. Unlike the usual format in
algebra for indicating multiplication, the mixed
number places the whole number on the left next
to the fraction to its right (with no symbols
between) and no multiplication is indicated by
this placement. In fact, it is addition of the
whole number plus the fraction that is indicated
by this arrangement. You may recall that mixed
numbers can result from improper fractions. An
improper fraction indicates division of a larger
numerator by a smaller denominator. When we carry
out that division incompletely to form a whole
number quotient plus a remainder portion of the
numerator (yet to be divided) we have produced
the mixed number (whole number plus a proper
fraction).
9
Adding Mixed Numbers
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  • To add mixed numbers we keep in mind that each
    mixed number is itself two numbers a whole
    number and a fraction to which it is added. Thus
    adding mixed numbers generally means we are
    adding four numbers two are whole numbers and
    two are fractions. Since addition can proceed in
    any order we can separately add the fractions
    together and the whole numbers together to give
    us the procedure for adding mixed numbers. The
    result is then a mixed number. Sometimes the
    fraction is an improper fraction whose value
    exceeds one in which case further simplification
    is required. We cover that next.

__________________________________________________
__________________________________________________
_
A mixed number that has an improper fraction is
not really following the rule for a mixed number
in which the fractional part is preferred to be a
proper fraction- less than one. When the mixed
number resulting from the addition of mixed
numbers produces an improper fraction, we convert
the improper fraction to its own mixed notation.
In that conversion a whole number and a proper
fraction result. The whole number generated from
the improper fraction is then added to the
original whole number to produce the sought after
mixed number result.
10
More on Mixed Numbers
  • So for example, lets consider the sum of
  • 2 7/8 3 5/9 .
  • After writing these with common denominators, we
    have instead
  • 2 63/72 3 40/72
  • Performing the indicated additions gives us
  • 5 103/72
  • Then reducing the improper fraction to its own
    mixed form yields,
  • 5 1 31/72 6 31/72,
  • where we have shown the final mixed result
    containing the whole number 6 and the proper
    fraction 31/72.

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11
Subtracting Mixed Numbers
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  • Subtracting mixed numbers is very similar to the
    addition of them. Here we subtract the fractional
    parts and the whole parts separately. If the two
    numbers each had proper fractional parts, the
    resulting fractional part will also be a proper
    fraction. Here another difficulty can arise when
    the subtracted fraction is larger than the other
    fraction because it will produce a negative
    fraction. LCS 8 describes the treatment of this
    case.
  • __________________________________________________
    __________________________________
  • When the fractional difference l/k i/k is
    negative we simply borrow 1 from m.. and add
    it to l/k prior to performing the fractional
    subtraction. The whole number part of the mixed
    fractional result is then decreased by 1 to be
    m 1. The fractional difference then has the
    1 k/k added to the prior negative fraction to
    produce a positive fraction (lk-i)/k. These two
    operations have the effect of adding and
    subtracting 1 from the expression thus leaving
    its value the same. It helps to consider an
    example.

12
Example Subtracting Fractions Where BorrowingIs
Required
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  • Lets compute
  • 7 2/7 3 5/7
  • for which we notice the fractional part will
    beless than zero. So we do the
    indicatedborrowing by writing,
  • 7 - 1 -3 7/7 2/7 -5/7
  • where the terms - 1 and 7/7 indicate the
    borrowing process. Notice that -1 7/7 0,
    so introducing these terms does not change the
    value of the expression. We finish this by
    performing the indicated operations to yield
  • 3 4/7
  • This is the desired mixed number result including
    a positive and proper fractional part.

13
Mathematical Linesand Line Segments
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Their Connection to Fractions From the
consideration of combining fractions we now move
to the study of lines and line segments. In a
practical sense the two topics are related That
is the measurement of line segments is often
expressed in mixed number notation- particularly
in the English system where inches, feet and
yards measure the lengths of them. In that
context it is often necessary to add or subtract
the mixed numbers representing these lengths.
  • The idealized mathematical straight line is
    described more precisely in advanced mathematics
    but for our purposes it is useful to give its
    (rather obvious) properties. For one, lines are
    very narrow- in fact they have zero width. And
    they are very long. They are extending in both
    directions without end. They are infinite,
    meaning that there is no finite bound where they
    end. Any such line can be defined by giving two
    points through which the line passes. In our
    description here we shall say that points A and
    B determine this line.
  • __________________________________________________
    _______________________________

14
Lengths of Lines Mathematical versus Segments
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  • It follows that the length of a mathematical line
    is without limit that is to say it is infinite.
  • __________________________________________________
    _________________________________
  • A more practical type of straight line is the
    line segment. It is simply the line between any
    two points on a mathematical line. In the
    previous example the points A and B laid on a
    mathematical line. Here they can be considered
    the endpoints of a line segment.
  • __________________________________________________
    __________________________________

15
Double Arrowed Overbar Notation for Mathematical
Line
  • Symbolically, a mathematical straight line can be
    represented by labeling any two points on such a
    line with letters or other symbols. We then
    construct a symbol for a line by putting the two
    letters together and then indicate it is the
    idealized mathematical line by putting a
    two-arrowed overbar over these letters. Thus if a
    line passes through points A and B we
    indicate it by
  • We can draw a portion of such a line as

  • A.
  • B.
  • The arrows are suggestive of the idea that the
    line does not end, but continues indefinitely.
  • _____________________________________

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16
Simple Overbar Notation for Line Segment
  • The notation we use to name a line segment is
    very similar to that used for the mathematical
    line differing only in the form of the overbar.
    Thus the line segment between A and B is
    given by
  • We can draw a line segment, again from point A
    to point B, as follows

  • B .
  • A .

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17
Combining Line Segments, End-to-End
  • Again, an important property of a line segment is
    that it begins and ends. In the drawing the line
    begins at point A and ends at point B. Also
    there is the related line segment that
    begins at point B and ends at point A.
  • __________________________________________________
    __________________________________
  • Sometimes it is desired to combine two
    neighboring line segments that share an endpoint
    and that both lie on the same mathematical
    straight line. If the second line segment begins
    at point B (the one shared with segment )
    we use C to designate the endpoint of the
    second segment. The combined line segment then
    begins at A and ends at C and we name it
    . Drawn as a graph this is shown as


  • C .

  • B .
  • A .
  • __________________________________________________
    _____________

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17
18
Length of Combined Line Segment
  • A property of a straight line is that the length
    of a combined line segment is the sum of the
    component lengths. We also note that the concepts
    of distance and length are the same for straight
    lines. However, when a line is curved the length
    (measured along the line) and the distance
    (measured along a straight line connecting the
    two end-points are generally different with the
    length greater than the distance.
  • Homework LCS 1 15
  • Please complete all of the problems in Problem
    Set 1 in the Saxon text on page 3. Do numbers 1
    through 30.

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