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STOICHIOMETRY

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STOICHIOMETRY Calculations Based on Chemical Equations Iron (III) oxide reacts with carbon monoxide to form iron and carbon dioxide. Fe2O3 + CO Fe + CO2 3 2 3 How ... – PowerPoint PPT presentation

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Title: STOICHIOMETRY


1
STOICHIOMETRY
  • Calculations Based on
  • Chemical Equations

2
Iron (III) oxide reacts with carbon monoxide to
form iron and carbon dioxide.
3
2
3
  • Fe2O3 CO ? Fe CO2

How many CO molecules are required to react with
25 particles of Fe2O3?
3
Iron (III) Oxide reacts with carbon monoxide to
form iron and carbon dioxide.
3
2
3
  • Fe2O3 CO ? Fe CO2

How many iron atoms can be produced by the
reaction of 2.5 x 105 particles of Fe2O3?
4
STOICHIOMETRIC RELATIONSHIPS
  • Formulas can also represent MOLES of substances
    involved in chemical reactions.
  • Equations define reaction ratios, i.e. the molar
    ratios of reactants and products

5
What mass of CO is required to react with 146
grams of iron (III) oxide?
Fe2O3 3CO ? 2Fe 3CO2
6
What mass of iron (III) oxide is required to
produce 8.65 grams of carbon dioxide?
Fe2O3 3CO ? 2Fe 3CO2
7
Limiting Reactants (Reagents)
  • and Percent Yield

8
Calculations need to be based on the limiting
reactant.
  • Example 1 Suppose a box contains 87 bolts, 110
    washers and 99 nails. How many sets of 1 bolt, 2
    washers and 1 nail can you use to create? What
    is the limiting factor?
  • 55 sets washers limit the amount

9
Calculations need to be based on the limiting
reactant.
  • Example 2 What is the maximum mass of sulfur
    dioxide that can be produced by the reaction of
    95.6 g carbon disulfide with 100. g oxygen?
  • CS2 O2 ? CO2 SO2
  • Start by balancing the equation

10
Calculations need to be based on the limiting
reactant.
  • Example 2 What is the maximum mass of sulfur
    dioxide that can be produced by the reaction of
    95.6 g carbon disulfide with 100. g oxygen?
  • CS2 3O2 ? CO2 2SO2
  • Now solve the problem

11
  • Example 2 What is the maximum mass of sulfur
    dioxide that can be produced by the reaction of
    95.6 g carbon disulfide with 100. g oxygen?
  • CS2 3O2 ? CO2 2SO2

Which reactant is LIMITING?
12
  • Example 2 What is the mass of sulfur dioxide
    that can be produced by the reaction of 95.6 g
    carbon disulfide with 100. g oxygen?
  • CS2 3O2 ? CO2 2SO2

O2 limits the amount of SO2 that can be produced.
CS2 is in excess.
13
  • Example 2 What is the mass of sulfur dioxide
    that can be produced by the reaction of 95.6 g
    carbon disulfide with 100. g oxygen?
  • CS2 3O2 ? CO2 2SO2

134 g of SO2 can be produced in this reaction.
14
Calculations need to be based on the limiting
reactant.
  • Example 3 What mass of CO2 could be formed by
    the reaction of 8.0 g CH4 with 48 g O2?
  • CH4 O2 ? CO2 H2O
  • Start by balancing the equation

15
Calculations need to be based on the limiting
reactant.
  • Example 3 What mass of CO2 could be formed by
    the reaction of 8.0 g CH4 with 48 g O2?
  • CH4 2O2 ? CO2 2H2O
  • Now solve the problem

16
  • Example 3 What mass of CO2 could be formed by
    the reaction of 8.0 g CH4 with 48 g O2?
  • CH4 2O2 ? CO2 2H2O

Which reactant is LIMITING?
17
  • Example 3 What mass of CO2 could be formed by
    the reaction of 8.0 g CH4 with 48 g O2?
  • CH4 2O2 ? CO2 2H2O

CH4 limits the amount of CO2 that can be
produced. O2 is in excess.
18
Many chemical reactions do not go to completion
(reactants are not completely converted to
products). Percent Yield indicates what
percentage of a desired product is obtained.
19
  • So far, the masses we have calculated from
    chemical equations were based on the assumption
    that each reaction occurred 100.
  • The THEORETICAL YIELD is the yield calculated
    from the balance equation.
  • The ACTUAL YIELD is the amount actually
    obtained in an experiment.

20
  • Look back at Example 2. We found that 134 g of
    SO2 could be formed from the reactants.
  • In an experiment, you formed 130 g of SO2. What
    is your percent yield?

21
Example A 10.0 g sample of ethanol, C2H5OH, was
boiled with excess acetic acid, CH3COOH, to
produce 14.8 g of ethyl acetate, CH3COOC2H5.
What percent yield of ethyl acetate is this?
  • CH3COOH C2H5OH ? CH3COOC2H5 H2O

22
Example A 10.0 g sample of ethanol, C2H5OH, was
boiled with excess acetic acid, CH3COOH, to
produce 14.8 g of ethyl acetate, CH3COOC2H5.
What percent yield of ethyl acetate is this?
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