Prediction of Breed Composition - PowerPoint PPT Presentation

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Prediction of Breed Composition

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Prediction of Breed Composition & Multibreed Genomic Evaluations K. M. Olson and P. M. VanRaden – PowerPoint PPT presentation

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Title: Prediction of Breed Composition


1
Prediction of Breed Composition Multibreed
Genomic Evaluations
K. M. Olson and P. M. VanRaden
2
Background - Prediction of Breed
  • 200 Breed specific SNP were used to verify an
    animal received the correct breed code in the
    quality control data step
  • Several animals had fewer breed-specific SNPs and
    lower genomic relationships and inbreeding
  • Wanted to investigate a more precise way to look
    at breed composition

3
Materials Methods Prediction of Breed
  • Y- Variable was breed of animal
  • Used both females and males
  • 3 different sizes of SNP sets were used for the
    genomic evaluation
  • The Full 43,385 SNP set
  • The proposed 3 K SNP set
  • The 600 breed specific set
  • Each breed has 200 used for the basic check
    currently not a genomic evaluation

4
Materials Methods Prediction of Breed
  • Training data set animal reliability set to 99
    and parent average reliability set to 50
  • Proven as of July 2009
  • Total of 14,039 animals across all breeds
  • Validation data set reliabilities set to 0
  • Unproven as of July 2009
  • 15,809 animals across all breeds

5
Results Prediction of Breed
  • All three tests were able to determine a Holstein
    that was by pedigree 1/8 (12.5) Jersey
  • 43 K test predicted her as 85.9 Holstein and
    13.3 Jersey
  • 3 K predicted she was 84.4 Holstein and 15.5
    Jersey
  • 600 SNP set she was 83.0 Holstein and 16.6
    Jersey

6
Results Prediction of Breed
Means and standard deviations for given breed of
the validation data set
SNP set/ Breed 43 K 3 K 600
Holstein (N 14,794) 1.0000.008 1.0040.031 1.0020.019
Jersey (N 919) 0.9960.028 0.9780.063 0.9890.036
Brown Swiss (N 96) 0.9940.021 0.9890.036 0.9920.051
7
Conclusions Prediction of Breed
  • The 43 K chip was the most accurate at prediction
    of breed composition
  • The 3 K chip could identify individuals that had
    large amounts (gt 13) of foreign DNA

8
Obstacles Prediction of Breed
  • There is a patent
  • Located at http//www.patentstorm.us/patents/75111
    27/fulltext.html
  • May not be accurate for animals from different
    populations
  • foreign animals
  • older animals

9
Background - Multibreed
  • Multibreed methods are currently used in
    traditional methods
  • Only within breed methods are used for genomics
    evaluations
  • Previous research has shown little improvement in
    accuracy from using all breeds with the 50K SNP
    chip however, little research has been done using
    multi-trait methodology

10
Objectives Multibreed genomic evaluations
  • To investigate three different methods of
    multibreed genomic evaluations using Holsteins,
    Jerseys, and Brown Swiss genotypes

11
Materials Methods Multibreed (Animals)
  • The training data set - animals were proven by
    Nov. 2004
  • Holsteins 5,331
  • Jerseys 1,361
  • Brown Swiss 506
  • The validation data set - animals were unproven
    as of Nov. 2004 and proven by June 2009
  • Holsteins 2,477
  • Jerseys 410
  • Brown Swiss - 182

12
Material Methods Multibreed (Methods)
  • Method 1 estimated SNP effects within breed then
    applied those effects to the other breeds
  • Method 2 (across-breed) used a common set of SNP
    effects from the combined breed genotypes and
    phenotypes
  • Method 3 (multi-breed) used a correlated SNP
    effects using a multitrait method ( as explained
    by VanRaden and Sullivan, 2010)

13
Results P Values for Protein Yield
Holstein Jersey Brown Swiss
Traditional
PTA lt 0.001 lt 0.001 0.061
GPTA lt 0.001 lt 0.001 0.086
R2adj 0.5045 0.4874 0.1030
Method 1
HOL GPTA lt 0.001 0.668 0.344
JER GPTA 0.873 lt 0.001 0.844
BSW GPTA 0.813 0.473 0.107
PTA lt 0.001 lt 0.001 0.054
R2adj 0.5041 0.4854 0.0978
14
Results P-values for protein yield
Holstein Jersey Brown Swiss
Method 2
PTA lt 0.001 lt 0.001 0.088
GPTA lt 0.001 lt 0.001 0.316
ABGPTA 0.002 0.290 0.007
R2adj 0.5063 0.4876 0.1337
Method 3
PTA lt 0.001 lt 0.001 0.080
GPTA 0.742 0.324 0.140
MBGPTA lt 0.001 lt 0.001 0.060
R2adj 0.5060 0.4916 0.1127
15
Results P-Values for protein yield
The traditional GPTA was not included in these
analyses
Holstein Jersey Brown Swiss
Method 2
PTA lt0.001 lt 0.001 0.2016
ABGPTA lt 0.001 lt 0.001 0.0023
R2adj 0.4742 0.4742 0.1336
Method 3
PTA lt 0.001 lt 0.001 0.055
MBGPTA lt 0.001 lt 0.001 0.081
R2adj 0.5060 0.4916 0.1067
16
Conclusions Multibreed Genomic Evaluation
  • Method 1 did not help the estimates for genomic
    evaluations
  • Method 2 increased the predictive ability,
    however the traditional GPTA accounted for more
    variation than the across-breed GPTA
  • Method 3 increased the predictive ability and the
    multi-breed GPTA accounted for more variation
    than the traditional GPTA

17
Implications
  • The multibreed genomic evaluations do slightly
    increase the accuracy of the evaluations, but may
    not warrant the increased computational demands
  • A higher density SNP chip would most likely
    increase the gains in accuracy for multibreed
    genomic evaluations
  • Multibreed would be needed for genomic selection
    in crossbred herds
  • Not much demand for that yet
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