Title: Chapter 6
1electronics fundamentals
circuits, devices, and applications
THOMAS L. FLOYD DAVID M. BUCHLA
Chapter 6 Series and Parallel Combination
Circuits
2Most practical circuits have combinations of
series and parallel components.
From Chapters 4 and 5
Components that are connected in series will
share a common path.
Components that are connected in parallel will be
connected across the same two nodes.
1 2
3Combination circuits
Circuits containing both series and parallel
circuits are called COMBINATION circuits
You can frequently simplify analysis by combining
series and parallel components.
Solve by forming the simplest equivalent circuit
possible.
An equivalent circuit is one that has
4is equivalent to
There are no electrical measurements that can
distinguish the boxes.
5Another example
There are no electrical measurements that can
distinguish the boxes.
6(No Transcript)
7- What Do We Know
- For Series Circuits
- Current at all points is the
- IT IR1 IR2
- Voltage across each resistor
- VT V1 V2
- For Parallel Circuit
- Current
- IT IR1 IR2
- Voltage at all nodes is the
- VT V1 V2
same
drops
divides across each resistor in the branch
same
8Seven Step Process for Solving a Combination
Circuit
- Simplify the circuit to a series circuit by
finding the effective equivalent resistance (REQ)
of each parallel section in the circuit. Redraw
the simplified circuit. - Calculate the total resistance (RT) of the
circuit by adding all REQs to the other series
resistances. - Calculate the total current (IT) using RT in
Ohms law. - Calculate the voltage drop across any series
resistances or REQs using Ohms law. - Calculate the branch currents in all parallel
sections of the circuit using the voltage drop
across REQ and Ohms law. - Use the branch currents and resistance values to
calculate the voltage of the parallel
resistances. - Make a summary of the voltage drops and currents
for each resistance to make sure they total
correctly.
9A simple series-parallel resistive circuit.
10R4 is added to the circuit in series with R1.
11R5 is added to the circuit in series with R2.
12R6 is added to the circuit in parallel with the
series combination of R1 and R4.
13FIGURE 65
14FIGURE 66
15FIGURE 67
16Sketch the circuits for nodesA to BA to CB to C
17Sketch the circuits for nodesA to B
18Sketch the circuits for nodesA to C
19Sketch the circuits for nodesB to C
20FIGURE 69
21FIGURE 610
22(No Transcript)
23Reduce the following circuit to REQ
246 O
2510 O
265 O
27IT
50 O
IT
2 amps
28FIGURE 613
29FIGURE 614
30FIGURE 615
31FIGURE 616
32FIGURE 617
33FIGURE 618
34FIGURE 619
35Review of voltage relationships.
36Kirchoffs current law What are the readings for
node A?
37FIGURE 621
38Loaded voltage divider
The voltage-divider equation was developed for a
series circuit. Recall that the output voltage is
given by
A
- A voltage-divider with a resistive load forms a
combination (parallel) circuit.
- The voltage divider is said to be LOADED.
- The loading reduces the total resistance from
node A to ground.
39Loaded voltage divider
What is the voltage across R3?
A
Form an equivalent series circuit by combining R2
and R3 then apply the voltage-divider formula to
the equivalent circuit
8.10 V
40FIGURE 622
41FIGURE 623
42FIGURE 624
43FIGURE 625
44FIGURE 626 A voltage divider with both unloaded
and loaded outputs.
45FIGURE 628
46FIGURE 629
47FIGURE 631
48FIGURE 632
49The loading effect of a voltmeter.
50Loading effect of a voltmeter
Given VS 10 V and R1 and R2 are not defective
but the meter reads only 4.04 V when it is across
either R1 or R2.
What is a possible explanation of the meter not
displaying 10 volts?
- A voltmeter has internal resistance
- This RINT can change the resistance of the
circuit under test. - A 1 MW internal resistance of the meter accounts
for the readings.
51FIGURE 634
52Wheatstone bridge
- The Wheatstone bridge consists of
- a dc voltage source and
- four resistive arms forming two voltage dividers.
- The output is taken between the dividers.
- Frequently, one of the bridge resistors is
adjustable. (R2)
.
53Balanced Wheatstone bridge
When the bridge is balanced, the output voltage
is
zero
The products of resistances in the opposite
diagonal arms are
equal.
54Wheatstone bridge.
Voltage Divider 1
Voltage Divider 2
55Wheatstone bridge.
V1V2 I1I3
V3V4 I2I4
56Wheatstone bridge
What is the value of R2 if the bridge is balanced?
330 W
470 W
12 V
384 W
270 W
57Finding an Unknown Resistance
Scale Factor
58Measuring a physical parameter using a transducer.
Unbalanced Wheatstone Bridge
- Unbalance occurs when VOUT ? 0
- Used to measure
- Mechanical Strain
- Temperature
- Pressure
- VOUT is converted to a digital output indicating
the value of the reading.
59VOUT VA-VB 0
6010
10
10
10
10
Using the Thermistor chart, what is VOUT when the
temperature is 50o C
VA8.8v
VB6.0v
VA-B2.8v
61Example of a load cell.
62Wheatstone Bridge
- Remove RL to make an open circuit between A B
- Calculate R1R3
- Calculate R2R4
- Calculate the voltage from A to ground
- Calculate the voltage from B to ground
165 W
179 W
7.5 V
6.87 V
63FIGURE 643
64FIGURE 644
65FIGURE 647
66FIGURE 648
67FIGURE 649 A Wheatstone bridge with a load
resistor connected between the output terminals
is not a straightforward series-parallel circuit.
68FIGURE 651
69FIGURE 652
70FIGURE 653
71FIGURE 654 Maximum power is transferred to the
load when RL RS.
72Maximum power transfer Theorem
The maximum power is transferred from a source to
a load when RL RS(resistance of the voltage
source)
The maximum power transfer theorem assumes the
source voltage and resistance are fixed.
73Maximum power transfer Theorem
What is the power delivered to the load?
The voltage to the load is
5.0 V
The power delivered is
74FIGURE 655
75FIGURE 656 Curve showing that the load power is
maximum when RL RS.
76Superposition theorem
- A way to determine currents and voltages in a
linear circuit that has multiple sources - Take one source at a time and
- Algebraically summing the results.
77Superposition theorem
- Four Step Process
- Leave one voltage or current source at a time in
the circuit (circuit 1) and replace the other
(circuit 2) with a short. - Calculate REQ/Total and then calculate the
voltage or current for the resistor(s). - Repeat steps 1 and 2 for the other circuit
(circuit 2). - Algebraically add the results for all sources.
78(No Transcript)
79Summary
Summary
What does the ammeter read for I2?
1.56 mA
6.10 kW
1.97 mA
0.98 mA
8.73 kW
2.06 mA
0.58 mA
1.56 mA
80Thevenins theorem and Wheatstone Bridge
Putting the load on the Thevenin circuits and
applying the superposition theorem allows you to
calculate the load current. The load current is
1.27 mA
.0152-.0191
81Troubleshooting
The effective troubleshooter must think logically
about circuit operation.
Understand normal circuit operation and find out
the symptoms of the failure.
Analysis
Decide on a logical set of steps to find the
fault.
Planning
Following the steps in the plan, make
measurements to isolate the problem. Modify the
plan if necessary.
Measurement
82Troubleshooting
The output of the voltage-divider is 6.0 V.
Describe how you would use analysis and planning
in finding the fault.
A
From an earlier calculation, V3 should equal 8.10
V. A low voltage is most likely caused by a low
source voltage or incorrect resistors (possibly
R1 and R2 reversed). If the circuit is new,
incorrect components are possible.
Decide on a logical set of steps to locate the
fault. You could decide to 1) check the source
voltage, 2) disconnect the load and check the
output voltage, and if it is correct, 3) check
the load resistance. If R3 is correct, check
other resistors.
Planning
Analysis
83FIGURE 658
84FIGURE 659
85FIGURE 660
86FIGURE 661
87FIGURE 662
88FIGURE 663
89FIGURE 664
90FIGURE 665
91FIGURE 666
92FIGURE 667
93FIGURE 668
94FIGURE 669
95FIGURE 673
96FIGURE 674 The meters indicate the correct
readings for this circuit.
97FIGURE 675
98FIGURE 676
99FIGURE 677
100FIGURE 678
101FIGURE 679
102FIGURE 680
103FIGURE 681
104FIGURE 682
105FIGURE 683
106FIGURE 684
107FIGURE 685
108FIGURE 686
109FIGURE 687
110FIGURE 688
111FIGURE 689
112FIGURE 690
113FIGURE 691
114FIGURE 692
115FIGURE 693
116FIGURE 694
117FIGURE 695
118FIGURE 696
119FIGURE 697
120FIGURE 698
121FIGURE 699
122FIGURE 6100
123FIGURE 6101
124FIGURE 6103
125FIGURE 6104
126FIGURE 6105
127FIGURE 6106
128FIGURE 6107
129FIGURE 6108
130FIGURE 6109
131FIGURE 6110
132Selected Key Terms
The effect on a circuit when an element that
draws current from the circuit is connected
across the output terminals.
Loading Load current Bleeder
current Wheatstone bridge
The output current supplied to a load.
The current left after the load current is
subtracted from the total current into the
circuit.
A 4-legged type of bridge circuit with which an
unknown resistance can be accurately measured
using the balanced state. Deviations in
resistance can be measured using the unbalanced
state.
133Selected Key Terms
A circuit theorem that provides for reducing any
two-terminal resistive circuit to a single
equivalent voltage source in series with an
equivalent resistance.
Thevenins theorem Maximum power
transfer Superposition
The condition, when the load resistance equals
the source resistance, under which maximum power
is transferred to the load.
A method for analyzing circuits with two or more
sources by examining the effects of each source
by itself and then combining the effects.
1341. Two circuits that are equivalent have the
same a. number of components b. response to an
electrical stimulus c. internal power
dissipation d. all of the above
1352. If a series equivalent circuit is drawn for a
complex circuit, the equivalent circuit can be
analyzed with a. the voltage divider
theorem b. Kirchhoffs voltage law c. both of
the above d. none of the above
1363. For the circuit shown, a. R1 is in series
with R2 b. R1 is in parallel with R2 c. R2 is
in series with R3 d. R2 is in parallel with R3
1374. For the circuit shown, a. R1 is in series
with R2 b. R4 is in parallel with R1 c. R2 is
in parallel with R3 d. none of the above
1385. A signal generator has an output voltage of
2.0 V with no load. When a 600 W load is
connected to it, the output drops to 1.0 V. The
Thevenin resistance of the generator is a. 300
W b. 600 W c. 900 W d. 1200 W.
1396. For the circuit shown, Kirchhoff's voltage law
a. applies only to the outside loop b. applies
only to the A junction. c. can be applied to any
closed path. d. does not apply.
1407. The effect of changing a measured quantity due
to connecting an instrument to a circuit is
called a. loading b. clipping c.
distortion d. loss of precision
1418. An unbalanced Wheatstone bridge has the
voltages shown. The voltage across R4 is a. 4.0
V b. 5.0 V c. 6.0 V d. 7.0 V
1429. Assume R2 is adjusted until the Wheatstone
bridge is balanced. At this point, the voltage
across R4 is measured and found to be 5.0 V. The
voltage across R1 will be a. 4.0 V b. 5.0 V c.
6.0 V d. 7.0 V
14310. Maximum power is transferred from a fixed
source when a. the load resistor is ½ the
source resistance b. the load resistor is equal
to the source resistance c. the load resistor is
twice the source resistance d. none of the above
144Quiz
Answers 1. b 2. c 3. d 4. d 5. b
6. c 7. a 8. a 9. d 10. b