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Chapter 16 - Energy and Chemical Change

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Title: Chapter 16 - Energy and Chemical Change


1
Chapter 16 - Energy and Chemical Change
2
Energy and Heat
  • Thermochemistry - concerned with heat changes
    that occur during chemical reactions
  • Energy - capacity for doing work or supplying
    heat
  • weightless, odorless, tasteless
  • if within the chemical substances- called
    chemical potential energy

3
Energy and Heat
  • Gasoline contains a significant amount of
    chemical potential energy
  • Heat - represented by q, is energy that
    transfers from one object to another, because of
    a temperature difference between them.
  • only changes can be detected!
  • flows from warmer ? cooler object

4
Exothermic and Endothermic Processes
  • Essentially all chemical reactions, and changes
    in physical state, involve either
  • release of heat, or
  • absorption of heat

5
Exo- and Endothermic Processes
  • In studying heat changes, think of defining these
    two parts
  • the system - the part of the universe on which
    you focus your attention
  • the surroundings - includes everything else in
    the universe

6
Exo- and Endothermic Processes
  • Together, the system and its surroundings
    constitute the universe
  • Thermochemistry is concerned with the flow of
    heat from the system to its surroundings, and
    vice-versa.

7
Exothermic and Endothermic Processes
  • The Law of Conservation of Energy states that in
    any chemical or physical process, energy is
    neither created nor destroyed.
  • All the energy is accounted for as work, stored
    energy, light, or heat.

8
Exothermic and Endothermic Processes
  • Heat flowing into a system from its surroundings
  • defined as positive
  • q has a positive value
  • called endothermic
  • system gains heat as the surroundings cool down

9
Exo- and Endothermic Processes
  • Heat flowing out of a system into its
    surroundings
  • defined as negative
  • q has a negative value
  • called exothermic
  • system loses heat as the surroundings heat up

10
Exothemic and Endothermic
  • Every reaction has an energy change associated
    with it
  • Exothermic reactions release energy, usually in
    the form of heat.
  • Endothermic reactions absorb energy
  • Energy is stored in bonds between atoms

11
Heat Capacity and Specific Heat
  • A calorie is defined as the quantity of heat
    needed to raise the temperature of 1 g of pure
    water 1 oC.
  • Used except when referring to food
  • a Calorie, written with a capital C, always
    refers to the energy in food
  • 1 Calorie 1 kilocalorie 1000 cal.

12
Heat Capacity and Specific Heat
  • The calorie is also related to the joule, the SI
    unit of heat and energy
  • named after James Prescott Joule
  • 4.184 J 1 cal
  • Heat Capacity - the amount of heat needed to
    increase the temperature of an object exactly 1 oC

13
Heat Capacity and Specific Heat
  • Specific Heat Capacity - the amount of heat it
    takes to raise the temperature of 1 gram of the
    substance by 1 oC (abbreviated c)
  • often called simply Specific Heat
  • Water has a HUGE value, compared to other
    chemicals
  • Movie

14
Specific Heats of Common Substances are provided
in a table in your book.
15
Heat Capacity and Specific Heat
  • For water, c 4.184 J/(g oC), and also c 1.00
    cal/(g oC)
  • Thus, for water
  • it takes a long time to heat up, and
  • it takes a long time to cool off!
  • Water is used as a coolant!

16
Heat Capacity and Specific Heat
  • To calculate, use the formula
  • q c x mass (g) x ?T
  • heat abbreviated as q
  • ?T change in temperature
  • c Specific Heat
  • Units are either J/(g oC) or cal/(g oC)

17
Energy Conversion Factors are given in a table in
your book.
18
Section 16.2Heat in Chemical Reactions and
Processes
  • OBJECTIVES
  • Calculate heat changes in chemical and physical
    processes.

19
Calorimetry
  • Calorimetry - the accurate and precise
    measurement of heat change for chemical and
    physical processes.
  • The device used to measure the absorption or
    release of heat in chemical or physical processes
    is called a Calorimeter

20
Calorimetry
  • Foam cups are excellent heat insulators, and are
    commonly used as simple calorimeters
  • Fig. 16.5, page 497

21
Calorimetry
  • Calorimetry experiments can be performed at a
    constant volume using a device called a bomb
    calorimeter
  • For systems at constant pressure, the heat
    content is the same as a property called Enthalpy
    (H) of the system

22
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23
Calorimetry
  • Changes in enthalpy ?H
  • q ?H These terms will be used interchangeably
    in this textbook
  • Thus, q ?H m x c x ?T
  • ?H is negative for an exothermic reaction
  • ?H is positive for an endothermic reaction

24
In terms of bonds
O
C
O
Breaking this bond will require energy.
Making these bonds gives you energy.
In this case making the bonds gives you more
energy than breaking them.
25
Exothermic
  • The products are lower in energy than the
    reactants
  • Releases energy

26
C O2 CO2
395 kJ
395kJ
27
Endothermic
  • The products are higher in energy than the
    reactants
  • Absorbs energy
  • Movie

28
CaCO3 CaO CO2
CaCO3 176 kJ CaO CO2
176 kJ
29
Sec. 16.23 Chemistry Happens in
  • MOLES
  • An equation that includes energy is called a
    thermochemical equation
  • CH4 2O2 CO2 2H2O 802.2 kJ
  • 1 mole of CH4 releases 802.2 kJ of energy.
  • When you make 802.2 kJ you also make 2 moles of
    water

30
Thermochemical Equations
  • A heat of reaction is the heat change for the
    equation.
  • The physical state of reactants and products must
    also be given.
  • Standard conditions for the reaction are 101.3
    kPa (1 atm.) and 25 oC

31
CH4 2 O2 CO2 2 H2O 802.2 kJ
  • If 10. 3 grams of CH4 are burned completely, how
    much heat will be produced?

1 mol CH4
802.2 kJ
10. 3 g CH4
16.05 g CH4
1 mol CH4
515 kJ
32
CH4 2 O2 CO2 2 H2O 802.2 kJ
  • How many liters of O2 at STP would be required to
    produce 23 kJ of heat?
  • How many grams of water would be produced with
    506 kJ of heat?

33
Summary, so far...
34
Enthalpy
  • The heat content a substance has at a given
    temperature and pressure
  • Cant be measured directly because there is no
    set starting point
  • The reactants start with a heat content
  • The products end up with a heat content
  • So we can measure how much enthalpy changes

35
Enthalpy
  • Symbol is H
  • Change in enthalpy is DH (delta H)
  • If heat is released, the heat content of the
    products is lower
  • DH is negative (exothermic)
  • If heat is absorbed, the heat content of the
    products is higher
  • DH is positive (endothermic)

36
Energy
Change is down
DH is lt0
Reactants
Products

37
Energy
Change is up
DH is gt 0
Reactants
Products

38
Heat of Reaction
  • The heat that is released or absorbed in a
    chemical reaction
  • Equivalent to DH
  • C O2(g) CO2(g) 393.5 kJ
  • C O2(g) CO2(g) DH -393.5 kJ
  • In thermochemical equation, it is important to
    indicate the physical state
  • H2(g) 1/2O2 (g) H2O(g) DH -241.8 kJ
  • H2(g) 1/2O2 (g) H2O(l) DH -282.5 kJ

39
Heat of Combustion
  • The heat from the reaction that completely burns
    1 mole of a substance.

40
Section 16.3Heat in Changes of State
  • OBJECTIVES
  • Calculate heat changes that occur during melting,
    freezing, boiling, and condensing.

41
Heats of Fusion and Solidification
  • Molar Heat of Fusion (?Hfus) - the heat absorbed
    by one mole of a substance in melting from a
    solid to a liquid
  • Molar Heat of Solidification (?Hsolid) - heat
    lost when one mole of liquid solidifies Movie

42
Heats of Fusion and Solidification
  • Heat absorbed by a melting solid is equal to heat
    lost when a liquid solidifies
  • Thus, ?Hfus -?Hsolid
  • Note Table 16.6, page 502
  • Sample Problem 16-4, page 504

43
Heats of Vaporization and Condensation
  • When liquids absorb heat at their boiling points,
    they become vapors.
  • Molar Heat of Vaporization (?Hvap) - the amount
    of heat necessary to vaporize one mole of a given
    liquid.

44
Heats of Vaporization and Condensation
  • Condensation is the opposite of vaporization.
  • Molar Heat of Condensation (?Hcond) - amount of
    heat released when one mole of vapor condenses
  • ?Hvap - ?Hcond

45
Heats of Vaporization and Condensation
  • The large values for ?Hvap and ?Hcond are the
    reason hot vapors such as steam is very dangerous
  • You can receive a scalding burn from steam when
    the heat of condensation is released!

46
Heats of Vaporization and Condensation
  • H20(g) ? H20(l) ?Hcond - 40.7kJ/mol

47
Heat of Solution
  • Heat changes can also occur when a solute
    dissolves in a solvent.
  • Molar Heat of Solution (?Hsoln) - heat change
    caused by dissolving one mole of a substance
  • Sodium hydroxide provides a good example of an
    exothermic molar heat of solution

48
Heat of Solution
  • NaOH(s) ? Na1(aq) OH1-(aq)
  • ?Hsoln - 445.1 kJ/mol
  • The heat is released as the ions separate and
    interact with water, releasing 445.1 kJ of heat
    as ?Hsoln thus becoming so hot it steams!

H2O(l)
49
Section 16.4Calculating Heat Changes
  • OBJECTIVES
  • Apply Hesss law of heat summation to find heat
    changes for chemical and physical processes.

50
Hesss Law
  • If you add two or more thermochemical equations
    to give a final equation, then you can also add
    the heats of reaction to give the final heat of
    reaction.
  • Called Hesss law of heat summation

51
Why Does It Work?
  • If you turn an equation around, you change the
    sign
  • If H2(g) 1/2 O2(g) H2O(g) DH-285.5 kJ
  • then, H2O(g) H2(g) 1/2 O2(g) DH
    285.5 kJ
  • also,
  • If you multiply the equation by a number, you
    multiply the heat by that number
  • 2 H2O(g) 2 H2(g) O2(g) DH 571.0 kJ

52
Why does it work?
  • You make the products, so you need their heats of
    formation
  • You unmake the products so you have to subtract
    their heats.
  • How do you get good at this?

53
Applying Hesss Law
  • 2H2O2(l) ? 2H2O(l) O2(g)
  • Can be shown in two equations
  • a) 2H2(g)O2(g) ? 2H2O(l) ?H -572 kJ
  • b) H2(g) O2(g) ? H2O2(l) ?H -188 kJ
  • Reverse the equation b) to make H2O2 a reactant
    and then double it.
  • c) 2H2O2(l)?2H2(g)2O2(g) ?H 376 kJ
  • Note how ?H -188 kJ was doubled and its sign was
    reversed.

54
Applying Hesss Law
  • Adding equations a) and c) reactants and products
    together yields
  • 2H2O2(l) 2H2(g) O2(g) ?
  • 2H2(g) 2O2(g) 2H2O(l)
  • Canceling like items of both sides reduces the
    equation to
  • 2H2O2(l) ? 2H2O(l) O2(g)
  • Adding equations a) and c) enthalpies yields
  • 376 kJ -572 kJ -196 kJ

55
Standard Heats of Formation
  • The DH for a reaction that produces one mol of a
    compound from its elements at standard conditions
  • Standard conditions are 25C and 1 atm.
  • The symbol is
  • The standard heat of formation of an element is
    zero element 0
  • This includes the diatomics like O2

56
Using Standard Heat of Formation
  • Table 16.7, page 510 has standard heats of
    formation for numerous compounds
  • The heat of a reaction can be calculated by
    subtracting the heats of formation of the
    reactants from the products

57
Example Standard Heat of Formation
  • CH4(g) 2 O2(g) CO2(g) 2 H2O(g)
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