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Analytical%20Gravimetric%20Determination

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Analytical Gravimetric Determination Suh Kwon Conclusion With the help of this experiment, you were able to find the amount of sulfate ions in a sample of alum ... – PowerPoint PPT presentation

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Title: Analytical%20Gravimetric%20Determination


1
Analytical Gravimetric Determination
  • Suh Kwon

2
Purpose
  • To measure the number of a given substance in a
    solution by precipitation, filtration, drying,
    and weighing
  • Approximating the amount of SO42- ions in a
    sample of alum, KAl(SO4)2 12H20

3
Background Information
  • Gravimetric analysis is used to determine the
    amount of a substance by finding its mass, and
    then using the mass to find the quantity of the
    substance
  • Example to find the measurement of solids
    suspended in a water sample, a known volume of
    water is filtered and the collected solids are
    weighed

4
For this experiment
  • The precipitate that will be formed in this
    experiment is barium sulfate, BaSO4
  • Forms very fine crystals
  • Beforehand, calculate how much 0.200 M Ba(NO3)2
    you would need to totally precipitate all of the
    sulfate ion present in solution

http//www.jinyakc.com/jy/My20Pictures/9.jpg
5
!!!
  • Make sure you add twice the calculated amount of
    Ba(NO3)2 because for every 1 mole of alum, there
    are 2 moles of Ba(NO3)2
  • KAl(SO4)2 12H2O 2Ba(NO3)2 ? KNO3 Al(NO3) 3
    2BaSO4 12H2O

6
Materials
  • Buchner Funnel
  • A piece of Whatman No. 42 filter paper
  • Filter flask
  • 1.059 g of alum compounds
  • 50.0 mL of distilled water
  • 22.3 mL (calculated) of 0.200 M Ba(NO3)2
  • Heating Plate
  • Analytical Balance
  • Drying oven set at 50C

7
An analytical balance is an instrument that's
used to measure mass at a very high degree of
precision.
Filter Flask
Analytical Balance
http//www.usdoj.gov/dea/photos/lab/analytical_bal
ance_mettler_ae-260.jpg
http//www.laboratoryequipmentworld.com/gifs/filte
r-flasks.jpg
Filter Paper
Buchner Funnel
http//upload.wikimedia.org/wikipedia/commons/5/52
/Buchner_funnel.jpg
http//www.isss.biz/prodImages/Whatman-Filter-Pape
r-Grade-2.jpg
http//www.rickly.com/sai/images/BUCHNER.JPG
8
Procedures
  • Dissolve the 1.059 g of alum in the 50.0 mL of
    distilled water
  • Add twice the amount of 0.200 M Ba(NO3)2 to alum
    solution, stirring constantly
  • Heat this solution for 15 minutes and allow the
    solution to stand overnight
  • Next Day You will discover that fine crystals
    had appeared in the solution

9
Procedures (2)
  • 4. Weigh the filter paper separately and
    determine its mass on the analytical balance
  • 5. Filter the solution through the Buchner
    funnel, containing the filter paper to collect
    the crystals
  • 6. Remove the filter paper and allow it to dry in
    the 50C drying oven
  • 7. Weigh the paper and crystals together and
    determine their total mass

10
http//www.creative-chemistry.org.uk/activities/im
ages/buchner.gif
http//depts.washington.edu/chem/courses/labs/162l
abs/images/PA230280.JPG
11
Data
  • INITIAL
  • Mass of alum 1.059 g
  • Volume of distilled water 50.0 mL
  • Amount of 0.200 M Ba(NO3)2 22.3 mL
  • COLLECTED
  • Mass of filter paper (alone) 1.675 g
  • Mass of filter paper filtered crystals 2.715 g

12
Equations
  • Balanced Chemical Formula
  • KAl(SO4)2 12H2O 2Ba(NO3)2 ? KNO3
    Al(NO3) 3 2BaSO4 12H2O
  • Ba2 SO42- ? BaSO4 (s)
  • Sulfate (Mass of Sulfate/Mass of Sample)
    100
  • Percent Error (Theoretical Value Actual
    Value) 100
  • Theoretical Value

13
Calculations
  • How much 0.200 M Ba(NO3)2 would be needed to
    totally precipitate all of the sulfate ion
    present in the alum solution
  • 1.059 g alum 1 mol of alum 2 mol Ba(NO3)2
    1 L of Ba(NO3)2 1000 mL 22.3 mL
  • 474.46 g alum 1 mol of alum
    0.200 mol Ba(NO3)2 1 L

14
  • The percent of sulfate ion in the alum based upon
    the experiment
  • 2.715 g filter paper barium sulfate
  • 1.675 g paper
  • 1.040 g BaSO4
  • 1.040 g BaSO4 1 mol BaSO4 1 mol SO42-
    96.04 g SO42- 0.4281 g SO42-
  • 233.37 g BaSO4 1 mol BaSO4 1
    mol SO42-
  • sulfate 0.4281 g SO42- 100
    40.43
  • 1.059 g alum

1
2
3
15
  • The theoretical of sulfate ion in the alum
  • 192.08 g SO42- 100 40.48
  • 474.46 g alum
  • The percent error in this investigation
  • error 40.43 40.48 100 -0.15
  • 40.48

16
Conclusion
  • With the help of this experiment, you were able
    to find the amount of sulfate ions in a sample of
    alum compound, comparing that value to the
    theoretical amount necessary
  • A negative percent error signifies that there was
    a production of a solid throughout the reaction
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