Analysis of Structures

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ME 221 StaticsLecture 29Sections 6.1 6.4
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Homework 10

• Chapter 7 problems
• 5, 8, 19, 21, 24, 26 35
• Due Wednesday, November 13

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Homework 11

• Chapter 6 problems
• 2, 3, 6 7 Method of Joints
• 32, 36, 47 53 Method of Sections
• 6.47 E-G should be 0.2m
• Due Friday, November 22

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Quiz 6

• Today

Exam 3
Friday, November 15
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Chapter 6 Analysis of Structures

• The knowledge of internal forces is a
  fundamental requirement for true design

• The Structural elements are
• Trusses
• Frames
• Machines

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Trusses
Composed of slender straight pieces connected
together by frictionless pins where all the loads
(no moments) are applied.
Each member will act as a two-force member
(either in tension or compression). All the
forces acting on a truss member are axial.
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Frames Are designed to support, prevent or
transmit loads (forces, no moments). At least
one member is not a two-force member.
Machines Are designed to transmit force, motion
or energy (forces and moments). Will always have
at least one member with multiple forces.
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Planar Trusses
If the planar truss (2-D) is statically
determinant, then the number of joints is related
to the number of reactions and internal members
by
2jmr j number of joints m number of
internal members r number of reactions
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Analysis of Trusses Using the Method of Joints
We need to solve for (1) - Internal forces
FAB, FAC, and FCA (2) - Reactions Ax, Ay and Cy
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Joint A
FAB cosaFACAx-Pax .(1) FAB
sinaAy-Pay (2)
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At Joint C
FCB
PCy
b
FCA
PCx
C
Cy
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At Joint B
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Using Matrix Notation
-1

Using manual calculations
Look for joints with 2 unknowns
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Example
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Example
6 kN
A
B
3 kN
0.9 m
C
D
E
1.2 m 1.2 m
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6 kN
A
B
4
4
5
9
15
3 kN
9
15
5
C
16
4
4
16
E
D