Title: Patterns of Inheritance
 1Patterns of Inheritance
  2Gregor Mendel
- 1822  1884 
 - Austrian monk 
 - Experimented with garden peas 
 - Provided a basis for understanding heredity 
 
  3Mendel contd
- Published a paper in 1866 stating that parents 
pass discrete heritable factors on to their 
offspring  - Factors retain individuality generation after 
generation  - Identified that each trait is inherited by a pair 
of factors, one from each parent  - One form of a factor may be dominant over an 
alternative form  - Reasoned that each egg and sperm must contain 
only 1 copy of a factor for each trait 
  4Mendel contd.
- Mendels law of segregation 
 - Each individual has two factors (genes) for each 
trait  - The factors segregate (separate) during the 
formation of gametes  - Each gamete contains only one factor from each 
pair of factors  - Fertilization gives each new individual 2 factors 
for each trait 
  5Modern Genetics  Genes
- Sections of chromosomes which give instructions 
for one characteristic or protein.  - Located at the same point or locus, on each 
member of a homologous pair  - All together make up the organisms genome. 
 - Controls the physical characteristics of a species
 
  6Modern Genetics - Alleles
- Alternative forms of the same gene on each 
chromosome  - One allele comes from each parent 
 - Dominant allele 
 - Masks other traits present 
 - Only 1 dominant allele needs to be present for a 
certain trait to be expressed  - Represented by a capital letter 
 - Recessive Allele 
 - 2 copies of the recessive allele need to be 
present for trait to be expressed  - Represented by a lower case letter 
 
  7Modern Genetics  Alleles contd
  8Modern Genetics  Alleles contd
- Genotype 
 - Genetic composition of a specific trait 
 - Homozygous dominant  2 dominant alleles 
 - Heterozygous  1 dominant allele and 1 recessive 
allele  - Homozygous recessive 2 recessive allele 
 - Phenotype 
 - Physical expression of a specific trait 
 - Homozygous dominant or heterozygous ? Dominant 
Trait  - Homozygous recessive ? recessive trait 
 
  9Single Gene Inheritance
- Simplest situation 
 - One gene carries all the information responsible 
for one trait  - Widows Peak 
 - Alternative forms of alleles for hairline shape 
 - Widows peak is dominant to straight hair line 
 - Wallele for widows peak 
 - w allele for straight hairline
 
  10Widows peak
  11Genotype related to phenotype
  12Single Gene Inheritance contd.
- Monohybrid cross 
 - Looks at inheritance of one trait only 
 - A punnett squares used to find all possible 
combinations of alleles. 
  13Single Gene Inheritance contd.
- Example 1 
 - If a homozygous woman with a widows peak 
reproduces with a man with a straight hairline, 
what kind of hairline will their children have? 
  14Single Gene Inheritance contd.
- Example 
 - If two heterozygous parents reproduce what kind 
of hairline will their children have?  
W w
W WW Ww
w Ww ww 
 15Single Gene Inheritance contd.
- Genetic Ratios 
 - Express ratios of possible outcomes 
 - Genotypic ratio 
 - Homozygous Dominant Heterozygous Homozygous 
Recessive  - Phenotypic ratio 
 - Dominant trait  recessive trait 
 - Often expressed as probability 
 - The probability resets and is the same for each 
pregnancy!  - Having one child with a trait has no effect on 
future children. 
  16Single Gene Inheritance contd.
- Look back to example 1 
 - What are the genotypic and phenotypic ratios? 
 - WW x ww 
 - Genotypic Ratio 
 - 0  4  0 
 - Phenotypic Ratio 
 - 10 
 - 100 Widows peak
 
- Ww x Ww 
 - Genotypic Ratio 
 - 1 2 1 
 - Phenotypic Ratio 
 - 3  1 
 - Probability is ¾ Widows Peak 
 - 75 
 - Probability ¼ Straight 
 - 25 
 
  17Single Gene Inheritance contd
- Determining Genotype 
 - No way to distinguish between a homozygous 
dominant individual and a heterozygous individual 
just by looking  - They are phenotypically the same 
 - Test cross may help us determine 
 - Used in breeders of plants and animals 
 - Cross unknown with a recessive individual 
 - We know one parent genotype, this will help us 
determine the other genotype  - If there are any offspring produced with the 
recessive phenotype, then the dominant parent 
must be heterozygous 
  18Single Gene Inheritance contd
- Example  In rats, large ears is dominant to 
small ears. A rat breeder has a female rat with 
large ears, which she breeds with a male rat with 
small ears. In the first litter, all rats are 
born with large ears.  - What is the genotype of the female rat? 
 - In a second litter from the same parents, 4 baby 
rats have large ears, one has small ears.  - What is the genotype of the female rat?
 
  19Single Gene Inheritance contd
- Practice problems 
 - Both a man and a woman are heterozygous for 
freckles. Freckles are dominant over no freckles. 
What is the chance that their child will have 
freckles?  - Both you and your sibling have attached ear 
lobes, but your parents have unattached lobes. 
Unattached earlobes (E) are dominant over 
attached (e). What are the genotypes of your 
parents?  - A father has dimples, the mother of his children 
does not, and all 5 of their children have 
dimples. Dimples (D) are dominant over no dimples 
(d). Give the probable genotypes of all persons 
concerned. 
  20Homework (WHAT??? Its BIO!)
- Bikini Bottom Beach Genetics
 
  21Independent Assortment
- Mendel reasoned from the results of his pea plant 
crosses that each pair of factors assorts 
independently into gametes  - Each trait is passed down individually. The 
allele you receive for any one gene is not 
related to any other alleles you receive.  - We can now explain this through independent 
alignment and crossing over in meiosis. (Fig 
23.6) 
  22Independent Assortment contd
  23Independent Assortment contd
- Called the Law of Independent Assortment 
 - Each pairs of factors assorts independently 
(without regard to how the others separate)  - All possible combinations of factors can occur in 
the gametes 
  24Independent Assortment contd
- Practice problems 
 - For each of the following genotypes, give all 
possible gametes  - WW 
 - WWSs 
 - Tt 
 - Ttgg 
 - AaBb 
 - For each of the following, state whether the 
genotype or a gamete is represented  - D 
 - Ll 
 - Pw 
 - LlGg
 
  25Dihybrid Cross
- Punnet squares, considering two-trait crosses at 
one time.  - Example 
 - The traits for hairline and finger length are 
both single gene traits. As before, widows peak 
is dominant over straight hairline. Having short 
fingers is considered dominant over long fingers. 
  - Two parents who are both heterozygous for both 
traits have children.  - Determine the genotypic and phenotypic ratios for 
their children.  
  26Dihybrid cross contd
- Possible Gametes? 
 - Genotypic Ratio? 
 - Phenotypic Ratio? 
 
  27Dihybrid Crosses contd
- Determining Ratios 
 - Product rule of probability 
 - The chance of 2 or more independent events 
occurring together is the product of their chance 
of occurring separately  - In our example 
 - Probability of widows peak  ¾ 
 - Probability of short fingers ¾ 
 - What is the probability of widows peak AND short 
fingers?  - ¾ x ¾  9/16
 
  28Dihybrid Crosses contd
- Recall from our single trait crosses 
 - Probability of widows peak  ¾ Probability of 
short fingers ¾  - Probability of straight hairline ¼ Probability 
of long fingers ¼  - Using the product rule 
 - Probability of widows peak and short fingers  
 X   - Probability of widows peak and long fingers  
X  3/16  - Probability of straight hairline and short 
fingers  ¼ X ¾  3/16  - Probability of straight hairline and long fingers 
 ¼ X ¼  1/16  
These values are standard for all heterozygous 
crosses! You dont need to memorize them, but 
should be able to figure them out in your head! 
 29Dihybrid Crosses contd
- Using the product rule 
 - Probability of widows peak and short fingers 
 - Probability of widows peak and long fingers 
 - Probability of straight hairline and short 
fingers   - Probability of straight hairline and long fingers 
  -  
 
  30Dihybrid Crosses contd
- Two-trait test cross 
 - Cross an individual with the dominant phenotype 
for each trait with an individual with the 
recessive phenotype of both traits  - W?S? x wwss
 
WS W? ?S ??
wwss WwSs Ws?s ?wSs ?w?s 
 31Dihybrid Cross contd
- Attached earlobes are recessive, What genotype do 
children have if one parent is homozygous for 
earlobes and homozygous dominant for hairline, 
and the other is homozygous dominant for 
unattached earlobes and homozygous recessive for 
hairline?  - If an individual from this cross reproduces with 
another of the same genotype, what are the 
chances that they will have a child with a 
straight hairline and attached earlobes?  - A child who does not have dimples or freckles is 
born to a man who has dimples and freckles (both 
dominant traits) and a woman who does not. What 
are the genotypes of all persons concerned? 
  32Polygenic Inheritance
- Not fully understood by geneticists. 
 - Generally 
 - One trait controlled by 2 or more genes at 
different loci  - The higher the number of dominant alleles you 
possess, the stronger the expression of the 
trait.  - Result is a continuous range of phenotypes 
 - Distribution resembles a bell curve 
 - The more gene pairs involved, the more continuous 
the pattern of variation  - Ex human height, skin pigmentation, eye colour
 
  33Polygenic inheritance contd 
  34Polygenic Inheritance contd
- Skin color 
 - Controlled by many gene pairs and many alleles 
 - Lets assuming a simple model of two alleles at 2 
loci  - A and B 
 - If two heterozygous parents have children, 
children can range from very light to very dark  
Genotype Phenotype
AABB Very Dark Skin
AABb or AaBB Dark Skin
AaBb, AAbb, or aaBB Medium brown skin
Aabb, or aaBb Light Skin
aabb Very light skin 
 35Polygenic Inheritance contd 
- Eye colour is controlled by 3 genes we have 
identified  - We suspect there are more 
 - Not a clear dominant and recessive 
 - Brown allele
 
  36Environmental Influences on Inheritance
- Environment can influence gene expression and 
therefore phenotype  - Ex sunlight exposure on skin coat color in 
Himalayan rabbits  - Human twin studies 
 - Polygenic traits are most influenced 
 - nature vs. nurture 
 - Identical twins separated at birth are studied 
 - If they share a trait in common even though 
raised in different environments, it is likely 
genetic 
  37Coat color in Himalayan rabbits
  38Incomplete Dominance
- Incomplete dominance 
 - Heterozygous individual has a phenotype 
intermediate to the two homozygous individuals  - Ex Curly-haired Caucasian woman and a 
straight-haired Caucasian man produce wavy-haired 
children  - When 2 wavy-haired people have children, the 
phenotypic ratio is 1 curly 2 wavy 1 straight 
  39Incomplete dominance
  40Codominance
- Multiple allele inheritance 
 - The gene exists in several allelic forms, but 
each person still has only 2 of the possible 
alleles  - Occurs when both alleles are equally expressed 
 - Ex type AB blood has both A antigens and B 
antigens on red blood cells  
  41Codominance contd.
- ABO blood types 
 - IA  A antigens on RBCs 
 - IB  B antigens on RBCs 
 - i  has neither A nor B antigens on RBCs 
 - Both IA and IB are dominant over I, IA and IB are 
codominant 
Phenotype Genotype
A IAIA or IAi
B IBIB or Ibi
AB IAIB
O ii 
 42Codominance contd.
- Paternity testing- ABO blood groups often used 
 - Can disprove paternity but not prove it 
 - Rh factor- another antigen on RBCs 
 - Rh positive people have the antigen 
 - Rh negative people lack it 
 - There are multiple alleles for Rh negative, but 
all are recessive to Rh positive 
  43Inheritance of blood type
  44Practice Problems
- A polygenic trait is controlled by three pairs of 
alleles. What are the two extreme genotypes for 
this trait?  - What is the genotype of the lightest child that 
could result from a mating between two 
medium-brown individuals?  - A child with type O blood is born to a mother 
with type A blood. What is the genotype of the 
child? The mother? what are the possible 
genotypes of the father?  - From the following blood types determine which 
baby belongs to which parents  - Baby 1 type O Mrs. Doe type A Mrs. Jones 
type A  - Baby 2 type B Mr. Doe type A Mr. Jones 
type AB  
  45Sex-linked inheritance
- Sex chromosomes 
 - 22 pairs of autosomes, 1 pair of sex chromosomes 
 - X and y 
 - In females, the sex chromosomes are XX 
 - In males, the sex chromosomes are XY 
 - Note that in males the sex chromosomes are not 
homologous  - Traits controlled by genes in the sex chromosomes 
are called sex-linked traits  - X chromosome has many genes, the Y chromosome 
does not 
  46Sex-linked inheritance contd.
- X-linked traits 
 - Red-green colorblindness is X-linked 
 - The X chromosome has genes for normal color 
vision  - XB  normal vision 
 - Xb  colorblindness 
 
Genotypes Phenotypes
XBXB female with normal vision
XBXb carrier female, normal vision
XbXb colorblind female
XBY male with normal vision
XbY colorblind male 
 47Cross involving an X-linked allele
  48Practice Problems
- Both the mother and the father of a colorblind 
male appear to be normal. From whom did the son 
inherit the allele for colorblindness? What are 
the genotypes of the mother, father, and the son?  - A woman is colorblind. What are the chances that 
her son will be colorblind? If she is married to 
a man with normal vision, what are the chances 
that her daughters will be colorblind? Will be 
carriers?  - Both the husband and the wife have normal vision. 
The wife gives birth to a colorblind daughter. Is 
it more likely the father had normal vision or 
was colorblind? What does this lead you to deduce 
about the girls parentage?  - What is the genotype of a colorblind male with 
long fingers is slong fingers? If all his 
children have normal vision and short fingers, 
what is the likely genotype of the mother? 
  49Inheritance of linked genes
- The sequence of individual genes on a chromosome 
is fixed because each allele has a specific locus  - All genes on a single chromosome form a linkage 
group  - When linkage is complete, a dihybrid produces 
only 2 types of gametes  - Any time traits are inherited together, a linkage 
group is suspected  - If very few recombined phenotypes appear in 
offspring, linkage is also suspected  
  50Inheritance of linked genes
- Crossing over between 2 alleles of interest, can 
result in 4 types of gametes  - Occurrence of crossing over can indicate the 
sequence of genes on a chromosome  - More frequent between distant genes
 
Fig. 23.14 
 51Practice Problems
- When AaBb individuals reproduce, the phenotypic 
ratio is about 31. What ratio was expected? What 
may have caused the observed ratio?  - The genes for ABO blood type and for fingernails 
are on the same homologous pair of chromosomes. 
In an actual family, 45 of offspring have type B 
blood and no fingernails, and 45 have type O 
blood and fingernails 5 have type B blood and 
fingernails, and 5 have type O blood and no 
fingernails. What process accounts for the 
recombinant phenotypes?