CHAPTER 5 The Straight Line - PowerPoint PPT Presentation

About This Presentation
Title:

CHAPTER 5 The Straight Line

Description:

CHAPTER 5 The Straight Line Learning Objectives 5.1 Understand the concept of gradient of a straight line. 5.2 Understand the concept of gradient of a straight line ... – PowerPoint PPT presentation

Number of Views:132
Avg rating:3.0/5.0
Slides: 24
Provided by: jIE45
Category:

less

Transcript and Presenter's Notes

Title: CHAPTER 5 The Straight Line


1
CHAPTER 5The Straight Line
2
Learning Objectives
  • 5.1 Understand the concept of gradient of a
    straight line.
  • 5.2 Understand the concept of gradient of a
    straight line in Cartesian coordinates.
  • 5.3 Understand the concept of intercept.
  • 5.4 Understand and use equation of a straight
    line.
  • 5.5 Understand and use the concept of parallel
    lines.

3
(No Transcript)
4
5.1 GRADIENT OF A STRAIGHT LINE
  • (A) Determine the vertical and horizontal
    distances between two given points on a straight
    line

F
E
G
  • Example of application AN ESCALATOR.
  • EG - horizontal distance(how far a person goes)
  • GF - vertical distances(height changed)

5
Example 1
  • State the horizontal and vertical distances for
    the following case.

10 m
16 m
Solution The horizontal distance 16 m The
vertical distance 10 m
6
(B)Determine the ratio of the vertical distance
to the horizontal distance
10 m
16 m
  • Let us look at the ratio of the vertical
    distance to the horizontal distances of the slope
    as shown in figure.

7
  • Vertical distance 10 m
  • Horizontal distance 16 m
  • Therefore,
  • Solution

8
5.2 GRADIENT OF THE STRAIGHT LINE IN CARTESIAN
COORDINATES
  • Coordinate T (X2,Y1)
  • horizontal distance
  • PT
  • Difference in x-coordinates
  • x2 x1
  • Vertical distance
  • RT
  • Difference in y-coordinates
  • y2 y1

y
R(x2,y2)
y2 y1
x2 x1
T(x2,y1)
P(x1,y1)
x
0
9
Solution
REMEMBER!!! For a line passing through two points
(x1,y1) and (x2,y2), where m is the gradient
of a straight line
10
  • Example 2
  • Determine the gradient of the straight line
    passing through the following pairs of points
  • P(0,7) , Q(6,10)
  • L(6,1) , N(9,7)
  • Solution

11
  • (C) Determine the relationship between the value
    of the gradient and the
  • Steepness
  • Direction of inclination of a straight line
  • What does gradient represents??
  • Steepness of a line with respect to the x-axis.

12
B
  • a right-angled triangle. Line AB is a slope,
    making an angle with the horizontal line AC

C
A
13
When gradient of AB is positive When gradient of AB is negative
y
y
B
B
x
x
0
0
A
A
  • inclined upwards
  • acute angle
  • is positive
  • inclined downwards
  • obtuse angle.
  • is negative

14
Activity Determine the gradient of the given
lines in figure and measure the angle between the
line and the x-axis (measured in anti-clocwise
direction)
y
Line Gradient Sign
MN
PQ
RS
UV
N(3,3)
V(1,4)
Q(-2,4)
S(-3,1)
x
0
M(-2,-2)
R(3,-1)
P(2,-4)
U(-1,-4)
15
  • REMEMBER!!!
  • The value of the gradient of a line
  • Increases as the steepness increases
  • Is positive if it makes an acute angle
  • Is negative if it makes an obtuse angle

16
Lines Gradient
AB 0



y
A
B
x
0
17
Lines Gradient

CD Undefined


y
D
C
x
0
18
Lines Gradient


EF Positive

y
F
E
x
0
19
Lines Gradient



GH Negative
y
H
G
x
0
20
Lines Gradient
AB 0
CD Undefined
EF Positive
GH Negative
y
D
H
F
A
B
G
E
C
x
0
21
5.3 Intercepts
y-intercept
x-intercept
  • Another way finding m, the gradient

22
5.4 Equation of a straight line
  • Slope intercept form
  • y mx c
  • Point-slope form
  • given 1 point and gradient
  • given 2 point

23
5.5 Parallel lines
  • When the gradient of two straight lines are
    equal, it can be concluded that the two straight
    lines are parallel.

Example Is the line 2x-y6 parallel to line
2y4x3?
  • Solution
  • 2x-y6y y2x-6 gradient is 2.
  • 2y4x3 gradient is
    2.
  • Since their gradient is same hence they are
    parallel.
Write a Comment
User Comments (0)
About PowerShow.com