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Thermodynamics of Reactions

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Thermodynamics of Reactions Spontaneity, Entropy, and Free Energy Chapter 16 – PowerPoint PPT presentation

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Title: Thermodynamics of Reactions


1
Thermodynamics of Reactions
  • Spontaneity, Entropy, and Free Energy
  • Chapter 16

2
1st Law of Thermodynamics
  • The energy of the universe is constant
  • (conservation of energy)

3
Spontaneous Processes
  • Can be fast OR slow.
  • Occurs without outside intervention

4
True, or Not True?
Why??
  • Ball rolls downhill spontaneously.
  • Ball rolls uphill spontaneously.
  • Wood burns spontaneously in O2.
  • CO2 and H2O spontaneously form wood.
  • Steel rusts spontaneously.
  • Rust spontaneously turns into iron and water.

5
Its All About Entropy
  • Entropy is
  • All about the ability of energy to spread out
  • Related to probability.
  • Over-simplified to be about disorder.

6
Positional Entropy
  • When a substance has more opportunities to exist,
    (ie, particles can have more than one
    arrangement) it is also said to have more
    positional entropy.
  • Increasing moles of gas
  • Increasing volume
  • Decreasing pressure
  • Changing state of matter ( s ? l ? g )
  • Exothermic rxns

7
Try Me Conceptual
  • Determine which of the following pairs has the
    most positional entropy
  • 1 mol H2 at STP or 1 Mol H2 at 100oC, 0.5 atm
  • 1 mol N2 at STP or 1 mol N2 at 100 K 2atm
  • 1 mol H2O(s) at 0oC or 1 mole H2O(l) at 20oC

8
2nd Law of Thermodynamics
  • Spontaneous processes increase the entropy of the
    universe.

DSuniverse DSsystem DSsurroundings
9
The Value of S
  • Sign is determined by enthalpy
  • exothermic
  • endothermic
  • Magnitude is determined by temperature

10
Try Me Calculation
  • The melting point of tungsten (W) is the second
    highest among the elements, at 3680 K. The
    enthalpy of fusion for this metal is 35.2 kJ/mol.
    What is the entropy of fusion?

11
3rd Law of Thermodynamics
  • The entropy of a perfect crystal at 0 Kelvin is
    zero.

In Phase Out of Phase Angle Bending Rotation Tr
anslation
vibrations
12
Entropy for a chemical reaction
  • DSorxn SnSop - SnSor

13
Try Me
  • Calculate the change in entropy at 25oC for the
    reaction
  • 2 NiS 3 O2 ? 2 SO2 2 NiO
  • Given Entropy Values
  • SO2 248 J/Kmol
  • NiO 38 J/Kmol
  • O2 205 J/Kmol
  • NiS 53 J/Kmol

14
Free Energy
  • Gibbs Free Energy- another method for determining
    spontaneity.
  • Also indicates the amount of available energy
    that is capable of doing work.
  • As an energy source is used, the energy is not
    destroyed, only converted to a non-usable form.

15
DG DH - TDS
  • Defines Gibbs energy in terms of enthalpy and
    entropy.
  • All three factors will contribute to reaction
    spontaneity.
  • When DG is negative, the reaction is spontaneous.

16
Rearrange that formula
  • Lets start with the following 3 formulae
  • DG DH TDS
  • DSsurr -DH/T
  • DSuniv DSsurr DSsyst

DSuniverse - DG /T
17
Fancy Pants Charts
DO NOT MEMORIZE
DH DS DG Spontaneous?
__ __ Always
__ __ /- When temp is low
/- When temp is high
__ Never
18
Free Energy in Chemical Reactions
  • Standard Free energy is used so that we can
    compare the relative tendency to occur.
  • DGo DHo TDSo

19
2SO2(g) O2(g) ? 2SO3(g)
  • The above rxn. Occurs at 25oC and 1 atm.
    Calculate DHo, DSo, and DGo using the following
    data
  • substance DHof So
  • kJ/mol J/Kmol
  • SO2(g) -297 248
  • SO3(g) -396 257
  • O2(g) 0 205

20
It also works like Hesss Law problems
  • What is the DGo for the reaction if the mechanism
    is
  • Cdi(s) O2(g) ? CO2(g) DGo -397kJ
  • Cgr(s) O2(g) ? CO2(g) DGo -394 kJ

21
Dependence on Pressure
  • Enthalpy does not depend on pressure.
  • Entropy does depend on temperature.
  • S low pressure gt S high pressure

22
DG DGo RT ln(P)
  • This can be adapted to reflect partial pressures
    for the reaction it describes. When that occurs,
    the formula can be re-written

DGo -RT ln(Q)
23
_at_ Equilibrium
  • K Q
  • The free energy is the lowest possible it will
    ever be for the system.

24
Try Me Out
  • The overall rxn for rusting iron by oxygen is
  • 4Fe(s) 3O2(g) ?? 2 Fe2O3(s)
  • _at_25oC, find the equilibrium constant given
  • Substance DHo So
  • Fe2O3(s) -826 90
  • Fe(s) 0 27
  • O2(g) 0 205

25
Free Energy and Work
  • Achieving the maximum amount of work from a
    process is highly unlikely because of transfers
    of energy.
  • DG represents the maximum possible quantity of
    work a system is capable of doing.
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