Title: Specific Heat
1Chapter 3
- Specific Heat
- Part 1 and Part 2
2Specific Heat
- Different substances require different amounts of
heat to change their temperature. - In general the specific heat of a substance
indicates how hard something is to heat up or
cool down. - Scientifically speaking the specific heat is the
amount of heat required to change the temperature
of 1 gram of a substance by 1ºC.
3- Which substance is the easiest to heat up or cool
down?
4?
- Which substance is the easiest to heat up or cool
down?
5- Which substance is the hardest to heat up or cool
down?
6?
- Which substance is the hardest to heat up or cool
down?
7?
- Which substance is the hardest to heat up or cool
down? - How might we observe the high specific heat of
water?
8Flying Freddie Spooner 2014 Tri-Valley
Cannonball Champion
9?
- Scientific interpretation of the specific heat of
water.
10The specific heat of water
- The specific heat of water is 4.184 J/gºC.
- To simplify our discussion we will round this to
4 J/gºC.
11The specific heat of water
- If we have one gram of water at 25ºC and we add
4J of energy to it what will the temperature be? - Answer 26ºC
12The specific heat of water
- If we have two grams of water at 30ºC and we
remove 16J of energy from it what will the
temperature be? - Answer 28ºC
13The specific heat of water
- The high specific heat of water has many
implications to our everyday lives.
14Importance of Waters High Specific Heat
- Maintenance of Body Temperature
15Importance of Waters High Specific Heat
- Heat Storage on a Larger Scale.
16Importance of Waters High Specific Heat
- Temperature fluctuations that permit life.
17Heat and Temperature Video (Physics
Demonstrations 16)
18How Much Heat?
- I want to heat some water.
- What do I need to know in order to determine the
amount of heat required? - Mass of water.
- Temperature Change
- Specific Heat of Water
19H m ?T Cp Heat (mass) x (change in
temperature) x (specific heat)
20Kilojoules
- kilo (k) 1000
- kJ 1000 J
- 4.08 kJ 4080 J
21- How much heat is necessary to heat 258g of water
from 25.0ºC to 100.0ºC? - (258g)(75.0ºC)(4.184J/gºC) 80,960.4J 81,000J
- 81.0 kJ
22- How much heat must be removed to cool 1058g of
copper from 325.0ºC to 18.0ºC? - (1058g)(307.0ºC)(0.385J/gºC) 125,050J
125,000J - 125 kJ
23How much water do I have?
52.8 ml 52.8 cm3 or 52.8 g
24- The mass of an unknown metal is 14.9 g. It is
heated to 100.0?C and dropped into 75.0 mL of
water at 20.0?C. The final temperature of the
system is 28.5?C. What is the specific heat of
the metal?
25- The mass of unknown metal is 17.19 g. It is
heated to 100.00?C and dropped into 25.00 mL of
water at 24.50?C. The final temperature of the
system is 30.05?C. What is the specific heat of
the metal?
Heat gained by the water Heat lost by the
metal m ?T Cp m ?T Cp (25.00g)(5.55C)(4.184
J/g ?C) (17.19g)(69.95C)(x)
Cp 0.483 J/g C
26Homework