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About Formulas

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Relationship between empirical and molecular formulas The ... 7.68) = 4.32 g Percent H2O = 4.32 g X 100% = 36% 12.00 g Percent composition from experimental ... – PowerPoint PPT presentation

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Title: About Formulas


1
About Formulas
2
Types of Bonding
3
Metals vs. Nonmetals
  • Most of the elements in the periodic table are
    metals.
  • Except for H, everything to the left of the
    staircase is a metal
  • Nonmetals are located to the right of the
    staircase.

4
Crystal Lattice vs. Molecule
  • Molecule Discrete unit, definite number of
    atoms. All molecules of a given compound are
    identical. Exact formula.
  • Crystal Lattice Regular, repetitive, 3-D
    arrangement of atoms, ions, or molecules. No set
    size. Not perfect. No two exactly alike.
  • Formula gives smallest whole number ratios.
    (Formula unit). Exact formulas NOT useful.

5
2-D repetitive patterns
6
NaCl
Crystals 3-D repetitive patterns
7
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8
Formulas
  • Tell the type number of atoms in a compound.
  • Microscopic level imagine 1 atom, molecule, or
    formula unit.
  • Formula gives atom ratios.
  • Macroscopic level imagine working in the lab
  • Formula gives mole ratio

9
Formulas
  • Ex 2H2O can mean
  • 2 molecules of water
  • 2 moles of water.
  • 2H2O molecules have 4 hydrogen atoms 2 oxygen
    atoms.
  • 2 Moles of H2O molecules have 4 moles of
    hydrogen atoms 2 moles of oxygen atoms.

10
Ionic vs. Covalent Formulas
  • By looking at the type of atoms, we can decide if
    the substance is an ionic compound or a molecular
    (covalent) compound.

Molecular compounds usually have all
nonmetals. Ionic compounds usually have metal
nonmetal.
11
Empirical Formula
  • Smallest whole number ratio of the elements in
    the compound.
  • Ionic compounds have only empirical formulas.
  • Covalent compounds have empirical and molecular
    formulas. They can be the same or different.

12
Molecular Formulas
  • For covalent (molecular) compounds.
  • Give the exact composition of the molecule.
  • Molecular compounds have both empirical and
    molecular formulas. They can be the same or
    different.

13
Say everything you can about
  • NaCl C6H6 C6H12O6
  • CH4 CF4 BeSO4
  • C8H18 KI C2H4Cl2
  • CaBr2 CuSO4?5H2O

Covalent, molecular
Ionic, empirical
Covalent, molecular
Covalent, empir., molec?
Covalent, empirical, molecular?
Ionic, empirical
Ionic, empirical
Covalent, molecular
Covalent, molecular
Ionic, empirical
Ionic, empirical
14
Say everything you can about
  • PH3 C2H4 Al2O3
  • SrI2 NF3 H2Se
  • CH3OH SiO2 H2O2
  • CCl4 XeF4 P4O10

15
Empirical Formulas from Composition
  • Convert to mass.
  • Convert to moles.
  • Divide by small.
  • Multiply til whole.
  • Note 1 last step not always used.
  • Note 2 sometimes you start at step 2, if they
    give analysis data in grams.

16
Compound 63.52 Fe 36.48 S
  • Convert to grams Assume 100 g sample-size to
    make math easy.
  • 63.52 g Fe and 36.48 g S
  • Convert to moles Divide by atomic masses.
  • 63.52 g Fe / 55.8 g Fe/mol Fe 1.138 mol Fe
  • 36.48 g S / 32.1 g S/mol S 1.136 mol S

17
Compound 63.52 Fe 36.48 S
  • Divide by small This is where you take the
    ratio.
  • 1.136 and 1.138 are essentially the same. Divide
    both by 1.136 and get 1 for each.
  • Empirical formula is FeS.

18
26.56 K, 35.41 Cr, remainder O
  • Assume 100-g sample size.
  • 26.56 g K
  • 35.41 g Cr
  • 38.03 g O
  • Convert to moles.
  • 26.56 g K / 39.1 g K/mol K 0.679 mol K
  • 35.41 g Cr / 52.0 g Cr/mol Cr 0.681 mol Cr
  • 38.03 g O / 16.0 g O/mol O 2.38 mol O

19
26.56 K, 35.41 Cr, remainder O
  • Divide by small
  • 0.679 and 0.681 are essentially the same.
  • Much smaller than 2.38.
  • Divide each by 0.68
  • K 1, Cr 1, O 3.5 KCrO3.5? No decs
  • Multiply til whole
  • K2Cr2O7. Multiply all three by 2, doesnt change
    relationship.

20
Relationship between empirical and molecular
formulas
  • The molecular formula is a whole number multiple
    of the empirical formula.
  • Molec. Formula n (Empirical Form.)
  • n is a small whole number, which multiplies the
    subscripts. Sometimes, n 1.

21
Molecular Formula
  • If you know the empirical formula and the molar
    mass, you can find the molecular formula.
  • Step 1 Find the mass of the empirical formula.
  • Step 2 Molar mass ? Empirical mass small
    whole number, n
  • Step 3 Multiply the subscripts in the empirical
    formula by n.

22
Finding Molecular Formulas
  • Find the molecular formula for the substance
    whose empirical formula is CH and whose molar
    mass 78.0 g
  • Step 1 Empirical mass 13.0 g
  • Step 2 Molar mass n 78.0/13.0
  • n 6.
  • Step 3 6 X subscripts in CH C6H6.

Empirical mass
23
What can you say about CuSO4?5H2O?
  • Its a hydrated salt.
  • For every mole of CuSO4, there are 5 moles of
    water.
  • If its heated, it dries out. The water goes
    into the air and youre left with the anhydrous
    salt, CuSO4.
  • CuSO4?5H2O ? CuSO4 5H2O

?
24
CuSO4?5H2O ? CuSO4 5H2O
?
  • The mole ratio in the formula can be used to
    predict how much water would be given off by any
    size sample.
  • If you had 2 moles of CuSO4?5H2O, how much water
    would you lose on heating?
  • If you had 5 moles of CuSO4?5H2O, how much water
    would you lose?

25
Percent Water in CuSO45H2O
  • Step 1 Calculate the formula mass.
  • Mass of salt Mass of water
  • Percent (Part/Whole) X 100
  • H2O Mass H2O/Formula Mass X 100

composition from the formula
26
Percent Water in CuSO45H2O
  • 12.00 grams of CuSO45H2O are heated gently.
  • The final mass after repeated heatings is 7.68
    grams. What is the of water?
  • Mass of H2O (12.00 7.68) 4.32 g
  • Percent H2O 4.32 g X 100 36

12.00 g
Percent composition from experimental data
27
CuSO4?xH2O ? CuSO4 xH2O
?
  • Use experimental data to find x
  • 12.00 grams of CuSO45H2O are heated gently.
    (Hydrated salt.)
  • 7.68 g mass anhydrous salt remaining mass
    CuSO4.
  • Mass of H2O (12.00 7.68) 4.32 g

28
CuSO4?xH2O ? CuSO4 xH2O
?
  • Note moles of CuSO4 moles of H2O can be
    determined.
  • Have grams already.
  • Convert to moles
  • Divide by small
  • Multiply til whole.

29
CuSO4?xH2O ? CuSO4 xH2O
?
  • 7.68 g CuSO4 / 159.6 g/mol
  • 0.04812 mol CuSO4
  • 4.32 g H2O / 18.0 g/mol
  • 0.240 mol H2O
  • Divide by small, which is 0.04812
  • CuSO4?5H2O
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