Title: Electric Potential
1Electric Potential
2Gravitational Potential Energy
3Electric Potential Energy
?PEE (qoE)?d Fd W
?PEE qoE(dA dB )
W DET ?PEE
- Does a proton at rest at point A have more or
less potential energy than it would at point B?
More
4Electric Potential Energy of Point Charges and
Work
- Much like the book is attracted to the earth due
to gravity, two unlike charges are attracted to
one another. - Conversely, like charges repel.
- It takes positive work to move unlike charges
away from one another and like charges closer
together.
5Electric Potential Energy
- What would happen if the charged particle q was
fixed in place and then particle qo was suddenly
released from rest? - It would accelerate away from q.
- It would accelerate towards q.
- It would stay where it is.
- How would the potential energy of this
- system change?
- It would increase.
- It would decrease.
- It would remain the same.
6Electric Potential
We know that W Fd qEd. We can define the
amount of work per unit of charge as
This is also called V (voltage) or potential
difference.
(You could conceive of an analogue as work / unit
mass, although I know of no use for it )
7Electric Potential
- SI Units joule/coulomb 1 volt (V)
- The Electric Potential is the energy per unit of
charge (J/C). - We may write it as to emphasize
- the fact that it is a potential difference and
that the zero is arbitrary (like gravity)
8Example 1 Electric Potential
- An object with 2.5?C of charge requires
1.00x10-3 Joules of energy to move it through an
electric field. What is the potential difference
through which the charge is moved?
9Characteristics of a Capacitor
E
- Since the electric field is constant, the force
acting on a charged particle will be the same
everywhere between the plates. - Fe qoE
FA FB FC
10Electric Potential and Work in a Capacitor
D
WAB FdB - FdA
A
qo
WAB qoE?d
F qoE
WAB qo
?V
qo
C
If WAB qoE?d, then what is WCD?
- WCD 0 Joules because the force acts
perpendicular to the direction of motion. - Do you remember that W Fdcos??
11Electric Potential of a Capacitor An alternative
- From mechanics, W Fd.
- From the previous slide, W qoEd
- From the reference table, ?V W/qo
Two equal and oppositely charged plates
A
B
qo
F qoE
Uniform Electric Field
?V WAB/qo Fd/qo qoEd/qo Ed
12Example 2Parallel Plates
- A spark plug in an automobile engine consists of
two metal conductors that are separated by a
distance of 0.50 mm. When an electric spark jumps
between them, the magnitude of the electric field
is 4.8 x 107 V/m. What is the magnitude of the
potential difference V between the conductors?
V Ed
V (4.8 x 107 V/m)(5.0 x 10-4m)
V 24,000V
13Example 3 Parallel Plates
- A proton and an electron are released from rest
from a similarly charged plate of a capacitor.
The electric potential is 100,000 V and the
distance between the two plates is 0.10 mm. - Which charge will have greater kinetic energy at
the moment it reaches the opposite plate? - Determine the amount of work done on each
particle. - Determine the speed of each particle at the
moment it reaches the opposite plate. - Determine the magnitude of the force acting on
each particle. - Determine the magnitude of the acceleration of
each particle.
14Example 3 Parallel Plates(cont.)
p
e-
- Begin by drawing a picture and listing what is
known - V 100,000V
- d 0.10 mm 1.0 x 10-4m
- qe qp 1.6 x 10-19C (ignore the sign. We are
only interested in magnitude.)
15Example 3 Parallel Plates(1 2)
- For 1, you could answer 2 first to verify.
- The answer is that the kinetic energy of both
particles will be the same - Why?
- because of the formula needed in question 2
applies to both charges, and work energy. - Hence Wproton Welectron
- qprotonV qelectronV
- Wproton Welectron (1.6x10-19C)(100,000V)
- Wproton Welectron 1.6x10-14 J
16Example 3 Parallel Plates(3)
- Apply the work-energy theorem to determine the
final speed of the electron and proton. - W ?KE
- Since the initial kinetic energy is equal to 0J
- W KEf
- W ½ mvf2
- Proton
- Electron
17Example 3 Parallel Plates(4)
- Since F qE, it will be the same for both
particles because their charges are the same and
the electric field is uniform between two
parallel plates. - We also know that W F?d. Since we know the
distance between the plates and the work done to
move either charge from one plate to another, we
can determine the force as follows
18Example 3 Parallel Plates(5)
- Since we have the force acting on each particle,
we can now calculate the acceleration of each
particle using Newtons 2nd Law.
19Equipotential Lines
- Equipotential lines denote where the electric
potential is the same in an electric field. - The potential is the same anywhere on an
equipotential surface a distance r from a point
charge, or d from a plate. - No work is done to move a charge along an
equipotential surface. Hence VB VA (The
electric potential difference does not depend on
the path taken from A to B). - Electric field lines and equipotential lines
cross at right angles and point in the direction
of decreasing potential.
20Equipotential Lines
Electric Field Lines
Decreasing Electric Potential / Voltage
21Equipotential Lines
Electric Field Lines
Note A charged surface is also an equipotential
surface!
Decreasing Electric Potential / Voltage
22Equipotential Lines (Examples)
- http//www.cco.caltech.edu/phys1/java/phys1/EFiel
d/EField.html
23Key Ideas
- Electric potential energy is the work required to
bring a positive unit charge from infinity to a
point in an electric field. - Electric potential (V) is the change in energy
per unit charge as the charge is brought from one
point to another. - The electric field between two charged plates is
constant meaning that the force is constant
between them as well. - The electric potential between two points is not
dependent on the path taken to get there.
(Similar to gravity and gravitational PE.) - Electric field lines and lines of equipotential
intersect at right angles.
24Electric Potential
We know that W Fd qEd. We can define the
amount of work
- SI Units joule/coulomb 1 volt (V)
- The Electric Potential Difference is equal to the
Work required to move a test charge from infinity
to a point in an electric field divided by the
magnitude of the test charge. - The Electric Potential is the energy per unit of
charge (J/C).