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Modern Chemistry Chapter 9 Stoichiometry

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Title: Modern Chemistry Chapter 9 Stoichiometry


1
Modern Chemistry Chapter 9Stoichiometry
2
Modern Chemistry Chapter 9Stoichiometry
  • composition stoichiometry deals with the mass
    relationships of elements in compounds.
  • reaction stoichiometry involves the mass
    relationships between reactants and products in a
    chemical reaction.

3
Types of Stoichiometry Problems
  • mole to mole (Both the given and the unknown
    quantities are amounts in moles.)
  • mole to mass (The given amount is in moles and
    the unknown amount is in grams.)
  • mass to mole (The given amount is in grams and
    the unknown amount is in moles.)
  • mass to mass (Both the given and the unknown
    amount is in grams.)

4
Mole Ratio Molar Mass
  • mole ratio- A conversion factor that relates the
    amounts in moles of any two substances involved
    in a chemical reaction.
  • Found by using the coefficients in the balanced
    formula equation of the reaction.
  • molar mass- Equal to the mass in grams of one
    mole of an element or a compound.
  • Found by adding the individual element atomic
    masses from the formula of the compound.

5
Section Review Problems
  • Do section review problems
  • 1 through 4 on page 301 of the textbook.

6
Section Review page 301
  • 1- The branch of chemistry that deals with mass
    relationships in compounds and in chemical
    reactions.
  • 2 HgO ? 2 Hg O2
  • 2- a) 2 mol HgO 2 mol HgO
  • 2 mol Hg 1 mol O2
  • 2 mol Hg 2 mol Hg
  • 2 mol HgO 1 mol O2
  • 1 mol O2 1 mol O2
  • 2 mol HgO 2 mol Hg

7
Section Review page 301
  • 3- It is used to convert moles of one substance
    into moles of another substance.
  • 4- The formula equation MUST be BALANCED so mole
    ratios can be determined.

8
Using Conversion Factors
  • Amount coefficient amount of
  • of given x of unknown unknown
  • substance coefficient substance
  • in moles of known in moles
  • moles x mole ratio moles of
  • given unknown
  • Do practice problems 1 2 on page 306 of text.

9
Page 306 1
  • 3 H2 N2 ? 2 NH3
  • 6 mol H2 x 2 mol NH3 4mol NH3
  • 3 mol H2

10
Page 306 2
  • 2 KClO3 ? 2 KCl 3 O2
  • 15 mol O2 x 2 mol KClO3 10 mol KClO3
  • 3 mol O2

11
Chapter 9 quiz 1- mole to mole calculations
  • 6 NaBr Mg3(PO4)2 ? 2 Na3PO4 3 MgBr2
  • Use the above balanced formula equation to solve
    the following
  • 1- 7.0 moles of NaBr will produce ? moles Na3PO4
  • 2- 3.0 moles of Mg3(PO4)2 will yield ? moles
    MgBr2
  • 3- 0.5 moles of NaBr will react with ? moles
    Mg3(PO4)2
  • 4- 2.5 moles of NaBr will yield ? moles Na3PO4
  • 5- 2.5 moles NaBr will produce ? moles MgBr2

12
6 NaBr Mg3(PO4)2 ? 2 Na3PO4 3 MgBr2
  • 1- 7 mol NaBr x 2 mol Na3PO4 2.3 mol
    Na3PO4
  • 6 mol NaBr
  • 2- 3 mol Mg3(PO4)2 x 3.0 mol MgBr2 9 mol
    MgBr2
  • 1 mol Mg3(PO4)2
  • 3- 0.5 mol NaBr x 1 mol Mg3(PO4)2 0.083 mol
  • 6 mol NaBr
  • 4- 2.5 mol NaBr x 2 mol Na3PO4 0.83 mol
    Na3PO4
  • 6 mol NaBr
  • 5- 2.5 mol NaBr x 3 mol MgBr2 1.25 mol
    MgBr2
  • 6 mol NaBr

13
Using Conversion Factors
  • amount of mass in
  • given x moles unknown x molar grams
    of
  • substance moles known mass of unknown
  • in moles unknown substance
  • moles x mole x molar mass
    of unknown
  • given ratio mass (in grams)
  • unknown
  • Do practice problems 1 2 on page 308 of the
    textbook.

14
Page 308 1 2
  • 2 Mg O2 ? 2 MgO
  • 2.00 mol Mg x 2 mol MgO x 40.3 g MgO 80.6 g
    MgO
  • 2 mol Mg 1 mol MgO
  • 6 CO2 6 H2O ? C6H12O6 6 O2
  • 10 mol CO2 x 1 mol C6H12O6 x 180 g C6H12O6 300
    g C6H12O6
  • 6 mol CO2 1 mol C6H12O6

15
Chapter 9 Quiz 2- mole-mass problems
  • 3 MgF2 Al2O3 ? 3 MgO 2 AlF3
  • Use the above balanced formula equation to answer
    the following questions.
  • 1- 2.0 mol MgF2 will yield ? grams of MgO
  • 2- 4.0 mol of Al2O3 ? ? grams of AlF3
  • 3- If 6.0 mol of MgO is produced, ? grams of
    AlF3
  • 4- 0.6 mol MgF2 ? ? grams of AlF3
  • 5- 2.75 mol Al2O3 ? ? grams of MgO

16
3 MgF2 Al2O3 ? 3 MgO 2 AlF3
  • 1- 2.0 mol MgF2 x 3 mol MgO x 40.3 g MgO
    80.6 g
  • 3 mol MgF2 1 mol MgO MgO
  • 2- 4.0 mol Al2O3 x 2 mol AlF3 x 84.0 g AlF3
    672.0g
  • 1 mol Al2O3 1 mol AlF3 AlF3
  • 3- 6.0 mol MgO x 2 mol AlF3 x 84.0 g AlF3
    336 g AlF3
  • 3 mol MgO 1 mol AlF3
  • 4- 0.6 mol MgF2 x 2 mol AlF3 x 84.0 g AlF3
    33.6 g AlF3
  • 3 mol MgF2 1 mol AlF3
  • 5- 2.75 mol Al2O3 x 3 mol MgO x 40.3 g MgO
    332gMgO
  • 1 mol Al2O3 1 mol MgO

17
Using Conversion Factors
  • mass (g) x 1 mol given x mol unknown
    moles of
  • of given molar mass mol given
    unknown
  • substance of given substance
  • grams x 1 x mole ratio moles unknown
  • molar mass
  • Do practice problems 1 2 on page 309 of the
    textbook.

18
Practice problems page 309
  • 2 HgO ? 2 Hg O2
  • 125 g O2 x 1 mol O2 x 2 mol HgO 7.81 mol HgO
  • 32 g O2 1 mol O2
  • 125 g O2 x 1 mol O2 x 2 mol Hg 7.81 mol Hg
  • 32 g O2 1 mol O2

19
chapter 9 quiz 3- mass-mole problems
  • Na2O CaF2 ? 2 NaF CaO
  • Use the above equation to solve the problems.
  • 1- 156.1 grams of CaF2 ? ? mol CaO
  • 2- 186 g Na2O ? ? mol NaF
  • 3- 31 g Na2O ? ? mol CaO
  • 4- 31 g Na2O ? ? mol NaF
  • 5- A yield of 84 g NaF ? ? mol CaO

20
Na2O CaF2 ? 2 NaF CaO
  • 1- 156.1 g CaF2 x 1 mol CaF2 x 1 mol CaO
    2.00 mol CaO
  • 78.1 g CaF2 1 mol CaF2
  • 2- 186.0 g Na2O x 1 mol Na2O x 2 mol NaF
    6.0 mol NaF
  • 62 g Na2O 1 mol Na2O
  • 3- 31.0 g Na2O x 1 mol Na2O x 1 mol CaO
    0.5 mol CaO
  • 62.0 g Na2O 1 mol Na2O
  • 4- 31.0 g Na2O x 1 mol Na2O x 2 mol NaF
    1.0 mol NaF
  • 62.0 g Na2O 1 mol Na2O
  • 5- 84.0 g NaF x 1 mol NaF x 1 mol CaO
    1.0 mol CaO
  • 42.0 g NaF 2 mol NaF

21
Chemistry Chapter 9- Stoichiometry Practice
Problems
  • 2 NaF CaO ? Na2O CaF2
  • 1- 4.5 moles of NaF will produce -?- moles of
    Na2O ?
  • 4.5 mol NaF x 1 mol Na2O/2 mol NaF 2.25
    moles Na2O
  •  
  • 2- 3.2 moles of CaO will produce -?- grams of
    CaF2 ?
  • 3.2 mol CaO x 1 mol CaF2/1 mol CaO x 78.1
    g CaF2/mol CaF2 249.9 g CaF2
  •  

22
  • 2 NaF CaO ? Na2O CaF2
  •  
  • 3- 168.0 grams of NaF will produce -?- moles of
    Na2O ?
  • 168.0 /42.0 x 1 /2 2.0 mol Na2O
  •  
  • 4- 112.2 grams of CaO will produce -?- moles of
    CaF2 ?
  • 112.2/56.1 x 1/1 2.0 mol CaF2
  •  
  •  

23
  • 5- Calculate the molar mass of each of the
    reactants products of the above balanced
    formula equation. Use the molar masses in the
    following problems.
  • a- AlN
  • (1 x 27.0) (1 x 14.0) 41.0 g/mol
  • b- Na2O
  • (2 x 23.0) (1 x 16.0) 62.0 g/mol
  • c- Al2O3
  • (2 x 27.0) (3 x 16.0) 102.0 g/mol
  • d- Na3N
  • (3 x 23.0) (1 x 14.0) 83.0 g/mol

24
  • 2 AlN 3 Na2O ? Al2O3 2 Na3N
  • 6- 82.0 grams of AlN will produce -?- moles of
    Al2O3 ?
  • 82.0/41.0 x 1/2 1.0 mol Al2O3
  •  
  • 7- 164.0 grams AlN will produce -?- moles of
    Na3N ?
  • 164.0/41.0 x 2/2 4.0 mol Na3N

25
  • 2 AlN 3 Na2O ? Al2O3 2 Na3N
  • 8- 2.5 moles of Na2O will produce -?- grams of
    Na3N ?
  • 2.5 x 2/3 x 83.0 138.3 g Na3N
  •  
  • 9- 0.75 moles of Na2O will produce -?- moles
    of Al2O3 ?
  • 0.75 x 1/3 0.25 mol Al2O3
  •  
  • 10- 11.0 moles of Na2O will produce -?- grams
    of Na3N ?
  • 11.0 x 2/3 x 83.0 608.7 g Na3N

26
  • 2 H2 O2 ? 2 H2O
  • 11- 8.0 grams of H2 will react with -?- moles
    of O2 ?
  • 8.0/2.0 x 1/2 2.0 mol O2
  •  
  • 12- 64.0 grams of O2 will produce -?- moles of
    H2O ?
  • 64.0/32.0 x 2/1 4.0 mol H2O
  •  
  • 13- 0.25 moles of H2 will produce -?- moles of
    H2O ?
  • 0.25 x 2/2 0.25 mol H2O

27
  • 2 H2 O2 ? 2 H2O
  • 14- 1.5 moles of H2 will produce -?- grams of
    H2O ?
  • 1.5 x 2/2 x 18.0 27.0 g H2O
  •  
  • 15- 14 moles of O2 will produce -?- moles of
    H2O ?
  • 14 x 2/1 28.0 mol H2O

28
Using Conversion Factors
  • mass (g) x 1 mol given x mol unknown x
    molar mass unknown mass
  • of given molar mass mol given
    1 mol unknown of un-
  • substance of given
    known
  • grams x 1 x mole ratio x molar mass
    mass of unknown
  • given molar mass
  • Do practice problems 1, 2, 3 on page 311 of
    textbook.
  • Do section review problems 1 - 5 on page 311 of
    textbook.

29
Practice problems page 311
  • NH4NO3 ? N2O 2 H2O
  • 32 g N2O x 1 mol N2O x 1 mol NH4NO3 x 80 g
    NH4NO3 60 g NH4NO3
  • 44 g N2O 1 mol N2O 1 mol
    NH4NO3

30
Chapter 9 quiz 4- mass-mass problems
  • Na2O CaF2 ? 2 NaF CaO
  • 1- 124 g Na2O ? ? grams NaF
  • 2- 124 g Na2O ? ? grams CaO
  • 3- 234.3 g CaF2 ? ? g NaF
  • 4- 234.3 g CaF2 ? ? g CaO
  • 5- 84.0 g NaF ? ? g CaO

31
Na2O CaF2 ? 2 NaF CaO
  • 1- 124 g Na2O x 1 mol Na2O x 2 mol NaF x
    42.0 g NaF 168 g
  • 62 g Na2O 1 mol Na2O 1 mol
    NaF
  • 2- 124 g Na2O x 1 mol Na2O x 1 mol CaO x
    56.1 g CaO 112.2 g
  • 62 g Na2O 1 mol Na2O 1 mol CaO
  • 3- 234.3 g CaF2 x 1 mol CaF2 x 2 mol NaF x
    42.0 g NaF 252 g
  • 78.1 gCaF2 1 mol CaF2 1 mol NaF
  • 4- 234.3 g CaF2 x 1 mol CaF2 x 1 mol CaO x
    56.1 g CaO 168.3 g
  • 78.1 gCaF2 1 mol CaF2 1 mol CaO
  • 5- 84.0 g NaF x 1 mol NaF x 1 mol CaO x 56.1
    g CaO 56.1 g
  • 42.0 g NaF 2 mol NaF 1 mol CaO

32
The MOLE HILL
  • x mole ratio
  • moles known moles unknown
  • molar mass x molar mass
  • of known of unknown
  • mass of known mass of unknown

33
Stoichiometry Practice Problems
  • 2 H2 O2 ? 2 H2O
  • 1) 2.5 mol H2 x 1 mol O2 1.25 mol O2
  • 2 mol H2
  • 2) 2.5 mol H2 x 2 mol H2O 2.5 mol H2O
  • 2 mol H2
  • 3) 2.5 mol H2 x 1 mol O2 x 32 g O2 40 g O2
  • 2 mol H2 1 mol O2
  • 4) 2.5 mol H2 x 2 mol H2O x 18 g H2O 45 g
    H2O
  • 2 mol H2 1 mol H2O

34
Stoichiometry Practice Problems
  • 2 H2 O2 ? 2 H2O
  • 5) 16 g H2 x 1 mol H2 x 1 mol O2 4.0 mol O2
  • 2 g H2 2 mol H2
  • 6) 16 g H2 x 1 mol H2 x 2 mol H2O 8.0 mol H2O
  • 2.0 g H2 2 mol H2
  • 7) 16 g H2 x 1 mol H2 x 1 mol O2 x 32 g O2 128
    g O2
  • 2.0 g H2 2 mol H2 1 mol O2
  • 8) 16 g H2 x 1 mol H2 x 2 mol H2O x 18 g H2O
    144 g H2O
  • 2.0 g H2 2 mol H2 1 mol H2O

35
Limiting Reactant Percentage Yield
  • limiting reactant is the reactant that limits the
    amount of the other reactant that can combine and
    the amount of product that can be formed in a
    chemical reaction.
  • excess reactant is the substance that is NOT
    completely used up in a chemical reaction.

36
Sample Practice Problems
  • See sample problem F on page 313 of textbook.
  • Do practice problems 1 on page 313.
  • See sample problem G on pages 314-315.
  • Do practice problems 1 2 on page 315.

37
QuickLAB
  • Do the QuickLAB titled Limiting Reactants in a
    Recipe on page 316 of the textbook.
  • Yes, cooking IS chemistry!

38
Percentage Yield
  • theoretical yield is the maximum amount of
    product that can be produced from a given amount
    of reactant
  • actual yield of a product is the measured amount
    of a product obtained from a reaction
  • percentage yield is the ratio of the actual yield
    to the theoretical yield multiplied by 100
  • percentage yield actual yield x 100
  • theoretical yield

39
Problems
  • see sample problem H on pages 317-318 of textbook
  • Do practice problems 1 2 on page 318.
  • Do section review problems 1 - 4 on page
    318.
  • Do critical thinking problems 37, 38, 39,
    40 on pages 322 323.

40
Chapter 9 test review
  • 20 multiple choice questions
  • definitions of composition reaction
    stoichiometry
  • mole ratios their definition use
  • SI units of molar mass
  • identify mole ratio from balanced formula
    equation
  • 5 mole-mole problems
  • Definitions practical applications of excess
    reactant limiting reactant
  • definitions practical applications of
    theoretical yield, actual yield, yield

41
Honors Chemistry Chapter 9 Test Review
  • 25 multiple choice
  • Know the definitions of reaction composition
    stoichiometry, mole ratio, and units of molar
    mass.
  • Know what mole ratio means and how it is used in
    stoichiometry.
  • Determine mole ratio using balanced formula
    equation. (2)
  • Perform mole to mole stoichiometric calculations
    (4).
  • Perform mole to mass stoichiometric calculations
    (1).
  • Perform mass to mole stoichiometric calculations
    (1).
  • Perform mass to mass stoichiometric calculations
    (1).
  • Know definitions and applications of limiting and
    excess reactants.
  • Know the definitions applications of actual
    yield, theoretical yield, and percent yield.

42
Practice 2
  • 2 Na3PO4 3 CaSO4 ? 3 Na2SO4 Ca3(PO4)2
  • Known 3 moles CaSO4 unknown ? Moles Na3PO4
  • 3 x 2/3 2 moles Na3PO4
  • Known 2.0 moles Na3PO4 unknown ? Moles
    Na2SO4
  • 2 x 3/2 3 moles Na2SO4
  • Known 1.5 moles Ca3(PO4)2 unknown ? Moles
    CaSO4
  • 1.5 x 3/1 4.5 moles CaSO4
  • Known 4.4 moles CaSO4 unknown ? Moles
    Na3PO4
  • 4.4 x 2/3 2.9 moles Na3PO4

43
  • 2 Na3PO4 3 CaSO4 ? 3 Na2SO4 Ca3(PO4)2
  • Known 6.0 moles Na3PO4 unknown ? Moles
    Na2SO4
  • 6.0 x 3/2 9.0 moles Na2SO4
  • Known 5.4 moles CaSO4 unknown ? Moles
    Na3PO4
  • 5.4 x 2/3 3.6 moles Na3PO4
  • Known 0.6 moles Na3PO4 unknown ? Moles
    CaSO4
  • 0.6 x 3/2 0.9 moles CaSO4

44
Stoichiometry Practice 3
  • 4 Na3N 3 O2 ? 6 Na2O 2 N2
  • Assume you have 12.0 moles of Na3N.
  • How many moles of O2 do you need?
  • How many moles of Na2O will you get?
  • How many moles of N2 will you get?

45
Stoichiometry Practice 3
  • 4 Na3N 3 O2 ? 6 Na2O 2 N2
  • Assume you have 12.0 moles of Na3N.
  • How many moles of O2 do you need?
  • 12 x 3/4 9 moles O2
  • How many moles of Na2O will you get?
  • 12 x 6/4 18 moles Na2O
  • How many moles of N2 will you get?
  • 12 x 2/4 6 moles N2

46
Practice 3
  • 4 Na O2 ? 2 Na2O
  • If you have 4 moles of Na, how many grams of O2
    will you need?
  • If you have 64 grams of O2, how many moles of
    Na2O will you produce?
  • If you have 46 grams of Na, how many grams of O2
    will you need?

47
Practice 3
  • 4 Na O2 ? 2 Na2O
  • If you have 4 moles of Na, how many grams of O2
    will you need?
  • 4 x 1/4 x 32 32 grams O2
  • If you have 64 grams of O2, how many moles of
    Na2O will you produce?
  • 64/32 x 2/1 4 moles Na2O
  • If you have 46 grams of Na, how many grams of O2
    will you need?
  • 46/23 x 1/4 x 32 16 grams O2
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