Title: Modern Chemistry Chapter 9 Stoichiometry
1Modern Chemistry Chapter 9Stoichiometry
2Modern Chemistry Chapter 9Stoichiometry
- composition stoichiometry deals with the mass
relationships of elements in compounds. - reaction stoichiometry involves the mass
relationships between reactants and products in a
chemical reaction.
3Types of Stoichiometry Problems
- mole to mole (Both the given and the unknown
quantities are amounts in moles.) - mole to mass (The given amount is in moles and
the unknown amount is in grams.) - mass to mole (The given amount is in grams and
the unknown amount is in moles.) - mass to mass (Both the given and the unknown
amount is in grams.)
4Mole Ratio Molar Mass
- mole ratio- A conversion factor that relates the
amounts in moles of any two substances involved
in a chemical reaction. - Found by using the coefficients in the balanced
formula equation of the reaction.
- molar mass- Equal to the mass in grams of one
mole of an element or a compound. - Found by adding the individual element atomic
masses from the formula of the compound.
5Section Review Problems
- Do section review problems
- 1 through 4 on page 301 of the textbook.
6Section Review page 301
- 1- The branch of chemistry that deals with mass
relationships in compounds and in chemical
reactions. - 2 HgO ? 2 Hg O2
- 2- a) 2 mol HgO 2 mol HgO
- 2 mol Hg 1 mol O2
- 2 mol Hg 2 mol Hg
- 2 mol HgO 1 mol O2
- 1 mol O2 1 mol O2
- 2 mol HgO 2 mol Hg
-
7Section Review page 301
- 3- It is used to convert moles of one substance
into moles of another substance. - 4- The formula equation MUST be BALANCED so mole
ratios can be determined.
8Using Conversion Factors
- Amount coefficient amount of
- of given x of unknown unknown
- substance coefficient substance
- in moles of known in moles
- moles x mole ratio moles of
- given unknown
- Do practice problems 1 2 on page 306 of text.
9Page 306 1
- 3 H2 N2 ? 2 NH3
- 6 mol H2 x 2 mol NH3 4mol NH3
- 3 mol H2
10Page 306 2
-
- 2 KClO3 ? 2 KCl 3 O2
- 15 mol O2 x 2 mol KClO3 10 mol KClO3
- 3 mol O2
11Chapter 9 quiz 1- mole to mole calculations
- 6 NaBr Mg3(PO4)2 ? 2 Na3PO4 3 MgBr2
- Use the above balanced formula equation to solve
the following - 1- 7.0 moles of NaBr will produce ? moles Na3PO4
- 2- 3.0 moles of Mg3(PO4)2 will yield ? moles
MgBr2 - 3- 0.5 moles of NaBr will react with ? moles
Mg3(PO4)2 - 4- 2.5 moles of NaBr will yield ? moles Na3PO4
- 5- 2.5 moles NaBr will produce ? moles MgBr2
12 6 NaBr Mg3(PO4)2 ? 2 Na3PO4 3 MgBr2
- 1- 7 mol NaBr x 2 mol Na3PO4 2.3 mol
Na3PO4 - 6 mol NaBr
- 2- 3 mol Mg3(PO4)2 x 3.0 mol MgBr2 9 mol
MgBr2 - 1 mol Mg3(PO4)2
- 3- 0.5 mol NaBr x 1 mol Mg3(PO4)2 0.083 mol
- 6 mol NaBr
- 4- 2.5 mol NaBr x 2 mol Na3PO4 0.83 mol
Na3PO4 - 6 mol NaBr
- 5- 2.5 mol NaBr x 3 mol MgBr2 1.25 mol
MgBr2 - 6 mol NaBr
13Using Conversion Factors
- amount of mass in
- given x moles unknown x molar grams
of - substance moles known mass of unknown
- in moles unknown substance
- moles x mole x molar mass
of unknown - given ratio mass (in grams)
- unknown
- Do practice problems 1 2 on page 308 of the
textbook.
14Page 308 1 2
- 2 Mg O2 ? 2 MgO
- 2.00 mol Mg x 2 mol MgO x 40.3 g MgO 80.6 g
MgO - 2 mol Mg 1 mol MgO
- 6 CO2 6 H2O ? C6H12O6 6 O2
- 10 mol CO2 x 1 mol C6H12O6 x 180 g C6H12O6 300
g C6H12O6 - 6 mol CO2 1 mol C6H12O6
15Chapter 9 Quiz 2- mole-mass problems
- 3 MgF2 Al2O3 ? 3 MgO 2 AlF3
- Use the above balanced formula equation to answer
the following questions. - 1- 2.0 mol MgF2 will yield ? grams of MgO
- 2- 4.0 mol of Al2O3 ? ? grams of AlF3
- 3- If 6.0 mol of MgO is produced, ? grams of
AlF3 - 4- 0.6 mol MgF2 ? ? grams of AlF3
- 5- 2.75 mol Al2O3 ? ? grams of MgO
163 MgF2 Al2O3 ? 3 MgO 2 AlF3
- 1- 2.0 mol MgF2 x 3 mol MgO x 40.3 g MgO
80.6 g - 3 mol MgF2 1 mol MgO MgO
- 2- 4.0 mol Al2O3 x 2 mol AlF3 x 84.0 g AlF3
672.0g - 1 mol Al2O3 1 mol AlF3 AlF3
- 3- 6.0 mol MgO x 2 mol AlF3 x 84.0 g AlF3
336 g AlF3 - 3 mol MgO 1 mol AlF3
- 4- 0.6 mol MgF2 x 2 mol AlF3 x 84.0 g AlF3
33.6 g AlF3 - 3 mol MgF2 1 mol AlF3
- 5- 2.75 mol Al2O3 x 3 mol MgO x 40.3 g MgO
332gMgO - 1 mol Al2O3 1 mol MgO
17Using Conversion Factors
- mass (g) x 1 mol given x mol unknown
moles of - of given molar mass mol given
unknown - substance of given substance
- grams x 1 x mole ratio moles unknown
- molar mass
- Do practice problems 1 2 on page 309 of the
textbook.
18Practice problems page 309
- 2 HgO ? 2 Hg O2
- 125 g O2 x 1 mol O2 x 2 mol HgO 7.81 mol HgO
- 32 g O2 1 mol O2
-
- 125 g O2 x 1 mol O2 x 2 mol Hg 7.81 mol Hg
- 32 g O2 1 mol O2
19chapter 9 quiz 3- mass-mole problems
- Na2O CaF2 ? 2 NaF CaO
- Use the above equation to solve the problems.
- 1- 156.1 grams of CaF2 ? ? mol CaO
- 2- 186 g Na2O ? ? mol NaF
- 3- 31 g Na2O ? ? mol CaO
- 4- 31 g Na2O ? ? mol NaF
- 5- A yield of 84 g NaF ? ? mol CaO
20Na2O CaF2 ? 2 NaF CaO
- 1- 156.1 g CaF2 x 1 mol CaF2 x 1 mol CaO
2.00 mol CaO - 78.1 g CaF2 1 mol CaF2
- 2- 186.0 g Na2O x 1 mol Na2O x 2 mol NaF
6.0 mol NaF - 62 g Na2O 1 mol Na2O
- 3- 31.0 g Na2O x 1 mol Na2O x 1 mol CaO
0.5 mol CaO - 62.0 g Na2O 1 mol Na2O
- 4- 31.0 g Na2O x 1 mol Na2O x 2 mol NaF
1.0 mol NaF - 62.0 g Na2O 1 mol Na2O
- 5- 84.0 g NaF x 1 mol NaF x 1 mol CaO
1.0 mol CaO - 42.0 g NaF 2 mol NaF
21Chemistry Chapter 9- Stoichiometry Practice
Problems
- 2 NaF CaO ? Na2O CaF2
- 1- 4.5 moles of NaF will produce -?- moles of
Na2O ? - 4.5 mol NaF x 1 mol Na2O/2 mol NaF 2.25
moles Na2O - Â
- 2- 3.2 moles of CaO will produce -?- grams of
CaF2 ? - 3.2 mol CaO x 1 mol CaF2/1 mol CaO x 78.1
g CaF2/mol CaF2 249.9 g CaF2 - Â
22- 2 NaF CaO ? Na2O CaF2
- Â
- 3- 168.0 grams of NaF will produce -?- moles of
Na2O ? - 168.0 /42.0 x 1 /2 2.0 mol Na2O
- Â
- 4- 112.2 grams of CaO will produce -?- moles of
CaF2 ? - 112.2/56.1 x 1/1 2.0 mol CaF2
- Â
- Â
-
23- 5- Calculate the molar mass of each of the
reactants products of the above balanced
formula equation. Use the molar masses in the
following problems. -
- a- AlN
- (1 x 27.0) (1 x 14.0) 41.0 g/mol
- b- Na2O
- (2 x 23.0) (1 x 16.0) 62.0 g/mol
- c- Al2O3
- (2 x 27.0) (3 x 16.0) 102.0 g/mol
- d- Na3N
- (3 x 23.0) (1 x 14.0) 83.0 g/mol
24- 2 AlN 3 Na2O ? Al2O3 2 Na3N
- 6- 82.0 grams of AlN will produce -?- moles of
Al2O3 ? - 82.0/41.0 x 1/2 1.0 mol Al2O3
- Â
- 7- 164.0 grams AlN will produce -?- moles of
Na3N ? - 164.0/41.0 x 2/2 4.0 mol Na3N
25- 2 AlN 3 Na2O ? Al2O3 2 Na3N
- 8- 2.5 moles of Na2O will produce -?- grams of
Na3N ? - 2.5 x 2/3 x 83.0 138.3 g Na3N
- Â
- 9- 0.75 moles of Na2O will produce -?- moles
of Al2O3 ? - 0.75 x 1/3 0.25 mol Al2O3
- Â
- 10- 11.0 moles of Na2O will produce -?- grams
of Na3N ? - 11.0 x 2/3 x 83.0 608.7 g Na3N
26- 2 H2 O2 ? 2 H2O
- 11- 8.0 grams of H2 will react with -?- moles
of O2 ? - 8.0/2.0 x 1/2 2.0 mol O2
- Â
- 12- 64.0 grams of O2 will produce -?- moles of
H2O ? - 64.0/32.0 x 2/1 4.0 mol H2O
- Â
- 13- 0.25 moles of H2 will produce -?- moles of
H2O ? - 0.25 x 2/2 0.25 mol H2O
27- 2 H2 O2 ? 2 H2O
- 14- 1.5 moles of H2 will produce -?- grams of
H2O ? - 1.5 x 2/2 x 18.0 27.0 g H2O
- Â
- 15- 14 moles of O2 will produce -?- moles of
H2O ? - 14 x 2/1 28.0 mol H2O
28Using Conversion Factors
- mass (g) x 1 mol given x mol unknown x
molar mass unknown mass - of given molar mass mol given
1 mol unknown of un- - substance of given
known - grams x 1 x mole ratio x molar mass
mass of unknown - given molar mass
- Do practice problems 1, 2, 3 on page 311 of
textbook. - Do section review problems 1 - 5 on page 311 of
textbook.
29Practice problems page 311
- NH4NO3 ? N2O 2 H2O
- 32 g N2O x 1 mol N2O x 1 mol NH4NO3 x 80 g
NH4NO3 60 g NH4NO3 - 44 g N2O 1 mol N2O 1 mol
NH4NO3
30Chapter 9 quiz 4- mass-mass problems
- Na2O CaF2 ? 2 NaF CaO
- 1- 124 g Na2O ? ? grams NaF
- 2- 124 g Na2O ? ? grams CaO
- 3- 234.3 g CaF2 ? ? g NaF
- 4- 234.3 g CaF2 ? ? g CaO
- 5- 84.0 g NaF ? ? g CaO
31Na2O CaF2 ? 2 NaF CaO
- 1- 124 g Na2O x 1 mol Na2O x 2 mol NaF x
42.0 g NaF 168 g - 62 g Na2O 1 mol Na2O 1 mol
NaF - 2- 124 g Na2O x 1 mol Na2O x 1 mol CaO x
56.1 g CaO 112.2 g - 62 g Na2O 1 mol Na2O 1 mol CaO
- 3- 234.3 g CaF2 x 1 mol CaF2 x 2 mol NaF x
42.0 g NaF 252 g - 78.1 gCaF2 1 mol CaF2 1 mol NaF
- 4- 234.3 g CaF2 x 1 mol CaF2 x 1 mol CaO x
56.1 g CaO 168.3 g - 78.1 gCaF2 1 mol CaF2 1 mol CaO
- 5- 84.0 g NaF x 1 mol NaF x 1 mol CaO x 56.1
g CaO 56.1 g - 42.0 g NaF 2 mol NaF 1 mol CaO
32The MOLE HILL
-
- x mole ratio
- moles known moles unknown
- molar mass x molar mass
- of known of unknown
- mass of known mass of unknown
33Stoichiometry Practice Problems
- 2 H2 O2 ? 2 H2O
- 1) 2.5 mol H2 x 1 mol O2 1.25 mol O2
- 2 mol H2
- 2) 2.5 mol H2 x 2 mol H2O 2.5 mol H2O
- 2 mol H2
- 3) 2.5 mol H2 x 1 mol O2 x 32 g O2 40 g O2
- 2 mol H2 1 mol O2
- 4) 2.5 mol H2 x 2 mol H2O x 18 g H2O 45 g
H2O - 2 mol H2 1 mol H2O
34Stoichiometry Practice Problems
- 2 H2 O2 ? 2 H2O
- 5) 16 g H2 x 1 mol H2 x 1 mol O2 4.0 mol O2
- 2 g H2 2 mol H2
- 6) 16 g H2 x 1 mol H2 x 2 mol H2O 8.0 mol H2O
- 2.0 g H2 2 mol H2
- 7) 16 g H2 x 1 mol H2 x 1 mol O2 x 32 g O2 128
g O2 - 2.0 g H2 2 mol H2 1 mol O2
- 8) 16 g H2 x 1 mol H2 x 2 mol H2O x 18 g H2O
144 g H2O - 2.0 g H2 2 mol H2 1 mol H2O
35Limiting Reactant Percentage Yield
- limiting reactant is the reactant that limits the
amount of the other reactant that can combine and
the amount of product that can be formed in a
chemical reaction. - excess reactant is the substance that is NOT
completely used up in a chemical reaction.
36Sample Practice Problems
- See sample problem F on page 313 of textbook.
- Do practice problems 1 on page 313.
- See sample problem G on pages 314-315.
- Do practice problems 1 2 on page 315.
37QuickLAB
- Do the QuickLAB titled Limiting Reactants in a
Recipe on page 316 of the textbook. - Yes, cooking IS chemistry!
38Percentage Yield
- theoretical yield is the maximum amount of
product that can be produced from a given amount
of reactant - actual yield of a product is the measured amount
of a product obtained from a reaction - percentage yield is the ratio of the actual yield
to the theoretical yield multiplied by 100 - percentage yield actual yield x 100
- theoretical yield
39Problems
- see sample problem H on pages 317-318 of textbook
- Do practice problems 1 2 on page 318.
- Do section review problems 1 - 4 on page
318. - Do critical thinking problems 37, 38, 39,
40 on pages 322 323.
40Chapter 9 test review
- 20 multiple choice questions
- definitions of composition reaction
stoichiometry - mole ratios their definition use
- SI units of molar mass
- identify mole ratio from balanced formula
equation - 5 mole-mole problems
- Definitions practical applications of excess
reactant limiting reactant - definitions practical applications of
theoretical yield, actual yield, yield
41Honors Chemistry Chapter 9 Test Review
- 25 multiple choice
- Know the definitions of reaction composition
stoichiometry, mole ratio, and units of molar
mass. - Know what mole ratio means and how it is used in
stoichiometry. - Determine mole ratio using balanced formula
equation. (2) - Perform mole to mole stoichiometric calculations
(4). - Perform mole to mass stoichiometric calculations
(1). - Perform mass to mole stoichiometric calculations
(1). - Perform mass to mass stoichiometric calculations
(1). - Know definitions and applications of limiting and
excess reactants. - Know the definitions applications of actual
yield, theoretical yield, and percent yield.
42Practice 2
- 2 Na3PO4 3 CaSO4 ? 3 Na2SO4 Ca3(PO4)2
- Known 3 moles CaSO4 unknown ? Moles Na3PO4
- 3 x 2/3 2 moles Na3PO4
- Known 2.0 moles Na3PO4 unknown ? Moles
Na2SO4 - 2 x 3/2 3 moles Na2SO4
- Known 1.5 moles Ca3(PO4)2 unknown ? Moles
CaSO4 - 1.5 x 3/1 4.5 moles CaSO4
- Known 4.4 moles CaSO4 unknown ? Moles
Na3PO4 - 4.4 x 2/3 2.9 moles Na3PO4
43- 2 Na3PO4 3 CaSO4 ? 3 Na2SO4 Ca3(PO4)2
- Known 6.0 moles Na3PO4 unknown ? Moles
Na2SO4 - 6.0 x 3/2 9.0 moles Na2SO4
- Known 5.4 moles CaSO4 unknown ? Moles
Na3PO4 - 5.4 x 2/3 3.6 moles Na3PO4
- Known 0.6 moles Na3PO4 unknown ? Moles
CaSO4 - 0.6 x 3/2 0.9 moles CaSO4
44Stoichiometry Practice 3
- 4 Na3N 3 O2 ? 6 Na2O 2 N2
- Assume you have 12.0 moles of Na3N.
- How many moles of O2 do you need?
- How many moles of Na2O will you get?
- How many moles of N2 will you get?
45Stoichiometry Practice 3
- 4 Na3N 3 O2 ? 6 Na2O 2 N2
- Assume you have 12.0 moles of Na3N.
- How many moles of O2 do you need?
- 12 x 3/4 9 moles O2
- How many moles of Na2O will you get?
- 12 x 6/4 18 moles Na2O
- How many moles of N2 will you get?
- 12 x 2/4 6 moles N2
46Practice 3
- 4 Na O2 ? 2 Na2O
- If you have 4 moles of Na, how many grams of O2
will you need? - If you have 64 grams of O2, how many moles of
Na2O will you produce? - If you have 46 grams of Na, how many grams of O2
will you need?
47Practice 3
- 4 Na O2 ? 2 Na2O
- If you have 4 moles of Na, how many grams of O2
will you need? - 4 x 1/4 x 32 32 grams O2
- If you have 64 grams of O2, how many moles of
Na2O will you produce? - 64/32 x 2/1 4 moles Na2O
- If you have 46 grams of Na, how many grams of O2
will you need? - 46/23 x 1/4 x 32 16 grams O2