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Calorimetry

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Title: Calorimetry


1
Calorimetry
  • Two types of calorimetry are commonly used
  • Constant-pressure Calorimetry
  • Specific heat
  • DHrxn or DHsoln
  • Bomb Calorimetry (Constant Volume Calorimetry)
  • DHcombustion

2
Calorimetry
  • In constant-pressure calorimetry,
  • Measurements are made in an open container.
  • Reactions occur at constant pressure
  • Calorimeter is insulated
  • Assume that the amount of heat gained from or
    lost to the surroundings is negligible
  • any heat gained or lost during a chemical
    reaction or process comes from or goes into the
    solution being studied.

3
Calorimetry
  • In constant-pressure calorimetry, the heat gained
    or lost by the solution (the liquid present) is
    measured as a means of determining how much heat
    was gained or lost by the reaction or process of
    interest.
  • If heat is lost by the chemicals (or object)
    during a reaction or process, then it must be
    gained by the solution and vice versa.
  • The heat lost or gained by the reaction (or
    object) and the solution are equal in magnitude
    but opposite in sign.
  • qobj - qsoln or qrxn - qsoln

4
Calorimetry
  • Calorimetry Simulation
  • Measuring the specific heat of a metal
  • How is the experiment performed?
  • What kind of data is collected?
  • How are the data used to determine specific heat?

5
Calorimetry
  • Determining specific heat or molar heat capacity
    experimentally
  • Heat an object with a known mass to 95-100oC.
  • Measure initial temperature of object.
  • Place known mass of water into calorimeter and
    measure its temperature.
  • Add hot object to the water
  • Measure the equilibrium temperature (i.e. final
    temperature) of the water and object.

6
Calorimetry
  • Types of data obtained from or used in a
    calorimetry experiment often include
  • Sample Data
  • Mass of sample (object or compound)
  • Tinitial (sample)
  • Tfinal (sample)
  • Solution Data
  • Mass of solution
  • Tinitial (solution)
  • Tfinal (solution)
  • Csoln
  • Often use specific heat of water if water is the
    solvent

7
Calorimetry
  • Using the data to find specific heat
  • Calculate the amount of heat gained by the water
  • qwater Cwater x mwater x DTwater
  • Calculate the amount of heat lost by the object
  • qobj - qwater
  • Calculate specific heat of object
  • Cobj qobj
  • mobj x DTobj

8
Calorimetry
  • Example A 55.0 g piece of aluminum metal at
    100.0oC was added to 51.3 g of water at 20.0oC.
    The equilibrium temperature of the system was
    35.0oC. If the specific heat of water is 4.18
    J/g.K, what is the specific heat of aluminum?

9
Calorimetry
10
Calorimetry
  • This is the same procedure you will use to
    calculate the specific heat of the metal sample
    you use in the lab.
  • Follow this procedure to do the calculations for
    Expt. 2.
  • You should expect a similar problem on your exam!

11
Calorimetry
  • Calorimetry Simulation
  • Measuring the molar heat of solution (DHsoln)
  • How is the experiment performed?
  • What kind of data is collected?
  • How are the data used to determine molar heat of
    solution?

12
Calorimetry
  • Determining molar heat of solution (DHsoln per
    mole of solute) from calorimetry data.
  • Place known mass of water into calorimeter.
  • Measure the initial temperature of the water.
  • Add known mass of solute to water.
  • Record equilibrium temperature of the resulting
    solution.

13
Calorimetry
  • Types of data collected when measuring molar heat
    of solution
  • Mass of water
  • Initial temperature of water
  • Mass of solute
  • Final temperature of solution

14
Calorimetry
  • Determining DHsoln per mole of solute from
    calorimetry data.
  • Assume Csoln Cwater 4.18 J/g-K unless told
    otherwise
  • Calculate the heat gained or lost by the entire
    solution
  • qsoln Csoln x mass of solution x DTsoln
  • Mass of solution mass of H2O mass of solute

15
Calorimetry
  • Calculate heat gained or lost by the solute
    (salt)
  • qsolute - qsoln
  • Calculate molar heat of solution
  • DHsoln per mole qsolute
  • mole solute

16
Calorimetry
  • Example When a 2.125 g sample of solid ammonium
    nitrate dissolves in 30.000 g of water in a
    constant pressure calorimeter, the temperature
    drops from 22.0oC to 16.9oC. Calculate the molar
    DHsoln (in kJ/mole NH4NO3 ) for the dissolution
    process
  • NH4NO3 (s) NH4 (aq) NO3- (aq)
  • Assume that the specific heat of the solution is
    the same as pure water (4.18 J/g.K).

17
Calorimetry
18
Calorimetry
19
Calorimetry
  • You should expect a calorimetry problem similar
    to this on your exam.
  • What would you actually observe when the
    dissolution process is exothermic?
  • What would you actually observe when the
    dissolution process is endothermic?

20
Calorimetry
  • For an exothermic process, the heat produced
    causes the temperature of the solution to
    increase. (DTsoln gt0)

Chemical particle
q
q
q
q
Heat released by chemical particle
q
q
q
21
Calorimetry
  • For an endothermic process, the heat gained comes
    from the reaction mixture and causes the
    temperature of the solution to decrease (DTsoln lt
    0)

q
Chemical particle
q
q
q
Heat gained by chemical particle from the rxn
mixture
q
q
22
Calorimetry
  • Bomb Calorimetry
  • Constant Volume Calorimetry
  • Used to study combustion reactions
  • Measure DHcombustion

23
Calorimetry
  • As combustion occurs,
  • Heat is released
  • Heat is absorbed by the calorimeter and its
    contents
  • Temperature of calorimeter contents increases.
  • The change in temperature of the calorimeter and
    its contents can be used to determine the heat of
    combustion.

24
Calorimetry
  • To calculate the molar heat of combustion from a
    calorimetry experiment
  • Calculate the heat absorbed by the calorimeter
    and its contents using the heat capacity of the
    calorimeter
  • qcal Ccal x DT
  • (Notice that you do not need a mass term because
    heat capacity has units of J/K)
  • Calculate the heat lost by the reactants
  • qrxn -qcal

25
Calorimetry
  • Calculate molar heat of combustion (DHcomb per
    mole reactant)
  • DHcomb qrxn
  • mole reactant

26
Calorimetry
  • Example When 2.00 g of methylhydrazine (CH6N2)
    is burned in a bomb calorimeter, the temperature
    of the calorimeter increases from 25.00oC to
    32.25oC. If the heat capacity of the calorimeter
    is 7.794 kJ/oC, what is the molar heat of
    combustion for CH6N2?

2CH6N2 (l) 5 O2(g) 2 N2 (g) 2 CO2(g)
6 H2O (g)
27
Calorimetry
28
Calorimetry
29
Hesss Law
  • The heats of reaction (DHrxn) have been measured
    and tabulated for many chemical reactions.
  • There are two approaches to determining the heat
    of reaction for a particular chemical reaction
  • Calorimetry
  • Use tabulated DHrxn to calculate the heat of
    reaction for another reaction of interest

30
Hesss Law
  • The enthalpy change for a reaction or process is
    a state function
  • Depends only on the amount of reactants and
    products used/formed and on their physical state
  • Does not depend on how the reaction was done.
  • one step vs. multiple steps

31
Hesss Law
  • Hesss Law
  • If a reaction is carried out in a series of
    steps, DH for the overall (one-step) reaction is
    equal to the sum of the DH for the individual
    steps.

32
Hesss Law
  • IMPORTANT
  • When applying Hesss Law, if you need to multiply
    or divide the coefficients of an equation by a
    number then the DH must also be multiplied by the
    same number
  • DH depends on amount of material
  • H2O (g) H2O (l) DH - 44 kJ
  • 2 H2O (g) 2 H2O (l) DH 2 (- 44 kJ) -
    88 kJ

33
Hesss Law
  • IMPORTANT
  • If a reaction has to be reversed, the magnitude
    of DH stays the same but the sign must be
    reversed.
  • H2O (g) H2O (l) DH - 44 kJ
  • H2O (l) H2O (g) DH 44 kJ

34
Hesss Law
  • Example Calculate the DHrxn for the combustion
    of C to CO
  • C (s) ½ O2 (g) CO (g)
  • given the following reactions
  • C (s) O2 (g) CO2 (g) DH - 393.5 kJ
  • 2 CO (g) O2 (g) 2 CO2 (g) DH - 566.0 kJ

35
Hesss Law
36
Hesss Law
  • Example Calculate DHrxn for
  • NO (g) O (g) NO2 (g)
  • using the following thermochemical equations.
  • NO (g) O3 (g) O2 (g) O2 (g) DH -198.9
    kJ
  • O3 (g) 3/2 O2 (g) DH -142.3 kJ
  • O2 (g) 2 O (g) DH 495.0 kJ

37
Hesss Law
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