Lecture 8: Dislocations - PowerPoint PPT Presentation

About This Presentation
Title:

Lecture 8: Dislocations

Description:

Lecture 8: Dislocations PHYS 430/603 material Laszlo Takacs UMBC Department of Physics Edge dislocation The crystal is partially cut, a new half-plane of atoms ... – PowerPoint PPT presentation

Number of Views:83
Avg rating:3.0/5.0
Slides: 12
Provided by: Lasz65
Category:

less

Transcript and Presenter's Notes

Title: Lecture 8: Dislocations


1
Lecture 8 Dislocations
  • PHYS 430/603 material
  • Laszlo Takacs
  • UMBC Department of Physics

2
Edge dislocation
  • The crystal is partially cut, a new half-plane of
    atoms inserted coherently with the rest of the
    structure and the bonds between layers
    re-established.
  • The Burgers vector is perpendicular to the
    dislocation line.

3
Dislocation on the surface of a real crystal
4
Sign convention for the Burgers vector Decide
the positive direction for the dislocation
line. Go around the line in a complete loop in
the positive direction. Draw a loop with the
same number of steps in a defect-free
lattice. The vector required to complete the
loop is the Burgers vector.
5
Screw dislocation
  • The crystal is partially cut, one side shifted by
    a lattice parameter, then the bonds are
    re-established between the two sides.
  • The Burgers vector is parallel to the line of
    the dislocation.

6
  • Dislocations are the primary carriers of plastic
    deformation.

7
  • Deformation can take place by both edge and screw
    dislocations

8
  • A mixed dislocation. The dislocation line can be
    bent, the Burgers vector remains the same along
    the dislocation.

9
Dislocation in a compound. There are both an
extra Mg and and extra O plane ending at the edge
of the dislocation.
10
Dislocation loop
  • Dislocations can begin and end at the surface of
    the crystal or at lattice defects. They can also
    form closed loops.
  • Notice that the Burgers vector is the same along
    the loop and its nature is edge or screw
    depending on the direction of the dislocation
    line.

11
Prismatic loop
  • The Burgers vector is perpendicular to the plane
    of the loop, thus it is edge dislocation all
    around. Equivalent to a partial extra lattice
    plane or a finite area of a lattice plane missing.
Write a Comment
User Comments (0)
About PowerShow.com