Structure/Function%20of%20Cell%20Components - PowerPoint PPT Presentation

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Structure/Function%20of%20Cell%20Components

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Title: PowerPoint Presentation Author: Gary Smith Last modified by: gs4030a Created Date: 9/17/2001 6:10:58 PM Document presentation format: On-screen Show – PowerPoint PPT presentation

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Title: Structure/Function%20of%20Cell%20Components


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Structure/Function of Cell Components
  • Living things are made of
  • Carbohydrates
  • Lipids
  • Proteins
  • Nucleic acids
  • CHNOPS
  • Carbon
  • Hydrogen
  • Nitrogen
  • Oxygen
  • Phosphorous
  • Sulphur

3
Basic Chemistry
Strong Bonds
  • Atoms make bonds
  • Ionic loss/gain of electrons
  • Covalent electrons are shared
  • Polar covalent unequal sharing of the electrons
  • Makes the atoms have a partial charge (polarity)
  • Hydrogen bonds
  • Between a polar covalently bonded hydrogen atom
    (e.g. to N or O) and another polar covalently
    bonded atom e.g. oxygen in a carbonyl group.
  • Polar covalent bonds, only a partial charge so
    relatively weak
  • Van der waals forces
  • Induced polarity (e.g. in C-H bond)
  • Hydrophobic Interactions
  • Non-polar groups tend to cluster together (away
    from water)
  • Polar groups tend to move towards water

Weak Bonds
4
CARBOHYDRATES
5
Carbohydrates
  • C, H, O
  • (CH2O)n
  • Monosaccharides - one monomer
  • Form rings in solution
  • Disaccharides - two monomers
  • Polysaccharides - many monomers
  • Monomers contain
  • 5 Carbon atoms - pentose
  • 6 carbon atoms - hexose

6
Carbohydrates
  • Saccharides can exist in solution as linear
    molecules or rings.
  • They interconvert between the two forms, but at
    equilibrium, 99 will be ring

7
Structural Variation in Carbohydrates
  • Special carbons
  • Carbon atoms 1-5 are chiral (optically active)
    i.e. OH and H groups on the C atoms can be
    ordered differently.
  • For C atoms 2-4 the arrangement of OH and H
    groups determines the monosaccharide .
  • Orientation of OH on Carbon 5 (in Hexoses)
    confers D (dextro rotatory) or L (laevorotatory)
    forms
  • D points right
  • L points left
  • Orientation of OH on Carbon 1 (in Hexoses)
    determines ? (down) or ? (up)

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Numbering
6
5
4
1
2
3
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The molecules are isomers, they differ in the
orientation of H and OH on C2-4.
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Note Fructose differs in the position of the
carbonyl important in forming rings
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? down, ? up
The OH group on the carbon next to the oxygen (C1)
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Forming Rings
1
Rings form between C1 and C5. An O atom acts as
a bridge (hence the 6 member ring).
2
Complex rearrangement
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4
5
6
13
Disaccharides
  • Two monosaccharides join together with a
    glycoside bond
  • Dehydration (condensation) reaction (elimination
    of water)
  • e.g. maltose (2 x glucose)
  • ? -D-glucose joined to ? -D-glucose
  • join at the C1 (?) and C4 atoms
  • ?1-4 glycoside bond

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  • ? 1,4, glycosidic bond - cellobiose

? 1,2 glycosidic bond -sucrose
? 1,6, glycosidic bond
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Polysaccharides
  • 3 major ones of interest
  • Starch
  • Glycogen
  • Cellulose

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STARCH
  • Comprised two components
  • Soluble part (20) - AMYLOSE
  • Continouous unbranched chain of glucose units (up
    to 300) joined by ?1-4 glycoside bonds.
  • Insoluble part (80) AMYLOPECTIN
  • Shorter ?1-4 chains (24-30), with ?1-6 branching

Starch, being insoluble exerts no osmotic
pressure, so is useful as a storage polysaccharide
21
GLYCOGEN
  • Animal storage polysaccharide
  • Similar to amylopectin,
  • Lower molecular weight
  • More highly branched
  • ?1-4 chains (up to 10), with ?1-6 branching

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CELLULOSE
  • Linear polymer of glucose units (up to 2800)
  • ? 1,4, glycosidic bonds
  • Cellulose fibre - parallel strands held together
    by hydrogen bonds

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