CHEM 120: Introduction to Inorganic Chemistry - PowerPoint PPT Presentation

1 / 101
About This Presentation
Title:

CHEM 120: Introduction to Inorganic Chemistry

Description:

CHEM 120: Introduction to Inorganic Chemistry Instructor: Upali Siriwardane (Ph.D., Ohio State University) CTH 311, Tele: 257-4941, e-mail: upali_at_chem.latech.edu – PowerPoint PPT presentation

Number of Views:353
Avg rating:3.0/5.0
Slides: 102
Provided by: Harri197
Category:

less

Transcript and Presenter's Notes

Title: CHEM 120: Introduction to Inorganic Chemistry


1
CHEM 120 Introduction to Inorganic Chemistry
  • Instructor Upali Siriwardane (Ph.D., Ohio State
    University)
  • CTH 311, Tele 257-4941, e-mail
    upali_at_chem.latech.edu
  • Office hours 1000 to 1200 Tu Th 800-900
    and 1100-1200 M,W, F

2
Chapters Covered and Test dates
  • Tests will be given in regular class periods 
    from  930-1045 a.m. on the following days
  • September 22,     2004 (Test 1) Chapters 1 2
  • October 6,         2004(Test 2)  Chapters  3,
    4
  • October 20,         2004 (Test 3) Chapter  5 6
  • November 3,        2004 (Test 4) Chapter  7 8
  • November 15,      2004 (Test 5) Chapter  9 10
  • November 17,      2004 MAKE-UP Comprehensive
    test (Covers all chapters
  • Grading
  • ( Test 1 Test 2 Test3 Test4 Test5)
    x.70 Homework quiz average x 0.30 Final
    Average
  •                               5

3
Chapter 4 Structure and properties of ionic and
covalent compounds
  • We now put atoms and ions together to form
    compounds

4
Chapter 4. Structure and Properties of Ionic and
Covalent Compounds
  • 1. Classify compounds as ionic, covalent, or
    polar covalent bonds.
  • 2. Write the formulas of compounds when provided
    with the name of the compound.
  • 3. Name common inorganic compounds using standard
    conventions and recognize the common names of
    frequently used substances.
  • 4. Predict the differences in physical state,
    melting and boiling points, solid-state
    structure, and solution chemistry that result
    from differences in bonding.
  • 5. Draw Lewis structures for covalent compounds
    and polyatomic ions.
  • 6. Describe the relationship between stability
    and bond energy.
  • 7. Predict the geometry of molecules and ions
    using the octet rule and Lewis structure.
  • 8. Understand the role that molecular geometry
    plays in determining the solubility and melting
    and boiling points of compounds.
  • 9. Use the principles of VSEPR theory and
    molecular geometry to predict relative melting
    points, boiling points, and solubilities of
    compounds.

5
Start learning the formulas and the names and
charges of the ions found in table
6
  • Why have we been so interested in where the
    electrons are in an atom? And what is the
    importance of valence electrons?
  • Valence es are involved in_______--the no of
    valence es has an important influence on ______
    of bonds formed. The filled inner core does not
    directly affect bond formation.

7
Compound
  • Bonds are formed by a transfer of ________ from
    one atom to another or by a ______ _________
    between 2 atoms.

8
Lewis (dot) Symbols
9
Lewis (dot) symbols
  • Introduced by G. N. Lewis
  • Useful for representative (sp block) elements
    only
  • Group no. no of valence e-s (no of dots)

10
Lewis symbols for A groups
  • The elements symbol represents the inner core of
    electrons. Put a dot for each valence electron
    around the symbol.
  • Remember that the no. of valence electrons for
    the A groups is equal to ?
  • Each unpaired electron may be used in bond
    formation

11
Remember the octet rule from chapter 3
  • So the ions formed by the elements in
  • IA
  • IIA
  • IIIA
  • VA
  • VIA
  • VIIIA

12
(No Transcript)
13
Ionic bonding
  • Extra stability has been noted for the noble gas
    configuration (8 e-s in valence shell)--(for A
    elements)
  • Ionic bonding
  • Each atom in the ionic bond

14
  • Ionic compounds are formed between
  • And
  • When forming an ionic bond each atom in the bond
    attains a noble gas configuration by a complete
    transfer of

15
  • An ionic bond is the electrostatic force that
    holds ions together in an ionic compound
  • An ionic bond is a very strong bond ionic cmpds
    have high m and b pts.

16
Typical ionic reactions with Lewis structures
17
What about Li and S?
18
What about Ca and O
  • Formula is

19
What about Ca and N?
  • Formula is

20
Covalent bonding
  • Not all bonds are ionic.
  • ________ bonds are bonds in which two (or more)
    electrons are ______ by two atoms.
  • One shared electron pair is

21
(No Transcript)
22
  • A reminder
  • Only valence electrons are involved in bonding.
    Group No. valence e-s for A elements.
  • Covalent bonds are formed
  • Each atom in bond attains noble gas configuration
    by sharing of e- pairs (H2 bond only has 2 e-s)

23
Covalent bond formation
  • Look at formation of H2 molecule.
  • H. .H ----gt HH (H-H)
  • 1s1 1s1 bond formed by
    overlap of
    1s orbitals

24
What about F2 or Cl2?
25

____ _____ - pairs of valence electrons not
involved in covalent bond formation Lewis
structure - representation of covalent bonding in
which lone pairs are shown as pairs of dots and
bonding pairs are (usually) shown as lines
26
Polar covalent bonding and electronegativity
  • Not all covalent bonds are formed btn the same 2
    atoms (as H2, homonuclear diatomic
    _______sharing of e-s in bond)

27
Polar covalent bonds
  • What about the bond in H-F?
  • It is known that F is more likely to attract e-s
    to itself than H, leading to an unequal sharing
    of the e- pair.
  • The covalent bond in which there is unequal
    sharing

28
Polar covalent bond or polar bond is a covalent
bond with greater electron density around one of
the two atoms
electron rich region
electron poor region
e- rich
e- poor
d
d-
9.5
29
Continuum of bond polarity
  • (Nearly) complete e- transfer ionic bond
  • Unequal sharing of e- pair polar covalent bond.
  • e-s are polarized toward Cl
  • Equal sharing of e- pair nonpolar covalent bond

30
Electronegativity
  • Electronegativity
  • .
  • Eneg is a relative concept. Elements with

31
Lanthanides 1.1-1,3 Actinides 1.3-1.5
32
Electronegativity differences
  • 0.2 - 0.5 will be a ________________ bond
  • 0.5 - 1.6 will be a ________________ bond
  • gt 1.6 will be a ________________ bond

33
Electronegativity differences
  • In general the _______ the difference in eneg btn
    the 2 atoms in the bond, the ____ ______ the
    bond.
  • If the difference is zero, bond (equal
    sharing of electron pair(s) (H2, Cl2, O2, F2, N2)

34
  • If the difference is gt0 and lt1.9, have a
    HCl (3.0 - 2.1) HF (4.0-2.1) OH (3.5-2.1)
  • If the difference is gt 1.9, have NaCl
    (3.0-0.9) CaO (3.5-1.0)

35
Classify as ionic or covalent
  • NaCl
  • CO
  • ICl
  • H2

36
  • Which bond is the most polar (most ionic), which
    the least polar (most covalent)?
  • Li-F Be-F B-F C-F N-F O-F F-F

37
  • Classify the following bonds as ionic,
    polar covalent, or covalent. A) the CC bond
    in H3CCH3
  • B) the KI bond in KI
  • C) the NB bond in H3NBCl3
  • D) the CF bond in CF4

38
Chemical formulas
  • Express composition of molecules (smallest unit
    of covalent cmpds) and ionic compounds in
    chemical symbols
  • H2O, NaCl

39
Writing formulas for ionic cmpds
  • Compounds are neutral overall. Therefore
  • NaCl is array of Na and Cl- ions
  • Na2S is array of Na and S2- ions

40
Predict the formulas for the cmpd formed btn
  • Potassium and chlorine
  • Magnesium and bromine
  • Magnesium and nitrogen

41
(No Transcript)
42
Symbol Name Symbol Name
H Hydrogen ion H- Hydride ion
Li Lithium ion F- Fluoride ion
Na Sodium ion Cl- Chloride ion
K Potassium ion Br- Bromide ion
Be2 Beryllium ion I- Iodide ion
Mg2 Magnesium ion O2- Oxide ion
Ca2 calcium ion S2- Sulfide ion
Ba2 barium ion N3- Nitride ion
Zn2 zinc ion P3- Phosphide ion
43
Formula Name Formula Name
NO3- nitrate CO32- carbonate
NO2- nitrite SO42- sulfate
CN- cyanide SO32- sulfite
MnO4- permanganate PO43- phosphate
OH- hydroxide PO33- phosphite
O22- peroxide ClO4- perchlorate
HCO3- hydrogen carbonate ClO3- chlorate
HSO4- hydrogen sulfate ClO2- chlorite
HSO3- hydrogen sulfite ClO- hypochlorite
HPO42- hydrogen phosphate CrO42- chromate
H2PO4- dihydrogen phosphate C2H3O- 2 acetate
44
Symbol (Stock system) Common Symbol (Stock system) Common
Cu copper(I) cuprous Hg22 mercury(I) mercurous
Cu2 copper(II) cupric Hg2 mercury(II) mercuric
Fe2 iron(II) ferrous Pb2 lead(II) plumbous
Fe3 iron(III) ferric Pb4 lead(IV) plumbic
Sn2 tin(II) stannous Co2 cobalt(II) cobaltous
Sn4 tin(IV) stannic Co3 cobalt(III) cobaltic
Cr2 chromium(II) chromous Ni2 nickel(II) nickelous
Cr3 chromium(III) chromic Ni4 nickel(IV) nickelic
Mn2 manganese(II) manganous Au gold(I) aurous
Mn3 manganese(III) manganic Au3 gold(III) auric
45
Polyatomic ions Table
  • Just have to memorize
  • NH4 ammonium ion
  • CO32- carbonate ion
  • CN- cyanide ion
  • HCO3- hydrogen (or bi) carbonate ion
  • OH- hydroxide

46
  • NO3- nitrate ion
  • NO2- nitrite ion
  • PO43- phosphate ion
  • SO42- sulfate ion
  • HSO4- hydrogen sulfate ion
  • SO32- sulfite ion
  • CH3COO- (C2H3O2-) acetate ion

47
  • These polyatomic ions also form ionic cmpds when
    they are reacted with a metal or a nonmetal in
    the case of the ammonium ion (or with each other
    as ammonium sulfate). These polyatomic species
    act as a

48
  • So the formula for the cmpd formed btn the
    ammonium ion and sulfur would be
  • and between calcium and the phosphate ion

49
  • Ionic cmpds do not exist in discrete pairs of
    ions. Instead, in the solid state, they exist as
    a three dimensional array--crystal lattice --of
    cations and anions--are neutral overall,

50
Given name, write formula
  • potassium oxide
  • magnesium acetate

51
Naming ionic cmpds
  • Name the cation and anion but drop the word ion
    from both. This includes the polyatomic ions.
  • Na2S
  • Ca3N2

52
Name
  • Na3PO4
  • NH4Cl
  • K2S

53
Cations with more than one charge
  • Cu copper(I) Cu2 copper(II)
  • So Cu2O is and
  • CuO is

54
Given name, write formula
  • Ammonium chloride
  • potassium cyanide
  • silver oxide
  • Magnesium chloride
  • Sodium sulfate
  • Iron(II) chloride

55
To name covalent cmpds
  • Name the parts as for ionic cmpds (CO carbon and
    oxide) but tell how many of each kind of atom by
    use of Greek prefixies. (Table 4.4)
  • The mono- (for 1) may be omitted for the first
    element

56
  • Prefix meaning
  • Mono- 1
  • Di- 2
  • Tri- 3
  • Tetra- 4
  • Penta- 5
  • Hexa- 6
  • Hepta- 7
  • Octa- 8
  • Nona- 9
  • Deca- 10

57
  • CO
  • CO2
  • P4S10
  • Boron trichloride
  • Water H2O Ammonia NH3

58
Write formula
  • Diboron trichloride
  • Sulfur trioxide
  • Potassium sulfide

59
Covalent cmpds
  • Remember covalent cmpds--
  • A _________ is the smallest unit of a covalent
    cmpd that retains the characteristics of the
    cmpd. Molecule - two or more atoms in a definite
    arrangement held together by chemical bonds.
    (H2O, Cl2) Cl2 is considered a molecule but not
    a cmpd
  • Molecular cmpds exist as

60
Comparison of properties of ionic and covalent
cmpds
  • Physical state
  • Ionic cmpds are
  • Molecular cmpds can be

61
Comparison continued
  • Melting (___________) and boiling
    (_________) pts
  • In general the melting and boiling temps are much
    _______for ionic cmpds than for molecular
    (covalent) cmpds. The ionic bond is very strong
    and requires a lot of (heat) energy to break the
    bond. The bond btn molecular species is not as
    strong.

62
Comparison continued
  • Structure in solid state
  • Ionic solids--
  • Covalent solids--

63
Comparison continued
  • In aqueous (H2O) solution
  • Ionic cmpds dissociate into the
  • Many covalent cmpds when dissolved in water
    retain their structure and molecular identity

64
  • Learn the names, formulas, charges, etc for those
    ions highlighted in table 4.3.
  • HCO3- you should learn as bicarbonate

65
Writing Lewis structures for covalent species
  • These rules are for covalently bonded cmpds only
    (btn 2 or more nonmetals)
  • Do not use them for ionic cmpds.
  • 1. Count the total no. of valence electrons (the
    group no. is equal to the no. of valence
    electrons).
  • if the species is an anion, increase the no. of
    valence electrons by the charge on the ion

66
  • if the species is a cation, subtract the charge
    of the cation from the total no. of valence
    electrons.
  • 2.Count the total no. of atoms, excluding H, in
    the molecule or ion. Multiply that no. by 8.
  • Exception multiply the no. of Hs by 2.
  • This tells you how many electrons you would need
    if you were putting 8 electrons around all atoms
    without any sharing of electrons (and 2 around
    all Hs).

67
  • 3. Subtract the no. of e-s calculated in step 1
    from the no. in step 2. This gives you the no. of
    e-s that must be shared to get an octet around
    all atoms in the molecule.
  • 4. no. of e-s that must be shared /2 gives you
    the no. of bonds.
  • 5. subtract the no. of e-s that are shared (from
    step 3) from the total no. of valence e-s. This
    gives you the no. of unshared e-s.
  • If you divide the no. of unshared e-s by 2 you
    get the no. of lone pairs.

68
  • Write the skeletal structure and fill in with the
    info you came up with. After youve put in the
    bonds calculated, fill in the octets.
  • H (and F) form only one bond. Therefore they can
    only be terminal atoms in a structure.
  • So you can not have
  • C---H---C
  • It has to be H---C--C

69
  • Examples
  • CH4
  • PCl3
  • SO32-
  • NO3-
  • CN-
  • COBr2 (C is bonded to O and Br atoms)
  • SO2
  • H3O (hydronium ion
  • N3-

70
Draw Lewis structure of CO2 i) Valence
electrons 4 2 x 6 16 ( 8 pairs) ii)
Central atom C O -- C -- O iii)
Give octet to carbon
-- O -- C --
O -- Try to
fill octet to O iv) Count electrons 4 bond
pairs 4 pairs 4 lone pairs 4 pairs
8 electron pairs
71
Multiple bonds
  • In general a triple bond (N2) is ________ than a
    double bond (O2) which is ________than a single
    bond (F2).
  • Bond order BO of 1--single bond, BO of 2--
    -double bond, BO of 3 --triple bond.
  • The stronger the bond,

72
Terminology used in describing Lewis structures
of molecules Bond pairs An electron pair shared
by two atoms in a bond. Lone pair An electron
pair found solely on a single atom. Single
covalent bond - Bond between two atoms when
they shared 1 pair Double covalent bond Bond
between two atoms when they shared 2
pairs. Triple covalent bond Bond between two
atoms when they shared 3 pairs. Lewis Structure,
Stability, Multiple Bonds, and Bond Energies
Bond order The stability of a covalent
compound is related to the bond energy. The
magnitude of the bond energy increases and the
bond length decreases in the order single bond
gt double bond gt triple bond. Bond Energy order
single lt double lt triple Bond length order
single (1) lt double (2) lt triple (3)
73
Resonance
  • Resonance structure 1 of 2 or more Lewis
    structures for a molecule (ion) that cant be
    represented with a single structure
  • Resonance use of

74
(No Transcript)
75
  • Each resonance structure contributes to the
    actual structure
  • no single structure is a complete description
  • positions of atoms must be the same in each, only
    electrons are moved around
  • actual structure is an average

76
  • Draw resonance structures for SO3 and N3-.

77
Exceptions to Octet Rule
  • There are three classes of exceptions to the
    octet rule.
  •  
  • 1) Molecules with an odd number of electrons
  • 2) Molecules in which one atom has less than an
    octet
  • 3) Molecules in which one atom has more than an
    octet.

78
Lets do Lewis structures for
  • CO2 (CS2)
  • O3 (SO2)
  • I3-

79
3D structure of species
  • Electrostatic forces in ionic bonds is
    _____________. But species with covalent bonds
    have electron pairs concentrated btn 2 atoms and
    is ..
  • We use VESPR theory to predict the shape of the
    covalently bound species.

80
VSEPR theory
81
VSEPR
  • Most stable geometry is one in which electron
    pairs (electron clouds) are as

82
Shapes of molecules (3D)
  • The geometry is determined by the atoms present
    in the species. See atoms that are bonded to
    other atoms. Dont see lone pairs but they
    influence geometry
  • I. Diatomics (2 atoms only) always ________
  • H2, HCl, CO X----X

83
  • II. Polyatomic (3 or more atoms) species
    Use VSEPR model to predict shapes

84
Steps in applying VSEPR
  • 1. Do Lewis structure
  • 2. Count total e- pairs (clouds) around central
    atom (A). Multiple bonds count as one electron
    pair (cloud). In reality multiple bonds are
    bigger than single bonds (electron clouds
    larger).

85
  • 3. Separate e- pairs into bonded pairs (B) and
    lone pairs (E)
  • 4. Apply table that I give you.
  • 5. Remember that lone pairs of e-s are
    invisible, but their presence affects the final
    molecular geometry!!!!!
  • Lone e- pair-lone e-pairs are more repulsive than
    bonded pair-lone pair repulsions or bonded
    pair-bonded pair repulsions.

86
VSEPR valence shell electron pair repulsion
  • 2 electron clouds around a central atom (A)

87
2 electron clouds
88
Three electron clouds
89
Three electron clouds
90
Four electron clouds
91
Table 4.5 (changed)
  • e bonded lone pairs geom
    angle clouds pairs pairs
  • 2
  • 3
  • 3
  • 4
  • 4
  • 4

92
Predict geometry
  • H2S
  • SO2
  • CO2
  • CF4
  • H2CO
  • ClO3-
  • ClO2-

93
Polar vs nonpolar cmpds
  • A molecule is polar if its centers of positive
    and negative charges do not coincide. If a
    molecule is polar we say that it acts as a
    dipole. In an electric field nonpolar molecules
    (positive and negative centers coincide) do not
    align with the field but polar molecules do.
  • Next we will see why this happens and the
    implications.

94
Molecules are subjected to electric field Polar
molecules align with field Nonpolar molecules are
not affected
95
Polar molecules
  • I. Diatomics, A-B
  • a.If A B have homonuclear diatomic has
  • b. A ? B have heteronuclear diatomic

96
  • II. Polyatomic species are more complicated.
  • Lets look at VSEPR cases considered.
  • General rule (my rule)

97
Which of these are polar?
  • H2S
  • SO2
  • CO2
  • CF4
  • AlCl3
  • CHCl3
  • SCl2

98
Properties based on electronic structure and
molecular geometry
  • Intramolecular forces within a molecule--bonds
  • Intermolecular forces between molecules--these
    determine important properties as melting and
    boiling points and solubility

99
Solubility
  • Like dissolves like
  • Polar cmpds dissolve in polar solvents as
    ionic and polar cmpds (HCl) in water
  • Nonpolar cmpds dissolve in nonpolar solvents
    oils in CCl4

100
Melting and boiling points
  • Stronger the intermolecular forces the higher the
    melting and boiling points
  • In general for cmpds of similar weight polar
    moleculaes have stonger forces than nonpolar
    cmpds
  • In general for similar structure the greater the
    mass the stronger the forces

101
Which have higher melting (boiling pts)
  • CO and NO
  • F2 and Br2
  • CH3CH2OH and CH3CH3
Write a Comment
User Comments (0)
About PowerShow.com