Solution Chemistry Test Review Work Stations

1
Solution Chemistry Test Review Work Stations
2
Station 1 Solubility Concepts

1. Identify the three factors that affect the rate
   of solution formation.
2. Identify the two components of a solution.
3. What units do we use to express solubility?
4. What are the factors that affect solubility?
5. What does a solution look like when it is
   supersaturated?
6. How can you determine the saturation point of a
   substance using lab techniques? (HINT think
   about the procedures of the Solubility Curve
   Lab from last week)

3
Station 1 Solubility Concepts Answer Key

• 1. Agitation, temperature change, particle size
• 2. Solute, solvent
• 3. grams solute/100 g of solvent
• 4. temperature and pressure
• 5. solid precipitates out when cooled
• 6. raise the solution until all solute
  dissolves. Lower temperature and record
  temperature at the instant solid crystals form in
  solution.

4
Station 2 Solubility Curves

• See next slide for worksheet.

5
Solubility WS DIRECTIONS Use the solubility
curve from the previous packet to answer the
following questions. ___________1) What is the
solubility of potassium nitrate in 100 grams of
water at 20 C ?___________2) What is the
solubility of potassium chloride in 100 grams of
water at 50 C ?___________3 )What is the
solubility of sodium chloride in 100 grams of
water at 90 C ? ___________4) What is the
minimum temperature needed to dissolve 60 grams
of potassium nitrate in 100 grams of
water___________5) What is the minimum
temperature needed to dissolve 35 grams of
potassium chloride in 100 grams of
water___________6) At what temperature do
potassium chloride and potassium nitrate have the
same solubility ?___________7) If 110 grams of
potassium chloride are mixed with 100 grams of
water at 20 C, how much will not dissolve
?___________8) If 120 grams of potassium
nitrate are mixed with 100 grams of water at 60
C, how much will not dissolve ?___________9)
If 15 grams of potassium chloride are added to
100 grams of water at 30 C, how much more must
be added to saturate the solution?___________10)
If 85 grams of potassium nitrate are added to
100 grams of water at 70 C, how much more must
be added to saturate the solution?___________11)
100 grams of water at 95 C are saturated with
sodium chloride. If this solution is cooled to
35C, how much of the solid will
precipitate? ___________12) 100 grams of water
at 90 C are saturated with potassium chloride.
If this solution is cooled to 35C, how much of
the solid will precipitate?___________13) How
much potassium chlorate will dissolve in 200
grams of water at 70 C ? ___________14) How
much potassium nitrate will dissolve in 300 grams
of water at 10 C ? ___________15) How much
potassium chloride will dissolve in 50 grams of
water at 50 C ?
6
Station 2 Solubility Curves

• 34 g
• 43 g
• 39g
• 37 C
• 25 C
• 20 C
• 76-77g
• 7 g
• 22g
• 51-55 g
• 2 g
• 18 g
• 70 g
• 66 g
• 21-22 g

7
Station 3 Molarity

• 1. Define Molarity, then calculate the molarity
  of each solution
• 1.0 mol KCl in 750 mL of solution
• 0.5 mol MgCl2 in 1.5 L of solution
• 2. Calculate the moles and grams of solute in
  each solution
• 1.0L of 0.50 M NaCl
• 500 mL of 2.0 M KNO3
• 250 mL of 0.10M CaCl2

8
Station 3 Molarity

• 1. a.1.3 M KCl, b.0.33 M MgCl2
• 2. a. 0.5 mol NaCl, 29 g NaCl
• b. 1.0 mol KNO3, 100 g KNO3
• C. 0.025 mol CaCl2, 2.8 g CaCl2

9
Station 4- molality

• 1. Distinguish between a 1 M solution and a 1 m
  solution.
• Describe how you would prepare a 1.00 m solution
  of glucose. (i.e., grams of glucose needed in
  1000 g of water?)
• Describe how you would prepare a 0.500 m solution
  of sodium chloride. (i.e., grams of sodium
  chloride in 1000 g of water?)

10
Station 4- molality

• 1. 1 M solution 1 mol of solute in 1 L of
  solution 1 m solution 1 mol of solute in
  1000g/1 kg of solvent
• 2. Dissolve 180 g (1 mole) of glucose in 1 kg of
  water.
• 3. Dissolve 29.3 g of NaCl (0.5 mole) in 1 kg of
  water.

11
Station 5 Percent Solutions

• 1. Calculate the grams of solute required to
  make the following solutions
• 2500 g of saline solution (0.90 NaCl (m/m))
• 0.050 kg of 4.0 (m/m) MgCl2
• What is the concentration ( in (v/v)) of the
  following solutions?
• a) 25 mL of ethanol (C2H5OH) is diluted to a
  volume of 150 mL with water.
• 175 mL of isopropyl alcohol (C3H7OH) is diluted
  with water to a total volume of 275 mL

12
Station 5 Percent Solutions

• 1. a. 23 g NaCl
• B. 2.0 g MgCl2
• a. 16 (v/v) ethanol
• b. 63.6 (v/v) isopropyl alcohol

13
Station 6 Molarity by Dilution

1. How many mL of 4.00 M KI are needed to prepare
   250.0 mL of 0.760 M KI?
2. How could you prepare 250 mL of 0.20 M NaCl using
   only a solution of 1.0 M NaCl and water?
3. How many milliliters of 0.500 M KCl solution
   would you need to dilute to make 100.0 mL of
   0.100 M KCl?

14
Station 6 Molarity by Dilution

• 1. 47.5 mL
• 2. Add 50 mL of the 1.0 M solution to a 250 mL
  volumetric flask, then fill to the mark.
• 3. 20 mL.

15
(No Transcript)